A. first law of motion
Explanation:
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A proton is released from rest in a uniform E – Field 8 x 104V/m directed alomg + ve x – axis, undergoes a displacement of 0. 5m in direction of field. Find: a) Change of potential for this displacement (A =» B)? B) Change of P.E for this displacement (A =» B)? C) The speed of proton after the displacement?
Answer:
a. -40 kV b. -6.408 fJ c. 2.77 × 10⁶ m/s
Explanation:
a) Change of potential for this displacement (A =» B)?
The potential energy change ΔV = -EΔx where E = electric field strength = 8 × 10⁴ V/m and Δx = displacement of charge = 0.5 m
So, ΔV = -EΔx
ΔV = -8 × 10⁴ V/m × 0.5 m
ΔV = -4 × 10⁴ V
ΔV = -40 × 10³ V
ΔV = -40 kV
B) Change of P.E for this displacement (A =» B)?
The change in potential energy ΔU = qΔV where q = proton charge = +1.602 × 10⁻¹⁹ C and ΔV = change in potential = -4 × 10⁴ V
So, ΔU = qΔV
ΔU = +1.602 × 10⁻¹⁹ C × -4 × 10⁴ V
ΔU = -6.408 × 10⁻¹⁵ J
ΔU = -6.408 fJ
C) The speed of proton after the displacement?
From the conservation of energy,
The electric potential energy change of the charge equals its kinetic energy change
ΔK + ΔU = 0
ΔK = -ΔU
ΔK = -(-6.408 × 10⁻¹⁵ J)
K₂ - K₁ = 6.408 × 10⁻¹⁵ J
where K₁ = initial kinetic energy of proton = 0 J (since it starts from rest)
K₂ = final kinetic energy of proton = 1/2mv² where m = mass of proton = 1.673 × 10⁻²⁷ kg and v = speed of proton
K₂ - K₁ = 6.408 × 10⁻¹⁵ J
1/2mv² - 0 = 6.408 × 10⁻¹⁵ J
1/2mv² = 6.408 × 10⁻¹⁵ J
v² = 2(6.408 × 10⁻¹⁵ J)/m
v = √[12.816 × 10⁻¹⁵ J)/1.673 × 10⁻²⁷ kg]
v = √[7.66 × 10¹² J/kg]
v = 2.77 × 10⁶ m/s
What kind of image is formed by an object that is placed beyond the center of curvature on the principal axis of a concave mirror?
A.
real, inverted, the same size as the object, and at the same distance as the object
B.
real, inverted, larger than the object, and farther from the mirror than the object
C.
virtual, upright, left-right reversal, the same size as the object, and at the same distance as the object
D.
real, inverted, smaller than the object, and closer to the mirror than the object
E.
virtual, upright, larger than the object, and farther from the mirror than the object
Answer:D.
Real, inverted, smaller than the object, and closer to the mirror than the object
Explanation: Real images will be inverted. As it is beyond the centre of curvature it is also beyond 2F which means that the image is inside the centre of curvature ( between F and 2F from the mirror ) As the image is closer to the mirror than the object it must be diminished in size
What happens to speed when you decrease the time needed to run the same distance?
Answer:
Faster
Explanation:
Which of the following items, when tested by litmus paper, would MOST LIKELY have a pH of 7?
A.
detergent
B.
distilled water
C.
ammonia
D.
lemon juice
Answer:
B- distilled water
Explanation:
mechanical energy is two types ??
Answer:
Yes Kinetic and Potential energy
What is the radius of a hemisphere with a volume of 61326 ft^3
, to the nearest tenth of a foot?
which obsevation would be evidence that heat was transferred by radiation?
why stationary magnet inside a coil does not induce a electric current
If your face is 62 cm in front of a plane mirror, where is the image of your face located?
62 cm in back of the mirror
62 cm below the mirror
62 cm in front of the mirror
31 cm in front of the mirror
[tex] \huge \mathrm{ Answer࿐ }[/tex]
The correct option is :
[tex]\hookrightarrow[/tex] 62 cm in back of the mirror
_____________________________
Explanation :Plane mirror always make a virtual and erect Image which is as far from the mirror as the object is !
_____________________________
[tex]\mathrm{ \#TeeNForeveR}[/tex]
Thom reads an article on the internet that that claims some lakes on Saturn are contain frozen methane. He reads that there is methane on Neptune, too. Which sentence best describes data that would suggest methane is frozen on Neptune?
a
Neptune's atmosphere has more methane than Saturn's.
b
Neptune's mass is less than Saturn's.
c
Neptune's surface temperature is colder than Saturn's.
d
Neptune's distance from the Sun is greater than Saturn's.
Answer: Neptune's distance from the Sun is greater than Saturn's.
Explanation:
The sentence that best describes data that would suggest methane is frozen on Neptune is that Neptune's distance from the Sun is greater than Saturn's.
Since Neptune is farther away from the Sun than Saturn, it implies that it has a colder temperature than Saturn and thus would suggest that methane is frozen on Neptune.
why does the velocity change when the boy hits the ball
Answer:
Freefall is a special case of motion with constant acceleration because acceleration due to gravity is always constant and downward. This is true even when an object is thrown upward or has zero velocity.
When a ball is thrown up in the air, its velocity is initially upward. Since gravity pulls the object toward the earth with a constant acceleration g, the magnitude of velocity decreases as the ball approaches maximum height. At the highest point in its route, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth.
Answer:
Acceleration from gravity is always constant and downward, but the direction and magnitude of velocity change. At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth
Explanation:
A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J.
Complete question:
A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find
(a) the force constant of the spring and (b) the amplitude of the motion.
Answer:
(a) the force constant of the spring = 47 N/m
(b) the amplitude of the motion = 0.292 m
Explanation:
Given;
mass of the spring, m = 200g = 0.2 kg
period of oscillation, T = 0.410 s
total mechanical energy of the spring, E = 2 J
The angular speed is calculated as follows;
[tex]\omega = \frac{2\pi}{T} \\\\\omega = \frac{2\pi}{0.41} \\\\\omega = 15.33 \ rad/s[/tex]
(a) the force constant of the spring
[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega^2 = \frac{k}{m} \\\\k = m \omega^2\\\\k = (0.2)(15.33)^2\\\\k = 47 \ N/m[/tex]
(b) the amplitude of the motion
E = ¹/₂kA²
2E = kA²
A² = 2E/k
[tex]A = \sqrt{\frac{2E}{k} } \\\\A = \sqrt{\frac{2\times 2}{47} }\\\\A = 0.292 \ m[/tex]
A projectile is launched from the ground with an initial velocity of 12ms at an angle of 30° above the horizontal. The projectile lands on a hill 7.5m away. The height at which the projectile lands is most nearly
A- 1.78m
B- 3.10m
C- 5.34m
D- 6.68m
E- 12.0m
Answer:
A. 1.78 m
Explanation:
Given;
initial velocity of the, u = 12 m/s
angle of projection, θ = 30°
the range of the projectile, R = 7.5 m
To obtain the height through which the projectile lands, we must calculate the maximum height reached by the projectile.
[tex]H = \frac{u^2\ sin^2\theta}{2g} \\\\H = \frac{(12)^2\times (sin(30))^2}{2 \times 9.8} \\\\H = \frac{144 \times (0.5)^2}{19.6} \\\\H = 1.84 \ m[/tex]
Therefore, the height is most nearly 1.78 m
Fossil's are the remains of ancient plants and animals which type of rock do you think is mostly likely to contain fossils?
Answer:
Sedimentary rocks.
Explanation:
A rock cycle can be defined as a concept used to describe the continuous process that leads to a rock's creation, formation, transformation from one form to another, destruction and reformation over a specific period of time. The natural phenomenons that influences the rock cycle are weathering, plate tectonic activity, erosion, etc.
A fossil can be defined as the mineral impression or remains of living organisms such as plants and animals that are prehistoric in nature.
Basically, the three (3) main types of rocks are; igneous rock, sedimentary rock and metamorphic rock.
Sediments come from living organisms such as plants to form organic sedimentary rocks and they are usually formed at pressure and temperature that doesn't destroy the fossils contained therein. Organic sedimentary rocks includes chalk, fossiliferous, coal, diatomite, etc. Also, some examples of inorganic land-derived sedimentary rocks are conglomerate, brescia and sandstone.
Hence, an organic sedimentary rock is a type of rock that contains or comprises of fossils.
How many beats per second are heard when two vibrating tuning forks having
frequencies of 342 Hz and 345 Hz are held side by side?
5 Hz
3 H2
343.5 HZ
687 Hz
Answer: b.) 3 hertz
explanaition: you subtract 345 from 342
morse code and string phone cup
1.What was different about the two methods?
2.If your string phone stretched out one block long, which method do you think would be clearer?
3. If you had a Morse Code expert on both ends to act like a computer taking in information, would that make a difference?
Answer:
Following are the responses to the given question:
Explanation:
Following are the difference in the speed and accuracy:
The biggest difference was its tone between both the cup method as well as the Morse code. One should talk using cup system and sequence system and let its covering be understood in Morse code, just a series of beeps weren’t tangible... Secondly, a method of cup involves a range string. Rukun Negara is often distributed by cable, but this is a greater range. It reaches concurrently in those other areas.
In the case of using the string method for the block, its distance and stiffness of the string are limited and the barriers are eliminated. It will certainly be convenient and clearer if one utilizes Sign language.
If two experts are acting like such a machine on both sides, their information between both the 2 persons is smoother and quicker as they will not have to wait for data from a third person which may create another pause at the time.
Morse code is faster, eventually. For some very small periods when sensitive information is not transmitted, strings or cup methods must be reserved.
During a chemical reaction, some substances are completely consumed while others my not be. What is the substance that is completely consumed in a chemical reaction?
Question 3 options:
reactant
product
a limiting reactant
Answer:
It is Limiting Reactant
Explanation:
Find the current
flowing out of the
battery in the
circuit.
The top ones being parallel gives 1/(1/30 + 1/40) = 120/7 ohms. The rightmost path in series gives 30 ohms, and then the parallel pair on the right is 1/(1/50 + 1/30) = 75/4 ohms. I = V/R => 9 / (75/4+120/7) [tex]\approx[/tex] .25A
Please mark Brainliest if this answer helped you!
Answer:
4.298
Explanation:
the answer is 4.298 on acellus
ABC
Question 18
A 110-kilogram bodybuilder and his 55-kilogram friend run up identical flights of stairs. The bodybuilder reaches the top
in 4.0 seconds while his friend takes 2.0 seconds. Compared to the power developed by the bodybuilder while running
up the stairs, the power developed by his friend is which of the following?
А
twice as much
B
the same
с
half as much
D
four times as much
Answer:
The answer is option C.Half as much
The correct answer is four times as much.
Let the friend's mass be m, then according to the question the bodybuilder's mass will be 2m.
Now they both cover the same distance but the bodybuilder takes 4s and his friend takes 2s. Hence, if the time taken by the friend is t then the bodybuilder takes 2t time.
That means if the velocity of the bodybuilder is v then the velocity of his friend will be 2v.
Now, Power is defined as the rate of work done.
P = W/t
and work done is the change in kinetic energy.
Now the power generated by the bodybuilder is:
[tex]P_{b}=\frac{\frac{1}{2}2mv^{2} }{2t} \\\\P_b=\frac{mv^2}{2t}[/tex] ............(1)
power generated by the friend is :
[tex]P_{f}=\frac{\frac{1}{2}m(2v)^{2} }{t} \\\\P_b=\frac{4mv^2}{2t}[/tex].............(2)
Comparing (1) and (2) we get:
The friend generates four times as much power as the bodybuilder.
Learn more:
https://brainly.com/question/4232216
Task: At the end of the lesson you will be asked to develop a final writing assignment on the environmental problerns
caused by invasive e algae e, and the methods used to restore the natural habitats e in Crystal River and Kings Bay,
ments
Essay Response: (3 Paragraphs)
5
• Describe the environmental problem caused by invasive algae in these areas and the goals of the Save Crystal River
project.
• Explain the steps in the process used to correct the problem.
. Finally, conclude with why the information gathered during the Save Crystal River project is important to the
environment now and to future generations,
If someone can answer this fast I will mark as brainlist and give them 100 points plzz I need the answer fast and right!!
Answer:
PLS PLS PLS mark brainliest
Explanation:
The following are the environmental problems caused by the invasive algae which is known as Lyngbya.
A. It blocks the sunlight from reaching the water, thereby depriving the plants in the water from accessing it. So they won't be able to manufacture their foods and eventually die off.
B. The algae produce offensive odour like rotten egg , which drive people and other organisms away.
C. The algae prevent oxygen from entering the water, and prevent the resident organisms from making use of it, which leads to their death.
D. The algae also give off heat into the chilly spring waters.
In conclusion, the goals of the Crystal River project is to save the living organisms in the river from extinction and to make it a livable environment for them.
Sally Scientist lifts up a stack of science books from the floor and puts them on a table 1 m above
the floor. If she lifted 180 newtons of books in 1.5 seconds, how many watts of power does she
have?
Answer:
P = 120 W
Explanation:
Force required to lift the book, F = 180 N
It is lifted 1 m above the floor in 1.5 s
We need to find the power of the student. Power is equal to work done divided by time taken. So,
[tex]P=\dfrac{Fd}{t}\\\\P=\dfrac{180\times 1}{1.5}\\\\P=120\ W[/tex]
So, the required power is equal to 120 W.
What is the difference between an object’s speed and its acceleration?
The speed of an object is the distance traveled in unit time, while acceleration of an object is the rate of change of velocity in respect to time
Which of the following best describes a nebula?
Explanation:
is a formation in space which is constituted mostly of helium, dust and other gases in various concentration
The relation between linear and angular acceleration is:
Answer:
α=atr
the relationship between linear accelaration and linear accelaration is proportional. The greater the angular acceleration is, the larger the linear (tangential) acceleration.
How would sound travel in outer space? Why would that make sense,
based on the chart below?
Explanation:
Sound does not travel at all in space. The vacuum of outer space has essentially zero air. Because sound is just vibrating air, space has no air to vibrate and therefore no sound. ... Radio is a form of electromagnetic radiation just like light and can therefore travel through the vacuum of space just fine
If Nitrogen gains three electrons, what will its charge be? *
Answer:
It's change will form the nitride ion
Which of the following is the unit of momentum
a) ms-1 b) Kg ms-1
c) Ns d) Kgms-2
Answer:
the answer is (b) Kg ms-1 .
What would Hubble's constant be if we found one galaxy moving away at 30,000 km/s at a distance of 600 Mpc?
Answer:
H₀ = 1.6 x 10⁻¹⁸ s⁻¹
Explanation:
The Hubble's Constant can be found by the following formula:
[tex]v = H_o D\\\\H_o = \frac{v}{D}[/tex]
where,
H₀ = Hubble's Constant = ?
v = speed of galaxy = 30000 km/s = 3 x 10⁷ m/s
D = Distacance = 600 Mpc = (6 x 10⁸ pc)(3.086 x 10¹⁶ m/1 pc)
D = 18.52 x 10²⁴ m
Therefore,
[tex]H_o = \frac{3\ x\ 10^7\ m/s}{18.52\ x\ 10^{24}\ m}[/tex]
H₀ = 1.6 x 10⁻¹⁸ s⁻¹
¿Crees que a más horas de sueño mayor descanso?
Answer:
La mayoría de los adultos necesitan entre 7 y 8 horas de sueño de buena calidad en un horario uniforme todas las noches.
Explanation:
An antelope runs 10 meters in .5 seconds, calculate its speed?
How long would it take a bicyclist to complete a 50 km race at a speed of 20 km/hour?
How far can a person walk at a speed of 1.7 m/s in 60 seconds?
Answer:
speed=10m5s=2m/s for the antelope