Answer:
The velocity ratio of the wedge is 0.15
Explanation:
Use the following formula to calculate the velocity ratio
Velocity Ratio = Distance Moved by effort / Distance moved by Load
Where
Distance Moved by effort = 3cm
Distance moved by Load = 20 cm
Placing values in the formula
Velocity Ratio = 3cm / 20 cm
Velocity Ratio = 0.15
why are antennas needed for radio, television, and cell phone transmission>
A. without a long antenna, the signal will not travel very far
B. the antenna allows you to direct your signal toward the intended target
C. the sound waves require a metal surface to bounce off
D. EM waves are created by oscillating electrons within the antenna
40 points + brainliest if correct please help
Answer:
A.without a long antenna, 're signal will not travel far
Dos masas con valores de 8kg y 12kg cada una se encuentran separadas por una distancia de 1m. Determinar la fuerza de atraccion gravitacional entre ellas si se compara con el valor de sus pesos Como es este valor?
The question is: Two masses with values of 8kg and 12kg each are separated by a distance of 1m. Determine the force of gravitational attraction between them if compared with the value of their weights. What is this value?
Answer: The force of gravitational attraction between them if compared with the value of their weights is [tex]640.704 \times 10^{-11} N[/tex].
Explanation:
Given: [tex]m_{1}[/tex] = 8 kg, [tex]m_{2}[/tex] = 12 kg
Distance = 1 m
Formula used is as follows.
[tex]F = \frac{G \times m_{1} \times m_{2}}{r^{2}}[/tex]
where,
F = force of gravitational attraction
G = gravitational constant = [tex]6.674 \times 10^{-11} N m^{2}/kg^{2}[/tex]
[tex]m_{1}[/tex] = mass of object 1
[tex]m_{2}[/tex] = mass of object 2
r = distance between the centers of these two objects
Substitute the values into above formula as follows.
[tex]F = \frac{G \times m_{1} \times m_{2}}{r^{2}}\\= \frac{6.674 \times 10^{-11} Nm^{2}/kg^{2} \times 8 kg \times 12 kg}{(1 m)^{2}}\\= 640.704 \times 10^{-11} N[/tex]
Thus, we can conclude that the force of gravitational attraction between them if compared with the value of their weights is [tex]640.704 \times 10^{-11} N[/tex].
How many valence electrons does the hydrogen and oxygen have in the following picture?
Answer:
can u make the picture less blurry pls
Explanation:
Please please help me :)
Answer:
Explanation:
2) From F=ma
Force =15×40=600N or kgm/s2
3)From the same equation making acceleration the subject of the formula will give
a=f÷m
=24÷4=6m/s2
4)m=f÷a
=45÷15=3kg
NEED HELP What is the energy transformation process when using a battery powered flashlight?Single choice.
(2 Points)
Electrical-electromagnetic-thermal
Electrical -light-thermal
Chemical-electrical-thermal-light
Chemical-thermal-light
Answer:
Chemical-thermal-lightChemical-electrical-thermal-lighthope it is helpful to you
help asap!
three resistors of 20. ohms, 30. ohms, and 60. ohms, respectively, are connected in series with a battery. a current of 2.0 amperes will flow through this circuit when the potential difference of the battery is a. 20.V b. 220 V c. 110 V d. 10.V.
Answer:
b. 220 V
Explanation:
Let resistors be R1, R2, and R3 respectively.
Given the following data;
R1 = 20 ohms
R2 = 30 ohms
R3 = 60 ohms
Current = 2 Amperes
To find the voltage;
First of all, we would determine the total effective resistance (RT).
For series circuit;
RT = R1 + R2 + R3
RT = 20 + 30 + 60
RT = 110 Ohms
Next, we find the voltage using the formula;
Voltage = current * resistance
Voltage = 2 * 110
Voltage = 220 Volts
R=70
R-40
M
120V
R, 90
W
Answer:
please type full question. Does not mean what you are trying to saying.A student on an amusement park ride moves in circular path with a radius of 3.5 m once every 4.5 s. What is the tangential velocity of the student?
Answer:
the tangential velocity of the student is 4.89 m/s.
Explanation:
Given;
the radius of the circular path, r = 3.5 m
duration of the motion, t = 4.5 s
let the student's tangential velocity = v
The tangential velocity of the student is calculated as follows;
[tex]v = \frac{2\pi r}{t} \\\\v = \frac{2 \pi \times 3.5}{4.5} \\\\v = 4.89 \ m/s[/tex]
Therefore, the tangential velocity of the student is 4.89 m/s.
A conducting bar moves along a circuit with a constant velocity. A constant magnetic field is perpendicular to the bar and circuit. The bar covers 1.50 m2 of area in 1.00 second. An EMF of 3.57 V is induced in the circuit. What is the strength of the magnetic field in Tesla?
Answer:
2.38 T
Explanation:
Since the number of coils and the change in time are both 1, I set it up as 3.57=1.50(x) and then solved for x to be 2.38 T.
As global population ______
a.) increases b.) decreases
food production must _____
a.) increase b.) decrease
Answer:
As global population a.) increases food production must a.) increase.
Example:
More people means more food must be produced.
At one moment during its flight a thrown basketball experiences a gravitational force of 1.5N down and air resistance of 0.40N(32 degree above horizontal). Calculate the magnitude and direction of of the net force of the ball
Answer:
1. The magnitude of the net force is 1.33 N.
2. The direction is 14.8° with respect to the vertical.
Explanation:
1. The magnitude of the net force is given by:
[tex] |F| = \sqrt{F_{x}^{2} + F_{y}^{2}} [/tex]
Where:
[tex]F_{x}[/tex]: is the sum of the forces acting in the x-direction
[tex]F_{y}[/tex]: is the sum of the forces acting in the y-direction
Let's find the forces acting in the x-direction and in the y-direction.
In the x-direction:
[tex] \Sigma F_{x} = -F_{a}cos(\theta) [/tex]
Where:
Fa: is the force of air resistance = -0.40 N. The negative sign is because this force is in the negative x-direction.
θ: is the angle = 32°
[tex] \Sigma F_{x} = -0.40 N*cos(32) = -0.34 N [/tex]
In the y-direction:
[tex] \Sigma F_{y} = F_{g} + F_{a}sin(\theta) [/tex]
Where:
[tex]F_{g}[/tex]: is the gravitational force = -1.5 N
[tex] \Sigma F_{y} = -1.5 N + 0.40 N*sin(32) = -1.29 N [/tex]
Hence, the magnitude of the net force is:
[tex] |F| = \sqrt{(-0.34 N)^{2} + (-1.29)^{2}} = 1.33 N [/tex]
2. The direction of the net force is:
[tex] tan(\alpha) = \frac{F_{x}}{F_{y}} = \frac{-0.34}{-1.29} [/tex]
[tex] \alpha = tan^{-1}(\frac{-0.34}{-1.29}) = 14.8 [/tex]
The angle is 14.8° with respect to the vertical.
I hope it helps you!
Why do scientists need an accurate atomic model? (2 points) The atom is the most important structure in the universe. The atom is the most important structure in the universe. It allows scientists to predict things about objects that are too small to see. It allows scientists to predict things about objects that are too small to see. Models allow scientists to avoid having to do real experiments. Models allow scientists to avoid having to do real experiments. The atom cannot be divided into smaller particles.
1. Answer:
It allows scientists to predict things about objects that are too small to see.
Explanation:
Atomic models are crucial to the scientific study of atoms. Through models, we represent atoms that we actually cannot see. Observation based study and testing is done through that model which helps us find flaws in one model so that a better model is made. In this way, it is helpful to study about atoms through atomic models.
2. Answer:
The correct step in a scientific experiment involving acids and bases is:
Using an indicator to measure the hydrogen ion concentration of a solution.
Explanation:
Two acids can never neutralize each other. The pH of a neutral solution is 7. Whereas pH of an acid is always less than 7.
Indicators are used to measure the pH of solutions. They give different colors in solutions with different solutions. So, in an experiment to check if the solution is acidic or basic, we need to measure its hydrogen ion concentration for which an indicator is used.
Hope I helped! Brainiest plz! Hope you make an 100% and have a wonderful day! -Amelia♥
Answer:
b
Explanation:
i took the test
Please select the word from the list that best fits the definition
Device that measures electric current
Answer:
ammeter
Explanation:
An ammeter is a measuring device used to measure the electric current in a circuit.
14 What is the weight of each of
the following masses on Eth?
a) 2 kg
b) 3.5kg
c) 5.25 kg
Newton’s
Explanation:
On earth,
g=10 m/s^2
When M=2 kg,
weight on earth=2×10
=20N
When M=3.5 kg,
weight on Earth=3.5×10
=35N
When M=5kg,
weight on Earth=5.25×10
=52.5N
All mutations are favorable and increase the ability for the
organism's offspring to survive.
TRUE
FALSE
10
5 points
What is the power of a small motor that can do 2500 J of work in 25 seconds?
0.01 Watts
100 Watts
1000 Watts
62500 Watts
Answer:
100 Watts
Explanation:
Energy can be defined as the ability (capacity) to do work.
Given the following data;
Energy = 2500 J
Time = 25 seconds
To find the power of the motor;
Power = energy/time
Substituting into the formula, we have;
Power = 2500/25
Power = 100 Watts
why are dams have broader walls at the bottom?
Does a battery produce electric currents?
Answer:
A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.
The distance from the center of the lens to its principal focus is called the focal length.
O A. True
O B. False
Answer:
true
Explanation:
Answer:
Explanation:
A. True
Two resistors, one with 7.00 Ω of resistance and the other with 11.00 Ω of resistance, are connected in series to a 9.00 V battery. How much power is dissipated by these two resistors?
Answer:
4.5 W
Explanation:
Applying,
P = V²/(R₁+R₂).................. Equation 1
Where P = Power, V = Voltage, R₁ and R₂ = values of the two resistor.
From the question,
Given: V = 9.00 V, R₁ = 7.00 Ω, R₂ = 11.00 Ω
Substitute these values into equation 1
P = 9²/(7+11)
P = 81/(18)
P = 4.5 Watt.
Hence the power dessipated by the two resistors is 4.5 watt
Explain why all living have genes and DNA but not all living things look the same. (Discuss, paragraph answers)
Answer:
All living organisms store genetic information using the same molecules DNA and RNA. Genes are maintained over an organism's evolution, however, genes can also be exchanged or "stolen" from other organisms.
1. What are the two main gases responsible for lowering down the pH.
2. Can we control an acid rain? Why or Why not?
3. When pH changes from 6 to 3, how many times does acidity increase?
Answer:
1. The three main acidic gases responsible for lowering the pH of rainwater are non-metal oxides produced by the burning of fossil fuels like coal, oil and natural gas. Sulfur dioxide is produced when fossil fuels containing sulfur impurities are burned.
2. A great way to reduce acid rain is to produce energy without using fossil fuels. Instead, people can use renewable energy sources, such as solar and wind power. Renewable energy sources help reduce acid rain because they produce much less pollution.
3. The pH scale is logarithmic, meaning that an increase or decrease of an integer value changes the concentration by a tenfold. For example, a pH of 3 is ten times more acidic than a pH of 4.
wait how does this work hehe this is kinda fun lol yay
Which best illustrates how the carrier wave would appear after pulse modulation?
Answer is the second one
After extensive, detailed calculation, contemplation, investigation, and consideration, my tentative guess is that the second choice is the correct one.
Two vehicles A and B accelerate uniformly from rest.
Vehicle A attains a maximum velocity of 30ms - in los
while B attains a maximum velocil) ol 40ms in the same
time. Both vehicles maintain these velocities for 6s belore
they are decelerated to rest in 6s and 4s respectively
Sketch on the same axes, velocity time graphs
for the motion of the vehicles
Calculate the velocity of each vehicle 18s aftur
the start. (VA
= 20ms -land vs
and vs = 20ms-')
How far will the two vehicles be from one
another during the moment in (ii) above?
(SA = 380m and SB
= 500m: SAB
120m). plz help
Answer:
(i) Please find attached the required velocity time graphs plotted with MS Excel
(ii) The velocity of vehicle A at the 18th second = 20 m/s
The velocity of vehicle B at the 18th second = 0 m/s
(iii) The distance between the two vehicles at the moment in (ii) above is 60 meters
Explanation:
The given parameters of the motion of vehicles A and B are;
The acceleration of vehicles A and B = Uniform acceleration starting from rest
The maximum velocity attained by vehicle A = 30 m/s
The time it takes vehicle A to attain maximum velocity = 10 s
The maximum velocity attained by vehicle B = 30 m/s
The time it takes vehicle B to attain maximum velocity = The time it takes vehicle A to attain maximum velocity = 10 s
The time duration vehicle A maintains its maximum velocity = 6 s
The time duration vehicle B maintains its maximum velocity = 4 s
(i) From the question, we get the following table;
[tex]\begin{array}{ccc}Time &V_A&V_B\\0&0&0\\10&30&40\\14&30&40\\16&30&20\\18&20&0\\22&0&\end{array}[/tex]
From the above table the velocity time graphs of vehicles A and B is created with MS Excel and can included here
(ii) The velocity of vehicle A at the start = 0 m/s
After accelerating for 10 seconds, the velocity of vehicle A = The maximum velocity of vehicle A = 30 m/s
The maximum velocity is maintained for 6 seconds which gives;
At 10 s + 6 s = 16 s, the velocity of vehicle A = 30 m/s
The time it takes vehicle A to decelerate to rest = 6 s
The deceleration of vehicle A, [tex]a_A[/tex] = (30 m/s - 0 m/s)/(6 s) = 5 m/s²
Therefore, we get;
v = u - [tex]a_A[/tex]·t
At the 18th second, the deceleration time, t = 18 s - 16 s = 2 s
u = 30 m/s
∴ v₁₈ = 30 - 5 × 2 = 20
The velocity of vehicle A at the 18th second, [tex]V_{18A}[/tex] = 20 m/s
For vehicle B, we have;
At the 14th second, the velocity of vehicle B = 40 m/s
Vehicle B decelerates to rest in, t = 4 s
The deceleration of vehicle B, [tex]a_B[/tex] = (40 m/s - 0 m/s)/(4 s) = 10 m/s²
For vehicle B, at the 18th second, t = 18 s - 14 s = 4 s
∴ [tex]v_{18B}[/tex] = 40 m/s - 10 m/s² × 4 s = 0 m/s
The velocity of the vehicle B at 18th second, [tex]v_{18B}[/tex] = 0 m/s
(iii) The distance covered by vehicle A up to the 18th second is given by the area under the velocity-time graph as follows;
The area triangle A₁ = (1/2) × 10 × 30 = 150
Area of rectangle, A₂ = 6 × 30 = 180
Area of trapezoid, A₃ = (1/2) × (30 + 20) × 2 = 50
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = A₁ + A₂ + A₃
∴ [tex]S_A[/tex] = 150 + 180 + 50 = 380
The distance covered in the 18th second by vehicle [tex]S_A[/tex] = 380 m
The distance covered by the vehicle B in the 18th second is given by the area under the velocity time graph of vehicle B as follows;
Area of trapezoid, A₅ = (1/2) × (18 + 4) × 40 = 440
The distance covered by the trapezoid, [tex]S_B[/tex] = 440 m
The distance of the two vehicles apart at the 18t second, [tex]S_{AB}[/tex] = [tex]S_B[/tex] - [tex]S_A[/tex]
∴ [tex]S_{AB}[/tex] = 440 m - 380 m = 60 m
The distance of the two vehicles from one another at the 18th second, [tex]S_{AB}[/tex] = 60 m.
A wave is moving at the rate of 40 cm/s. Its wavelength is 5 cm. What is the frequency of the wave? INCLUDE THE CORRECT UNIT!
Answer:
Solution given:
velocity=40cm/s
wave length=5cm
we have
frequency =velocity/wavelength=40/5=8hertz.
the frequency of the wave is 8 hertz.
what does it mean to "conserve money" or to "conserve resources"
Answer:
Conserve money means to save money. Conserve resources means the same thing but with resources; so conserve resources means to save resources.
Explanation:
Pravat exerts a force of 30 N to lift a bag of groceries 0.5 m. How much work did Pravat do on the bag?
Answer:
15 J
Explanation:
Work = Force x Distance
15= 30 x 0.5
Have a blessed day!
Answer:Pravat did 15 J of work
Explanation:
In the diagram, R1 = 40.0 ohm, R2 = 25.4 ohm, and R3 = 70.8 ohm. What is the equivalent resistance of the group?
The resistors [tex]R_1 and R_2 [/tex]are in series connection, so the equivalent resistance of [tex]R_1 and R_2[/tex] will be their sum.
[tex] \boxed{ \mathrm{R_t = R_1 + R_2}}[/tex]
[tex]R_t= 40 + 25.4[/tex][tex]R_t= 65.4 \: \: ohms[/tex]Now, the equivalent resistance of [tex](R_1 and R_2)[/tex] and [tex]R_3 [/tex] is the total resistance of the circuit, and since they are in parallel connection, Total resistance :
[tex] \mathrm{ \dfrac{1}{ R_{eq}}} = \dfrac{1}{65.4} + \dfrac{1}{70.8} [/tex][tex] \dfrac{1}{R_{eq}} = \dfrac{65.4 + 70.8}{4630.32} [/tex][tex] \frac{1}{R_{eq}} = \dfrac{136.2}{4630.32} [/tex][tex]R_{eq} = \dfrac{4630.32}{136.2} [/tex][tex]R_{eq} = 33.996 \: \: ohms[/tex][tex] \boxed{ \mathrm{R_{eq} = 34 \: ohms}} \: (approx)[/tex]_____________________________
[tex]\mathrm{ \#TeeNForeveR}[/tex]
Where is an object's center of gravity?
The center of gravity (CG) location is the average location of all the weights of an object. The center of gravity is the balance point of an object, also expressed as the point where all the mass appears to be located.
The location of the body's center of gravity is where its mass is concentrated. The human body's center of gravity is a fictitious position where the gravitational force is claimed to appear to act (COG). It is where the body's overall bulk seems to be concentrated.
What is an object's center of gravity?The center of gravity of an object is the point at which its weight is most evenly distributed. Any object's travel through space may be completely explained in terms of how its center of gravity moves from one location to another and, if it is free to spin, how it rotates around that center of gravity.
Therefore, In physics, the center of gravity is a hypothetical location within a solid where, for the sake of convenience in some computations, the body's whole weight may be assumed to be concentrated.
Learn more about center of gravity here:
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