Answer:
Once static friction gives up, it allows the box to begin sliding across the floor, the frictional force acting on the box, is now the force of sliding friction exerted by the floor on the box
Explanation:
.
How do microorganisms work as decomposers in an ecosystem
Answer:
they eat what is decomposing speeding up the decomposition
What simple machine did you find the most useful in everyday life? Explain why.
Simple machines are advantageous because they lessen labor requirements or enable people to undertake things that would otherwise be beyond their capacity.
What six simple machines can you recall?The airplane, wedge, screw, lever, pulley, and wheel-and-axle are the six most typical simple machines. They are made to change the direction or strength of the force (remember that work is equal to force times distance), which makes the task easier to complete.
Which basic machines are the most popular ones?Simple machines including the axle, wheel and axle, pulleys, inclined plane, screw, wedge, and lever are frequently utilized. Although simple machines may increase or decrease the forces which can be applied on them, they have no effect on the overall amount of work required to complete the activity.
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if a vehicle is of length 4.7 m on the average, what is the average spacing between vehicles at the above traffic density?
Average vehicle spacing at higher traffic density is 35.4 m for a vehicle with a length of 4.7 m.
Let's assume that Traffic flows at 96 km/h as per international data.
We need to find average vehicle spacing.
It indicates that a 96 km stretch of traffic gets cleared in one hour. In addition, 2400 cars may be supported in one lane for an hour. It implies that at least 96km must be taken up by 2400 automobiles. Congestion results from more vehicles moving at the same speed but occupying a smaller space as the number of automobiles increases.
Here, the key to the issue is that you must just consider length. 96 kilometres equal 96,000 metres at this time. If 2400 automobiles take up this much space [just lengthwise], 1 car will take up 96000/2400 m. it is 40 metres. Therefore, each automobile may use up 40m. But the automobile is 4.2 metres long.
It can thus also have a free space of 40 - 4.6 = 35.4 m.
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A 7. 00-kg box is attached to a 3. 00-kg box by rope 1. The 7. 00-kg box is pulled by rope 2 with a force of 25. 0 N. Determine the acceleration of the boxes and the tension in rope 1. The coefficient of friction between the ground and the boxes is 0. 120
Answer:
net force=applied force
Explanation:
...........................................
In the Soapbox Derby in, young participants build non-motorized cars with very low-friction wheels. Cars race by rolling down a hill. Assume that the track begins with a 51-ft-long (1 m= 3.28 ft) section tilted 14 ∘ below horizontal.
What is the maximum possible acceleration of a car moving down this stretch of track?
If a car starts from rest and undergoes this acceleration for the full l, what is its final speed in m/s ?
(a) The maximum possible acceleration of a car moving down this stretch of track is 2.38 m/s².
(b) The final speed of the car is 8.6 m/s.
What is the coefficient of friction on the incline?The coefficient of friction acting on the inclined surface is calculated by applying the following formula.
μ = tanθ
where;
θ is the angle of inclination of the inclineμ = tanθ
μ = tan (14)
μ = 0.25
The maximum possible acceleration of a car moving down this stretch of track is calculated as follows;
ma = μmg cosθ
a = μg cosθ
a = ( 0.25 x 9.8 m/s² ) x cos (14)
a = 2.38 m/s²
The final speed of the car when accelerating at maximum acceleration is calculated as follows;
s = distance travelled by the car = length of the incline
s = ( 1 m / 3.28 ft ) x ( 51 ft ) = 15.55 m
v² = u² + 2as
where;
u is the initial speed of the car = 0v is the final speedv² = 0 + 2as
v² = 2as
v = √ ( 2as )
v = √ ( 2 x 2.38 x 15.55 )
v = 8.6 m/s
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Two tiny conducting spheres are identical any carry charges of `-20.0 mu C` and `+50.0 muC`. They are separated by a distance of 2.50 cm. The spheres are brought into contact and then separated to a distance of 2.50 cm. Determine the magnitude of the force that each sphere now experiences, and state whether the force is attractive or repulsive.
A. 1.30 x 10^(2) N, attractive
B. 3.24 x 10^(3) N, attractive
C. 3.24 x 10^(3) N, repulsive
D. 1.44 x 10^(4) N, repulsive
The magnitude of the force that each sphere before contact and after contact are 1.438 × 10¹⁶ N and 3.5 × 10¹⁴ N respectively.
"Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them." It runs on the same track as the two charges, which are thought of as point charges.
Q₁ = -20 C
Q₂ = +50 C
Distance d = 2.5 cm equals 0.025 metres
F = (k Q₁ Q₂)/d² = (8.99 × 10⁹ × 20×50) /(0.025)² = 1.438×10¹⁶ N
Given that, the charges have opposing signs, the force is alluring.
The charge on each sphere after contact,
Q = Q₁ + Q₂/2 = -20+ 50/2 = -20 + 25 = 5 C
Magnitude of force = k Q²/d² = (8.99× 10⁹ × 5²)/(0.025)² = 224.75× 10⁹/(0.000625) = 359600× 10⁹ = 3.5 × 10¹⁴ N
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a car can sustain a maximum acceleration of 1 m/s/s, a maximum deceleration of 2 m/s/s, and a top speed of 20 m/s. determine the minimum amount of time it will take for this car to travel one kilometer if it starts from rest and finishes at rest, i.e., stops at the one kilometer mark g
If it starts from rest can travel 1000m, in a straight path, and again it has to come to rest at the end of 1000m, then minimum 70s will be taken.
According to the question, the car starts off at a stop, travels up to a top speed of 20 m/s, and then comes to a stop. This implies that the vehicle must have first reached its maximum speed before braking to a stop.
Let, [tex]T_1[/tex] and [tex]T_2[/tex] be the time for acceleration (attaining maximum velocity) and deceleration (come to the rest) respectively.
Then,
[tex]T_1[/tex] = (Maximum velocity - initial velocity) / acceleration
⇒ [tex]T_1=\frac{20-0}{1}=20sec[/tex]
Then, distance travelled in time [tex]T_1[/tex],
⇒ [tex]S_1=UT_1+\frac{1}{2}aT_1^2[/tex]
⇒ [tex]S_1=0+\frac{1}{2}*1*20^{2}[/tex]
⇒ [tex]S_1= 200m[/tex]
Similarly,
⇒ [tex]T_2=\frac{0-20}{-1}=20sec[/tex]
⇒ [tex]S_2=UT_2+\frac{1}{2}aT_ 2^2[/tex]
⇒ [tex]S_2=(20*20)-(\frac{1}{2}*1*20^2)[/tex]
⇒ [tex]S_2=400-200=200m[/tex]
∴ Distance travelled at uniform velocity is
⇒ [tex]S = 1000-(S_1+S_2)[/tex]
⇒ [tex]S=1000-(200+200)=1000-400=600m[/tex]
This 600m is travelled at a speed of 20m/s.
and time of travel for constant velocity is
⇒ [tex]T_3=\frac{S}{V}[/tex]
⇒ [tex]T_3=\frac{600}{20}=30sec[/tex]
Hence, total time for travel
⇒ [tex]T=T_1+T_2+T_3=(20+20+30)sec=70sec[/tex]
On a V-T graph, it can be displayed here(See picture).
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A baseball pitcher can throw a 132 km/h (82 mph) curve ball that
rotates about 6. 0×102 rpm. What is the angular velocity of the
thrown ball? The pitcher's throwing motion lasts about 0. 15 s, and
the moment of inertia of the ball is 8. 0x10-5 kg-m?. What average
torque did the pitcher exert on the ball?
If someone can please solve this right now it’ll be a big help!!
According to its definition, the net force is the total of all the forces operating on an object.So, 108.46 N force is exerted on the ball.
What is the ball's angular velocity when it is thrown?According to its definition, the net force is the total of all the forces operating on an object.
Mass can be propelled forward by net force.In motion or at rest, another force exerts its influence on the body.When a system contains a sizable number of forces, the term "net force" is employed.
It is given that,
Initial velocity of the baseball, u = 0
The baseball's final speed was 97 mph, or 43.36 m/s.
Mass of baseball, m = 0.15 kg
Distance, s = 1.3 m
(a) Let a be the acceleration of the baseball. Use third equation of motion as :
a = 43.36 /2*1.3
a = 723.11 m/s
Force is given by :
F = m a
F = 0.15 * 723.11= 108.46 N
So, 108.46 N force is exerted on the ball.
(b) The pitcher would need to increase the force so as to alter the required force to reach the same speed if the mass of the ball is decreased.
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will wants to allow sunlight into his living room, but he needs to angle the light to avoid glare on his tv. which window treatments will achieve this result?
Blinds window treatments will allow sunlight into his living room, but he needs to angle the light to avoid glare on his tv.
Even additional light will enter through the open window, further illuminating the space. You should think about some strategic lighting solutions for dark spaces in addition to trying to increase any available natural light.
East and west-facing windows frequently receive excessive sunlight, exposing these rooms to the sun at its hottest part of the day. The warmth in the room rises due to the sun's glare through these windows, which might make it difficult to read or watch television.
According to Lowe's, temporary heat-control window film should be used to cover windows that face south and west in order to reduce glare from the sun. This film is specifically created to prevent UV sun rays while yet allowing allowing some daylight to enter.
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a 700 kg car moving at 20 m/s collides with a stationary truck with mass 1400 kg. the two vehicles interlock as a result of the collision. what is the speed of the car/truck combination? what type of collision is this (elastic, inelastic, or explosion)?
The speed of the car truck combination is calculated to be 0.667 m/s and it is a type of inelastic collision.
Mass of the car m₁ = 700 kg
Velocity of the car u₁ = 20 m/s
Mass of the stationary truck m₂ = 1400 kg
Velocity of the stationary truck u₂ = 0
The momentum before collision is, m₁ u₁ = 700× 20 = 1400 kg m/s
As, we know from the principle of conservation of linear momentum,
momentum before the collision of trucks is equal to momentum after the collision of trucks.
The momentum after the collision is (m₁ + m₂) vf = 1400 kg m/s
(700 + 1400) vf = 1400
2100 vf = 1400
vf = 0.667 m/s
Now, let us compare kinetic energies before and after collision.
Kinetic energy before collision = 1/2 m₁ u₁² = 1/2 × 700× 20² = 14×10⁴ kg m/s
Kinetic energy after collision =1/2 (m₁+m₂) vf₂ = 1/2(700 + 1400) 0.667² = 467.13 kg m/s
As kinetic energy is not conserved, the type of collision is said to be an inelastic collision.
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while a car travels around a circular track at a constant speed, its group of answer choices velocity is zero. none of the above acceleration is zero. inertia is zero.
Answer: None of the options.
What is energy ?
-- energy, in physics, the capacity for doing work. It may exist in capacities, kinetic, thermal, electrical, chemical, nuclear, or other various forms.
-- There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another
When we talk about uniform circular motion (constant speed) we yet have a changing velocity and therefore, acceleration.
How is this possible?
-- Well, velocity is a vector, and as a vector it has magnitude (the speed) and direction.
-- So, while an object performs a uniform circular motion, althought its speed is not changing, its direction does change.
-- And, since acceleration is the variation of velocity in time , certainly there is acceleration here.
On the other hand, Inertia is mathematically expressed as:
This means that for a system with a given axis of rotation and a given total mass , the greater the distance from the axis to the object that performs the circular motion, the greater the inertia.
This also means that inertia depends directly on the mass of the system and the radius of the circular motion, therefore, as long as these elements exist, in a circular motion the inertia will always be different from zero.
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a meter stick is supported at each end by a spring scale. a heavy mass is then hung on the meter stick so that the spring scale on the left hand side reads four times the value of the spring scale on the right hand side. if the mass of the meter stick is negligible compared to the hanging mass, how far from the right hand side is the large mass hanging?
The mass is dangling 4/5 of the length of the metre stick away from the right side if the mass of the metre stick is insignificant in comparison to the hanging mass.
The turning force on an item is measured by torque, which is computed by dividing the force by the separation from the pivot point.
Let's designate the forces on the left and right spring scales as F1 and F2, respectively.
F1 = 4F2, as we are aware.
The left side's torque is F1 * L, while the right side's torque is F2 * L (L is the distance from the right side).
Accordingly, F1 * L = F2 * L 4 F2 * L = F2 * L, the total torque on the left side must match the total torque on the right side.
It is evident that L = 4L/5.
In other words, the mass is dangling 4/5 of the way down the metre stick from the right side.
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a gardener mows a lawn with a push mower. the handle of the mower makes an angle of 32 degrees. if a 209 n force is applied along the handle of the 18 kg mower, what is the normal force exerted on the mower?
The normal force exerted on the mower is 290.8 N. The result is obtained by using the concept of Newton's first law.
What is Newton's first law?Newton's first law states that every object will remain at rest or keep constantly moving in a straight line unless an external force acts upon it.
The equation of Newton's first law can be expressed as
∑F = 0
A gardener mows a lawn with a push mower with
Angle, θ = 32 degreesForce, F = 209 NMass = 18 kgFind the normal force exerted on the mower?
We use g = 9.8 m/s².
See the illustration picture of forces directions in the attachment!
The direction of normal force is up. Using the Newton's first law, we will add parallel forces.
∑F = 0
Fn - F sin θ - W = 0
Fn = F sin θ + W
Fn = 209 sin 32° + 18 × 10
Fn = 209 (0.53) + 180
Fn ≈ 290.8 N
Hence, the mower will exert the normal force of 290.8 N.
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which diagram best represents the position of a ball , at equal time intervals as it falls freely
The diagram that represents the position of a ball, at equal time intervals, as it falls freely is diagram B.
What is free fall kinematics?The acceleration of an item in free fall is -9.8 m/s/s. (The minus symbol represents a downward acceleration.) For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.
vf = g x t where g is the acceleration of gravity. The value for g on Earth is 9.8 m/s/s. This formula is used to determine the object's speed after being dropped from rest for any period of time.
Therefore, the correct option is B. diagram B.
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The question is incomplete. Your most probably complete question is given below: the options are attached below.
how much charge flows from each terminal of a 12.0 v battery when it is connected to a 7 microf capacitor?
The amount of the charge flowing through the terminals of the battery is found to be 0.084C.
The voltage of the battery is given to be 12 V and the capacitance of the capacitor is given to be 7 micro F.
As per the standard relations, the amount of the charge flowing through the terminal of the battery will be given by,
Q = CV
Where,
Q is the charge through the battery,
C is the capacitance of the capacitor,
V is the voltage of the battery.
Putting all the values,
Q = 12 x 7/1000
Q = 0.084 C.
So, the charge flowing is 0.084 C.
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oak is 0.8 as dense are water and therefore floats in water. what weight of water will be displaced by a 50 kg floating oak beam?
613.25 N is the weight of water will be displaced by a 50 kg floating oak beam, if oak is 0.8 times dense of water.
Density of water, = 1000 kg/m³
Density of oak, = 0.8 × 1000 = 800 kg/m³
Floating of an object is possible if the upward force exerted by the water is equal to the weight of the object. And this upward force is equal to the weight of water displaced by the floating object.
Volume of the water displaced by the 50 kg oak, V = 50/800 = 0.0625 m³
Mass of the displaced water = 0.0625 × 1000 = 62.5 kg
Weight of the displaced water = 62.5 × 9.81 = 613.13 N.
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20N , 5m
2. If the crate does not move, does Ignacio perform any work? Does he use any
power? Explain.
th
probl
Study the illustration above, and then answer the following questions on a separate
sheet of paper.
1. Ignacio is trying to move this crate. What are the two equations you can use to
calculate the power Ignacio must use to move the crate?
3. What else do you need to know to find the power Ignacio uses when he moves
the crate?
4. Ignacio moves the crate in 10 s. How much power, in watts, does he use?
5. Carolina moves the crate in 5 s. How much power, in joules per second, does
she use?
6. Felix moves the crate twice as far as Ignacio and Carolina in 5 s. How much
power, in watts, does he use?
The quantity of internal and mechanical energy that things contain fluctuates as a result of work.
How can you tell if someone is working on something or not?Example of a Work, An item must be subjected to a force and move in the direction of the force in order for work to be done on it.The quantity of internal and mechanical energy that things contain fluctuates as a result of work. Energy is contributed to a system or an item when work is done on it. A system or item transfers part of its energy to something else when it does work. When a ball is thrown, a hand exerts force while an arm swings forward.To learn more about mechanical energy refer to:
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if half of the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration (in m/s2) it can achieve on wet concrete where the coefficient of kinetic friction is 0.5 and the coefficient of static friction is 0.7.
The maximum acceleration that the flatbed truck can achive on wet concrete is 5[tex]m/s^{2}[/tex]
The maximum acceleration a truck can achieve on wet concrete is determined by the coefficient of friction between the two drive wheels and the surface.
Taking into account the coefficients of static and kinetic friction between the drive wheels and a wet concrete surface—0.7 and 0.5, respectively—the maximum acceleration of a truck with half its weight supported by its two drive wheels can be calculated using Newton's Second Law of Motion.
According to Newton's Second Law, F = ma, where F is force, m is mass and a is acceleration.
Since the truck has half its weight supported by its two drive wheels, we know that F = 0.5 mg (where m is mass and g is gravitational acceleration). Thus, when solving for a (acceleration), we have:
a = F/m
= 0.5mg/m
= 0.5g
= 4.9 [tex]m/s^{2}[/tex] ≈ 5 [tex]m/s^{2}[/tex]
This means that on wet concrete with coefficients of static friction and kinetic friction at 0.7 and 0.5 respectively, the maximum acceleration a truck with half its weight supported by its two driving wheels can achieve is 5 [tex]m/s^{2}[/tex].
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A substance has a triple point at a temperature of 17 ∘C and a pressure of 3. 2 atmospheres. In what states can the substance exist on the surface of Earth at sea level (open to the atmosphere)?
Due to changes in temperature and pressure, the substance can exist either as a solid or a gas.
Given The triple point temperature is, (T) = 17 ∘C
The pressure of substance at triple point (P) = 3.2atm
The triple point is the temperature at which a certain substance can exist in all three of its major forms (solid, liquid and gas). Generally speaking, there are three stages of states that can be used to classify the states of matter. At sea level, we will experience conditions with a pressure of 1 atm and a temperature of 25∘C. At the sea level surface of the Earth, the triple point temperature is exceeded and the pressure decreases. The material can therefore exist in both the solid and gas phases. As a result, we can draw the conclusion that the substance can exist in both a solid and a gaseous state due to temperature and pressure variations.
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The part of the reader that consists of a laser, optical filters, light-collecting optics, and beam-shaping devices that is designed to project and guide a precisely controlled laser beam back and forth across the plate as the plate moves through the scan area is the Group of answer choices
The correct option is (b) i.e. optical system. It is made up of a laser, optical filters, light-collecting optics, and beam-shaping components.
A scanner assembly, as it relates to digital imaging and document scanning, typically consists of a laser, optical filters, light-collecting optics, and beam-shaping devices. The laser is used to project a precise, concentrated beam of light onto the surface of the plate or document being scanned. Optical filters are used to control the wavelength and intensity of the light being used. Light-collecting optics, such as lenses, are used to focus the beam of light onto the plate or document. Finally, beam-shaping devices, such as mirrors or prisms, are used to guide the beam of light as it scans across the plate or document. The scanner assembly is designed to move the beam of light back and forth across the plate in a controlled manner, capturing an image of the plate or document as it does so.
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Question - The part of the reader that consists of a laser, optical filters, light-collecting optics, and beam-shaping devices that is designed to project and guide a precisely controlled laser beam back and forth across the plate as the plate moves through the scan area is the
a) photodetector
b) optical system
c) drive mechanism
d) photostimulable luminescence
A fox fleeing from a hunter encounters a 0.745 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.50 m/s at an angle of 45.0°, beginning the jump 1.99 m from the fence. By how much does the fox clear the fence? Treat the fox as a particle.
The fox which is fleeing from a hunter encounters a 0.745 m tall fence and this fox can clear the fence with a height of up to 0.895 meters.
What is Velocity?Velocity can be defined as the rate of change in the displacement of an object. It is a vector quantity as it has both the magnitude and direction. The change in velocity of an object is known as acceleration.
Given,
Initial velocity (u) = 7.50 m/s
Launch angle, θ = 45°
Height of fence = 0.745 m
Trajectory of Projectile is given by:
y = x tanθ - gx²/ 2u²cos²θ
For x = 1.99 m
y = 1.99 × tan 45° - 9.8 × (1.99)²/ 2 × (7.5)² × (cos45°)²
y = 1.99 × 1 - 9.8 × 3.96/ 2 × 56.25 × (1)²
y = 1.99 - 38.80/112.5
y = 1.99 - 0.345
y = 1.64m
At x = 1.99 m, the value of y = 1.64 m
Therefore, fox clear fence by a margin = 1.64 - 0.745 = 0.895 meters.
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A pipe discharges storm water into a creek. Water flows horizontally out of the pipe at 1.9 m/s, and the end of the pipe is 3.1 m above the creek.
How far out from the end of the pipe is the point where the stream of water meets the creek?
The distance from the end of the pipe is the point where the stream of water meets the creek is 1.52 m.
What is the time taken for the water to flow?
The time taken for the water to fall from the given height is calculated as follows;
t = √ ( 2h / g )
where;
g is acceleration due to gravityh is the height of fallt = √ ( 2 x 3.1 / 9.8 )
t = 0.8 s
The horizontal distance travelled by the stream of water is calculated as;
x = vt
x = 1.9 m/s x 0.8 s
x = 1.52 m
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a cubical gaussian surface surrounds two charges q1 6.8 10 12 c and q2 2.0 10 12 c as the drawing shows what is the electric flux passing through the surface how do i get the answer as 0.54 n m 2 c a see answer
For the given statement the Electric flux through the surface is 0.54 N m 2 /C.
Note: we are considering the distance between two charges to be 0.1 m
Electric flux in electromagnetism is a measurement of the electric field passing through a certain surface. The SI unit for the scalar quantity known as electric flux is newton-meters squared per coulomb (N m 2 /C). N · m 2 /C )
The electric flux passing through a surface can be calculated using the equation:
Φ = E * A = (k * q1 + k * q2) / r^2 * A
k = Coulomb's constant = 8.99 x 10^9 N * m^2 / C^2
r = distance between the charges = 0.1 m
A = surface area = 0.1 m * 0.1 m = 0.01 m^2
Now if we calculate:
Φ = (k * q1 + k * q2) / r^2 * A = [(0.01 m^2)]* [(8.99 x 10^9 N * m^2 / C^2) *( 6.8 x 10^-12 C)] + [(8.99 x 10^9 N * m^2 / C^2) * (2 x 10^-12 C)] / (0.1 m)^2 = 0.54 N * m^2 / C.
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the motor has a resistance of 9.7 ohms . when the motor switch is closed (meaning that branch of the circuit now has current flowing through it), what power does the bulb consume?
Lighting uses typically range from 2 to 100 watts (W), depending on size and kind.
A 60W bulb consumes how much electricity?A 60W light bulb was previously used as an example. By virtue of its 60W rating, it consumes 60 joules of energy every second it is turned on. This indicates that 216,600 joules of energy would be expended over the length of 3,600 seconds, or 60 minutes.Lighting uses typically range from 2 to 100 watts (W), depending on size and kind. LED bulbs only require 2 to 18 W, compared to the 25 to 100 W used by conventional incandescent lamps. 110 volts or less and typically less than 1 amp are drawn by light bulbs.Lighting uses typically range from 2 to 100 watts (W), depending on size and kind.To learn more about electricity refer to:
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To determine the density of a piece of glass, a forensic technician places the glass in a liquid with a density of 2. 1 g/mL. The glass sinks. What should the technician do now?
a. Record that the density is greater than 2. 1 g/mL and stop the analysis.
b. Add a liquid with a density less than 2. 1 g/mL until the glass begins to float.
c. Add a liquid with a density greater than 2. 1 g/mL until the glass begins to float.
d. Record that the density is less than 2. 1 g/mL and stop the analysis
The technician can either note that the density is more than 2.1 g/mL and halt the analysis, or he can add more liquid until the glass starts to float.
The density of a material is an indicator of how heavy it is in relation to its size. An object will float when submerged in water if its density is lower than that of the water, while sinking if its density is higher. A differentiating characteristic that is unrelated to a substance's volume is its density. By suspending a glass sample in a liquid solution, one can calculate the density of an unknown glass sample. The density of the liquid is then determined, either directly or by comparison with a glass sample.
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A source produced 15 waves in 3 seconds , The distance between a crust is 15cm . Find frequency and wavelength
Frequency and wavelength is 100m/s.
Exactly how is frequency calculated?Pictures for Calculate the frequency and wavelength. The formula for frequency expressed in terms of time is given as follows: f = 1/T, where T is the duration of a cycle expressed in seconds and f is the frequency expressed in hertz. The frequency formula is stated as f = / where denotes the wave speed and the wavelength of the wave.
Explanation:
In 3 seconds, the source is generating 15 waves.
In a second, there are 15/3 waves, or 5 waves, produced.
Thus, the frequency is 5 Hz.
assuming that the wave length /2 = 10 cm
so that =20 cm
speed = frequency *wavelength v=5*20
v=100m/s.
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how many decibels are emitted from a jet plane with a sounf intensity of 8.5*10^2 watts per square meter
The jet plane emits 149 914 decibels at 8.2 .
What is the jet plane?
The Principal Differences. The key difference between a jet and an airplane is that to be a jet, a plane has to have a jet engine. Essentially, every jet is an airplane but not every airplane is a jet. A jet engine could either be a turbojet or turbofan, while a non-jet engine is usually a turboprop.A jet aircraft (or simply jet) is an aircraft (nearly always a fixed-wing aircraft) propelled by jet engines.While the typical VLJ and light jet carry a maximum of six passengers, a mid-size business jet offers comfortable seating for up to 10 passengers.A Jet aircraft flies much faster at higher altitudes, as high as 33,000–49,000 ft, than a propeller-powered aircraft. The Jet engine consists of an engine with a rotary air compressor powered by a turbine, with the leftover power providing thrust via a propelling nozzle.To learn more about jet refers to:
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a stream 1 km wide has a constant current of 4 km/h. at what angle to the shore should a person navigate a boat, which is maintaining a constant speed of 16 km/h, in order to reach a point directly opposite? (give your answer for acute angle in decimal degrees, rounded to one decimal place.)
angle to the shore should a person navigate a boat, which is maintaining a constant speed of 16 km/h, in order to reach a point directly opposite is 75.5 degrees.
Since the stream is flowing parallel alongside the shore, it takes the vector form of v {stream} = [0,4]
the boat velocity is perpendicular to the stream, it's takes the vector form of v{boat} = [-16,0]
The resultant velocity of the boat is the sum of the velocity of the boat and stream, thus it takes the form
v{total} = [-16,0] + [0,4]
= [ -16,4]
the cosine of angle to the shore,
cos {theta} = v{total} . v {stream} / ||v{total} || x ||v {stream}||
= [ -16,4] . [0,4] / (16x4)
= 16/64
= 0.25
angle = 75.7 degrees.
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Regardless of which method of delivery a speaker might think is appropriate for a speaking event, the audience has expectations about how messages should be delivered as well. This is a situation that speakers need to carefully consider before selecting a delivery method for their speech.
-true
-false
Delivery method for their speech is True.
How does the context of the speaking event affect the audience's expectations for the delivery of a speech?The context of the speaking event can greatly affect the audience's expectations for the delivery of a speech. For example, in a formal setting such as a business conference, the audience may expect a more professional and formal delivery, with the use of slides or visual aids and a well-structured speech. In contrast, at a casual event such as a family gathering, the audience may expect a more relaxed and conversational delivery, with less emphasis on visual aids and a more informal structure. Additionally, the topic of the speech, the background of the audience and the purpose of the speech can also affect the audience's expectations. Therefore, a speaker should be aware of the context of the event, and adjust their delivery method accordingly.
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Two Small Spheres Spaced 20.0 Cm Apart Have Equal Charge. &Nbsp; How Many Excess Electrons Must Be Present On Each Sphere If The Magnitude Of The Force Of Repulsion Between Them Is 4.57 X 10-21 N? &Nbsp; Number Of Electrons = ?This problem has been solved!You'll get a detailed solution from a subject matter expert that helps you learn core concepts.See AnswerTwo small spheres spaced 20.0 cm apart have equal charge.How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57 x 10-21 N?Number of Electrons = ?
The number of excess electrons in each sphere is equal to 1.24 x 10^-19 C / 1.6 x 10^-19 C/electron = 0.78 x 10^19 electrons.
How to calculate the number of excess electrons?The number of extra electrons in each sphere can be calculated using Coulomb's law. Coulomb's law states that the repulsive force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.
F = k * (q1 * q2) / d^2
where F is the repulsive force, q1 and q2 are the charges on the two spheres, d is the distance between the spheres, and k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2).
Since the repulsive force is 4.57 x 10-21 N and the distance between the spheres is 20 cm = 0.2 m, we can rearrange the equations to find the charge on each sphere.
q1 = sqrt(F * d^2 / k)
q1 = square root (4.57 x 10-21 N * (0.2 m)^2 / (8.99 x 10^9 Nm^2/C^2)) = 1.24 x 10^-19 C
So the number of extra electrons in each sphere is equal to 1.24 x 10^-19 C / 1.6 x 10^-19 C/electron = 0.78 x 10^19 electrons.
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