A 500 kg car starts with a force of 1000 N

1) Calculate the acceleration with which the car starts.
2) Determine the speed of the car 15 seconds after starting if we know what part of the rest

Answer:

Sphere is a geometrical object in dimensional space  that surface of a circle and ball.

Explanation:

Sphere is that the circular objects in the two dimensional space (1) circle

(2) disk. Two dimensional space is a set of points and the distance of that point,The two points of Sphere that length and center.

Sphere can constructed as the named of surface form circle about  any diameter. circle is the special type of the revolution replacing the circle,

sphere is the distance r is the radius of the ball and circle  is the center of mathematical ball,as the center and the radius of the sphere is to respectively.

The ball and sphere has not be maintained mathematical references  as a solid references. A sphere of any radius is centered at the number of zero.

Answer:

Explanation:

T = 8 s

angular frequency ω = 2π / T

= 2 π / 8

= π / 4

x ( t ) = A ( sinωt + π / 2 ) because initial phase difference is π / 2

= A cos ωt

= A cos π t / 4  

v = Aω sinωt

= 2 x π / 4 sinωt

= .5 π sinπt / 4

when t = 2

v = .5 π sinπ x 2 / 4

= .5 π x 1

= 1.57  cm /s

At t = 3 s

v = .5 π sin π x 3 / 4

= .5 π sin 135°

= .5 π / √ 2

= 1.11 cm /s

Answer:

3.5 kg

Explanation:

use the equation; (m1v1i) + (m2v2i) = (m1v1f) + (m2v2f)

= m1(0) - m1v1f = m2v2f - m2(0)

= (-2.0)(15)/-20

= 1.5 kg

then add the other piece (2.0kg)

1.5 + 2.0 = 3.5 kg

The mass of firework before explosion is 3.50kg.

mass flying to right  m1 = 2kg

                                v1  = 15 m/s

mass flying to left m2  = ?

                                v2 = - 20m/s

 initial velocity u = 0

by conservation of linear momentum

m1v1+ m2v2 = (m1+m2 ) u

2x 15- m2x 20 = 0

                 m2 = 1.50kg

therefore mass of firework before explosion

                   m1+m2

                     2+ 1.50

                  = 3.50kg

Mass is the amount of matter in a physical body. It  also measures the body's inertia, the resistance to acceleration when a net force is applied. The mass of an object also determines  its gravitational force on other objects. The basic SI  unit of mass is the kilogram.

Body mass is always constant. One way to calculate mass:

mass = volume × density. Weight is a measure of the gravitational force acting on a mass. The SI unit of mass is the "kilogram".

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Answer:

Explanation:

Given,

Force ( f ) = 30 N

Acceleration(a) = 7.6 m/s

Now, Let's find the mass of the ball

Using the Newton's second law of motion:

We get:

[tex]force \: = mass \: \times acceleration[/tex]

plug the value

[tex]30 \: = m \: \times 7.6[/tex]

Use the commutative property to reorder the terms

[tex] 30 = 7.6 \: m[/tex]

Swap the sides of the equation

[tex]7.6m = 30[/tex]

Divide both sides of the equation by 7.6

[tex] \frac{7.6 \: m}{7.6} = \frac{30}{7.6} [/tex]

Calculate

[tex]m = 3.94 \: kg[/tex]

Hope this helps..

Best regards!!

Answer:

[tex]\displaystyle \boxed{\mathrm{3.95 \: kg }}[/tex]

Explanation:

[tex]\mathrm{force \: (N) = mass \: (kg) \times acceleration \: (m/s^2)}[/tex]

[tex]\mathrm{force = 30N}[/tex]

[tex]\mathrm{acceleration = 7.6 \: m/s^2 }[/tex]

[tex]\mathrm{Find \: the \: mass.}[/tex]

[tex]\mathrm{30 = m \times 7.6}[/tex]

[tex]\displaystyle \mathrm{m =\frac{30}{7.6} }[/tex]

[tex]\displaystyle \mathrm{m = 3.947... }[/tex]

Answer:

8996kg*m/s/s

Explanation:

Given:

a=26m/s/s

m=346kg

Required:

f=?

Formula:

f=m*a

Solution:

f=346kg*26m/s/s

f=8996kg*m/s/s

Hope this helps ;) ❤❤❤

Answer:

[tex]\boxed{F = 8996 \ Newton}[/tex]

Explanation:

Given:

Mass = m = 346 kg

Acceleration = a = 26 m/s²

Required:

Force = F = ?

Formula:

F = ma

Solution:

F = 346 * 26

F = 8996 Newton

Answer:

A. 119kg

B.0.53m from head

Explanation:

A. Weight = 730+340.

=1170N

F= Wg

W = 1170/9.8

= 119kg

If x is distance from head to CG then 1.92–x is the other distance.

Moments must equal

470x = 330(1.89–x)

470x = 623.7 – 330x

1170x = 623.7

x = 0.53m from head

Answer:

Ammonia, [tex](NH_{3})[/tex]

Explanation:

If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.

In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia ([tex]NH_{3}[\tex]) compound.

In chemistry, the Vanadyl Phthalocyanine (VopC) comprises of a catalytic domain that activates host cells GTPase Rac irreversibly, through the deamide side chain of the residue existing at position 61.

Also, we know that a deamidation reaction gives off Ammonia, [tex](NH_{3})[/tex] and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.

Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase).

Answer:

Because ocean tides are the effect of ocean water responding to a gravitational gradient, the moon plays a larger role in creating tides than does the sun. But the sun's gravitational gradient across the earth is significant and it does contribute to tides as well.

i hope this help i

i try to explain and like i sayed i hope this help u.

Answer:

the moon

Explanation:

ive passed the grade you learned this in

Answer:

20 m

Explanation:

Given:

v = 0 m/s

a = -10 m/s²

t = 4 s / 2 = 2 s

Find: Δy

Δy = vt − ½ at²

Δy = (0 m/s) (2 s) − ½ (-10 m/s²) (2 s)²

Δy = 20 m

Answer:

The acceleration of the object is 4 m/s².

Explanation:

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass i.e.

[tex]a=\dfrac{k}{m}[/tex] ...(1)

Let us assume that the question is a certain force acting upon an object with mass 2 kg produces an acceleration of 38 m/s². if the same force acts upon another object whose mass is 19 kg, what would this object's acceleration be

Equation (1) can be written as :

[tex]\dfrac{a_1}{a_2}=\dfrac{m_2}{m_1}[/tex]

Here,

a₁ = 38 m/s², a₂ =?, m₁ = 2 kg, m₂ = 19 kg

So,

[tex]\dfrac{38}{a_2}=\dfrac{19}{2}\\\\a_2=4\ m/s^2[/tex]

So, the acceleration of the object is 4 m/s².

Answer:

The total frictional force equals 60 N

Explanation:

We know that F - f = ma where F is the applied force, f is the frictional force, m the mass of the object and a its acceleration.

Now, since the cart moves with constant velocity, its acceleration is zero. So, a = 0.

So F - f = ma

F - f = m(0) = 0

F - f = 0

So, F = f

From the above, we see that the frictional force equals the applied force which is equal to 60 N.

So, f the total frictional force equals 60 N

ANSWER

C 11.5 m/s

EXPLANATION

Answer:

11.5m/s south

Explanation:

Online classes

Answer:

a)4500V

b)750V

Explanation:

Given:

Distance between the plate=

6.00 cm

We need to convert to m

Then the Distance between the plate=

0.06m

electric field strength between two parallel plates =

7.50 × 104 V/m .

Then E= 7.50 × 104 V/m .

(a) What is the potential difference between the plates?

potential difference between the plates can be calculated using the formula below

Δ Vab=ED

Where E is the given electric field strength

D= The Distance between the plate

ΔVab=7.50 × 10⁴V/m ×

0.06m

= 4500V

(b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?

the potential 1cm from the zero volt plate

Then the 1cm must be converted to m

= 0.01m

Let us say plate A as the plate at 0 volts:

The potential increases linearly going from plate A (0 V) to plate B (4500V).

Therefore,if the potential difference between A and B, separated by 6 cm, is 4500 V, then the potential difference between A and a point located at 1 cm from A is can be calculated also

If the plate with Lowest potential is taken to be zero then

=ΔVab=Vab-Vb=Va-0=Va=ED

Va=7.50 × 10⁴V/m × 0.01=750V

Answer:

Hydrogen used in fuel cells has the energy to weight ratio ten times greater than lithium-ion batteries. Consequently, it offers much greater range while being lighter and occupying smaller volumes. It can also be recharged in a few minutes, similarly to gasoline vehicles.

Answer:

a) tangent ; b) 153.88 yds ; c) No , less than or equal to 45° ; D) 45°

Explanation:

Given the following ;

From the triangle sketch :

Base length = 50 yards

Angle of elevation = 72°

a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line?

Using trigonometry :

The height of the blimp will be calculated using :

Tangent :

Tan θ = opposite / Adjacent

B.) How high above the ground is the blimp?

Using :

Tan θ = opposite / Adjacent

Θ = 72° ; adjacent = 52, opposite = height(h)

Tan 72° = h / 50

h = 3.0776835 * 50

h = 153.88 yds

C.) In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement?

1 yard = 3 Feets

153.88 yards = 3 * 153.88

= 461.65 feets

No, because the height of the blimp is 461.65 Feets which is greater than 150 Feets.

To make viewing possible, the angle of elevation should be:

50 yards is equivalent to (3 * 50) = 150 feets

Max imum Height of blimp = 150 Feets

From pythagoras ;

Tanθ = 150 Feets / 150 Feets

Tanθ = 1

θ = tan^-1(1)

θ = 45°

To make viewing advertisement possible, angle of elevation should not exceed 45°

d.)If height of blimp is 150 Feets, then the exact angle of elevation will be 45°

Answer:

tension is how much force is being exerted on each end of the string, whereas length is how long the string is. So assuming that the string has finite mass, then the tension on the string should increase proportionally to the string according to Newton's law f=ma.

Explanation:

Answer:

particles

Explanation:

Answer: 43.2 J

Explanation:

Work = change in KE

initial KE = 0

final KE = 1/2mv^2 = 1/2(0.370 kg)(15.2778 m/s)^2 = 43.2 J

i'm not sure about sig figs though

Answer:

        v = √k/m    x

Explanation:

We can solve this exercise using the energy conservation relationships

starting point. Fully compressed spring

        Em₀ = [tex]K_{e}[/tex] = ½ k x²

final point. Cart after leaving the spring

        [tex]Em_{f}[/tex] = K = ½ m v²

        Em₀ = Em_{f}

        ½ k x² = ½ m v²

        v = √k/m    x

Answer:

Package's vertical displacement(s) = 22.12 meter

Explanation:

Given:

Speed of plane = 120 m/s

Total distance = 255 m

Find:

Package's vertical displacement(s)

Computation:

Time taken = Distance / Speed

Time taken = Total distance / Speed of plane

Time taken = 255 / 120

Time taken = 2.125 s

Acceleration due to gravity(g) = 9.8 m/s²

Initial velocity (u) = 0

So,

Package's vertical displacement(s) = ut + (1/2)gt²

Package's vertical displacement(s) = (0)(2.125) + (1/2)(9.8)(2.125)²

Package's vertical displacement(s) = 22.12 meter

Answer: -22.1

Explanation:

I just did the Khan Academy and that was the answer, not the one provided by that one person. :)))

Answer:

Explanation:

For entropy change the formula is

ΔS = ΔQ / T

ΔQ = Δ H

ΔS = Δ H / T

Given

Δ H = + 162.8 kJ

We can take equilibrium temperature as average temperature of the whole process

So, T = 273 + 87 = 360 K

ΔS = Δ H / T

=  162.8 kJ  / 360

= +  0.508 kJ / K .

When the magnitude of the heat transfer for the process is 162.8 kJ, Then the entropy change for the mixing process, in kJ/K is = + 0.508 kJ / K

For The entropy change, the formula is

Then ΔS = ΔQ / T

After that ΔQ = Δ H

Then ΔS = Δ H / T

Given as per question are:

Then Δ H = + 162.8 kJ

Now We can take equilibrium temperature as average temperature of the whole process are:

So, T is = 273 + 87 = 360 K

Then ΔS = Δ H / T

After that = 162.8 kJ / 360

Therefore, = + 0.508 kJ / K.

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A negaive ion has more electrons bound to it than protons in its nucleus.

I would suggest an easier route. So for example, I would research light energy, where it comes from, and what causes it. I won't be able to do the work for you though.

Answer:

560 N/m

Explanation:

F = kx

75 N = k (0.61 m − L)

210 N = k (0.85 m − L)

Divide the equations:

2.8 = (0.85 − L) / (0.61 − L)

2.8 (0.61 − L) = 0.85 − L

1.708 − 2.8L = 0.85 − L

0.858 = 1.8L

L = 0.477

Plug into either equation and find k.

75 = k (0.61 − 0.477)

k = 562.5

Rounded to two significant figures, k = 560 N/m.

Answer:

False

Explanation:

Total internal reflection is a condition that occurs when light travels from dense medium to less dense medium.

From the table given in the question above,

Refractive Index of Whale oil = 1.460

Refractive Index of vacuum = 1

From the above, we can see that the whale oil has a higher Refractive Index than vacuum. This implies that the whale oil is denser than the vacuum.

Therefore, total internal reflection will occur when light travels from whale oil to vacuum because the whale oil is denser than the vacuum.

Answer:

D. Displacement

Explanation:

got it right on edge

Average velocity is different than average speed because calculating average velocity involves Displacement, therefore the correct option is option D.

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.  It can also be represented by the infinitesimal rate of change of displacement with respect to time. The unit of velocity is meter/second.

The mathematical expression for velocity is given by

velocity= displacement  / time taken

In the displacement time graph the slope of the curve represent the velocity of the object ,the rate of change of velocity is known as the acceleration of the object .

In the velocity time graph the slope of the curve represent the acceleration of the body, The unit of acceleration is metre per second Square

The total distance traveled by an object is different than the total displacement covered by it because the displacement is a vector quantity and it is calculated on the basis of the shortest distance traveled by the body or object.

The main difference between the distance and the displacement is that displacement can be positive or negative or zero but distance can never be negative.

Let’s understand understand with example of average velocity ,suppose an object is moving with 200 m displacement covered in a time of 15 seconds then the average velocity of the object is 13.33 m/s.

Thus, average velocity is different than average speed because calculating average velocity involves Displacement, therefore the correct option is option D.

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Answer:

The amount of charge increases.

Explanation:

For a capacitor that has its plates still connected to a battery, the voltage on the capacitor remains constant. If the distance between the two plates of this capacitor is decreased, the capacitance will increase, and then the charge on the plate will increase in accordance with the relationship

Q =CV

From this relationship, if V is held constant, then Q has to increase for C to increase also.

Answer:

[tex]\boxed{\mathrm{Density = 1.1 \ g/cm^3}}[/tex]

Explanation:

Volume of fresh water:

Volume = Mass / Density

Volume = 1600/1

[tex]V_{1}[/tex] = 1600 cm³

Volume of sea water:

Volume = Mass / Density

Volume = 1200/1.2

Volume = 1000 cm³

So,

Total Volume when they are mixed = 1600+1000

Total Volume when they are mixed = 2600 cm³

And,

Total Mass when they are mixed = 1600+1200

Total Mass when they are mixed = 2800 g

Now, Measuring the density of the mixture:

Density = Mass / Volume

Density = 2800/2600

Density = 1.1 g/cm³

Answer:

[tex]\mathrm{1.086 \: g/cm^3 }[/tex]

Explanation:

Volume of fresh water ⇒ 1600 cm³

Density of fresh water ⇒ 1 g/cm³

Volume of sea water ⇒ 1200 cm³

Density of sea water ⇒ 1.2 g/cm³

[tex]density=\frac{mass}{volume}[/tex]

[tex]mass=density \times volume[/tex]

Calculate mass of fresh water.

[tex]m=1600 \times 1[/tex]

[tex]m=1600 \: g[/tex]

Calculate the mass of sea water.

[tex]m=1200 \times 1.2[/tex]

[tex]m=1440 \: g[/tex]

Find the density of the mixture.

[tex]density=\frac{mass}{volume}[/tex]

[tex]\rho = \frac{1600+1440}{1600 + 1200}[/tex]

[tex]\rho = \frac{3040}{2800}[/tex]

[tex]\rho= 1.0857...[/tex]

Answer: A. The forces on an object in motion are balanced.

Explanation:

The dynamic equilibrium is defined as the phase when an object moves at a constant velocity such that all forces on the object are balanced.

Simple case of dynamic equilibrium: A horizontal force is applied to an object making it run with a constant velocity across a surface.

Hence, the statement describes dynamic equilibrium is " The forces on an object in motion are balanced. "

So, the correct option is "A".

Answer:

Hope this helps!

Answer:

The distance of the goggle from the edge of the pool is 4.726 m

Explanation:

The given information are;

The depth of the swimming pool = 3.0 m deep

The height of the laser pointer above the swimming pool edge = 1.0 m

The distance from the pool edge the laser  pointer enters the water  = 2.0 m

The angle between the pool and the laser = ∅ = tan⁻¹(1/2) = 26.57°

Therefore, the angle of incidence to the vertical [tex]\theta_i[/tex],  = θ - ∅ = 90 - 26.57° = 63.43°

By Snell's law we have;

The ratio of the sin of the angle of incidence to the sin of the angle of refraction is a a constant equal to the ratio of the refractive indices as follows;

[tex]\dfrac{sin (\theta_i)}{sin (\theta_r} =\dfrac{n_r}{n_i}[/tex]

Where:

[tex]n_r[/tex] = Refractive index of the refractive medium which is water = 1.33

[tex]n_i[/tex] = Refractive index of the incidence medium which is air = 1.00

Therefore;

[tex]\theta_r = sin^{-1} \left (\dfrac{n_i \times sin (\theta_i)}{n_r} \right) = sin^{-1} \left (\dfrac{1\times sin (63.43)}{1.33} \right) = 42.26 ^{\circ}[/tex]

We have that tan([tex]\theta_r[/tex]) = (Distance of the goggles from the point directly above the point of incidence of the beam)/(The water depth)

tan(42.26) = (The horizontal distance of the goggles from the point of incidence of the laser on the water surface)/(3.0)

∴ The horizontal distance of the goggles from the point of incidence of the laser on the water surface = 3.0 × tan(42.26) = 2.726 m

The distance of the goggle from the edge of the pool = The horizontal distance of the goggles from the point of incidence of the laser on the water surface + The distance from the edge of the water surface the laser enters the water

The distance of the goggle from the edge of the pool = 2.726 + 2 = 4.726 m

The distance of the goggle from the edge of the pool = 4.726 m.