A B-52 bomber jet flies at a horizontal velocity of 286.2 m/s and at an altitude of 7500 m above the ground. How far away horizontally should a payload be dropped to land on a target?

Answers

Answer 1

Answer:

11196.14 m

Explanation:

From the question given above, the following data were obtained:

Horizontal velocity (u) = 286.2 m/s

Height (h) = 7500 m

Horizontal distance (s) =?

Next, we shall determine the time taken for the payload to get to the target. This can be obtained as follow:

Height (h) = 7500 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

7500 = ½ × 9.8 × t²

7500 = 4.9 × t²

Divide both side by 4.9

t² = 7500 / 4.9

Take the square root of both side

t = √(7500 / 4.9)

t = 39.12 s

Finally, we shall determine the horizontal distance as follow:

Horizontal velocity (u) = 286.2 m/s

Time (t) = 39.12 s

Horizontal distance (s) =.?

s = ut

s = 286.2 × 39.12

s = 11196.14 m

Thus the payload will travel 11196.14 m horizontally in order to hit the target


Related Questions

n
Which of the following has a crystalline appearance?
baking soda
salt
baking powder
corn starch

Answers

Salt has a crystalline appearance.

Answer:

B: Salt

Explanation:

I answered this correct beforehand.

Which Box in the diagram above, should this picture go into?
Box A
ООО
O Box B
O Box C



Plzz answerr idk

Answers

What diagram? There isn’t one

A high-speed train in Japan travels a distance of 300. kilometers in 3.60 x 103 seconds. What is the average speed of this train? (Turn the time into hours by using a unit conversion)​

Answers

Answer:

The average speed is 83.3 m/s

Explanation:

How much time will it take for a truck to travel 20 meters if it is traveling at 4 m/s?

Answers

Answer:

The answer is 5 s

Explanation:

The time taken can be found by using the formula

[tex]t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{20}{4} \\ [/tex]

We have the final answer as

5 s

Hope this helps you

the answer to this question is 5s

The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.0059 m/s/s, what is the sun’s acceleration toward the Earth?

Answers

Answer:

this is the answer according to my calculations

Explanation:

0.001.9

Plyometrics can help a person maintain cardiorespiratory fitness. Please select the best answer from the choices provided. T F

Answers

Answer: IT IS TRUE

Explanation:

Hope this helps

Plyometrics can help a person maintain cardiorespiratory fitness T

It is TRUE that plyometrics can help a person maintain cardiorespiratory fitness

Plyometrics

Plyometrics is a type of exercise training that works with the principle of using speed and force of different movements to build muscle power.

Plyometrics include different types of exercises such as pushups, throwing, running, jumping, and kicking.

Learn more about plypmetrics:

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what is the spring constant for a spring if pulling it back .0391m causes a force in the opposite direction of .922N?
-0.361N
.361N
-2.36N
2.36N

Answers

Answer: correct me if i'm wrong but is it 0.361N

A rock falls off a cliff that is 82 m high. How fast is the rock moving when it hits the ground?

Answers

Answer:

40.1m/s

Explanation:

This is a kinematics problem

x = 82m

a = -9.8m/s^2

v(initial) = 0

Find: v(final)

Using kinematics equation:

vf^2 = vi^2 + 2a(delta)x

vf^2 = 0 + 2*(-9.8)*(82)

vf = sqrt(1607.2) = 40.09m/s

The is traveling with a velocity of 40.1m/s when it hits the ground.

A man has a mass of 66 kg on Earth. What is his weight in Newtons?

Answers

Answer:

answer is 66 kilograms-force = 647.2389 newtons

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 646.8 \ Newtons }}[/tex]

Explanation:

Weight in Newtons can be found by multiplying the mass times the acceleration of gravity.

[tex]W=m*g[/tex]

The mass of the man is 66 kilograms on Earth.

Earth has an acceleration of gravity that is 9.8 meters per square second.

[tex]m= 66 \ kg \\g=9.8 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]W=66 \ kg *9.8 \ m/s^2[/tex]

Multiply.  

[tex]W=646.8 \ kg*m/s^2[/tex]

1 kg * m/s² is equal to 1 Newton, therefore our answer of 646.8 kg *m/s² is also equal to 646.8 Newtons, or N.

[tex]W=646.8 \ N[/tex]

The man's weight in Newtons in 646.8 Newtons.

In the human circulatory system, arteries carry blood away from the heart to different parts of the body. Veins carry blood from different parts of the body back to the heart. A scientist claims that the greater the amount of exercise a person performs, the greater the amount of oxygen (O2) the body uses. He records the oxygen concentration in the blood of people while they are riding an exercise bike. The graphs show the results of this investigation.



a. Identify at least two systems within the human body that work together during exercise.

b. Explain how the evidence from the data in the graphs supports or does not support the scientist’s claim.

Answers

Answer:

There are many different systems involved in when we exercise, the three main ones are the Respiratory system which is involved in breathing the circulatory system which is about circulation of blood around the body and finally the muscular system and finally the Muscular system which is about how we move.

Explanation:

If the data consistently do not support the hypothesis, then CLEARLY, the hypothesis is NOT a reasonable explanation of what you are investigating. The hypothesis is rejected, and we search for a new interpretation, an new hypothesis that supports the experimental data

Respiratory and circulatory systems are the two systems within the human body that work together during exercise.

How does the respiratory and circulatory systems work together during exercise?

The respiratory system:

allows the exchange of gases intake of oxygen and exhalation of carbon-dioxide.oxygenation of blood at the lungs.

The circulatory system:

transports deoxygenated blood to the lungs for oxygenation.delivers oxygenated blood to the appropriate tissue.Hence, during exercise more oxygen is used by the body.The claim by scientist is true?

During exercise:

breathing rate increases from about 15 times per minute to roughly 40–60 times per minute.heart rate also rises, providing more oxygen to reach your muscles and allowing them to continue moving.

To learn more about respiratory system, circulatory system, blood, exercise, and oxygen here,

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20. Show that an acceleration of 0.67 m/s/s is the result if a force of 1000N is exerted on a 1500 kg
car.

Answers

Explanation:

Given parameters:

Mass of the car = 1500kg

Force applied  = 1000N

Acceleration  = 0.67m/s²

Unknown:

Proof that the acceleration will result from the applied force on the car

Solution:

According to newton's second law of motion,

       Force  = mass x acceleration

 So;

 Acceleration  = [tex]\frac{Force }{mass}[/tex]

Now insert the parameters and solve;

 Acceleration = [tex]\frac{1000}{1500}[/tex]   = 0.67m/s²

We have shown that the acceleration is 0.67m/s²

Write an equation of the line in slope-intercept form.
Please explain.

Answers

Answer:

 y =  [tex]-\frac{1}{4}[/tex]x + 3

Explanation:

The equation of a straight line is given as:

              y  =  mx + c

y and x are the coordinates

m is the slope

c is the y -intercept

 The y-intercept = 3;

Slope  = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

x₁ = 0

x₂ = 4

y₁ = 3

y₂ = 2

 Slope = [tex]\frac{2-3}{4 -0 }[/tex]  = [tex]-\frac{1}{4}[/tex]

 

       y = mx + c

       y =  [tex]-\frac{1}{4}[/tex]x + 3

Why is physics worth knowing about

Answers

Answer:

Physics can help you in your everyday life.

Explanation:

It can also help you in life treating situations.


1.
A student pushes against a wall with 20 N of force and the wall does not move. In this situation, the
wall exerts -
A.

A.20 N of force in the same direction as the push.
B.20 N of force in the opposite direction of the push.
C.less than 20 N of force.
D.more than 20 N of force.

Answers

Answer:

B

Explanation:

This is a balanced force. In a balanced force, nothing happens.

The answer is B and he unlocks mastered ultra instinct

A turtle is moving at a speed of 1.5 m/s for a time of 120 s. What is the distance the turtle travels?

Answers

Answer:

The answer is 180 m

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

distance = velocity × time

From the question we have

distance = 1.5 × 120

We have the final answer as

180 m

Hope this helps you

Answer:

180 meters

Explanation:

1.5 m/s x 120 s

A tourist wishes to catch a train in 1.2 hours, which is 115 km away. If she spends the first half-hour going 90km/h, how fast will she need to go to get to station on time?

Answers

Answer:

100km/hr

Explanation:

From the problem statement we know that distance of the trip is 115km

Expected time for the trip = 1.2hrs

→ If she spends the first half-hour going 90km/hr,

    Here  time  = 0.5hr

              speed  = 90km/hr

 The distance covered;

    Distance covered   =  Speed x time

    Distance covered  = 90 x 0.5  = 45km

→The remaining distance will be:

        Total distance - distance covered

              115km  - 45km  = 70km

→ The remaining time;

      1.2hr - 0.5hr  = 0.7hr

 Speed  = [tex]\frac{distance}{time}[/tex]  

  Insert the parameters and solve;

  Speed  = [tex]\frac{70}{0.7}[/tex]   = 100km/hr

For the remaining lap, the tourist must travel at a rate of 100km/hr to catch up.

Math Practice: Cart A loaded with blocks (600g) moving left at 0.7m/s hits stationary cart B (200g).
After the collision, both carts move left, Cart A at speed 0.27m/s.

What is the velocity of cart B after the collision? Show your work.

Answers

Answer:

The velocity of cart B after the collision is 1.29 m/s.

Explanation:

We can find the velocity of cart B by conservation of linear momentum:

[tex] p_{i} = p_{f} [/tex]

[tex] m_{A}v_{A_{i}} + m_{B}v_{B_{i}} = m_{A}v_{A_{f}} + m_{B}v_{B_{f}} [/tex]

Where:

[tex]m_{A}[/tex] is the mass of cart A = 600 g = 0.6 kg            

[tex]m_{B}[/tex] is the mass of cart B = 200 g = 0.2 kg

[tex]v_{A_{i}}[/tex] is the inital velocity of cart A = 0.7 m/s

[tex]v_{A_{f}}[/tex] is the final velocity of cart A = 0.27 m/s

[tex]v_{B_{i}}[/tex] is the initial velocity of cart B = 0

[tex]v_{B_{f}}[/tex] is the final velocity of cart B =?

Taking the left direction as the positive horizontal direction:

[tex] 0.6 kg*0.7 m/s + 0 = 0.6 kg*0.27 m/s + 0.2 kg*v_{B_{f}} [/tex]

[tex] v_{B_{f}} = 1.29 m/s [/tex]

                       

Therefore, the velocity of cart B after the collision is 1.29 m/s.

I hope it helps you!  

Explain how bar graphs can show comparisons between 2 topics.

Answers

Answer:

A bar chart is typically used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

Explanation:

A bar chart also known as a bar graph can be defined as the graphical representation of data (informations) by using vertical columns or rectangular bars. When a data set is observed, a bar chart can be used to graphically represent or record the total or overall amount of information contained therein. Generally, bar charts are used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

The bar graph has a x-axis and a y-axis used to represent the various categories of data collected.

In this scenario, the x-axis is used to denote the points earned by the teams while the y-axis is used to denote the seasons as seen in the image attached.

Hence, point scores by team (Team A, B and C) per seasons (2002, 2003, 2004 and 2005) can best be compared through the use of a bar chart (graph).

Answer:

Answer above is correct i only put this:

Explanation:

A bar chart is typically used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest

Answers

I am pretty sure it’s A
The cue exerts force onto the white ball which pushes the blue ball into the direction of the hole.

Answer:

A. Cue, White Ball, Blue Ball

Explanation:

Visualize in which order things are being hit

Write one example situation of Newton's Third Law involving mass that are the same.

Answers

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

A windshield hits a bug with force of 10 N.
What force does the bug hit the windshield?
Explain using Newton's third law.

Answers

The big hits the windshield with a force of 10N. Newton’s third law states that every action must have an equal and opposite reaction

What happens to the gravitational force between two objects as the bodies become closer to each other? A. The gravitational force begins to repel the objects. B. The gravitational force increases. C. The gravitational force decreases. D. The gravitational force stays the same.

Answers

Answer:

Explanation:

The gravitational force between two objects becomes weaker if the two objects are moved apart and stronger if they are brought closer together; that is, the force depends on the distance between the objects.

The gravitational force between two objects as the bodies become closer to each other increases.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F ∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

As distance decreases the Force increases

To know more about Force :

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Unit 2 kinetic energy mastery test

Answers

Answer: kinetic energy is Energy of motion.

Explanation:

A car travels west for 200000 m in 12600 s what’s its velocity

Answers

Answer:

Velocity = 15.87m/s

Explanation:

Given the following data;

Distance, d = 200000m

Time, t = 12600secs

*To find the velocity*

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

[tex]Velocity = \frac{distance}{time}[/tex]

Substituting into the equation, we have;

[tex]V = \frac{200000}{12600}[/tex]

Velocity = 15.87m/s

Therefore, the velocity of the car is 15.87 meters per seconds due west.

How does changing the initial mass of the copper affect how much heat energy it has?

Answers

Answer:

Increasing the temperature of the copper made the final temperature increase and decreasing the temperature of the copper made the final temperature decrease. ... How does changing the initial mass of the copper affect how much heat energy it has? The more copper, the more heat energy.

Explanation:

Decreasing the temperature of the copper made the final temperature decrease. But the mass remains constant.

What is heat energy?

Heat is energy that is transmitted from one body to another as a result of a temperature differential. When two bodies of different temperatures come into contact,

Thermal expansion is the tendency of matter to alter its form, area, volume, and density in response to a change in temperature.

Thermal expansion is caused by heating. The mass remains constant. The loudness rises. As a result, the density drops.

To learn more about heat energy refer to the  link;

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Dr. Aloysius found four homogeneous mixtures, but he thinks that only three are alloys. He tests each one and determines their elemental compositions. Which of the following is not a possible alloy?

A. carbon and boron
B. iron an nickel
C. aluminum and magnesium
D. iron, carbon, and nickel

Answers

Answer:

A. carbon and boron

Explanation:

Carbon and boron is not an alloy.

An allow forms between metals and metals using their huge electron could.

Carbon is a non-metal, boron is a also a non-metal

Two non-metals combining together does not make an alloy.

Iron, nickel, aluminum  are all metals.

Answer:

carbon and boron

Explanation:

carbon and boron

What is the average amount of time an American spends consuming media in a week?
A. 10 hours
B. 18 hours
C. 22 hours
D. 28 hours
Please collect the best answer from the choices provided
HURRY!!

Answers

Answer: D. 28 hours

Explanation: on edge 2020 :))

The average amount of time an American spends consuming media in a week is 28 hour.

What is Media?

Media is the plural form of medium, which (broadly speaking) describes any channel of communication. This can include anything from printed paper to digital data, and encompasses art, news, educational content and numerous other forms of information.

The average amount of time an American spends consuming media in a week is 28 hour.

To learn more about media refer to the link:

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hey guys, l need some help! what is the weight of potatoes of mass 75 kg on the surface of the earth? (g=9.8m/s square) ans=735N l need process

Answers

Answer:

735N

Explanation:

Weight is a measurement of force.

F = Force

m = mass

a = acceleration

F = m*a

F = 75kg*9.8m/s²

F = 735N

Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 3.04 m away from a waterfall 0.585 m in height, at what minimum speed must a salmon jumping at an angle of 41.7 ◦ leave the water to continue upstream? The acceleration due to gravity is 9.81 m/s 2 . Answer in units of m/s.

Answers

Answer:

V₀ = 5.47 m/s

Explanation:

The jumping motion of the Salmon can be modelled as the projectile motion. So, we use the formula for the range of projectile motion here:

R = V₀² Sin 2θ/g

where,

R = Range of Projectile = 3.04 m

θ = Launch Angle = 41.7°

V₀ = Minimum Launch Speed = ?

g = 9.81 m/s²

Therefore,

3.04 m = V₀² [Sin2(41.7°)]/(9.81 m/s²)

V₀² = 3.04 m/(0.10126 s²/m)

V₀ = √30.02 m²/s²

V₀ = 5.47 m/s

Emily rides on a horizontal rotating platform of radius r at an amusement park
and moves at a linear velocity, vt = 1 m/s, one third the way from the center to the
outer edge, and a rotational velocity of 2 RPM. How much would her linear and
rotational velocities be if she moves to the outer edge?

Answers

Answer:

Her linear velocity on the outer edge is 3 m/s

Her rotational velocity, is constant at 2 RPM

Explanation:

The given parameters are;

The radius of the rotating platform = r

The linear velocity  v(t) = 1 m/s

The position Emily is riding = 1/3 the distance from the center

The rotational velocity = 2 RPM = 2 Revolutions per minute

The formula for angular velocity, ω is given as follows;

ω = θ/t

Where;

θ = The angle rotated

t = The time taken for the rotation

Given that the rotational velocity = 2 RPM

1 revolution = 2·π radians

The angular velocity, ω = 2×π×(2 RPM) = 4·π rad/min = 4·π/60 rad/seconds

ω = 4·π/60 rad/seconds

The linear velocity, v = r₁×θ/t = r₁×ω

Where;

r₁ = 1/3 × r

v = 1 m/s = 1/3 × r  × 4·π/60 rad/seconds

∴ r = 1/(1/3 × 4·π/60) = 45/π meters

r = 45/π meters

Therefore her linear velocity, v₂ and her rotational velocity if she moves to the outer edge will be given as follows;

v₂ = r × ω = 45/π × 4·π/60 = 3 m/s

Her linear velocity on the outer edge, v₂ = 3 m/s

Her rotational velocity, remains at 2 RPM.

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