A body of mass m1 = 1.5 kg moving along a directed axis in the positive sense with a velocity
of 11 ms-1 collides head-on with a body of mass m2 = 14 kg moving in the negative sense
with a velocity of 5 ms-1. If the velocity of m1 after the collision is 1 m s-1 in the negative
sense, Apply your scientific knowledge and understanding of collisions to solve the problem
and find the final velocity of m2.

Answer: 0.15 m/s

Explanation:

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Answer:

The input force (effort) is the amount of effort used to push down on a rod, or pull on a rope in order to move the weight. In this example, the force the little guy is using to pull the elephant is the input force.

Explanation:

Answer:

Here u go

Explanation:

Mass of air in the room m= volume of room×density of air

=(5m×4m×3m)(1.20kgm3)=72kg

Weight of air, W=mg=(72kg)(9.8ms2)=706N.

Answer:

person above is correct, i did the work and got the smae answer

Answer:

convection

Explanation:

I hope this helps

Answer: B- A and C

Explanation:

A P E X

The optical devices uses light. The correct option for the optical devices can form images that are larger than the original object is B i.e A and C.

The device which uses light for the meaningful purpose is called optical devices.

The device which form the images larger than the object are the converging type of lens or mirror.

The lens which is converging is the convex lens denoted by C in diagram and the converging mirror is the concave mirror denoted by A.
Therefore, the correct option for the optical devices can form images that are larger than the original object is B i.e A and C.

Learn more about optical devices.

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Answer:

I = 1.09 A

Explanation:

Here, 5 ohm and 12 ohm resistor are connected in parallel. Using the parallel combination of resistors as follows :

[tex]\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R}=\dfrac{1}{5}+\dfrac{1}{12}\\\\ R=3.52\ \Omega[/tex]

Now R and 2 ohm resistors are in series. Let the equivalent be [tex]R_{eq}[/tex]. So,

[tex]R_{eq}=3.52+2\\\\=5.52\ \Omega[/tex]

Let I be the current. Using Ohm's law,

V = IR

[tex]I=\dfrac{V}{R_{eq}}\\\\I=\dfrac{6}{5.52}\\\\I=1.086\ A[/tex]

or

I = 1.09 A

So, the correct option is (c).

Answer:

Explanation:

Remark

The only thing that might trip you up is what to do with the angle. The vertical component of the 15 degrees does no work against anything. So the 15 degrees limits the horizontal force.

The formula is

Work = F * d * cos(15)

The givens are

F = 2000 N

d = 30 m

Cos(15) = 0.9659

Solution

Work = 2000 * 30 * cos(15)

Work = 57,955

Rounded to two places would be 5.8 * 10^4

C

Answer: Well the charges in 9c are positive so  5c is th force between the two making the ansewr

Explanation:

Answer:

C    (3RD OPTION)

Explanation:

E2020

Answer:

Hey mate.....

Explanation:

This is ur answer.....

A voltmeter is an instrument used for measuring electric potential difference between two points in an electric circuit. It is connected in parallel. It usually has a high resistance so that it takes negligible current from the circuit.

Hope it helps you,

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Answer:

v = 1.7 m/s

Explanation:

Given that,

Initial velocity of the object, u = 1 m/s

Acceleration of the object, a = 1 m/s²

We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.

[tex]v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v^2=2(1)(1)+1^2\\\\v=\sqrt3\\\\v=1.7\ m/s[/tex]

So, the final velocity of the object is 1.7 m/s.

Answer:

about 4.5 billion years ago from a dense cloud of interstellar gas and dust. The cloud collapsed, possibly due to the shockwave of a nearby exploding star, called a supernova. When this dust cloud collapsed, it formed a solar nebula a spinning, swirling disk of material.

Explanation:

Answer:

a. Constructive interference.

b. [tex]0.34\; \rm m[/tex].

c. [tex]0.68\; \rm m[/tex].

d. [tex]1.02\; \rm m[/tex].

Explanation:

Frequency of this sound wave: [tex]f = 250\; \rm Hz = 250\; \rm s^{-1}[/tex].

Speed of this sound wave: [tex]v = 340\; \rm m \cdot s^{-1}[/tex].

Calculate the wavelength of this sound wave:

[tex]\begin{aligned} \lambda &= \frac{v}{f} \\ &= \fraac{340\; \rm m \cdot s^{-1}}{250\; \rms^{-1}} \approx 1.36\; \rm m\end{aligned}[/tex].

Path difference refers to the absolute value of the difference between:

When the observer in this question is on the line between the two speakers at [tex]d[/tex] meters from the midpoint, the corresponding path difference would be [tex]2\; d[/tex] meters. (Add [tex]d\![/tex] to the distance from the closer source, and subtract [tex]d\!\![/tex] from the distance from the other source.)

The question states that sound from the two speakers are in-phase. In other words, at every instant, the sound wave from the two speakers are at the same phase at the position of each speaker.

Because wave from the two sources are in-phase at the source:

Path difference is [tex]0[/tex] when the observer is at the midpoint. That would correspond to constructive interference.

The first destructive interference (minimum intensity) corresponds to a path difference of [tex]\lambda / 2[/tex]. Along the line, that would be observed at [tex](1/2) \cdot (\lambda / 2) = 0.34\; \rm m[/tex] from the midpoint.

The next constructive interference (maximum intensity) would be observed when path difference is [tex]\lambda[/tex]. Along the line, that would be observed at [tex](1/2)\cdot \lambda = 0.68\; \rm m[/tex] from the midpoint.

The second destructive interference (minimum intensity) would be observed when path difference is [tex](1 + (1/2))\, \lambda[/tex]. Along the line, that would be observed at [tex](1/2) \cdot ((3/2)\cdot \lambda) = 1.02\; \rm m[/tex] from the midpoint.

Answer:

Explanation:

300m/s2

If you did 3x18 this would equal 54

Answer:

The increase internal energy is 1,760.41[tex]\overline 6[/tex] J

Explanation:

The given parameters of the worker, sledgehammer, and rail line are;

The mass of the spike driven into the rail, m₁ = 0.500 kg

The mass of the sledgehammer, m₂ = 2.50 kg

The speed of the sledgehammer, v = 65.0 m/s

The fraction of the hammers kinetic energy, KE, converted to the internal energy of the hammer and the spike, Δ[tex]E_{internal}[/tex] = 1/3 × KE

Therefore, we have;

The kinetic energy, KE, of the sledgehammer is given by KE = 1/2·m₂·v²

Where;

m₂ = The mass of the sledge hammer = 65.0 m/s

v = The velocity o the sledgehammer

∴ KE = 1/2 × 2.50 kg × (65.0 m/s)² = 5,281.25 J

Therefore;

The increase internal energy, Δ[tex]E_{internal}[/tex] = 1/3 × 5,281.25 J = 1760.41[tex]\overline 6[/tex] J

Answer:

Force = 3.204Newton

Explanation:

Given the following data;

Pressure = 178

Area = 18 mm² to meter = 18/1000 = 0.018 m²

To find the force;

Force = pressure * area

Force = 178 * 0.018

Force = 3.204 Newton.

Answer:

the correct answer is e

Explanation:

In projectile launching, the range or distance on the x-axis is given by the expression

         R = [tex]\frac{v_o^2 \ sin 2 \theta }{g}[/tex]

where v₀ is the initial velocity θ the launch angle.

When analyzing this expression is maximum when the sine function is maximum

           sin 2 θ = 1

           2θ = sin⁻¹  1

          2 θ = 90

           θ = 90/2

           θ = 45º

reviewing the answers there are no correct ones since the maximum angle occurs for 45º

if we analyze with these angles we have

θ = 40

            sin 2θ = sin 2 40 = 0.98

θ = 35

             sin 2 35 = 0.939

θ = 43

             sin 2 43 = 0.998

θ = 48

             sin 2 48 = 0.994

if we take the written angles the range is maximum for 43º

therefore the correct answer is e

Answer:

Amiodarone

Explanation:

Answer:

By Newton's second law, it reduces the magnitude of the acceleration, without changing its direction.

F = unbalanced force

m = mass

a = acceleration

a = F/m

Answer:

Energy conversion

Explanation:

We regularly use automobile which runs on the chemical energy of the fuels such as diesel and petrol, the chemical energy from the fuel would convert into the thermal energy which is used to drive the engine of the vehicle,further the thermal energy converted into the mechanical energy which is used to drive the prime mover of the automobile.

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

We frequently utilize vehicles that operate on chemical energy from fuels like diesel and gasoline.

This chemical energy is transformed into thermal energy, which drives the engine of the vehicle, and then mechanical energy, which drives the prime mover of the vehicle.

Thus, we can say that the transfers and transformations of energy are necessary to operate the technology.

Learn more about thermal energy from here, refer to the link;

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Explanation:

its means the quantity in question is a scalar quantity, has only magnitude but no direction, for example. speed,has no reference to direction of motion, since the speed of a body say 5 m/s( the direction of the body has not been stated) but the velocity of a body say 5m/s to the east has a reference to direction of the motion.

That's why velocity is different from speed

frequency is equal to number of oscillations or vibrations upon time

therefore,

check picture

Answer:

The other child must sit the same meters as the N child so they an be balanced.

Explanation:

i think this is the incomplete page that you are showing but the answer is

:-

Answer:

The third charge needs to be placed at [tex]x \approx 0.57\; \rm m[/tex].

Explanation:

Both [tex]q_1[/tex] and [tex]q_2[/tex] would attract [tex]q_3[/tex].

These two electrostatic attractions need to balance one another. Hence, they need to be opposite to one another. Therefore, [tex]q_1[/tex] and [tex]q_2[/tex] need to be on opposite sides of [tex]q_3[/tex]. That is possible only if [tex]q_3 \![/tex] is on the line segment between [tex]q_1 \![/tex] and [tex]q_2 \![/tex].

Assume that [tex]q_3[/tex] is at [tex]x\; \rm m[/tex], where [tex]0 < x < 3.72[/tex] (in other words, [tex]q_3 \![/tex] is on the line segment between [tex]q_1[/tex] and [tex]q_2[/tex], and is [tex]x\; \rm m \![/tex] away from [tex]q_2 \![/tex].)

Let [tex]k[/tex] denote Coulomb's constant.

The magnitude of the electrostatic attraction between [tex]q_1[/tex] and [tex]q_3[/tex] would be:

[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}}[/tex].

Similarly, the magnitude of the electrostatic attraction between [tex]q_2[/tex] and [tex]q_3[/tex] would be:

[tex]\displaystyle \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].

The magnitudes of these two electrostatic attractions need to be equal to one another for the resultant electrostatic force on [tex]q_3[/tex] to be [tex]0[/tex]. Equate these two expressions and solve for [tex]x[/tex]:

[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}} = \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].

[tex]\displaystyle \frac{q_1}{(3.72 - x)^{2}} = \frac{q_2}{x^{2}}[/tex].

[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1}[/tex].

[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1} = \frac{1}{30}[/tex].

By the assumption that [tex](0 < x < 3.72)[/tex], it should be true that [tex](x > 0)[/tex] and [tex](3.72 - x > 0)[/tex]. Therefore, [tex]\displaystyle \frac{x}{(3.72 - x)} > 0[/tex].

Take the square root of both sides of the equation [tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{1}{30}[/tex].

[tex]\displaystyle \sqrt{\frac{x^2}{(3.72 - x)^{2}}} = \sqrt{\frac{1}{30}}[/tex].

[tex]\displaystyle \frac{x}{3.72 - x} = \frac{1}{\sqrt{30}}[/tex].

[tex]\sqrt{30}\, x = 3.72 - x[/tex].

Therefore:

[tex]\left(1 + \sqrt{30}\right)\, x = 3.72[/tex].

[tex]\displaystyle x = \frac{3.72}{1 + \sqrt{30}} \approx 0.57[/tex].

Hence, [tex]q_3[/tex] should be placed at [tex]x \approx 0.57\; \rm m[/tex].

Answer:

Its a wave

Explanation:

THis is one

Answer: a light wave

Explanation: a pex