A bowling ball is let go from a height of 30 cm. What is the velocity of the
ball just before it hits the ground?
Select one:
о
0.30 m/s.
О
17 m/s.
O
24 m/s
a
1.3 m/s
Answers
Answer:
The answer is 0.30 m/s
Explanation:
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Related Questions
How much 2 M HBr is needed to neutralize 380 mL of 0.1 M NH4OH?
Answers
Answer:
19ml
Explanation:
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a force of attraction between objects that is due to their masses and distance between objects
a. gravity
b. weight
c. mass
Answers
Answer:
the answer is gravity
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Which process is exothermic?
a) the vaporization of water b) the freezing of water c)the sublimation of dry ice d ) the boiling of liquid nitrogen
Answers
Answer:
Freezing of water
Explanation:
When water becomes a solid it releases heat into its surroundings (warming it up).
B) A company president would like to offer a 4.00 L cylinder containing 500 g of chlorine in the new catalog. The cylinders you have on hand have a rupture pressure of 40 atm. Use both the ideal gas law and the van der Waals equation to calculate the pressure in a cylinder at 25°C. Given a = 6.58 L2 atm mol-2 and b = 0.056 L mol-2, Cl =35.5. (5 marks)
Answers
Answer:
43.1atm is the pressure using gas law and 27.2atm using Van der Waals Law.
Explanation:
Ideal gas law is:
PV = nRT
Where P is pressure in atm
V is volume = 4.00L
n are moles of the gas (For chlorine Molar Mass: 70.90g/mol):
500g * (1mol / 70.90g) = 7.052 moles
R is gas constant = 0.082atmL/molK
T is absolute temperature = 25°C + 273 = 298K
To solve the pressure, P:
P = nRT/V
P = 7.052mol*0.082atmL/molK*298K / 4.00L
P = 43.1atm is the pressure using gas law.
Van der Waals equation is:
[tex]P + a(\frac{n}{V})^2 * (V-nb) = nRT[/tex]
Where a is 6.58L²atm*mol⁻²
b = 0.056Lmol⁻²
Solving for pressure:
[tex]P + a(\frac{n}{V})^2 = \frac{nRT}{(V-nb)}[/tex]
[tex]P = \frac{nRT}{(V-nb)}-a(\frac{n}{V})^2[/tex]
[tex]P = \frac{7.052mol*0.082atmL/molK*298K}{(4.00L-7.052mol*0.056L*mol)}-6.58L^2mol^{-2}(\frac{7.052mol}{4.00L})^2[/tex]
P = 172.323 / 3.6051 - 20.4866
P = 27.2atm using Van der Waals Law
Vitamin B12, cyanocobalamin, is essential for human nutrition. It is concentrated in animal tissue but not in higher plants. Although nutritional requirements for the vitamin are quite low, people who abstain completely from animal products may develop a deficiency anemia. Cyanocobalamin is the form used in vitamin supplements. It contains 4.34% cobalt by mass. Calculate the molar mass of cyanocobalamin, assuming that there is one atom of cobalt in every molecule of cyanocobalamin. WebAssign will check your answer for the correct number of significant figures. g/mol
Answers
Answer:
645 g/mol
Explanation:
Step 1: Given data
Percent by mass of cobalt in cyanocobalamin: 4.34%
Step 2: Determine the molar mass of cyanocobalamin
There is one atom of cobalt in every molecule of cyanocobalamin, or what is the same, there is 1 mole of atoms of Co in every mole of molecules of cyanocobalamin. Given the molar mass of Co is 28.01 g/mol, the molar mass of cyanocobalamin is:
100 g B12/4.34 g Co × 28.01 g Co/1 mol Co × 1 mol Co/1 mol B12 = 645 g/mol
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What are one advantage and one disadvantage of sexual reproduction?
What is one advantage and one disadvantage of asexual reproduction?
Answers
Answer:asexual- Energy is not required to find a mate. Offspring are genetic clones. A negative mutation can make asexually produced organisms susceptible to disease and can destroy large numbers of offspring. Some methods of asexual reproduction produce offspring that are close together and compete for food and space.
Explanation:During sexual reproduction the genetic material of two individuals is combined to produce genetically diverse offspring that differ from their parents.