a) A full fuel tank that consists of 75% propane and 25% methane leaks its contents of 1.5 Kg into a 3m X 3m X 3m room at 25° C and 1 atm. After a long time, the fuel gas and room air are well mixed. Is the mixture in the room flammable? And what is the equivalence ratio of the mixture? (Take lean flammability limits for propane as 2.37% and for methane as 5.0% by volume)
b) If the lean limit for propane is 2.37% by volume in air at 25° C and atmospheric pressure, what would be the lean flammability limit value for the propane diluted with 20 % by CO₂ by volume at the same conditions? And how much minimum amount of CO2 will be needed to render the mixture totally non-flammable in any conditions?

Answers

Answer 1

A) The mixture in the room is flammable, and the equivalence ratio needs to be determined.

B) The lean flammability limit for propane diluted with 20% CO₂ by volume depends on the specific flammability limits of the propane-CO₂ mixture, and the minimum amount of CO₂ needed to render the mixture non-flammable varies.

A) To determine if the mixture in the room is flammable, we need to compare the equivalence ratio of the fuel-air mixture to the flammability limits of propane and methane. The equivalence ratio is calculated by dividing the actual fuel-air ratio by the stoichiometric fuel-air ratio. If the equivalence ratio falls within the flammability limits, the mixture is flammable. However, we don't have the exact composition of the fuel-air mixture, so we cannot determine the equivalence ratio and conclusively say if the mixture is flammable.

B) The lean flammability limit for propane diluted with 20% CO₂ by volume cannot be determined without the specific flammability limits of the propane-CO₂ mixture. The addition of CO₂ will alter the flammability characteristics, and the limits will depend on the interactions between propane and CO₂. The minimum amount of CO₂ needed to render the mixture totally non-flammable in any conditions would also vary based on the specific flammability limits. It would require further analysis and knowledge of the flammability limits of the propane-CO₂ mixture to determine the lean flammability limit and the minimum amount of CO₂ required.

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Related Questions

You are asked to design a small wind turbine (D = x + 1.25 ft, where x is the last two digits of your student ID). Assume the wind speed is 15 mph at T = 10°C and p = 0.9 bar. The efficiency of the turbine is n = 25%, meaning that 25% of the kinetic energy in the wind can be extracted. Calculate the power in watts that can be produced by your turbine. Scan the solution of the problem and upload in the vUWS before closing the vUWS or moving to other question.
x=38

Answers

The power that can be produced by the wind turbine is approximately 8,776 watts.

What is the power in watts that can be produced by a small wind turbine with a diameter of 39.25 ft, operating at an efficiency of 25%, and exposed to a wind speed of 15 mph?

To calculate the power that can be produced by the wind turbine, we need to consider the available kinetic energy in the wind and the efficiency of the turbine.

The kinetic energy in the wind can be calculated using the equation:

KE = 0.5 * ρ * A * V^3

Where:

- KE is the kinetic energy

- ρ is the air density (convert 0.9 bar to appropriate units)

- A is the swept area of the turbine (A = π * (D/2)^2)

- V is the wind speed (convert 15 mph to appropriate units)

Then, we can calculate the power output by multiplying the kinetic energy by the turbine efficiency:

Power = KE * n

Substituting the given values and converting the units appropriately, you can calculate the power in watts that can be produced by your wind turbine.

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In a television set the power needed to operate the picture tube is 95 W and is derived from the secondary coil of a trans- formace. There is a creat of 53 mA in the secondas, coil. The primary coil is connected to 120-V receptante. Find the lens NJN of the transformer.

Answers

Therefore, the turns ratio of the transformer is 2264.15. Answer: The turns ratio of the transformer is 2264.15.

In a television set, the power needed to operate the picture tube is 95 W and is derived from the secondary coil of a transformer. There is a current of 53 mA in the secondary coil.

The primary coil is connected to a 120-V receptacle. We need to find the turns ratio of the transformer.A transformer is a device that changes the voltage and current level in an alternating current electrical circuit.

The transformer is made up of two coils of wire wrapped around a common ferromagnetic core. When an alternating current flows through the primary coil, a changing magnetic field is produced in the core.

This magnetic field induces an alternating current in the secondary coil.

The voltage in the secondary coil is determined by the turns ratio of the transformer.

The turns ratio is the ratio of the number of turns in the secondary coil to the number of turns in the primary coil.The power in the primary coil is given by:

P = V x I

whereP is the power in watts

V is the voltage in volts

I is the current in amps

The power in the secondary coil is given by:

P = V x I

where P is the power in watts

V is the voltage in volts

I is the current in amps

Since the power is the same in both the primary and secondary coil, we can equate the two equations:

Pprimary = PsecondaryVprimary x Iprimary

= Vsecondary x Isecondary

We can rearrange this equation to find the turns ratio:

Nsecondary/Nprimary = Vsecondary/Vprimary

Nsecondary/Nprimary = Iprimary/Isecondary

Nsecondary/Nprimary = 120/0.053

Nsecondary/Nprimary = 2264.15

Since the turns ratio is the ratio of the number of turns in the secondary coil to the number of turns in the primary coil, the number of turns in the secondary coil is:

Nsecondary = Nprimary x 2264.15

Nsecondary = Nprimary x 2264.15

The lens NJN of the transformer is given by the turns ratio of the transformer. Therefore, the turns ratio of the transformer is 2264.15. Answer: The turns ratio of the transformer is 2264.15.

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Write a Matlab code to plot the continuous time domain signal for the following spectrum:
X (jω) = 2sin(ω)/ω

Answers

Here is a MATLAB code to plot the continuous-time domain signal for the given spectrum: X(jω) = 2sin(ω)/ω.

% Define the frequency range

w = -10*pi:0.01*pi:10*pi;

% Compute the spectrum X(jω)

X = 2*sin(w)./w;

% Plot the signal in the time domain

plot(w, X)

xlabel('Frequency (rad)')

ylabel('Amplitude')

title('Continuous-Time Domain Signal')

grid on

The MATLAB code provided above allows us to plot the continuous-time domain signal for the given spectrum X(jω) = 2sin(ω)/ω.

First, we define the frequency range 'w' over which we want to evaluate the spectrum. In this case, we use a range of -10π to 10π with a step size of 0.01π.

Next, we compute the values of the spectrum X(jω) using the element-wise division operator './'. We calculate 2*sin(w)./w to obtain the values of X for each frequency 'w'.

Finally, we plot the signal in the time domain using the 'plot' function. The 'xlabel', 'ylabel', and 'title' functions are used to label the axes and title of the plot. The 'grid on' command adds a grid to the plot for better visualization.

By running this MATLAB code, we can obtain a plot that represents the continuous-time domain signal corresponding to the given spectrum.

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An aircraft is flying at a speed of 480 m/s. This aircraft used the simple aircraft air conditioning cycle and has 10 TR capacity plant as shown in figure 4 below. The cabin pressure is 1.01 bar and the cabin air temperature is maintained at 27 °C. The atmospheric temperature and pressure are 5 °C and 0.9 bar respectively. The pressure ratio of the compressor is 4.5. The temperature of air is reduced by 200 °C in the heat exchanger. The pressure drop in the heat exchanger is neglected. The compressor, cooling turbine and ram efficiencies are 87%, 89% and 90% respectively. Draw the cycle on T-S diagram and determine: 1- The temperature and pressure at various state points. 2- Mass flow rate. 3- Compressor work. 4- COP.

Answers

1- The temperature and pressure at various state points:

State 1: Atmospheric conditions - T1 = 5°C, P1

= 0.9 bar

State 2: Compressor exit - P2 = 4.5 * P1, T2 is determined by the compressor efficiency

State 3: Cooling turbine exit - P3 = P1, T3 is determined by the temperature reduction in the heat exchanger

State 4: Ram air inlet - T4 = T1,

P4 = P1

State 5: Cabin conditions - T5 = 27°C,

P5 = 1.01 bar

2- Mass flow rate:

The mass flow rate can be calculated using the equation:

Mass flow rate = Cooling capacity / (Cp × (T2 - T3))

3- Compressor work:

Compressor work can be calculated using the equation:

Compressor work = (h2 - h1) / Compressor efficiency

4- Coefficient of Performance (COP):

COP = Cooling capacity / Compressor work

Please note that specific values for cooling capacity and Cp (specific heat at constant pressure) are required to calculate the above parameters accurately.

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When filled to capacity, the unpressurized storage tank contains water to a height of h = 34 ft. The outside diameter of the tank is 7.3 ft and the wall thickness is 0.646 in. Determine the maximum normal stress and the absolute maximum shear stress on the outer surface of the tank at its base. (Weight density of water = 62.4 lb/ft3.)

Answers

The given data:Height of the storage tank, h = 34 ftOutside diameter of the tank, D = 7.3 ftWall thickness, t = 0.646 inWeight density of water, w = 62.4 lb/ft³.

We need to determine the maximum normal stress and the absolute maximum shear stress on the outer surface of the tank at its base.So, the following formulae are used:Volume of the tank = [tex]πD²h/4 = π(7.3)²(34)/4 = 1988.29 ft³.[/tex]

Weight of the water = Volume of the tank × weight density of water = 1988.29 × 62.4 = 124236.1 lb.

The water in the tank is trying to expand and the tank is resisting this expansion. Thus, there will be a radial stress on the tank at the bottom.The maximum normal stress at the base of the tank,

σmax = wH/2t + P/4t

Where P = Weight of the water in the tank = 124236.1 lbH = Height of the water in the tank = 34 ft

[tex]σmax = (62.4 × 34)/(2 × 0.646) + 124236.1/(4 × 0.646) = 23618.2 + 48325.6 = 71943.8 lb/ft²= 71943.8/144 = 499.6 psi[/tex].

The absolute maximum shear stress on the outer surface of the tank at its base, τmax = P/2At the base, the direction of the normal stress is radial and the direction of the shear stress is tangential.

Therefore, τmax = 124236.1/2 = 62118.05 lb/ft²= 62118.05/144 = 431.4 psi

In this question, the maximum normal stress and the absolute maximum shear stress on the outer surface of the tank at its base is to be determined. The formulae used to solve this problem are as follows:

The maximum normal stress at the base of the tank, σmax = wH/2t + P/4tThe absolute maximum shear stress on the outer surface of the tank at its base, τmax = P/2When the water is filled in the tank, it tries to expand and the tank resists this expansion.

Therefore, there is a radial stress on the tank at the bottom. The maximum normal stress at the base of the tank is calculated by using the formula σmax = wH/2t + P/4t. Here, w is the weight density of water, H is the height of the water in the tank, t is the thickness of the wall, and P is the weight of the water in the tank.

Substituting the given values, we get

[tex]σmax = (62.4 × 34)/(2 × 0.646) + 124236.1/(4 × 0.646) = 23618.2 + 48325.6 = 71943.8 lb/ft².[/tex]

The absolute maximum shear stress on the outer surface of the tank at its base is calculated by using the formula τmax = P/2. Here, P is the weight of the water in the tank. Substituting the given values, we get

τmax = 124236.1/2 = 62118.05 lb/ft².

Therefore, the maximum normal stress and the absolute maximum shear stress on the outer surface of the tank at its base are 499.6 psi and 431.4 psi, respectively.

Thus, we can conclude that the maximum normal stress and the absolute maximum shear stress on the outer surface of the tank at its base are 499.6 psi and 431.4 psi, respectively.

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In the manufacturing of self-lubricating bearings by powder metallurgy, an important secondary operation that is out after sintering is. a) Infiltration b) impregnation c) Cold isostatic pressing d) Hot isostatic pressing

Answers

The correct option is b) Impregnation is an important secondary operation that is carried out after sintering in the manufacturing of self-lubricating bearings by powder metallurgy.

Impregnation involves filling the interconnected porosity of the sintered bearing with a lubricant or resin. This process helps to enhance the self-lubricating properties of the bearing by providing a continuous lubricating film within the bearing structure. The lubricant or resin infiltrates the pores of the sintered material, improving its ability to reduce friction and wear.

In contrast, infiltration (a) refers to the process of filling the porosity of a sintered part with a material different from the base material, such as a metal or alloy. Cold isostatic pressing (c) involves subjecting the sintered part to high-pressure isostatic compression at room temperature. Hot isostatic pressing (d) is a similar process but performed at elevated temperatures.

While these processes may be used in powder metallurgy, impregnation specifically addresses the enhancement of self-lubricating properties in bearings.

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deposited uniformly on the Silicon(Si) substrate, which is 500um thick, at a temperature of 50°C. The thermal elastic properties of the film are: elastic modulus, E=EAI=70GPa, Poisson's ratio, VFVA=0.33, and coefficient of thermal expansion, a FaA=23*10-6°C. The corresponding Properties of the Si substrate are: E=Es=181GpA and as=0?i=3*10-6°C. The film-substrate is stress free at the deposition temperature. Determine a) the thermal mismatch strain difference in thermal strain), of the film with respect to the substrate(ezubstrate – e fim) at room temperature, that is, at 20°C, b)the stress in the film due to temperature change, (the thickness of the thin film is much less than the thickness of the substrate) and c)the radius of curvature of the substrate (use Stoney formula)

Answers

Determination of thermal mismatch strain difference Let's first write down the given values: Ea1 = 70 GP a (elastic modulus of film) Vf1 = 0.33 (Poisson's ratio of film)α1 = 23 × 10⁻⁶/°C (coefficient of thermal expansion of film).

Es = 181 GP a (elastic modulus of substrate)αs = 3 × 10⁻⁶/°C (coefficient of thermal expansion of substrate)δT = 50 - 20 = 30 °C (change in temperature)The strain in the film, due to temperature change, is given asε1 = α1 × δT = 23 × 10⁻⁶ × 30 = 0.00069The strain in the substrate, due to temperature change, is given asεs = αs × δT = 3 × 10⁻⁶ × 30 = 0.00009.

Therefore, the thermal mismatch strain difference in thermal strain), of the film with respect to the substrate(ezubstrate – e film) at room temperature, that is, at 20°C is 0.0006. Calculation of stress in the film due to temperature change Let's calculate the stress in the film due to temperature change.

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The return air from a space is mixed with the outside air in the ratio of (4:1) by mass. The mixed air is then entering the heating coil. The following data refer to the space: Inside design conditions (t-25°C; = 50%), outdoor air conditions (t= 5°C; = 60%), and the room Sensible Heat Ratio SHR is -0.5, Determine: (a) the supply air dry-bulb and wet-bulb temperature (b) the supply mass flow rate for 1 m³/min supply air; (c) the sensible and latent heat in kW; (d) the fresh air volume flow rate, in m³/min; and (d) the total load of the heating coil.

Answers

Inside design conditions (t-25°C; Φ = 50%)Outdoor air conditions (t= 5°C; Φ = 60%)Mixed air ratio = 4:1Sensible Heat Ratio (SHR) = -0.5(a) The supply air dry-bulb temperature The supply air temperature can be calculated by enthalpy method.

In the enthalpy method, the difference between the enthalpy of mixed air and the enthalpy of outdoor air is multiplied by the SHR and then added to the enthalpy of the outdoor air to get the enthalpy of the supply air. The enthalpy of the outdoor air can be calculated from the psychrometric chart.

It is found to be 20.07 kJ/kg. The enthalpy of mixed air can be calculated using the formula: Enthalpy of mixed air = (Mass of return air x Enthalpy of return air) + (Mass of outdoor air x Enthalpy of outdoor air) The mass of outdoor air is 1/5th of the total mass of the mixed air, while the mass of the return air is 4/5th of the mixed air.

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The base current is 34.23 mA and current gain, Boc is 100. The collector current in A is

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In the given problem, we are given the value of base current, which is I_{B}=34.23 mAand current gain, which is B_{oc}=100. To find the collector current, we can use the relation, I_{C}=B_{oc}*I_{B} Putting the given values in the above relation,

we getI_{C}=100*34.23*10^{-3}I_{C}=3.423 A Therefore, the collector current is 3.423 A (Amperes). The current gain of a transistor is the ratio of the output current to the input current. It is a dimensionless quantity. The collector current of a transistor is controlled by the base current through the current gain of the transistor. When the base current flows, the transistor is switched on and it allows the current to flow through the collector-emitter junction.The current gain of a transistor is usually denoted by the symbol B. The value of B can be in the range of a few tens to several hundred. It is usually given by the manufacturer and is one of the key parameters of the transistor.

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2.6 kg/s of a mixture of nitrogen and hydrogen containing 30% of nitrogen by mole, undergoes a steady flow heating process from an initial temperature of 30°C to a final temperature of 110°C. Using the ideal gas model, determine the heat transfer for this process? Express your answer in kW.

Answers

We can calculate the total heat transfer for the process by summing the heat transfers of nitrogen and hydrogen:

To determine the heat transfer for the process, we can use the equation:

Q = m * cp * ΔT

where:

Q is the heat transfer (in joules),

m is the mass flow rate of the mixture (in kg/s),

cp is the specific heat capacity of the mixture (in joules per kilogram per degree Celsius),

ΔT is the change in temperature (in degrees Celsius).

Given:

Mass flow rate of the mixture: 2.6 kg/s

Mole fraction of nitrogen: 30%

Initial temperature: 30°C

Final temperature: 110°C

First, we need to determine the mass flow rates of nitrogen and hydrogen in the mixture:

Mass flow rate of nitrogen = (Mole fraction of nitrogen) * (Total mass flow rate)

Mass flow rate of nitrogen = 0.30 * 2.6 kg/s = 0.78 kg/s

Mass flow rate of hydrogen = Total mass flow rate - Mass flow rate of nitrogen

Mass flow rate of hydrogen = 2.6 kg/s - 0.78 kg/s = 1.82 kg/s

Next, we need to calculate the specific heat capacities of nitrogen and hydrogen:

Specific heat capacity of nitrogen (cpN2) = 1.04 kJ/kg·°C

Specific heat capacity of hydrogen (cpH2) = 14.3 kJ/kg·°C

Now, we can calculate the heat transfer for each component:

Heat transfer for nitrogen = (Mass flow rate of nitrogen) * (Specific heat capacity of nitrogen) * (Change in temperature)

Heat transfer for nitrogen = 0.78 kg/s * 1.04 kJ/kg·°C * (110°C - 30°C)

Heat transfer for hydrogen = (Mass flow rate of hydrogen) * (Specific heat capacity of hydrogen) * (Change in temperature)

Heat transfer for hydrogen = 1.82 kg/s * 14.3 kJ/kg·°C * (110°C - 30°C)

Total heat transfer = Heat transfer for nitrogen + Heat transfer for hydrogen

By plugging in the values and performing the calculations, we can determine the heat transfer for the process in kilowatts (kW).

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There is an air flow with a temperature of 32.0℃, and it is humidified by making it flow over a container filled with water and whose length is 1.2 m. The temperature at the air-water interface is 20.0 ℃. If the initial humidity of the air is 25.0% and its speed is 0.15 m/s.
You are asked to determine:
a. The mass transfer coefficient.
b. The rate of evaporation of water per unit width of the container.
For this purpose, you must use the following empirical correlation:
Sℎ = 0.664Re^0.5Sc^0.333
- Sherwood number (Sh)
- Schmidt number (Sc)
Psat(20.0℃) = 0.02308 atm
Psat(32.0℃) = 0.04696 atm
R= 0.082 atm l/Kmol
Dwater in air = 2.77 ∙ 10−5 m^2⁄s
NH2O: it is expressed in mol/m^2s

Answers

The rate of evaporation of water per unit width of the container is 5.45 × 10^-6 mol/(m.s).

Given data:

Temperature of air, T_1 = 32.0 ℃

Length of the container, L = 1.2 m

Temperature at the air-water interface, T2 = 20.0 ℃

Initial humidity of air, H_1 = 25.0%

Speed of air, V = 0.15 m/s

Water vapour pressure at T2,

Psat = 0.02308 atm

Water vapour pressure at T1,

P = 0.04696 atm

Gas constant, R = 0.082 atm l/Kmol

Diffusion coefficient of water in air, Dwater = 2.77 × 10^-5 m^2⁄s

Using the Sherwood Number equation:

Sℎ = 0.664Re^0.5Sc^0.333

Where Re is Reynolds's Number and Sc is Schmidt's Number.

Mass transfer coefficient = Dwater / L ShSc= 0.7

for air-water interface at 25°CSc = 2.14 × 10^-5 / 0.0343 = 6.23 × 10^-4 (calculated from Sc = v/D)

Re = ρvd/μ = 1092.8 (calculated from Re = VDwater/ν, where ν = viscosity of air = 1.81 × 10^-5 kg/m.s)

Therefore, Sh = 2.0 (calculated from Sherwood Number equation)

Mass transfer coefficient = Dwater / L Sh

= 2.77 × 10^-5 / (1.2 × 2) = 1.15 × 10^-5 m/s

Calculating the rate of evaporation of water per unit width of the container:

RH1 = H1 Psat / P - Psat

= 6.85% (Relative humidity)

Mass transfer rate = KH2O A RH = KH2O L RH1

W= 1.15 × 10^-5 × 1.2 × 6.85 / 18

= 5.45 × 10^-6 mol/(m.s)

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A specimen of aluminum having a rectangular cross section 9.8 mm×12.8 mm(0.3858in×0.5039in.) is pulled in tension with 35300 N(7936Ibf) force, producing only elastic deformation. The elastic modulus for aluminum is 69GPa (or 10×10^6psi ). Calculate the resulting strain.

Answers

The resulting strain experienced by the aluminum specimen under a tensile force of 35300 N is approximately 0.00051, or 0.051%.

This value is obtained using the stress-strain relationship, which is derived from Hooke's law.

To explain further, the stress on the aluminum specimen is calculated first. Stress is the force applied divided by the area over which it is distributed. In this case, the cross-sectional area is 9.8 mm × 12.8 mm = 0.12544 cm². The stress thus equals the force (35300 N) divided by the area (0.12544 cm²), which gives 281300000 Pascal or 281.3 MPa. Using the formula for strain (which is stress divided by the modulus of elasticity), the strain equals 281.3 MPa divided by 69000 MPa (which is 69 GPa), resulting in a strain of approximately 0.00051, or 0.051%.

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An insulated piston-cylender device initially contains 30 L of of air at 120 kPa and 27°C. Air is now heated for 5 min by a 50-W resistance heater placed inside the cylinder. The pressure of air is maintained constant during this process, and surroundings are at 27°C and 100 kPa. Determine the Exergy destroyed during this process.

Answers

Given data, Initial volume, V₁ = 30 L Initial pressure, P₁ = 120 k Pa Initial temperature, T₁ = 27°CFinal pressure, P₂ = 120 k Pa Final temperature, T₂ = 27°CHeat supplied, Q = 50 W Time taken, t = 5 min.

Surrounding temperature, T₀ = 27°C Surrounding pressure, P₀ = 100 kPa The exergy destroyed during a process can be calculated using the formula, Exergy destroyed = Exergy supplied - Exergy output The Exergy supplied can be calculated using the formula.

Exergy supplied = Q(T₁ - T₀) / T₁ The Exergy output can be calculated using the formula:Exergy output = (P₁ V₁ / η) ln(P₂ / P₀)whereη is the isentropic efficiency of the process. It is given that air is heated at constant pressure. Therefore, η = Substitute the given values in the above equations to get the exergy destroyed.

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Question 2 The RCM3 process entails asking eight questions about the asset or the system under review. 2.1 Which is the first question would you consider as part of the initial steps in the RCM process? (1) 2.2 With an aid of an example, explain the difference between a primary and a secondary function. Please note: examples taken from the textbook/study guide will not be considered. (4) 2.3 With an aid of an example, describe the multiple performance standards of an equipment of your choice. Please note: examples taken from the textbook/study guide will not be considered. (4) 2.4 With an aid of an example, explain the difference between partial failure and total failure of an equipment of your choice. Please note: examples taken from the textbook/study guide will not be considered. (4)
2.5 What is meant by the operating context of a physical asset in RCM? Provide an example of an asset with different operating contexts (2) [15]

Answers

The first question to consider as part of the initial steps in the RCM (Reliability Centered Maintenance) process is "What are the functions and performance standards of the asset or system?".

Why "what are the functions and performance standards of the asset or system"?

When initiating the RCM process, it is crucial to clearly identify and understand the functions and performance standards of the asset or system under review. This involves determining the primary purpose and objectives of the asset or system as well as the specific performance requirements it needs to meet.

By establishing a solid understanding of the functions and performance standards, the subsequent steps in the RCM process such as identifying failure modes and consequences can be carried out effectively. This initial question sets the foundation for conducting a comprehensive analysis of the asset or system and ensures that maintenance strategies align with the desired performance objectives.

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Can you give me strategies for my plant design? (for a 15 story hotel building)
first system: Stand-by Gen
seconds system: Steam
third system: Air Duct/AHU
thank you

Answers

In addition to these specific systems, it's essential to consider the overall building design and integration of these systems to maximize efficiency and occupant comfort.

1. Stand-by Generator System: - Determine the power requirements of the hotel building, including essential systems such as elevators, Emergency lighting, fire alarm systems, and critical equipment - Choose a standby generator with sufficient capacity to meet the power demand during power outages - Ensure proper integration of the standby generator system with the electrical distribution system to provide seamless power transfer - Conduct regular maintenance and testing of the standby generator to ensure its reliability during emergencies.    

   2. Steam System: - Identify the steam requirements in the hotel building, such as hot water supply, laundry facilities, and kitchen equipment - Size the steam boiler system based on the maximum demand and consider factors like peak usage periods and safety margins - Install appropriate steam distribution piping throughout the building, considering insulation to minimize heat loss - Implement control strategies to optimize steam usage, such as pressure and temperature control, and steam trap maintenance.

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Develop a project with simulation data of a DC-DC converter: Buck Boost a) 12V output and output current between (1.5 A-3A) b) Load will be two 12 V lamps in parallel/Other equivalent loads correction criteria c) Simulation: Waveforms (input, conversion, output) of voltage and current in general. Empty and with load. d) Converter efficiency: no-load and with load e) Frequency must be specified f) Development of the high frequency transformer, if necessary g) Smallest size and smallest possible mass. Reduce the use of large transformers. >>> Simulation can be done in Multisim or in another software of your choice.

Answers

Project Description:In this project, we will simulate a DC-DC converter known as a Buck-Boost converter. The objective is to design a converter that produces a 12V output with an output current ranging between 1.5A and 3A.

The load for the converter will consist of two 12V lamps connected in parallel or other equivalent loads as per the correction criteria.

The simulation will involve analyzing the waveforms of the input voltage and current, conversion voltage and current, and output voltage and current. The simulation will be conducted for both empty (no-load) conditions and with the specified load.

Efficiency analysis will be performed to determine the converter's efficiency under both no-load and loaded conditions. The efficiency will be calculated as the ratio of the output power to the input power.

The frequency of operation for the converter needs to be specified. Generally, a high-frequency operation is preferred to reduce the size and mass of the components. The specific frequency will depend on the requirements and constraints of the project.

If necessary, the design will involve the development of a high-frequency transformer. The transformer will be designed to meet the size and mass requirements while ensuring efficient power transfer.

The main objective of the project is to achieve the smallest possible size and mass for the converter while reducing the reliance on large transformers. The design will prioritize compactness and efficiency.

Simulation software such as Multisim or any other suitable software of your choice can be used to perform the simulation and analysis of the DC-DC converter.

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Angle of loll (10 marks) (a) A vessel is experiencing an Angle of Loll. What is the value of the righting lever GZ in this situation? (b) Determine the angle of loll for a box shaped vessel of length L = 12m, breadth B = 5.45m when floating on an even-keel at a draft of d = 1.75m. The KG is 2.32m.

Answers

(a) The value of the righting lever GZ in a vessel experiencing an Angle of Loll can be determined based on the vessel's stability characteristics.

The righting lever, GZ, represents the moment arm between the center of buoyancy (B) and the center of gravity (G), indicating the vessel's stability. To calculate GZ, the metacentric height (GM) and the heeling arm (GZh) must be considered. GM is the vertical distance between the center of gravity and the metacenter, while GZh is the distance between the center of gravity and the center of buoyancy at a given heel angle. GZ is then determined by subtracting GZh from GM.

(b) To determine the angle of loll for a box-shaped vessel, several factors need to be considered. The angle of loll occurs when a vessel has a negative metacentric height (GM) and is in an unstable condition. The formula to calculate the angle of loll is:

Angle of Loll = arctan(GM / KG)

In this case, the vessel has a length (L) of 12m, breadth (B) of 5.45m, and draft (d) of 1.75m. The KG, which represents the distance from the keel to the center of gravity, is given as 2.32m. By substituting these values into the formula, the angle of loll can be determined.

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For a pure gas that obeys the truncated virial equation, Z = 1 + BP / RT, show whether or not the internal energy changes (a) with isothermal changes in pressure and (b) with isothermal changes in volume.

Answers

a) The internal energy is also a function of the number of molecules present and the degrees of freedom of the molecules and b) Therefore, it may be concluded that the internal energy does not change with isothermal changes in pressure and volume.

The equation of state is a relation between the pressure, volume, and temperature of a substance. A number of real gases don't conform to the ideal gas equation. Virial equations, which are series expansions of the gas compressibility factor (Z) as a function of pressure, temperature, and, in some cases, molecular volume, are often used to represent these deviations. The truncated virial equation is a virial equation that only includes the first two terms of the virial expansion.

The internal energy is one of the thermodynamic variables that define the thermodynamic state of a system. The internal energy is the energy that a system has as a result of the motion and interactions of its particles. The internal energy per mole of a pure gas is given by the following equation:

U = 3 / 2 RT

For a pure gas that obeys the truncated virial equation, Z = 1 + BP / RT,

a) When pressure is isothermally altered, the internal energy of the gas remains constant.

The internal energy of an ideal gas is a function of temperature alone and not pressure or volume. The internal energy is also a function of the number of molecules present and the degrees of freedom of the molecules.

b) When volume is isothermally altered, the internal energy of the gas remains constant.

The internal energy of an ideal gas is a function of temperature alone and not pressure or volume. The internal energy is also a function of the number of molecules present and the degrees of freedom of the molecules.

Therefore, it may be concluded that the internal energy does not change with isothermal changes in pressure and volume.

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Which statement is not correct about the mixed forced and natural heat convection? a In a natural convection process, the influence of forced convection becomes significant if the square of Reynolds number (Re) is of the same order of magnitude as the Grashof number (Gr). b Natural convection can enhance or inhibit heat transfer, depending on the relative directions of buoyancy-induced motion and the forced convection motion. c The effect of natural convection in the total heat transfer is negligible compared to the effect of forced convection.
d If Grashof number (Gr) is of the same order of magnitude as or larger than the square of Reynolds number (Re), the natural convection effect cannot be ignored compared to the forced convection.

Answers

Natural convection can enhance or inhibit heat transfer, depending on the relative directions of buoyancy-induced motion and the forced convection motion.The statement that is not correct about the mixed forced and natural heat convection is Option C.

The effect of natural convection in the total heat transfer is negligible compared to the effect of forced convection.

The mixed forced and natural heat convection occur when there is a simultaneous effect of both the natural and forced convection. The effect of these two types of convection can enhance or inhibit heat transfer, depending on the relative directions of buoyancy-induced motion and the forced convection motion. Buoyancy-induced motion is responsible for the natural convection process, which is driven by gravity, density differences, or thermal gradients. Forced convection process, on the other hand, is induced by external means such as fans, pumps, or stirrers that move fluids over a surface.Natural convection process tends to reduce heat transfer rates when the direction of buoyancy-induced motion is opposing the direction of forced convection. Conversely, heat transfer rates are increased if the direction of buoyancy-induced motion is in the same direction as the direction of forced convection. The effect of natural convection in the total heat transfer becomes significant if the square of Reynolds number (Re) is of the same order of magnitude as the Grashof number (Gr). If Grashof number (Gr) is of the same order of magnitude as or larger than the square of Reynolds number (Re), the natural convection effect cannot be ignored compared to the forced convection.

In conclusion, the effect of natural convection in the mixed forced and natural heat convection is significant, and its effect on heat transfer rates depends on the relative directions of buoyancy-induced motion and the forced convection motion. Therefore, statement C is incorrect because the effect of natural convection in the total heat transfer cannot be neglected compared to the effect of forced convection.

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Explain why semiconducting materials and the behaviour
of semiconductor junctions play an important role in the working
principle and performance of Light-emitting diode
(LED).

Answers

Semiconducting materials and the behaviour of semiconductor junctions play a crucial role in the working principle and performance of Light-emitting diode (LED).Explanation: LEDs work on the principle of electroluminescence, in which a material emits light in response to an electric current passing through it. This property is exhibited by certain semiconducting materials that have a bandgap, which is the difference in energy levels between the valence and conduction bands.

When an LED is connected to a power source, an electric current flows through the device and causes electrons to move from the negative (n-type) to the positive (p-type) region of the semiconductor material. The electrons release energy as they move from the conduction band to the valence band, which produces photons of light.The behaviour of the semiconductor junctions is also essential to the performance of LEDs. A junction is formed by the contact between the n-type and p-type regions of the semiconductor material, which creates a depletion region that acts as a barrier to the flow of electrons and holes. This region is crucial because it helps to confine the charge carriers to the active region of the device, which maximizes the efficiency of the electroluminescent process.The construction of the p-n junction is also critical in ensuring the proper functioning of LEDs. The junction must be carefully engineered to ensure that it has the correct doping levels, thickness, and quality of the interface, among other factors. This helps to ensure that the device has the correct electrical and optical properties to emit light efficiently.

Finally, the choice of semiconducting materials used in LEDs is critical to their performance. Different materials have different bandgap energies, which determine the color of light that is emitted when the device is activated. Materials such as gallium arsenide, indium gallium nitride, and silicon carbide are commonly used in the construction of LEDs because they exhibit excellent electroluminescent properties.

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1. What is a strain gauge? 2. Explain Hooke's law and give the formula for this law. 3. What is Young's modulus and how is it measured? 4. Do stiff materials have high or low values of modulus? 5. What is the Poisson's ratio and what dimension does it have? 7. What type of circuit is usually used in strain measurement? Why?

Answers

The Strain gauge is an electrical element used for measuring mechanical deformation or strain in materials. It works based on the piezoresistive effect that means when mechanical stress is applied on any piezoresistive material it causes the change in its resistance.

The strain gauge is used for measuring small deformations in different mechanical applications.2. Hooke's Law: Hooke's law is a physical law that states that when a load is applied to a solid material it causes the material to deform. The amount of deformation is directly proportional to the load applied on it. Hooke's law is given by the formula F=kx. Where F is the force applied, x is the deformation caused in the material, and k is a constant called the spring constant.

Young's Modulus: Young's modulus is defined as the ratio of the stress applied to the strain caused in the material. It is used to measure the stiffness of the material. Wheatstone Bridge Circuit: Wheatstone bridge circuit is usually used in strain measurement. It is an electrical circuit used to measure an unknown electrical resistance. In strain measurement, the strain gauge is connected to one arm of the Wheatstone bridge circuit and the voltage is measured across the other two arms of the bridge circuit. This voltage is proportional to the strain caused in the material.

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Q5) Given the denominator of a closed loop transfer function as expressed by the following expression: S²+85-5Kₚ + 20 The symbol Kₚ denotes the proportional controller gain. You are required to work out the following: 5.1) Find the boundaries of Kₚ for the control system to be stable.
5.2) Find the value for Kₚ for a peak time Tₚ to be 1 sec and percentage overshoot of 70%.

Answers

The denominator of a closed-loop transfer function is given as follows:S² + 85S - 5Kp + 20In this question, we have been asked to determine the boundaries.

To determine the limits of Kp for stability, we have to determine the values of Kp at which the poles of the transfer function will be in the right-hand side of the s-plane (RHP). This is also referred to as the instability criterion. As per the Routh-Hurwitz criterion, if all the coefficients of the first column of the Routh array are positive.

So let us form the Routh array for the given transfer function. Routh array:S² 1 -5Kp85 20The first column of the Routh array is [1, 85]. To ensure the system is stable, the coefficients of the first column should be positive. From equation (2), we see that the system is stable irrespective of the value of Kp.

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For a 3-bus power system, the real and reactive powers are specified at all buses except the swing bus. The Newton Rephson method is chosen to solve the lood flow problem 1- What is the order of the Jacobian matrix ? 2- Determine the element in the Jacobson matrix, representing the variation of the real power at bus 2 with respect to the variation of the magnitude of the voltage at bus 2 3- Determine the element in the Jacobian matrix, representing the variation of the reactive power at bus 3 with respect to the variation of the angle of the voltage at bus 2

Answers

1. The order of the Jacobian matrix is equal to the number of unknowns in the power flow problem. In a 3-bus power system, the unknowns typically include the voltage magnitudes and voltage angles at each bus except the swing bus. Therefore, the order of the Jacobian matrix would be (2n - 1), where n is the number of buses in the system. In this case, since there are three buses, the order of the Jacobian matrix would be (2 * 3 - 1) = 5.

2. To determine the element in the Jacobian matrix representing the variation of the real power at bus 2 with respect to the variation of the magnitude of the voltage at bus 2, we need to compute the partial derivative of the real power at bus 2 with respect to the voltage magnitude at bus 2 (∂P2/∂|V2|).

The Jacobian matrix for the power flow problem consists of partial derivatives of the power injections at each bus with respect to the voltage magnitudes and voltage angles at all buses. Let's denote the Jacobian matrix as J.

The element representing ∂P2/∂|V2| in the Jacobian matrix can be denoted as J(2, 2), indicating the second row and second column of the matrix.

To determine the element in the Jacobian matrix representing the variation of the reactive power at bus 3 with respect to the variation of the angle of the voltage at bus 2, we need to compute the partial derivative of the reactive power at bus 3 with respect to the voltage angle at bus 2 (∂Q3/∂θ2).

Similarly to the previous question, the element representing ∂Q3/∂θ2 in the Jacobian matrix can be denoted as J(3, 2), indicating the third row and second column of the matrix.

1. The order of the Jacobian matrix for a 3-bus power system is 5.

2. The element in the Jacobian matrix representing the variation of the real power at bus 2 with respect to the variation of the magnitude of the voltage at bus 2 is J(2, 2).

3. The element in the Jacobian matrix representing the variation of the reactive power at bus 3 with respect to the variation of the angle of the voltage at bus 2 is J(3, 2).

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Merits and Demerits between HRC/Drop-Out Fuses and other
different types of
fuses

Answers

HRC and drop-out fuses have both merits and demerits when compared to other types of fuses. It is up to the user to decide which type of fuse is best suited for their specific needs.

HRC (High Rupturing Capacity) and drop-out fuses are some of the types of fuses that have both merits and demerits as compared to other types of fuses.

The demerits and merits of each type of fuse are discussed in detail as follows:

Demerits of HRC and Drop-Out Fuses:

The following are the demerits of the HRC and drop-out fuses:

They are more expensive than other types of fuses. Due to their complexity, they require more maintenance, which adds to their cost.

They are unsuitable for low voltages because they require a lot of current to trigger, which can be dangerous.

They have a higher tripping time than other types of fuses, which can cause damage to equipment.

Merits of HRC and Drop-Out Fuses:

The following are the merits of the HRC and drop-out fuses:

They can handle a larger amount of current than other types of fuses, which means they can protect larger electrical systems.

They have a higher breaking capacity, which means they can handle large current surges without breaking down.

They have a longer lifespan than other types of fuses, which makes them more reliable.

They are safer because they have a lower risk of causing a fire or explosion due to their design. Other types of fuses have a higher risk of failure due to their design, which can lead to a fire or explosion.

Overall, HRC and drop-out fuses have both merits and demerits when compared to other types of fuses. It is up to the user to decide which type of fuse is best suited for their specific needs.

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If the number of turns in the coil is increased, the induced electromotive force in the coil will A. Increase B. Decrease C. Remains same D. None of the above

Answers

If the number of turns in the coil is increased, the induced electromotive force in the coil will A. Increase.

According to Faraday's law of electromagnetic induction, the magnitude of the induced electromotive force (EMF) in a coil is directly proportional to the rate of change of magnetic flux passing through the coil. The magnetic flux is influenced by factors such as the strength of the magnetic field and the number of turns in the coil.

When the number of turns in the coil is increased, more individual loops are present, resulting in a larger surface area for magnetic flux to pass through. As a result, a greater amount of magnetic flux is linked with the coil, leading to a higher rate of change of flux and an increased induced EMF.

Therefore, increasing the number of turns in the coil enhances the effectiveness of electromagnetic induction, resulting in a greater induced electromotive force.

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In the following problems, the given loads are superimposed service loads; that is, they do not include the weights of the beams (unless noted otherwise). For structural steel beams (unless otherwise noted), assume a yield stress of 50 ksi (345 MPa). For timber beams, all beams are solid, rectangular shapes and Appendices E and F are applicable. Consider only moment and shear (unless otherwise noted). Select the lightest W shape to support a uniformly distrib- uted load of 2.1 kips/ft on a simple span of 24 ft.

Answers

The lightest W shape that can support a uniformly distributed load of 2.1 kips/ft on a simple span of 24 ft is [insert the W shape designation].

To determine the lightest W shape, we need to consider the maximum moment and shear forces generated by the given load. Given a uniformly distributed load of 2.1 kips/ft and a span of 24 ft, the total load on the beam can be calculated as (2.1 kips/ft) x (24 ft) = 50.4 kips.

Next, we need to calculate the maximum moment and shear values at the critical sections of the beam. For a simply supported beam under a uniformly distributed load, the maximum moment occurs at the center of the beam, and the maximum shear occurs at the supports.

Using standard beam formulas, we can determine the maximum moment (M) as (wL[tex]^2[/tex])/8, where w is the load per unit length and L is the span length. Substituting the values, we get M = (2.1 kips/ft) x (24 ft)[tex]^2[/tex] / 8 = 151.2 kip-ft.

The maximum shear (V) can be calculated as wL/2, which gives V = (2.1 kips/ft) x (24 ft) / 2 = 50.4 kips.

With the maximum moment and shear values, we can refer to the load tables for W shapes to find the lightest beam that can support these loads. The selection should consider the yield stress of the structural steel beams, which is given as 50 ksi.

By comparing the load capacity of different W shapes, we can identify the lightest shape that can safely support the given load. The specific W shape designation will depend on the load tables provided, and it should be chosen to ensure the beam's capacity is greater than or equal to the calculated maximum moment and shear values.

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The two von-Mises Stress plots shown below are created from the same FE solution. Comment on the difference in the two plots and why the information is different.

Answers

I can explain the factors that could cause differences in two such plots based on the same FE solution.

Possible differences between two von-Mises stress plots based on the same Finite Element (FE) solution could be due to the difference in the visual presentation like color mapping, scale settings, or the choice of elements for displaying results (e.g., element edges, nodes, etc.). Different stress visualization methods can represent the same data differently. For instance, one plot might be using a linear color scale while the other uses a logarithmic one. Or one plot may show results at element centers, and another at nodes, creating an appearance of difference due to averaging of adjacent element stresses at nodes.

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It is true that the continuity equation below is valid for viscous and inviscid flows, for Newtonian and Non-Newtonian fluids, compressible and incompressible? If yes, are there(are) limitation(s) for the use of this equation? Detail to the maximum, based on the book Muson.δt/δrho +∇⋅(rhoV)=0

Answers

The continuity equation given by Muson,

 δt/δrho +∇⋅(rhoV) = 0

is true for viscous and inviscid flows, for Newtonian and Non-Newtonian fluids, compressible and incompressible. This is because the continuity equation is a fundamental equation of fluid dynamics that can be applied to different types of fluids and flow situations.

The continuity equation is a statement of the principle of conservation of mass, which means that mass can neither be created nor destroyed but can only change form. In fluid dynamics, the continuity equation expresses the fact that the mass flow rate through any given volume of fluid must remain constant over time. The equation states that the rate of change of mass density (ρ) with time (δt) plus the divergence of the mass flux density (ρV) must be zero.There are limitations to the use of the continuity equation, however. One limitation is that it assumes that the fluid is incompressible, which means that its density does not change with pressure. This is a reasonable assumption for many fluids, but it is not valid for all fluids.

For example, gases can be compressed and their density can change significantly with pressure.Another limitation of the continuity equation is that it assumes that the fluid is homogeneous and isotropic, which means that its properties are the same in all directions. This is not always the case, especially in complex flow situations such as turbulent flow. In these situations, the continuity equation may need to be modified or replaced with more complex equations to account for the effects of turbulence.

Furthermore, it is important to note that the continuity equation is a local equation, which means that it applies only to a small volume of fluid. To apply it to a larger volume of fluid, it must be integrated over the entire volume. Finally, it should be noted that the continuity equation is a linear equation, which means that it applies only to small changes in fluid density and velocity. For larger changes, nonlinear effects may need to be taken into account.

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6. ¬¬¬_____m2 (10) What cross-sectional area is required for rate of kinetic energy advected by the flow to reach KE = 1.21 GW? 7. ____KW (10) At KE = 1.21 GW, what is total enthalpy rate of the flow? Six more students arrive with a better idea. They suggest we suddenly stop the flow, and harness the newly liberated flow energy. 8. ____kW (10) How much flow energy (power) is there in our lovely little stream? Hint: flow energy rate=PV Alumni arrive, clearly disappointed. They insist we're not quite ambitious enough. They provide funding to relocate the entire operation to Venezuela, where we proceed to have our 88 mph water hurled over Angel Falls, then down into Devil's Canyon, a mere 3200 ft below. 9. ____KW (10) Now, how much power is available in our stream to be extracted in some steady flow device? 10. ____(10) Is this a bad idea (Hint: yes)? Explain. Be sure to discuss how much power you think could be extracted.

Answers

6. The cross-sectional area required for the rate of kinetic energy advected by the flow to reach KE = 1.21 GW is given byA = (2KE)/(ρV3 )where KE = 1.21 GW = 1210000000 J/s, ρ = 1000 kg/m3, and V = 8 m/s.Thus, [tex]A = (2 × 1210000000)/(1000 × 83 )= 36702.4 m27. At KE = 1.21 GW.[/tex]

The total enthalpy rate of the flow is given by [tex]H = KE + (PV )= KE + (1/2)ρV2= 1210000000 + 0.5 × 1000 × 82= 194560000 W8[/tex]. The flow energy (power) in the stream is given by[tex]Q = PVAQ = 1000 × 8 × 2.8= 22400 W9.[/tex] The power available in the stream to be extracted in some steady flow device is given by Pavail = ηQHPavail = ηρgHQ = VA thus, Pavail = ηρgAV = (0.85)(1000 kg/m3)(9.81 m/s2)(285 m2/s)= 2350000 W10.

Yes, this is a bad idea because the net power output of the hydropower plant is given by the difference between the power input and the power lost due to inefficiency. Since the efficiency of a hydropower plant is typically between 80-90%, the maximum power output will be reduced by at least 10-20%. Thus, the maximum power that can be extracted from the stream will be 80-90% of 2350000 W, which is between 1880000-2115000 W.

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Find the inner and outer diameter di and d₂ of a hollow shaft having the same strength as asolid shaft with adiameter of d= 8am and weight of 60%. The shortened material is the same.

Answers

Inner diameter di = √(d² - 32) cm and outer diameter d₂ = √(d² + 32) cm. Hollow shaft should have the same strength as the solid shaft

Given: Diameter of solid shaft = d = 8 cm

Weight of solid shaft = 60%

Hollow shaft should have the same strength as the solid shaft

Assuming the material of the solid and hollow shaft is the same.To find: Inner diameter di and outer diameter d2 of hollow shaft.

Solution: Let's assume the outer radius of solid shaft be r and inner radius of hollow shaft be r1.Hence, r = d/2 = 8/2 = 4 cm

For solid shaft: Weight of the solid shaft = πr²Lρ = 0.6πr²Lρ ...(1)Where L = Length of the solid shaftρ = Density of the materialFor hollow shaft:Weight of the hollow shaft = π/4 (d₂² - di²)Lρ = 0.6πr²Lρ ...(2)π/4 (d₂² - di²) = πr²d₂² - di² = 4r²d₂² - di² = 4×4² (since r = 4 cm)d₂² - di² = 64 ...(3)Also, from the equation of torsional stress τ = (T×r) / (J)where T = twisting momentr = radius of shaftJ = Polar moment of inertia of shaftFor solid shaft:τ = (T×r) / (J)τ = (T×d/2) / (π/2 (d⁴/32))τ = 16T / (πd³) ...(4)For hollow shaft:τ = (T×r) / (J)τ = (T×(di+d₂)/2) / (π/2 ((d₂⁴-di⁴)/32))τ = 16T(di+d₂) / (π(d₂⁴-di⁴)) ...(5)But from equation 4 and 5, τsolid = τhollowd²/4 = (di²+d₂²)/2di²+d₂² = 2d² ...(6)Using equation 3 in equation 6:d₂² + 64 - di² = 2d²d₂² - di² = 2d² - 64

From equations 3 and 6, we have to solve for d₂ and di.So, d₂² + (2d² - 64) = 2d²d₂² - 64 = d²d₂ = √(d² + 64/2) = √(d² + 32)di² + (2d² - 64) = d²di² = √(d² - 32)Therefore, inner diameter di = √(d² - 32) cm and outer diameter d₂ = √(d² + 32) cm.

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On separate coordinate planes, sketch the graphs of the given functions over the interval -2 x 2. a) f(x) = sin r b) g(x) = |sin x| c) h(x) = sin |x| Describe and analyse the property business cycles. which of the following statements is true about a projectile at the instant at which it is at the highest point of its parabolic trajectory? group of answer choices its velocity is zero. both a and c the vertical component of its velocity is zero. the horizontal component of its velocity is zero. its acceleration is zero. An example of a mutualistic relationship could be (check all that apply)Group of answer choicesA. A hookworm living in the intestines of a fishB. the fungus and algae portions of a lichenC. An Acacia tree species providing food for ants which protect the tree from herbivoresD. Ravens and vultures eating a roadkill carcassE. A hummingbird drinking nectar and pollinating the flower Animals share a unique set of genes. Choose the statement below that best describes this molecular homologies. a.These sets of genes are referred at x-box genes b.These genes are important for the different morphologies of the developing embryo c.These genes are important in deuterstome development d.These genes are shared by animal's closest protist relative [4 points] An analyte measured at 272 nm showed absorbance of0.0885, and when the same analyte solution was subjected to 254 nm,it showed absorbance of 0.2557. (i) Which is the better wavelengthto Bees add the enzyme glucose oxidase to honey through their saliva. Describe the processes of producing the functional enzyme and the chemical reaction this enzyme catalyses. What is the reaction product and how does it impact on microbial activity. You need to include as a minimum the following processes in your explanation: transcription, RNA processing, translation, substrate(s) and product(s) of the enzyme reaction, characteristic(s) of the product(s) and how this relates to microbial activity. Describe a way to avoid or prevent cancer. What could cause cancer? 1 Ff B 1 U X2 x 8 > 2 Learn Video I 3. Find the directional derivative of V=rz 2 cos2 along the direction A=2r z and evaluate it at (1,/2,2).