A baseball outfielder catches a fly ball traveling 25.0 m/s with his gloved hand. When he catches the 0.140 kg baseball, the outfielder’s hand recoils by 10.0 cm. How much force did the outfielder’s hand exert in catching the ball?

Answers

Answer 1
10cm=0.1m

s=0.1
u=25
a=?
v=0

v ²=u ²+2as
0=25 ²+2a(0.1)
0=625+ 0.2 a
-625=0.2a
a=-3125 m/s²

F=ma
F=(0.14)(-3125)
F=-437.5N

F=437.5

Related Questions

Three charged particles of charges 3 μC, -2 μC, and 4 μC are placed on the X-Y plane at (1 cm, 0), (2.5 cm, 0), and (1 cm, 2 cm) respectively. Determine the magnitude and direction of the force acting on a -2 μC charge.

Answers

Answer:

The total force is [tex]F_{tot}=4.29\: N[/tex]

The direction is [tex]\omega=32.43^{\circ}[/tex]

Explanation:

First, we need to find the angle with respect to the horizontal, of the force between q2 (-2 μC) and q3 (3 μC).

Let's use the tangent function.

[tex]tan(\alpha)=\frac{2}{1.5}[/tex]

[tex]\alpha=53.13^{\circ}[/tex]  

Now, let's find the magnitude of the force F(12).

[tex]|F_{12}|=k\frac{q_{1}q_{2}}{d_{12}}[/tex]

Where:

k is the Coulomb constant (9*10⁹ NC²/m²)q1 is 3 μCq2 -2 μCd(12) is the distance between q1 and q2 ( 1.5 cm = 0.015 m)

[tex]|F_{12}|=9*10^{9}\frac{3*10^{-6}*2*10^{-6}}{0.015}[/tex]

[tex]|F_{12}|=3.6\: N[/tex]

The magnitude of the force F(23) will be:

[tex]|F_{23}|=k\frac{q_{2}q_{3}}{d_{23}}[/tex]

The distance between these charges is:

[tex]d_{23}=\sqrt{1.5^{2}+2^{2}}[/tex]

[tex]d_{23}=2.5\: m[/tex]

[tex]|F_{23}|=9*10^{9}\frac{2*10^{-6}*4*10^{-6}}{0.025}[/tex]

[tex]|F_{23}|=2.88\: N[/tex]

So, we have the force F(12) in the second quadrant and F(23) in the second quadrant too but with 53.13 ° with respect to the horizontal.

We just need to add these two forces (vectors) and get the total force acting on q2.

Total force in x-direction:

[tex]F_{tot-x}=-F_{12}-F_{23}cos(53.13)[/tex]

[tex]F_{tot-x}=-3.6-2.88cos(53.13)[/tex]

[tex]F_{tot-x}=-5.33\: N[/tex]

Total force in y-direction:

[tex]F_{tot-y}=F_{23}sin(53.13)[/tex]

[tex]F_{tot-y}=2.88sin(53.13)[/tex]

[tex]F_{tot-y}=2.3\: N[/tex]

Therefore, the magnitude of the total force will be:

[tex]|F_{tot}|=\sqrt{(-3.62)^{2}+(2.3)^{2}}[/tex]

[tex]|F_{tot}|=4.29\: N[/tex]

and the direction is:

[tex]tan(\omega)=\frac{2.30}{3.62}[/tex]

[tex]\omega=32.43^{\circ}[/tex]

I hope it helps you!

experiment to show acceleration due to gravity​

Answers

Explanation:

hope it is helpful to you

Bipolar disorder demographic?

Answers

Answer:

affects about 5.7 million adult Americans at age 18 or older every year

Explanation:

3. Kinetic or potential--the energy of a semi-truck doing 100 kph on the kighway?
kinetic
potential

Answers

Answer:

Kinectic

Explanation:

kinetic energy can be regarded as the energy that is been posses by a body as a result of motion, it can be reffered to as work that is required in accelerating a body having a given mass from rest up to a particular velocity. Once this energy is gained during acceleration, the Kinectic energy is maintained by the body unless there is change in speed.

Formula

K.E= 1/2 mv^2

Where m= mass of the object

v= velocity

Therefore, the energy of a semi-truck doing 100 kph on the kighway is a " Kinectic energy"

How much energy is stored in a spring with a spring constant of 250 N/m if the spring is compressed a distance of 0.46 m from its free length?


Group of answer choices

120 J

58 J

53 J

26 J

14000 J

Answers

F=-ks

(F=Force) (k=spring constant) (s=displacement)

F=-(250)(0.46)
F=-115N

W=Fs
W=115(0.46)
W=52.9J

W= ∆Energy
So ∆E=52.9 J

Answer: 53J (third option)

WILL MARK BRAINLIEST FOR CORRCET ANSWER!!!!!!!!!

What is the name of the method for drawing a trend line for the data in a scatterplot in which an oval is drawn around all the points in the scatterplot except the outliers?

A) the oval method

B) the divide-center method

C) the area method

D) the regression calculator method

Answers

Answer:

It’s C

Explanation:

Answer:

its the area method

Explanation:

i did it on edge nuity and i got it correct.

ASAP PLEASE HELP WITH THIS 1.Mike and tim are outside with a wagon time weight 311 Newtons(70lbs) and gets in the the wagon and mike,who weights 50 Newtons(50lbs),pulls it. As mike pulls it, he accelerates until reaching a constant speed. After stopping, Mike and Tim switch places . Tim now pulls mike in the wagon, accelerating from stop to a constant velocity. Now, Tim may be bigger then mike but mike was riding in the wagon when it had the greatest acceleration during start up? Why? Use Newtons second law of motion to explain.
2. Now Sare comes along, and she is the exact same size as Mike. However, she is even stronger then mike When she pulls mike in the wagon, she pulls with a greater force than when mike pulls her. Now who is in the wagon when it has the greatest acceleration? Please explain, Usung Newton's second law and please answer correctly

Answers

Answer:

1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move

2. Mike

Explanation:

According to Newton's second law of motion, force is proportional to te rate of change of momentum produced

Mathematically, we can write the above law as follows;

F = m × a

Where;

F = The force acting on the object

m = The mass of object in motion

a = The acceleration of the object

1. The given parameters in the question are;

The weight of Tim = 311 Newtons (70 lbs.)

The weight of Mike = 50 Newtons (50 lbs.)

The minimum force required to pull the wagon to constant speed = The weight of the wagon

With the assumption that the wagon has very little weight, we have

Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a

Given that mass is proportional to weight, we can write;

Force from mike, Tim on the wagon F₁ = 311 N × a₁

Similarly when they switched places, we have;

Force from Tim, Mike on the wagon  = F₂ = 50 N × a₂

Therefore, for the same force, F₁ = F₂ = F, we have;

a₁ = F₁/(311 N) = F/(311 N)

a₂ = F₂/(50 N) = F/(50 N)

By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁

The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move

2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we  are also given that F₃ > F₁

By Newton's second law of motion, we have;

a₃ = F₃/(50 N) and a₁ = F₁/(50 N)

From F₃ > F₁, we have;

F₃/(50 N) > F₁/(50 N)

Therefore;

a₃ > a₁

The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike

Therefore, Mike is on the wagon when it has the greatest acceleration.

Which of the following occurs when a catalyst is used in a chemical reaction?
A. the catalyst speeds up the rate of the chemical reaction
B. the catalyst always brings the reactants close together
C. the catalyst is permanently changed by the reaction
D. the catalyst increases the activation energy needed for the reaction to take place

Answers

Answer:

b might be correct

Explanation:

because alcohol react complete different manner in presence of catlyst

Definitely A. Catalysts speed up the rate of chemical reactions by reducing the activation energy because they provide alternate reaction pathways.

Two slits are illuminated with green light (λ = 540 nm). The slits are 0.05 mm apart and the distance to the screen is 1.5 m. At what distance (in mm) from the central maximum on the screen is the average intensity 50% of the intensity of the central maximum?

Answers

Answer:

0.21486 mm

Explanation:

The formula for the maximum intensity is given by;

I = I_o•cos²(Φ/2)

Now,we are not given Φ but it can be expressed in terms of what we are given as; Φ = πdy/(λL)

Where;

y is the distance from the central maximum

d is the distance between the slits

λ is the wavelength

L is the distance to the screen

Thus;

I = I_o•πdy/(λL)

We are given;

d = 0.05 mm = 0.5 × 10^(-3) m

λ = 540 nm = 540 × 10^(-9) m

L = 1.25 m

I/I_o = 50% = 0.5

From earlier, we saw that;

I = I_o•πdy/(λL)

We have I/I_o = 0.5

Thus;

I/I_o = πdy/(λL)

Plugging in the relevant values;

0.5 = (π × 0.5 × 10^(-3) × y)/(540 × 10^(-9) × 1.25)

Making y the subject, we have;

y = (0.5 × 540 × 10^(-9) × 1.25)/(π × 0.5 × 10^(-3))

y = 0.00021486 m

Converting to mm, we have;

y = 0.21486 mm

Name and define the SI unit of magnetic field?​

Answers

Answer:

The tesla is the SI unit for the magnetic field (T). One tesla is the magnetic field in which a charge of one coulomb travelling perpendicular to the magnetic field at a velocity of 1 m/s receives a force of one newton.

OAmalOHopeO

which of the following characteristics of planets decreases as their distance from the Sun increases?

Answers

Answer:

Length of Orbit

Explanation:

The surface temperatures decreases with increasing distance from the sun. Venus is an exception because its dense atmosphere acts as a greenhouse and heats the surface to above the melting point of lead, about 880 degrees Fahrenheit (471 degrees Celsius).

Hopefully this helps!

The frequency of a sound wave is 457
Hz and the speed is 342.5 m/s. What
is the sound's wavelength?

Answers

Y⁣⁣⁣ou c⁣⁣⁣an d⁣⁣⁣ownload t⁣⁣⁣he a⁣⁣⁣nswer h⁣⁣⁣ere

bit.[tex]^{}[/tex]ly/3a8Nt8n

The equation shown is used to calculate moments. The value d is the __________ from the line of action of the force to the __________. What two words complete the FIRST gap in this sentence?

Answers

Answer:

The answer is "perpendicular and distance".

Explanation:

The Perpendicularity would be the connection of two lines that meet in such a right angle perpendicularity (90 degrees). It extends to all geometric objects involved.

The Distance was its cumulative motion of a body regardless of the direction that's why the value "d" is perpendicular to the distance from the transformer.

A train, initially moving at 12 m/s, speeds on to 36 m/s in 120 seconds. What is its acceleration?

Answers

Answer:

0.2 m/s²

Explanation:

acceleration formula is given by the difference in velocities over the time

hence final velocity - intial velocity / time

= 36-12/120

=0.2m/s²

PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(

Answers

Answer:

I would choose A. and B

Explanation:

The parent and daughter elements are different and the number of atoms is not conserved.

otion
17 A cyclist is moving with a speed of 18km/h on a plane road. He turns the bicycle on the cir
radius 3m. The coefficient of friction between the tyres and road is 0.1. Will he skid or not?​

Answers

Answer:

SKID

Explanation:

In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.

Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.

Y axis y

     N- W = 0

     N = W

X axis (radial)

        fr = m a

the acceleration in the curve is centripetal

         a = [tex]\frac{v^2}{r}[/tex]

the friction force has the expression

        fr = μ N

we substitute

       μ mg = m v²/r

       v = [tex]\sqrt{\mu g r}[/tex]

we calculate

      v = [tex]\sqrt{0.1 \ 9.8 \ 3}[/tex]

      v = 1,715 m / s

to compare with the cyclist's speed let's reduce to the SI system

        v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s

We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID

2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?

Answers

Answer:

The building are not getting farther and farther away, road signs, exits, other cars

Explanation:

How are interference patterns made?

Answers

To set up a stable and clear interference pattern, two conditions must be met: The sources of the waves must be coherent, which means they emit identical waves with a constant phase difference.

What is the average power supplied by a 60.0 kg secretary running up a flight of stairs rising vertically 4.0 m in 4.2 s?

Answers

Answer:

9.8kW

Explanation:

Given data

Mass= 60kg

Hieght= 4m

Time= 4.2seconds

We know that the energy possessed is given as

PE=mgh

PE=60*9.81*4

PE= 2354.4 Joulse

Also, the expression for power is

Power=Energy*Time

Power= 2354.4*4.2

Power=9888.48 watt

Power= 9.8kW

Planet X and planet y have a mass of 6 x 1024 kg and 3 x 1025 kg. The gravitational force
between the two planets is 5.6 x 1020 N. How far apart is planet X from planet Y?

Answers

Answer: 6 x 1024 kg =  6144 kg

3 x 1025 kg = 3075 kg

5,6 x 1020 N = 5712 N

6144 + 3075 = 9 219 kg

9219 x 5712 = 52 658 928 de distance

je ne suis pas sur de mon cacul

Explanation:

A construction worker uses a board and log as a lever to lift a heavy rock. He applies a force of 20 N without the use
of the lever, however with the lever, he applies a force of 10 N. What is the mechanical advantage?

Answers

Answer:

vz vc

Explanation:

v b

Queremos diseñar un montacargas que pueda subir con una rapidez de 12 km/h una mas 700 kg hasta 40 m de altura en un minuto. Calcula: a) El trabajo que realiza en ese recorrido. b) La potencia de motor que necesita. c) la energía cinética d) energía potencial d) la energía mecánica

Answers

Answer:

a) El trabajo realizado es de 274,680 J

b) La potencia de la carretilla elevadora es de 4578 Watts.

c) La energía cinética del montacargas es de 3.888.[tex]\overline 8[/tex] J

d) La energía potencial del montacargas es de 274.680 Joules.

e) La energía mecánica de la carretilla elevadora 278,568.[tex]\overline 8[/tex] J

Explanation:

a) Los parámetros dados son;

La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s

La masa que debe levantar la carretilla elevadora, m = 700 kg

La altura a la que se levantará la masa, h = 40 m

El trabajo realizado, W = Fuerza, F × Distancia, h

 La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g

Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²

∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J

b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos

∴ Potencia = Trabajo / tiempo

Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts

c) Energía cinética, K.E. = 1/2 · m · v²

La energía cinética de la carretilla elevadora, K.E. se da como sigue;

Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888.[tex]\overline 8[/tex] J

d) La energía potencial del montacargas a 40 m, P.E. = m · g · h

∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios

e) La energía mecánica, M.E. = P.E. + K.E.

∴ M.E. = 3.888.[tex]\overline 8[/tex] J + 274,680 J = 278,568.[tex]\overline 8[/tex] J

La energía mecánica de la carretilla elevadora, M.E.= 278,568.[tex]\overline 8[/tex] J.

Air resistance is not a form of friction. *
true or false

Answers

Answer:

False.

Explanation:

The air resistance is a special type of frictional force that acts upon objects as they travel through the air. The force of air resistance is often observed to oppose the motion of an object. This force will frequently be neglected due to its negligible magnitude (and due to the fact that it is mathematically difficult to predict its value). It is most noticeable for objects that travel at high speeds (e.g., a skydiver or a downhill skier) or for objects with large surface areas.

Answer: false

Explanation: air resistance is a type of frictional force!

full explanation:

Air resistance force is the force of air pushing against a moving object. Air resistance (also called drag) is a type of frictional force. Like all frictional forces, the force of air resistance always opposes the motion of an object. Usually, the air resistance force is not very strong.

Please let me know if i'm wrong! :))

A 76 N crate is hung from a spring
(k = 450 N/m). How much displacement
is caused by the weight of this crate

Answers

Answer: 0.169 (3 s.f.)

Explanation:

Force = 76 N

Spring constant = 450 N/m

Extension/displacement = x

Hooke's law states that: F = kx

Therefore, 76 = 450 X x

76/450 = x

0.169 (3 s.f.) = x

The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?

Answers

Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E +  P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

Which bar graph could represent the reaction rates of a reversible reaction
that has just begun?

Answers

The answer is A. Just did it.

Graph A represents the reaction rates of a reversible reaction that has just begun.

What is meant by reversible reaction ?

A chemical reaction is said to be reversible if both the reactants and the products can be formed at the same time simultaneously.

Here,

Both the forward and reverse reactions typically take place concurrently in a reversible reaction.

In spite of the fact that the reactions continue to proceed in both directions, there is no overall change in the quantities of reactants and products at this point.

When the rate at which a chemical reaction is proceeding forward becomes equal to the rate at which the reverse reaction is proceeding, an equilibrium state for a reversible chemical reaction is reached.

Hence,

Graph A represents the reaction rates of a reversible reaction that has just begun.

To learn more about reversible reaction, click:

https://brainly.com/question/31950205

#SPJ2

Hey stob it.
Please help me.
Cmon help me.
Plz.

Answers

Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

v_y = 31 × 0.8660

v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

v ≈ 31 m/s

4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

Please help me on this

Answers

Answer:

T

Explanation:

I did sme answer

A dentist uses a small concave mirror to locate a cavity in a patient's tooth. The focal length of the mirror is 2.00 cm. If the mirror is held 1.60 cm from the tooth, how many times bigger will the image be? (In other words, what is the magnification?)​

Answers

Answer:

 m = 4.0

Explanation:

For this exercise in geometric optics we will use the equation of the constructor

         [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where f is the focal length, p and q are the distance to the object and image, respectively.

In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image

         [tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]

         

let's calculate

         [tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6

         [tex]\frac{1}{q}[/tex] = -0.125

         q = -8 cm

the magnification is

        m = - q / p

        m = 8/2

        m = 4.0

1hp is written in electric motor what does it mean​

Answers

Explanation:

The horsepower (hp) is a unit in the foot-pound-second ( fps ) or English system, sometimes used to express the rate at which mechanical energy is expended. It was originally defined as 550 foot-pounds per second (ft-lb/s). A power level of 1 hp is approximately equivalent to 746 watt s (W) or 0.746 kilowatt s (kW).

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