Answer:
[tex]x =\frac{-R}{2}[/tex]
Explanation:
From the question we are told that mass
Thin layer radius [tex]= 2R[/tex]
Generally the expression for ths solution is given as
Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2
the center of mass will not move at initial state
Considering the center of mass of both bodies
[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]
[tex]x =\frac{-R}{2}[/tex]
Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]
The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
Given-
Radius of the ball is [tex]R[/tex].
the mass of the ball is [tex]m[/tex].
The mass of the thin shell is [tex]m[/tex].
The radius of the thin shell is [tex]2 R[/tex].
For the two bodies with mass [tex]m[/tex], the center of mass can be given as,
[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]
In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,
[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]
[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]
[tex]x_{cm} =x[/tex]
Distance for center of mass can also be given as,
[tex]x_{cm} =m\times o[/tex]
[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]
[tex]x_{cm} =\dfrac{-R}{2}[/tex]
Comparing both the values of the distance of center of mass we get,
[tex]x =\dfrac{-R}{2}[/tex]
Hence, The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
For more about the center of mass follow the link below,
https://brainly.com/question/8662931
What movement allows us to move our side to side?
Answer:
Ball-and-socket joints
Explanation:
A light, flexible rope is wrapped several times around a hollow cylinder with a weight of 40 N and a radius of 0.25m that rotates without friction about a fixed horizontal axis. The cylinder is attached to the axle by spokes of a negligible moment of inertia. The cylinder is initially at rest. The free end of the rope is pulled with a constant force P for a distance of 5 m, at which point the end of the rope is moving 6 m/s. If the rope does not slip on the cylinder, what is the value of P
Answer:
The value is [tex]P = 14.7 \ N[/tex]
Explanation:
From the question we are told that
The weight of the hollow cylinder is [tex]W = 40 \ N[/tex]
The radius of the hollow cylinder is [tex]r = 0.25 \ m[/tex]
The distance which it is pulled is [tex]d = 5 \ m[/tex]
The velocity of the end of the rope is [tex]v = 6 \ m/s[/tex]
Gnerally the mass of the hollow cylinder is
[tex]m = \frac{W}{g }[/tex]
=> [tex]m = \frac{ 40 }{ 9.8 }[/tex]
=> [tex]m = 4.081 \ kg[/tex]
Generally angular displacement for the distance covered is mathematically represented as
[tex]\theta = 2 \pi * \frac{ d } {2\pi r }[/tex]
=> [tex]\theta = 2 \pi * \frac{ 5 } {2\pi r }[/tex]
=> [tex]\theta = \frac{ 5 } { 0.25}[/tex]
=> [tex]\theta =20[/tex]
Generally the torque experienced by the hollow cylinder is mathematically represented as
[tex]P * r = I * \alpha[/tex]
Here I is the moment of inertia
=> [tex]P * r = m r^2 * \alpha[/tex]
=> [tex]\alpha = \frac{P }{ mr }[/tex]
Generally from kinematic equation
[tex]w_f ^2 = w_i ^2 + 2\alpha \theta[/tex]
=> [tex]w_f ^2 = w_i ^2 + 2\alpha \theta[/tex]
Generally the final angular velocity is mathematically
[tex]w_f = \frac{v}{r}[/tex]
=> [tex]w_f = \frac{ 6 }{ 0.25 }[/tex]
=> [tex]w_f = 24 \ m/s[/tex]
Generally the initial angular velocity is Zero given that the hollow cylinder was at rest before rolling
[tex]24^2 = 0^2 + 2* \frac{P}{4.081 *0.25 } * 20[/tex]
=> [tex]24^2 = 0^2 + 2* \frac{P}{mr} * 20[/tex]
=> [tex]P = 14.7 \ N[/tex]
What is the net force of the diagram?
which number is larger value : 5.6*10^23 or 8.9*10^6
Need Help
Answer:
5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps
Explanation:
When an object moves, where does the energy come from?
Answer:
Kinetic energy.
Explanation:
This is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy.
A sign is attached to the side of a building as seen below. The sign is attached to a steel rod. A wire connects to the end of the rod for support. The mass of the sign is 50 kg. Determine the supporting force exerted by the cable
Answer:
500N
Explanation:
50kgx10N/kg
= 500N
An atom of lithium (Li) forms an ionic bond with an atom of chlorine (Cl) to form lithium chloride. How are the valence electrons of these atoms rearranged to form this bond?
A few valence electrons are shared between the atoms.
Many valence electrons are shared between the atoms.
Electrons are transferred from the chlorine atom to the lithium atom.
Electrons are transferred from the lithium atom to the chlorine atom.
Answer:
electrons are transferred from the lithium atom to the chlorine atom
Answer:
D
Explanation:
I just took the test :)
PLZ HELP MEEEEEEE,;-;
Answer:
thxs for the points
Explanation:
because just started
A car weighing 19600N is moving with a speed of 30 m/sec on a level road. If it is brought to rest in a distance of 100 m. Find the average distance friction force acting on it
Answer:
F = -8820 N
Explanation:
Given that,
The weight of a car, W = 19600 N
Initial speed of the car, u = 30 m/s
It is brought to rest, final velocity, v = 0
Distance, d = 100 m
We need to find the average friction force acting on it.
Firstly we find the acceleration of the car using third equation of motion. Let it is a.
[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2[/tex]
Average frictional force,
F = ma
m is mass, [tex]m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg[/tex]
F = 1960 kg × -4.5 m/s²
= -8820 N
So, the average friction force acting on it is 8820 N.
what is gravity???☺️
Answer:
Gravity
Explanation:
its an invisible force that pulls objects
toward each other.
hope it helps
a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3
Answer:2.47
Explanation:
So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!
Your maximum heart rate is the maximum number of times your heart can contract in one minute
True or false
Answer:
True
Explanation:
It is true i am right
A single celled organism is found in a sample of water. It contains a nucleus as well as other membrane bound organelles and possesses collagen for movement. This organism most likely belongs to which kingdom?
Answer:
Explanation:
The cell is the smallest living organism that contains all the features of life, and most all life on the planet begins as a single-cell organism. Two types of single-celled organisms currently exist: prokaryotes and eukaryotes, those without a separately defined nucleus and those with a nucleus protected by a celluA single-celled organism is found living in a deep sea vent at the bottom of the ocean in extremely hot water. If it is examined further, which of the following is most likely to be found within it? It will have DNA that is not contained in a nucleus since it is likely a member of the domain Archaea.lar membrane.
What is the kinetic energy of a jogger with a mass of 70.8 kg traveling at a speed of 2.4 m/s?
90 points if you get it right :)
pls help me with this
Answer:
A screw
Explanation:
1. A race starts out at rest and accelerates to 30m/s over a period of 10s. What is the acceleration of the car?
O 3.0 m/s
O 3.0 m.s2
O 2.0 m/s2
O 5.0 m/s2
Answer:3.0m/s
Explanation:
Mr. D's dog Gromit jumped out of a second story window (through the screen) and fell to the ground below. The window is 15 feet high, the acceleration of gravity is 9 m/s', and there are 3.28 feet in each meter. What was the final velocity of this crazed dog? (True story, don't worry he's fine and now he knows about gravity)
Answer:
Vf = 9.46 m/s
Explanation:
In order to find the final velocity of the dog we can use third equation of motion:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height of window = (15 ft)(1 m/3.28 ft) = 4.57 m
Vf = Final Velocity of Dog = ?
Vi = Initial Velocity of Dog = 0 m/s
Therefore,
(2)(9.8 m/s²)(4.57 m) = Vf² - (0 m/s)²
Vf = √(89.572 m²/s²)
Vf = 9.46 m/s
a 10 kilogram steel ball is dropped from the top of a tower 100 meters high the kinetic energy of the ball just before it sttikes the ground is most nearly
Explanation:
If we assume negligible air resistance and heat loss, we can assume that all of the Gravitational potential energy of the ball will turn into Kinetic energy as it falls toward the ground.
Therefore our Kinetic energy = mgh = (10kg)(9.81N/kg)(100m) = 9,810J.
29. A student notices that wearing care colors insight makes him feel warmer se he decides to conduct an experiment. He kese seces of bored and was
each one around a bete beten places alive betties in direct sunlight and measures the temperature of the water in each clean hout
what is the independent variable in this exermet
the temperature of the water
the outside temperature
the color of the con
Answer:
This question is unclear but the answer is:
the color of the con
Explanation:
In an experiment, the independent variable is the variable that is changed or manipulated by the experimenter to achieve a measurable response.
In this experiment which involves a student that notices that wearing care colors insight makes him feel warmer se. He decides to conduct an experiment by manipulating the colors of the cares, hence, the color of the con is the independent variable.
Why is a teacher's feedback valuable?
Answer:
Because they could help you move on better with your strategy and ultimately get you better scores on tests
Answer:
Through feedback, teachers can provide the students with suggestions for development, learning strategies and corrections for errors. The importance of constructive feedback allows for many positive opportunities. This component also enhances a student's self-efficacy and provides an avenue for motivation.
A force of 900N acts on
a stationary body
for 40sec and the body acquires the velocity of360 m/s calculate mass a body.
Answer:
Explanation:
It is still using F = m*a -- just in a disguised form.
Givens
F = 900 N
vf = 360 m/s
vi = 0
t = 40 second
Formulas
a = (vf - vi)//t
F = m * a
Solution
a = (360 - 0)/ 40
a = 9
F = m * a
900 = m * 9
m = 900/9
m - 100 kg. Doesn't seem high enough.
Answer:
a= V- u/t
a= 360 - 0 /40 = 9 m/sec2
F = MA
900 = M * 9
M = 900/9
M= 100 kg
The law of __________________________ says that people think of similar objects as belonging together.
Answer:
Explanation:is the law means that the police are the law
A racecar is driving around a circular track. The car is moving with a speed of 49.7 m/s, and the track has a radius of 114 m. What is the magnitude of the centripetal acceleration of the car?
Answer:
21.67 m/s²
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 49.7 m/s
Radius (r) = 114 m
Centripetal acceleration (a) =?
The centripetal acceleration can be obtained by using the following formula:
a = v²/r
a = 49.7² / 114
a = 2470.09 / 114
a = 21.67 m/s²
Therefore, the centripetal acceleration of the car is 21.67 m/s²
what is the uses of space weather data?
Answer:
Space Weather Data
They are used to produce forecasts, such as the monthly sunspot number forecast. Most notably, sunspot numbers represent one of the longest continuous climate records available. The data give scientists the means to make many forecasts and issue space weather advisories and alerts.
Explanation:
A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The defender catches the ball carrier in a completely inelastic collision. What was the kinetic energy of the ball carrier/defender system BEFORE the tackle?
Answer:
3,544.375Joules
Explanation:
Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;
Kinetic energy = 1/2mv²
m is the mass of the body
v is the velocity
For the ball carrier;
KE = 1/2(75)(6.5)²
KE = 3168.75/2
KE = 1584.375Joules
For the defender;
KE = 1/2(80)(7)²
KE = 3920/2
KE = 1960Joules
The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender
kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules
A student rings a brass bell with a frequency of 200 Hz. The sound wave
travels through brass, air, and glass. What is the wavelength of the wave in
brass?
Medium
Wave speed
(m/s)
Brass
4,700
Air
346
Glass
5,640
A. 2.3 m
B. 0.43 m
C. 0.043 m
D. 23.5 m
Answer:
Option D. 23.5 m
Explanation:
From the question given above, the following data were obtained:
Frequency = 200 Hz
Speed of sound in brass = 4700 m/s
Wavelength of sound in brass =?
We can obtain the wavelength of the sound in the brass by using the following formula as illustrated below:
Wave speed = wavelength × frequency
4700 = wavelength × 200
Divide both side by 200
Wavelength = 4700 / 200
Wavelength = 23.5 m
Thus, the wavelength of the sound in the brass is 23.5 m
1. A book is at rest on a tabletop. Diagram the forces acting on the book.
The free-body diagram of the forces acting on a book resting on a table is shown in the figure.
When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.
So, the forces acting on a book resting on a tabletop are:
1. Weight of the book, W(downward)
2. Normal force (N) perpendicular to the surface in contact.
Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.
To know more about forces, click here:
https://brainly.com/question/13191643
#SPJ6
what is the function of brushes in D.C motor
Answer:
to transfer the voltage
Explanation:
The brushes make physical contact with the commutator. When a DC voltage is applied to the brushes, that voltage is transferred into the commutator which, in turn, powers the windings. This electrical input generates a magnetic field around the armature.
If clouds were made of cotton-candy what is rain
Answer:
If clouds were made of cotton candy, I think rain would be soda.
Or liquified sugar.
:)
Answer:
Liquid Sugar
Explanation:
For an example, let's look at normal clouds. They're made of water vapor, and when they rain it's because the water vapor condenses and forms a droplet heavy enough that it falls out of the sky. In both sides of the equation, they're still made out of water. So, logically, cotton candy is made almost 100% with sugar, right? All that's happened is the sugar is heated and liquified and pushed through very small holes until they cluster together and form the fluffy treat you know today. Back to the leading question, though: "If clouds were made of cotton-candy, what is rain?". Rain is the liquid form of clouds (gas), and cotton candy is the (solid) form of itself. So in order for it to rain, it needs to liquefy itself. When melted at 367°F, sugar becomes a liquid, so in that case THAT is what cotton candy would rain if it were a cloud.
≧◡≦
Mocha here! If this answer helped you, please consider giving it brainliest because I would appreciate it greatly. Have a wonderful day!
a ball bounce on the ground. at what position (A,B,C)does the ball have the greatest potential energy? kinetic energy? explain your answer.
Answer:
What is the meaning of the kinetic I think the answer is both the ball has both Kinetic and potential energy so I think is the answer is true