The initial velocity of the ball would be 14.7 m/s.
What is initial velocity?Initial velocity is the speed and direction of an object at the start of its motion. It is a vector quantity, meaning it has both magnitude (the speed) and direction. Initial velocity is usually denoted by the letter v, with an arrow above it to indicate its direction.
The speed with which the ball player threw the ball can be calculated using the equation v = √2gh,
where v is the initial velocity,
g is the acceleration due to gravity (9.8 m/s2), and
h is the height from which the ball was thrown.
In this case, h = 3.46 s, so the initial velocity of the ball would be v = √2(9.8)(3.46) = 14.7 m/s.
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A 77.0 kg woman, initially at rest, slides
down a 42.6 m long waterslide inclined
at 42.3°. At the bottom, she is moving
20.3 m/s. How much work did friction
do on the woman?
Answer:
5.791244495 KNm
Explanation:
hope it helps
Answer:
-5770
Explanation:
other guy is trash
the maximum amount of weight a jack can lift is called its
The "Load Capacity" of a jack refers to the greatest weight it can support. Maximum weight of cargo that has been authorised by the country where the vehicle was registered.
Define the term Load Capacity?We can determine the necessary minimum capacity for a trailer jack by analysing the concentration of loads in a typical trailer.
The capacity should take into consideration both the jack's responsibility to sustain the weight and the lifting mechanism's capability to lift it.The tongue of a conventional trailer is designed to support 10% to 15% of a gross trailer weight when the trailer is positioned horizontally. Take the gross trailer weight then multiply it by the number of trailer jacks required to support the trailer. 15 to determine the tongue's theoretical weight. Choose a jack with a safety margin with which you are familiar with and that can support that weight.Thus, the "Load Capacity" of a jack refers to the greatest weight it can support.
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there exists a point near two charges where the electric field is equal to zero. is the electric potential at that same point also equal to zero?
The electric potential at that same point also equal to zero where electric field is also zero.
The work energy required to carry a unit of electric charge from a reference point to a particular point in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential). It is, more specifically, the energy per unit charge for a test charge that is so small that the disturbance of the field under investigation is insignificant.
The expression for electric potential at a point due to a charge Q is given as,
[tex]P=K\times\frac{Q}{R}[/tex]
while expression for electric field at the same point is,
[tex]E=K\times\frac{Q}{R^{2} }[/tex]
And the resultant electric potential or field will be the vector sum in the case of electric field and algebraic sum in the case of potential. Because, electric field is a vector quantity and electric potential is a scalar quantity.
So, zero electric field does not guarantees that electric potential will also be zero. It will depend on the distance (r) of the point from the two charges.
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19. A rock that is thrown vertically downward travels
10.0 m before hitting the ground. If it strikes the
ground at a velocity of 15.0 m/s, how long did it
take to reach the ground?
It took 2.04 seconds for the rock to reach the ground, after it was thrown vertically downward at a velocity of 15.0 m/s.
What is velocity?
Velocity is a vector quantity that describes the rate of change of an object's position in a specific direction. It is defined as the distance an object travels per unit of time. The standard unit of velocity is meters per second (m/s) in the International System of Units (SI).
To determine how long it took for the rock to reach the ground, we can use the equation:
d = v0t + (1/2)gt^2
Where d is the distance traveled, v0 is the initial velocity (which is zero for a rock that is thrown vertically downward), t is the time, and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Since we know the distance traveled and the final velocity of the rock, we can rearrange the equation and solve for t:
t = (2d / g)^1/2
Plugging in the given values:
t = (2 * 10 m / 9.8 m/s^2)^1/2 = (2 * 10 / 9.8)^1/2 = 2.04 s
Therefore, it took 2.04 seconds for the rock to reach the ground, after it was thrown vertically downward at a velocity of 15.0 m/s.
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A woman wearing an in-ear hearing aid listens to a television set at a normal volume of approximately 60 dB. To hear it, she requires an amplification of 30 dB, so the hearing aid supplies sound at 90 dB to the ear canal, which we assume to be circular with a diameter of 7. 0 mm. What is the output power of the hearing aid?
The output power of the hearing aid is approximately 1.6 micro-watts.
What is the sound level supplied to the ear canal by the hearing aid?
The sound stage furnished to the ear canal by using the hearing resource is ninety dB. This is precise within the trouble assertion, in which it's miles said that the female calls for an amplification of 30 dB to pay attention the tv set at a regular extent of 60 dB. Consequently, the hearing resource materials sound at ninety dB to the ear canal. The sound degree is measured in decibels (dB) and is used to specific the relative loudness of a sound. The higher the decibel degree, the louder the sound is.
A sound stage of 90 dB is considered loud and can reason harm to the ears if uncovered to it for an extended time frame.
Lets find the intensity as follows,:
β = 10log( I / Io) where Io = 10^-12 W/m^2
90dB = 10log( I / 10^-12 W/m^2)
9 = log ( I / 10^-12)
10^9 = I / 10^-12
I = .001 W/m^2
Put this into the equation of I = P/a
The diameter is .0076m so the radius us .0038m
a = pi(.0038^2) = 4.534x10^-5 m^2
Then we multiply that by the intensity above
(.001 W/m^2)(4.534x10^-5 m^2) = 4.534x10^-8 W
output power of the hearing aid = 4.534x10^-8 W
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The distance (miles) a rider travels on a mountain trail is given by s(t) = 3t^3 + 2t^2 + 4. What is the rider's acceleration after two minutes?
A.
36 miles/min2
B.
38 miles/min2
C.
40 miles/min2
D.
44 miles/min2
Answer:
To determine the rider's acceleration after two minutes, we need to find the second derivative of the distance function s(t) = 3t^3 + 2t^2 + 4 with respect to time. In other words, we need to find the rate of change of the rider's velocity.
The first derivative of s(t) with respect to time is v(t) = 9t^2 + 4t.
The second derivative of s(t) with respect to time is a(t) = 18t + 4.
Now that we have the second derivative, we can find the acceleration after two minutes.
a(2) = 18(2) + 4 = 40 miles/min^2
Therefore the rider's acceleration after two minutes is C. 40 miles/min^2
a 20 kg box is attached to a compressed spring that has a spring constant of 300 n/m. the box is resting on a frictionless surface and the spring is compressed 30 cm. how fast will the box be moving after the spring releases the box?
The box will be moving at the speed of 1.16 m/s, when the spring is compressed by 30 cm, if the spring constant is 300 n/m and the mass of the box is 20 kg.
Potential energy stored in the spring during compression of x cm, U = 0.5 kx²
Kinetic Energy possessed by the object moving at a speed of v, = 0.5 mv²
0.5 × 20 × v² = 0.5 × 300 × 0.3²
v² = (0.5 × 300 × 0.3²)/(0.5 × 20)
v² = 1.35
v = √1.35
v = 1.16 m/s
So the box will be moving at a speed of 1.16 m/s.
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why should you only use the fine focus when trying to put a specimen in sharp focus when using the 40x objective lens?
Using the fine focus when trying to put a specimen in sharp focus when using the 40x objective lens ensures that the specimen is brought into focus as accurately and precisely as possible.
This knob is used to adjust the specimen's focus. Additionally, it is used to highlight specific areas of the specimen. The coarse focus knob should often be used to get near before switching to the fine focus knob for fine tweaking.
The fine focus allows for a much finer adjustment of the specimen's position to be made, which is necessary when using a higher magnification objective lens like the 40x.
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a 60 kg hiker wishes to climb 1200 meter high if he can generate a sustained average power of 500 watts, how long will the climb take
The time it will take do the hiker to climb the 1200m high wall is 1,411.2 seconds.
How to calculate time from power?Power refers to the measure of the rate of doing work or transferring energy.
Power = Work done/time
Since work = force × distance the body is moved
Power = (m × g × h) / t
Where;
m = the mass of the bodyg = the acceleration due to gravityh = the height the body has fallent = the time the body has fallenAccording to this question, a 60kg hiker wishes to climb 1200m high. If he can generate a sustained average power of 500 watts, the time it will take to climb is as follows;
500 = 60 × 9.81 × 1200/t
500t = 705,600
t = 1,411.2 seconds
Therefore, 1,411.2 seconds is the time it will take the hiker.
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Where are the carbon atoms before the chemical reaction starts?
Carbon atoms combine with carbon dioxide molecules to form ethanol. The area of the atom where a chemical reaction takes place is called the electron cloud.
What molecule are carbon atoms in before the chemical change?In ethanol, carbon atoms join molecules of carbon dioxide. The electron cloud is the region of the atom that is involved in a chemical process. The area of the atom surrounding the nucleus is called the electron cloud. The particle that caused the reaction to take place is an electron, which is found in the electron cloud.
A chemical reaction neither creates nor destroys atoms. Rearranging the atoms occurs. Due to this, new compounds are created that have properties that differ from the initial substances.
The materials that initiate a chemical reaction are known as reactants, while the materials created as a result of the reaction are known as products.
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a hot rod of mass 1000 kg, starting from rest reaches a speed of 130 m/s in only 29 s. what is the average output power?
A 1000 kilogramme FRICTION is driving at a pace of 130 metres per second. To bring a car to a stop, the brakes are applied. Hence, 223 J is the average output power
What causes road friction?To prevent sliding vehicles or spinning wheels, friction or traction are essential. The act of rubbing one surface or object against another is known as friction. The maximum acceleration and shortest stopping distance are determined by the friction between the tyres of your car and the road.
Is the friction on tyre roads static?Because there is only frictional force acting on the car, friction is acting backwards. The amount of friction that can be applied to a vehicle's tyres to prevent road traction is as high as.
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analysis of a bus crashgiven the following theoretical data for the collision, answer the following questions and complete the data table. show work! bus suv m v p m v p total momentum before collision 1600 kg 10 m/s 600 kg 0 after collision 1600 kg 3 m/s 600 kg 1. what is the change in momentum of the bus?
The change in the momentum of the bus is 10600 kg-m/s, if bus of 1600 kg crashes with a SUV of 600 kg.
The mass of the bus, m₁ = 1600 kg
The mass of the SUV, m₂ = 600 kg
Initial velocity of the bus, v₁ = 10 m/s
initial velocity of the SUV, v₂ = 0 (at rest)
Velocity of the bus after collision, v₃ = 3 m/s
Velocity of the SUV after collision, v₄ = 1 m/s
The change in momentum(Δp) is given by,
Δp = (m₁v₁ + m₂v₂) - (m₁v₃ + m₂v₄)
Δp = (1600 × 10 + 600 × 0) - (1600 × 3 + 600 × 1)
Δp = 16000 - 5400
Δp = 10600 kg-m/s
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beneath the surface of which moon of jupiter is there the strongest evidence for the existence of a subsurface ocean of liquid water?
Beneath the surface of Jupiter's moon of Europa there exists the strongest evidence for the existence of a subsurface ocean of liquid water.
Based on the icy composition of Jupiter's moon named Europa scientists impose the concept that there is the most likely material to make this magnetic signature is a global ocean of salty water. And the result of this magnetic field still is the best evidence for reporting the existence of an ocean on Europa.
Therefore, beneath the surface of Europa's moon of Jupiter, there exists the strongest evidence for the existence of a subsurface ocean of liquid salty water.
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2. the water level of a tank on a building roof is 20 m above the ground. a hose leads from the tank bottom to the ground. the end of the hose has a nozzle, which is pointed straight up. what is the maximum height to which the water could rise? what factors would reduce this height?
The maximum height of the water after coming out of the nozzle is affected is by the initial speed and the value of the
The water level of the tank on the building is 20m. The hose leads from the tank bottom to the ground and leads to the nozzle that is point to the top.
Here, we know, the energy will also be conserved because the there is o external force, so the kinetic energy at the top will be equal to the potential energy at the bottom in the ideal case.
Now, we can write,
1/2mv² = mgh
v = √(2gh)
g is the acceleration due to gravity and the h is the height of the tank.
Putting values,
v = √(2 x 10 x 20)
v = 20 m/s
Now, we can use the equation of motion,
v = √(2hg)
h = v²/2g
v is the speed of the water from the nozzle.
h = 10m.
This is because we have considered the ideal case where there is no energy loss, so water will go till a height of 10m when it comes out of the nozzle. The height rise is affected by the initial speed.
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what are the two main metals that make up the outer and inner core?
The core is almost entirely comprised of metal, notably iron and nickel, in contrast to the crust and mantle, which are rich in minerals. The iron-nickel alloys in the core are denoted by the chemical symbols NiFe.
The densest sort of solid matter in space is metal. They are often made of heavier metals that have not undergone chemical fusion. Iron and nickel are the most frequent metallic elements that have not yet been mixed, at least inside our Solar System. As we can see from Earth's structure, metals may be liquid like rocks in the hot cores of huge bodies. Consequently, the iron- and nickel-rich metals dominate the core. In the case of Earth, we know that the metal is melted in the outer core, yet there is high-pressure solid metal within that liquid (inner core).
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A 30 kg dog is running at 1 m/s and quickly comes to a stop when she sees her bone.
What is the work required for her to come to a complete stop?
The work required for the dog to come to a complete stop is -900 J (work = force x distance = (30 kg x 9.8 m/s^2) x (1 m))
What is the distance over which the force is applied?The distance over which the force is applied, in this case, would be the distance the dog travels as it slows down to a stop. This distance would depend on the initial velocity of the dog, the force applied to slow it down, and the amount of time it takes for the dog to come to a stop. In this case, the initial velocity is 1 m/s and the force applied is the opposite of the dog's weight, or -30 kg x 9.8 m/s^2. However, without information on the amount of time it takes for the dog to come to a stop or the deceleration of the dog, it is not possible to determine the exact distance over which the force is applied.
It is important to note that the distance over which force is applied is a scalar value and is independent of the direction of motion.
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consider steady one-dimensional heat conduction through a cylindrical or spherical layer. what can you say about the rate of heat transfer through the layer
The rate of heat transfer through the layers of the cylinder will be constant.
There is no heat flow from the sides of the object. The cross-sectional area of a body in the direction of heat flow is constant. This is called one-dimensional heat flow because the temperature of a body is a function of only one dimension (distance from each side of the body). Heat transfer from the hot combustion gases includes forced convection through the hot gas boundary layer, conduction through the cylinder wall, and forced convection (including boiling) into the coolant liquid in head, engine block, and piston.
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A spider monkey (mass 40 kg) is frolicking through the jungle at a speed of 3. 0 m/s. All of a sudden, a panther appears and tries to eat the monkey. The monkey begins to run frantically—now he has a speed of 14. 0 m/s. How much work does the monkey do to increase its speed?
When a panther appears and attempts to eat the monkey, the monkey performs 3740 J of work to increase its speed.
What is work?Work in physics is the energy transferred to or from an object by applying force along a displacement. In its most basic form, work equals the product of force strength and distance traveled for a constant force aligned with the direction of motion. Work is the transfer of energy caused by a force acting on an object as it moves. The work done by a force on an object is calculated as the product of the magnitude of the force multiplied by the magnitude of the displacement multiplied by the cosine of the angle between them.
Here,
W=1/2mv1²-1/2mv2²
=1/2*40(14²-3²)
=3740 J
The monkey does 3740 J of work of increase its speed when a panther appears and tries to eat the monkey.
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A ball of mass 2 kg is attached to a vertical spring. The ball displaces 0. 1 m once it is attached. What is the spring constant?
The spring constant of spring when a ball of mass 2 kg is attached to a vertical spring and is displaced 0. 1m once it is attached is 196.
Given the mass of ball (m) = 2kg
The distance the ball displaced (x) = 0.1m
We know that from Newtons laws of motion F = ma where F is the force acting on an object a is the acceleration.
Here, since the ball is attached to the vertical spring the acceleration acting on the ball is due to gravity. So a = g = 9.8m/s^2.
The restoring force acting on the vertical spring is given as:
Fr = kx where k is spring constant and x is the distance the ball displaced.
As restoring force is balanced by the weight of the ball, Fr = F
Then mg = kx such that k = mg/x
k = 2 x 9.8 / 0.1 = 196
Hence the spring constant of the spring = 196
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Answer:
Explanation:
Since F = ma
And a is 9.8
m = 2
F = 2*9.8
F = 19.6
Hookes Law:
F = kx
So 19.6 = k*0.1
So k = 196
Which equation can you use to calculate the mechanical advantage of a simple machine?
MA = delta x1 / delta x0
MA = delta xi - delta x0
MA = delta xi * delta x0
MA = delta x0 / delta x1
The equation that can be used to calculate the mechanical advantage of a simple machine is as follows: MA = delta x0 / delta x1 (option D).
How to calculate mechanical advantage?Mechanical advantage is the ratio of the output force produced by a machine (especially a simple machine) to the applied input force.
The mechanical advantage (MA) is used to analyze the forces in simple machines like levers and pulleys.
Mechanical advantage = Fo/Fi
Where;
Fo = output forceFi = input forceAccording to this question, option D best describes the equation that can be used to calculate the mechanical advantage of a simple machine.
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a tin can has a volume of 1100 cm3 and a mass of 80 g. approximately how many grams of lead shot can it carry without sinking in water?
The tin can carry approximately 880 grams of lead shot without sinking in water.
To calculate this: Start with the equation for buoyancy: Buoyant force = Density of fluid x Volume x Gravity
Substitute in the values for the tin can: Buoyant force = Density of water x 1100 cm3 x 9.8 m/s^2
Convert the volume to liters: 1100 cm³ = 1.1 liters
Substitute in the density of water (1 g/cm^3): Buoyant force = 1 x 1.1 x 9.8
Solve for the buoyant force: Buoyant force = 10.78 N
To find the maximum weight of lead shot that the can carry without sinking, subtract the weight of the can (80 g) from the buoyant force (10.78 N) and convert it to grams: 898 g
So the tin can carry approximately 898 grams of lead shot without sinking in water.
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Hermann ebbinghaus’ research would most likely predict that?
Mike would rapidly forget most of the material that he read. Dr. Ummel conducts a memory experiment where he shows a fight between two men and describes the contact as "punching" to one group and "tapping" to the other group.
What is meant by memory ?
The capacity or method for repeating or recalling what has been learnt and retained, particularly through associative mechanisms. As he got older, his memory started to fail.Sensory memory, short-term memory, and long-term memory are the three basic types of memory that are discussed.Memory is the capacity to retain and recall knowledge when necessary. Working memory, short-term memory, long-term memory, and sensory memory are the four main categories of memory.Storage refers to where long-term data is kept, whereas memory refers to where short-term data is kept. The term "memory" is most frequently used to describe the main storage on a computer, such as RAM. Information is also processed in memory.To learn more about memory refer to
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Which of these is a benefit of desalination technology?
• A. Toxic salty residue
• B. High energy cost
• C. Fresh drinking water
O D. High financial cost
Desalination removes potentially harmful minerals and chemicals in addition to the salt that is present in your water.
What advantages does desalination technology offer? The fact that a desalination plant makes drinking water readily available to people who need it most is undoubtedly one of its main advantages.Even in countries with access to fresh water, this holds true whether there is a drought or a natural calamity.Desalination removes potentially harmful minerals and chemicals in addition to the salt that is present in your water.Physical separation of microorganisms by chemical processes is used to remove them.In addition to removing salt, desalination also gets rid of potentially dangerous metals, chemicals, and microorganisms from your water source.By physically rejecting bacteria via chemical processes, it eliminates microorganisms.To learn more about desalination technology refer
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can i run my car's air conditioning while waiting a few minutes before i attempt to deflood the car engine again?
You can run the car’s air conditioning before attempt to unflood the car engine.
If you aren't short on gas, you can leave your car idling with the air conditioner on for as long as you wish. However, you shouldn't do this with the engine off, since this will quickly drain the battery and leave you in need of a jumpstart. Internal Combustion Engines (ICEs) that have been flooded with too much fuel are rendered inoperable. Sometimes, giving a flooded engine some time to dry out is the best solution.
You can let the excess gas out of your car by opening the hood and leaving it that way for as long as possible. After waiting around 20 minutes, try to start the car up again without pressing the gas. If that doesn't work, you might want to inspect the spark plugs.
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calculate the average density of the earth in g/cm 3 , assuming our planet is a perfect sphere. (b) in about 5 billion years, at the end of its lifetime, our sun will end up as a white dwarf that has about the same mass as it does now but is reduced to about 15,000 km in diameter. what will be its density at that stage?
The average density of the Earth in g/cm3 is 5.51 g/cm3 and the density at the stage when the sun will end up as a white dwarf in diameter is [tex]1.1X10^{6} g/cm^{3}[/tex].
For solving the part (a) of the question, we know that,
Mass of the Earth: 5.97x [tex]10^{24} \\[/tex] kg.
Radius of the Earth: 6.37 x [tex]10^{6}[/tex] m.
The formula of the density is :
Density = Mass/ Volume.
Here, Volume is 4/3 [tex]\pi[/tex][tex]r^{3}[/tex].
Substituting all the values written above in the density equation,
Density is 5.51 g/cm3 .
For solving the part (a) of the question, we know that,
Mass of the Sun: 1.99x [tex]10^{30} \\[/tex] kg.
Radius : 7500 km
The formula of the density is :
Density = Mass/ Volume.
Here, Volume is 4/3 [tex]\pi[/tex][tex]r^{3}[/tex].
Substituting all the values written above in the density equation,
Density is 1.1X10^{6} g/cm^{3}.
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a horizontal clothesline is tied between 2 poles, 18 meters apart. when a mass of 2 kilograms is tied to the middle of the clothesline, it sags a distance of 5 meters. what is the magnitude of the tension on the ends of the clothesline?
The magnitude of the tension on the ends of the clothesline is 175N.
Tension is a mechanical term that describes the opposing resisting force that a rope or string experiences when it experiences a weight at the end of it. It can be measured in Newtons. It can be found all the way down a rope or thread.
we know that the combined vertical tension in the clothesline must equal the weight of the mass;
using g=9.8m/s/s, W=2kgx 9.8m/s/s = 19.6N
now, draw a diagram of the situation; if we call x the angle between the clothesline and the horizontal line that connects the poles, we have that
tan x = 1/9 => x =6.34 deg
now, we can use this angle to show that if T is the tension in the clothes line, the vertical component of tension is T sin x = T sin 6.34
since both sides of the line exert a tension up, we have that
2 T sin 6.34 = W = 19.6 N
or T= 175N.
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the volume of a gas is proportional to the temperature of a gas is known as
Charles's law means that the volume of a gas is directly proportional to its absolute temperature
Simple Gas Laws - Boyle's Law, Charles' LawBoyle's Law tells us that the volume of a gas increases as the pressure decreases. Charles's law tells us that the volume of a gas increases with increasing temperature
This is stated by Karl's law, also known as the law of volumes
For a dry gas sample, its volume and Kelvin temperature are directly proportional if the pressure is kept constant
Mathematical representation -
[tex]\begin{equation*} PV=nRT \end{equation*}[/tex] P : is a Pressure(Pa)
[tex]\begin{equation*} V=\frac{nRT}{P} \end{equation*}[/tex] V : is volume ([tex]m^{3}[/tex])
T : absolute temperature (K)
R : gas constant [tex]\begin{equation*} 8.314K^{-1}.mol^{-1} \end{equation*}[/tex]
n : amount of substance of the gas (mole)
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find the time it takes the electron to travel through the region of the electric field, assuming it does not hit the side walls
The time taken by the electron is [tex]3.33*10^{-8} seconds[/tex] .
Complete question:
An electron traveling at [tex]3*10^{6} m/s[/tex] enters a 0.1 m region with a uniform electric field. Find the time it takes the electron to travel through the region of the electric field, assuming it does not hit the side walls.
(See the figure attached)
Since, no field and hence no force act on the electron along X-direction.
Hence, [tex]v_{x}[/tex] remains constant.
Now time taken = t = l/[tex]v_{x}[/tex]
Where,
l = length of field = 0.1 m
v = speed of electron = [tex]3*10^{6} m/s[/tex]
Putting this value in above equation, we get t = [tex]3.33*10^{-8} seconds[/tex] .
Electrostatics is a branch of physics that deals with the phenomena and properties of stationary or slow-moving electric charges. Electrostatic phenomena arise from the forces that electric charges exert on each other and are described by Coulomb’s law.Even though electrostatically induced forces seem to be relatively weak.To know more about electrostatics visit:
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3. Luke writes a very important note to Tyreke, who sits 5.8 m away, and folds it into a
paper airplane. The message must get there before the bell, in 6.5 seconds! At what
speed must he fly the paper airplane?
Distance traveled time is 4 meters per second.Count the number of seconds it would take the plane to fly a mile and convert that number to seconds.
How do you calculate distance traveled by an Aeroplane?The formula in this situation is Distance = Rate/Time.Rate (or Speed) times Distance traveled time.Adding together the distances covered by each plan results in a total distance of 1275 km.Though each flight takes 1.5 hours to complete, the planes' velocities are different by a hundred kilometers per hour.
The speed, in meters per second, of a paper airplane that flies 24 meters in 6 seconds will be 4 meters per second.
Distance traveled by airplane = 24 meters.
Time taken = 6 seconds
Therefore, the speed will be:
= Distance / Time taken
= 24 meters / 6 seconds
= 4 meters per second.
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how did the ancients know the planets were different from the stars? choose one: a. they saw that the planets move with respect to the stars over the course of many nights. b. the planets have a larger angular size in our sky than the stars. c. they observed moons orbiting around the planets. d. they noticed that the planets orbit the sun, while the stars do not.
The correct answer is option d. The ancients realized that stars did not revolve around the Sun like the planets do, and thus arrived at this conclusion.
One of the ways the ancients knew the planets were different from the stars was by observing their motion in the night sky. Unlike stars, which appear stationary in the sky, the planets were observed to move along a regular path relative to the stars. This movement was known as planetary retrograde and could be observed over the course of many nights.
The ancients also noticed that the planets have a larger angular size in our sky than the stars. This made them more easily distinguishable and allowed them to be distinguished from the stars.
Finally, the ancients noticed that some of the planets had moons orbiting them, which none of the stars did. This was a key factor in distinguishing the planets from the stars.
All in all, the ancients knew the planets were different from the stars by observing their movement in the night sky, noticing the angular sizes, and observing the moons orbiting some of the planets. By understanding these phenomena, the ancients were able to catalog the heavenly bodies and give them each a name.
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