A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker's outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball was on a path to reach the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Answers

Answer 1

THIS IS THE COMPLETE QUESTION

basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Yes, exactly 0.6 seconds after the shot is launched.

Yes, between 0.64 seconds and 0.65 seconds after the shot is launched

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

No, the shot is not blocked.

Answer:

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Given that the

equation for shot block height h = 9 + 25t – 16t2.

equation for ball height h = 6 + 30t – 16t2.

From the question ,it can be deducted that the shot is made before two tenths of a second or 0.2seconds

CHECK THE ATTACHMENT TO COMPLETE THE DETAILED SOLUTION

A Basketball Player Is Shooting A Basketball Toward The Net. The Height, In Feet, Of The Ball T Seconds

Answer 2

We can say that the leaping player do not block the shot and thus, the answer is it is No, the shot is not blocked.

What is a shot?

In terms of basketball, a shot is known to be the act of throwing a given basketball to a hoop.

Note that in the scenario above, since the ball has reaches the net at about 1.7 seconds after the shooter launches it, We can say that the leaping player do not block the shot and thus, the answer is it is No, the shot is not blocked as it will be hard for the player to do.

See full question below:

Yes, exactly 0.6 seconds after the shot is launched.

Yes, between 0.64 seconds and 0.65 seconds after the shot is launched

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

No, the shot is not blocked.

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Related Questions

The y-intercept in the linear equation −2y−4x−6=0 is _[blank]_. will give brainliest

Answers

Answer:

-3 is the value of the location where the line crosses the y-axis,and is commonly referred in the slope-intercept form of a line "the intercept". Now it may be your teacher expects you to answer this as the point on the plane where the y-intercept occurs, and that should be the point (0, -3). Make sure you follow your teacher's notation.

Step-by-step explanation:

Re-write the equation given in slope=intercept form by isolating the variable "y" on one side of the equation and expressing the rest in slope*x + y-intercet form:

[tex]-2y-4x-6=0\\-4x-6=2y\\y=-2x-3\\[/tex]

which tells us that the slope of the line is -2 and it y-intercept is "-3".

Now, watch out because you may be asked to write the actual coordinates of the y-intercept, which are: (0, -3)

giving the x-coordinate 0 and the y-value where the line crosses the y-axis.

Answer:

-3.

Step-by-step explanation:

-2y - 4x - 6 = 0

-2y = 4x + 6

y = -2x - 3

So, the y-intercept is (0, -3).

Hope this helps!

Answers

Complete question is;

Francis surveyed a random sample of 70 students at Franklin High School about their favorite season. Of the students surveyed, 18 chose fall as their favorite season. There are 1816 students at Franklin High School. Based on the data, what is the most reasonable estimate for the number of students at Franklin High School whose favorite season is fall?

Answer:

467

Step-by-step explanation:

We are told that 18 out of 70 of the surveyed students' favorite season is fall. This when expressed in fraction, gives; 18/70.

Now we need to multiply this fraction by the total number of Franklin High School students in order to get the estimate for the number of students at Franklin High School whose favorite season is fall. Total number of students = 1816. Thus, estimate is;

1816 × 18/70 = 467

Thus, the most reasonable estimate for the number of students at Franklin High School whose favorite season is fall would be 467.

Factor completely [tex]3x^3-3x^2-18x[/tex].
A - 3x(x + 3)(x + 2)
B - 3x(x + 3)(x − 2)
C - 3x(x − 3)(x + 2)
D - 3x(x − 3)(x − 2)
Will give Brainliest!

Answers

Answer:

The answer is 3x(x - 3)(x + 2)

Step-by-step explanation:

3x³ - 3x² - 18x

Factor out 3x from the expression

We have

3x ( x² - x - 6)

Solve the terms in the bracket

We have

3x ( x² + 2x - 3x - 6)

Factor out x the expression in the bracket

We have

3x ( x ( x + 2) - 3( x + 2) )

Factor out x + 2 from the expression in the bracket

We have the final answer as

3x ( x - 3) (x + 2)

Hope this helps you.

if AB is 3/4 and CD is 8/-6 are the parallel, perpendicular or niether

Answers

Answer:

neither

Step-by-step explanation:

parallel lines have the same slope, perpendicular lines' slopes are the negative inverse of eachother.

Which expression represents a difference of squares ?

Answers

Answer:

first and last options

Step-by-step explanation:

Difference of squares are in the form a² - b². The only choices that satisfy this are 25x² - 36 and 1 - 16x².

Answer:

1 and 4

Step-by-step explanation:

Which pair shows equivalent expressions?

Answers

Answer:

2(2/5x+2)=4x/5+4

Step-by-step explanation:

2(2/5x+2)=4x/5+4

4x/5 +4=4x/5 +4

trig and picture pls help

Answers

Answer:

Im pretty sure that the answer is 32.

Step-by-step explanation:

Hope this helps

Find the length of the side labeled x. Round intermediate values to the nearest tenth. Use the rounded values to calculate the next value. Round your final answer to the nearest tenth.

Answers

Answer:

11.67

Step-by-step explanation:

Data given in the question

∠ADC = 42°

∠BAC = 68°

Let us assume that AC be Y

Now

In ΔACD

tan 42° = AC ÷ CD = Y ÷ x ...............................(i)

In ΔACB

tan 68° = BC ÷ AC = 26 ÷ Y ..........................(ii)

Now take the value of Y from the equation (ii)

Y = 26 ÷ Tan 68° ...................... (iii)

Now place the value of Y in equation (i)

So,

Tan 42° = 26 ÷ tan 68° × X

X = 26 ÷ tan 68° × Tan 42° ......................(iv)

Now placing the values of tan 42° and tan 68° in equation (iv)

So,

X = 26 ÷ 0.900 × 2.475

= 11.67

The tan 42° = 0.900

And, the tan 68° = 2.475

Last year Peter spent a total of 8 1/6 hours on community service. Visits to old folks' homes made up 4/7 of the total time. How much time did he spend in visiting old folks homes?
B) This year Peter plans to spend 1 1/5 of his time spent last year on community service.
(i) Find the time he will spend on community service.
(ii) How much more time will he spend this year than last year?

Answers

Answer:

A. 4 2/3 hours

B. (i) 9 4/5 hours

(ii) 1 19/30

Step-by-step explanation:

Firstly, to find the number of hours he used in visiting old folks, what we have to do is to multiply the fraction of hours he used by the total number of hours.

Mathematically, that would be;

4/7 * 8 1/6

8 1/6 is same as 49/6

So the number of hours he spent visiting old folks would be ;

49/6 * 4/7 = 14/3 = 4 2/3 hours

B. What we do here is simply multiply the fraction now by what he spent last year.

That would be 1 1/5 * 8 1/6 hours

= 6/5 * 49/6 = 49/5 = 9 4/5 hours

ii) Now we want to know how much more time will be spent this year than last year.

What to do here simply is to subtract the time taken last year from what we have this year

That would be;

49/5 - 49/6 = 49/30 = 1 19/30

Please Help...Anyone? I am revising for a test tomorrow, so please explain how you get the answer, too.. The ratios of the ages of Sunil and his Wife is 4:3. After 4 years, the ratio will be 9:7. What is the present age of Sunil

Answers

Answer:

32 years old

Step-by-step explanation:

Please see attached picture for full solution.

Let Sunil's present age be 4x and his wife's present age be 3x.

When constructing parallel lines with a compass and straightedge, how should you start the construction? Measure the length of the original line and make an arc. Create a line that intersects the given line with your straightedge. Open the compass to the width of the line and draw two arcs. Use a straightedge to create two arcs above and below the line.

Answers

Answer:

The second choice.

Step-by-step explanation:

Open the compass to the width of the line and draw two arcs.

These arcs should be on the same side of the original line.

You can then draw the parallel line with the straight edge just touching the top of each arc.

Parallel lines can be drawn using compass and straightedge using the concept of corresponding angle.

What are the parallel lines?

Two lines are called parallel when they never meet each other if they are increased on the either side of them.

When constructing parallel lines with a compass and straightedge we can follow the below mentioned steps.

1. At first we need to draw a straight line. Then take a random point on it.

2. After that, we need to take a random point above the line that is drawn. Then, we need to connect two points.

3. After that, draw two arcs using the compass. First arc is on the angle formed by two lines drawn. The next arc is on the line that connects two points.

4. Now using the compass, we can copy the angle formed on the first line on the point above the first line.

5. Now, complete the angle on the point above the first line. These two lines are parallel lines.

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PLEASE HELP!!!! BRAINLIEST FOR RIGHT ANWSER

Answers

Answer:

d.tigers have a great IQR because they were some very heavy tigers.(high outliers)

Find the product of the following.
i) –5a2bc, 6ab, 8abc2
ii) –3x2y and (5y – xy)
iii) x2y2z2 and (xy – yz + zx)
iv) (p+6)and (q–7)
v) (2x+7)and(x2 –5x+6) vii) (x + y + 5) and (2x – 2y – 3)
PLEASE I NEED THE ANSWER NOW

Answers

Answer:

i) -240[tex]a^{4}b^{3} c^{3}[/tex]

ii) -15x²y² + 3x³y²

iii)x³y³z³ - x²y³z³ + x³y²z³

iv) pq -7p+6q-42

v)9x²-33x +42

vii) 2x² - 2y² + 7x -13y - 15

Step-by-step explanation:

To find product here means to multiply the algebraic expressions together

i) (–5a²bc)×(6ab)×(8abc² )

multiply like terms together

= -240[tex]a^{4}b^{3} c^{3}[/tex]

ii) (–3x²y) ×(5y – xy)

(–3x²y)×(5y) – (–3x²y) ×(xy)

multiply like terms together