Answer:
the maximum vertical height the person in the cart can reach is 18.42 m
Explanation:
Given;
mass of the person, m₁ = 45 kg
mass of the cart, m₂ = 43 kg
velocity of the system, v = 19 m/s
let the maximum vertical height reached = h
Apply the principle of conservation mechanical energy;
[tex]P.E = K.E\\\\mgh_{max} = \frac{1}{2} mv^2_{max}\\\\gh_{max} = \frac{1}{2} v^2_{max}\\\\h_{max} = \frac{v_{max}^2}{2g} \\\\h_{max} = \frac{19^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m[/tex]
Therefore, the maximum vertical height the person in the cart can reach is 18.42 m
A horizontal force of 40N is needed to pull a 60kg box across the horizontal floor at which coefficient of friction between floor and box? Determine it to three significant figures even through that's quite unrealistic. How much work is done in overcoming friction between the object and floor if the box slides 8m along horizontally on the floor?
Answer:
Coefficient of friction is [tex]0.068[/tex].
Work done is [tex]320~J[/tex].
Explanation:
Given:
Mass of the box ([tex]m[/tex]): [tex]60[/tex] kg
Force needed ([tex]F[/tex]): [tex]40[/tex] N
The formula to calculate the coefficient of friction between the floor and the box is given by
[tex]F=\mu mg...................(1)[/tex]
Here, [tex]\mu[/tex] is the coefficient of friction and [tex]g[/tex] is the acceleration due to gravity.
Substitute [tex]40[/tex] N for [tex]F[/tex], [tex]60[/tex] kg for [tex]m[/tex] and [tex]9.80[/tex] m/s² for [tex]g[/tex] into equation (1) and solve to calculate the value of the coefficient of friction.
[tex]40 N=\mu\times60 kg\times9.80 m/s^{2} \\~~~~~\mu=\frac{40 N}{60 kg\times9.80 m/s^{2}}\\~~~~~~~=0.068[/tex]
The formula to calculate the work done in overcoming the friction is given by
[tex]W=Fd..........................(2)[/tex]
Here, [tex]W[/tex] is the work done and [tex]d[/tex] is the distance travelled.
Substitute [tex]40[/tex] N for [tex]F[/tex] and [tex]8 m[/tex] for [tex]d[/tex] into equation (2) to calculate the work done.
[tex]W=40~N\times8~m\\~~~~= 320~J[/tex]
A car pulled by a tow truck has an acceleration of 2.0 m/s^2. What is the mass of the car if the net force on the car is 3,500 N?
Answer:
ans: 1750 kg
Explanation:
F = ma
so ,
m = F/a
= 3500 / 2
= 1750 kg
State the relation between acceleration and momentum
Answer:
Acceleration is the rate of change in velocity. Momentum is the mass times the velocity. So if you multiply the mass times the acceleration, you get the of change of momentum.
In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves with a constant acceleration. The following data are collected for the cart.
t(s) x(m)
0 0
1 4
2 16
3 36
4 64
The acceleration of the cart is most nearly:_____
Given :
Initial velocity , u = 0 m/s² .
To Find :
The acceleration of the cart.
Solution :
Since, acceleration is constant.
Using equation of motion :
[tex]x = ut + \dfrac{at^2}{2}\\\\x = \dfrac{at^2}{2}[/tex]
Putting, t = 1 s and x = 4 m in above equation, we get :
[tex]4 = \dfrac{a(1)^2}{2}\\\\a = 8 \ m/s^2[/tex]
Therefore, the acceleration of the cart is 8 m/s².
PLEASE HELP ME WITH THIS ONE QUESTION
What is the rest energy of a proton? (c = 2.9979 x 10^9 m/s, mp = 1.6726 x 10^-27)
Answer:
Energy = 1.5032*10^(-10) Joules
Explanation:
By Einstein's relativistic energy equation, we know that the energy of a given particle is given by:
Energy = rest energy + kinetic energy.
= m*c^2 + (γ - 1)*mc^2
Where γ depends on the velocity of the particle.
But if the proton is at rest, then the kinetic energy is zero, and γ = 1
Then the energy is just given by:
Energy = m*c^2
Where we know that:
mass of a proton = 1.67*10^(-27) kg
speed of light = c = 2.9979*10^(8) m/s
Replacing these in the energy equation, we get:
Energy = ( 1.6726*10^(-27) kg)*( 2.9979*10^(8) m/s)^2
Energy = 1.5032*10^(-10) kg*m^2/s^2
Energy = 1.5032*10^(-10) J
A basketball player shoots toward a basket 4.9 m away and 3.0 m above the floor. If the ball is released 1.8 m above the floor at an angle of 60 o above the horizontal, what must the initial speed be if it were to go through the basket
Answer:
v₀ = 6.64 m / s
Explanation:
This is a projectile throwing exercise
x = v₀ₓ t
y = y₀ + v_{oy} t - ½ g t²
In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m
the time to reach the basket is
t = x / v₀ₓ
we substitute
y- y₀ = [tex]\frac{ v_o \ x \ sin \theta }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }[/tex]
y - y₀ = x tan θ - [tex]\frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }[/tex]
we substitute the values
3 -1.8 = 3.0 tan 60 - [tex]\frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}[/tex]
1.2 = 5.196 - 176.4 1 / v₀²
176.4 1 / v₀² = 3.996
v₀ = [tex]\sqrt{ \frac{ 176.4}{3.996} }[/tex]
v₀ = 6.64 m / s
Appliances A, B, and C consume 250, 480 and 1450 watts of power, respectively. The system voltage is 120V, and the circuit breaker is rated at 15 amps. Which combinations of the three appliances can be on at the same time, and which combinations will trip the circuit breaker
Answer:
Appliance A and B can work together without tripping
Explanation:
We will calculate the amount of current consumed by each appliances.
Appliance A
P = VI
I = P/V
I = 250/120 = 2.08 A
Appliance B
I = 480 /120 = 4 A
Appliance C
I = 1450/120
I = 12.08 A
Hence, appliance C will trip the circuit as it consumes a lot of electricity.
In the series circuit, if the potential difference across the battery is 20 V and the potential difference across R1 is 12 V, what is the potential difference across R2
Answer:
The correct answer is "8 V".
Explanation:
Given:
Potential difference across battery,
= 20 V
Potential difference across R1,
= 12 V
Now,
On applying the Kirchorff loop, we get
⇒ [tex]E-I_1R_1-I_2R_2=0[/tex]
⇒ [tex]E-V_1-V_2=0[/tex]
⇒ [tex]V_2=E-V_1[/tex]
On putting values, we get
⇒ [tex]=20-12[/tex]
⇒ [tex]= 8 \ V[/tex]
The potential difference across the resistance R2 will be "8 Volts.
What is Kirchoff;s law?According to the kirchoff's law in a loop of a circuit when there are number of the resistances so the sum of all the potential differences will be zero.
It is given that:
Potential difference across battery,= 20 V
Potential difference across R1,= 12 V
Now,
On applying the Kirchorff loop, we get
⇒ [tex]\rm E-I_1R_1-I_2R_2=0[/tex]
⇒ [tex]\rm E-V_1-V_2=0[/tex]
⇒ [tex]\rm V_2=E-V_1[/tex]
On putting values, we get
⇒ [tex]V_2=20-12=8\ volt[/tex]
Hence the potential difference across the resistance R2 will be "8 Volts.
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The area around a magnet containing all of magnetic Lines of force is called
Answer:
Magnetic Field
Explanation:
The area around a magnet containing all of magnetic Lines of force is called the magnetic field.
What is the magnitude of the current in the R= 6 Ω resistor?
kirchhoff
Answer:
Here's an explanation but not the answer
Explanation:
When a resistor is traversed in the same direction as the current, the ... Traversing the internal resistance r1 from c to d gives −I2r1. ... I1 = I2 + I3 = (6−2I1) + (22.5− 3I1) = 28.5 − 5I1.
motto that will help in reaching a goal in life that related the projectile motion
Explanation:
hmm! very good questions I hope u understand
Question 24 of 33 Which of the following is an example of uniform circular motion? A. A car speeding up as it goes around a curve O B. A car slowing down as it goes around a curve 2 C. A car maintaining constant speed as it goes around a curve D. A car traveling along a straight road
Answer:
Uniform Circular Motion is the Movement or Rotation of an Object along a circular Path at constant speed.
OPTION C IS YOUR ANSWER!.
The work function of titanium metal is 6.93 x 10-19 J. Calculate the kinetic energy of the ejected electrons if light of frequency 2.50 X 1015 s-1 is used to irradiate the metal.
Answer:
g m t o k liye cbbhhhf to be be free and ear is not a short time to be a short of a week and I am a short kat key and ear to be free and ear is not a short time and ear buds and duster for a short of a week of the action is not by the action is not a short time to make sure to be free and duster and not by the way to
Explanation:
ahhhhhhh to be be free and ear is nothing to be be free and ear is not a short time to be be free and ear is not by the class is not a a short time to be be free and
It is 2058 and you are taking your grandchildren to Mars. At an elevation of 34.7 km above the surface of Mars, your spacecraft is dropping vertically at a speed of 293 m/s. The spacecraft is to make a soft landing -- that is, at the instant it reaches the surface of Mars, its velocity is zero. Assume the spacecraft undergoes constant acceleration from the elevation of 34.7 km until it reaches the surface of Mars. What is the magnitude of the acceleration
Answer: [tex]1.23\ m/s^2[/tex]
Explanation:
Given
At an elevation of [tex]y=34.7\ km[/tex], spacecraft is dropping vertically at a speed of [tex]u=293\ m/s[/tex]
Final velocity of the spacecraft is [tex]v=0[/tex]
using equation of motion i.e. [tex]v^2-u^2=2as[/tex]
Insert the values
[tex]\Rightarrow 0-(293)^2=2\times a\times (34.7\times 10^3)\\\\\Rightarrow a=-\dfrac{293^2}{2\times 34.7\times 10^3}\\\\\Rightarrow a=-1.23\ m/s^2[/tex]
Therefore, magnitude of acceleration is [tex]1.23\ m/s^2[/tex].
A 1350 kg automobile has a kinetic energy 3.24 x 106 J. What is the velocity of the car?
Answer:
219 m/s
Explanation:
Kinetic energy is calculated using the formula:
KE = 1/2mv²Given:
m = 1350 kg KE = 3.24 · 10⁶ JWe can solve for the unknown variable v.
Substitute these known values into the formula.
3.24 · 10⁶ = 1/2(1350)v² 3.24 · 10⁶ = 675v² (3.24 · 10⁶) / 675 = v² v² = 48,000v = 219.09 m/sThe velocity of the car is around 219 m/s.
A harmonic force of maximum value 25 N and frequency of 180 cycles>min acts on a machine of 25 kg mass. Design a support system for the machine (i.e., choose c, k) so that only 10% of the force applied to the machine is transmitted to the base supporting the machine.
Answer:
registrar y de h2rhrjlekeek tert2h2jwkwlwlwlwlwlwñlwk
In order to increase his gravitational potential energy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb
Answer:
Hola eres nuevo yo nací en el 2021 del 4 de junio21. The value of 'g on the surface of earth is 9.8 m/s. If mass of Jupiter is 319 times the mass of the
arth and its radius is 11 times the radius of the earth, find the value of 'g' on the surface of Jupiter.
What will be the weight of a man having mass 50 kg on the surface of Jupiter?
Vhy? Also write solve step by step
.
The answer is in the photo. Hope you are satisfied.Have a nice day ☺️
To solve this we must be knowing each and every concept related to acceleration due to gravity and its calculation. Therefore, the value of 'g' on the surface of Jupiter is 25.8m/s².
What is acceleration due to gravity?
Gravitational acceleration is indeed a vector, which implies it has a direction and a magnitude. The acceleration caused by gravity at the Earth's surface is denoted by the symbol g. It possesses a standard value of 9.80665 m/s².
Mathematically, the formula for acceleration due to gravity can be given as
g = G M /R²
G=6.674 x 10⁻¹¹ m³ kg⁻¹s⁻²
Mass of Jupiter=319×mass of earth
Radius of Jupiter=11×radius of earth
substituting all the given values in the above equation, we get
g = 6.674 x 10⁻¹¹× 319×6×10²⁴ /(11×6378 10³)²
On calculations, we get
g=25.8m/s²
Therefore, the value of 'g' on the surface of Jupiter is 25.8m/s².
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What do different forms of energy have in common?
A. They can push or pull on objects.
B. They give objects mass.
C. They can cause changes in matter.
d
D. They can cause objects to move.
Helllp meeee
An 800-kHz radio signal is detected at a point 4.5 km distant from a transmitter tower. The electric field amplitude of the signal at that point is 0.63 V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. What is the magnetic field amplitude of the signal at that point
Answer:
[tex]B_2=2.1nT[/tex]
Explanation:
From the question we are told that:
Frequency [tex]F=800kHz[/tex]
Distance [tex]d=4.5km[/tex]
Electric field amplitude [tex]B_2=0.63V/m[/tex]
Generally the equation for momentum is mathematically given by
[tex]B=\frac{E}{C}[/tex]
Therefore
[tex]B_2=\frac{0.63}{3*10^8}[/tex]
[tex]B_2=0.21*10^{-8}[/tex]
[tex]B_2=2.1nT[/tex]
WILL GIVE 50 POINTS TO CORRECT ANSWER‼️
A capacitor has 4.33 x 10-7 C of
charge on it when 3.45 V is applied.
How much energy is stored in the
capacitor?
Answer:
7.47×10¯⁷ J
Explanation:
From the question given above, the following data were obtained:
Charge (Q) = 4.33×10¯⁷ C
Potential difference (V) = 3.45 V
Energy (E) =?
The energy stored in a capacitor is given by the following equation:
E = ½QV
Where
E => is the energy.
Q => is the charge.
V => is the potential difference.
With the above formula, we can obtain the energy stored in the capacitor as follow:
Charge (Q) = 4.33×10¯⁷ C
Potential difference (V) = 3.45 V
Energy (E) =?
E = ½QV
E = ½ × 4.33×10¯⁷ × 3.45
E = 7.47×10¯⁷ J
Thud, the energy stored in the capacitor is 7.47×10¯⁷ J
Answer:
The answer would be 7.47x10^-7J
Explanation:
Put in 7.47 then -7
How much heat is absorbed by 60g of copper when it is heated from 20°C to 80°C
Answer:
I HOPE THIS IS CORRECT
Explanation:
It is heated from 20°C to 80°C. We need to find the heat absorbed. It can be given by the formula as follows : So, 1386 J of heat is absorbed.
A particle with charge 3.01 µC on the negative x axis and a second particle with charge 6.02 µC on the positive x axis are each a distance 0.0429 m from the origin. Where should a third particle with charge 9.03 µC be placed so that the magnitude of the electric field at the origin is zero?
Answer:
The third particle should be at 0.0743 m from the origin on the negative x-axis.
Explanation:
Let's assume that the third charge is on the negative x-axis. So we have:
[tex]E_{1}+E_{3}-E_{2}=0[/tex]
We know that the electric field is:
[tex]E=k\frac{q}{r^{2}}[/tex]
Where:
k is the Coulomb constant q is the charger is the distance from the charge to the pointSo, we have:
[tex]k\frac{q_{1}}{r_{1}^{2}}+k\frac{q_{3}}{r_{3}^{2}}-k\frac{q_{2}}{r_{2}^{2}}=0[/tex]
Let's solve it for r(3).
[tex]\frac{3.01}{0.0429^{2}}+\frac{9.03}{r_{3}^{2}}-\frac{6.02}{0.0429^{2}}=0[/tex]
[tex]r_{3}=0.0743\: [/tex]
Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.
I hope it helps you!
A car moves round a circular track of radius 0.3m of two revolution per/sec find its angular velocity.
Answer:
the angular velocity of the car is 12.568 rad/s.
Explanation:
Given;
radius of the circular track, r = 0.3 m
number of revolutions per second made by the car, ω = 2 rev/s
The angular velocity of the car in radian per second is calculated as;
From the given data, we convert the angular velocity in revolution per second to radian per second.
[tex]\omega = 2 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 4\pi \ rad/s = 12.568 \ rad/s[/tex]
Therefore, the angular velocity of the car is 12.568 rad/s.
Two blocks A and B with mA = 2.9 kg and mB = 0.87 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 6 N. Determine the tension in the string connecting the two blocks.
Answer:
Tension = 1.38 N
Explanation:
Given that:
Mass of block A [tex]m_A[/tex] = 2.9 kg
mass of block B [tex]m_B[/tex] = 0.87 kg
Force F = 6 N
Assume a = acceleration of the blocks.
Then:
[tex]m_A[/tex] (a) + [tex]m_B[/tex] (a) = 6
2.9a + 0.87a = 6
3.77a = 6
a = 6/3.77
a = 1.59 m/s²
Suppose T to be the tension in the string.
If we take a look at the forces acting on the first block, then:
F - T = [tex]m_A[/tex] (a)
T = F - [tex]m_A[/tex] (a)
T = 6 - 2.9(1.59)
T = 6 - 4.62
T = 1.38 N
A 50 Ω resistor in a circuit has a current flowing through it of 2.0 A. What is the power dissipated by the resistor?
A. 50 W
B. 200 W
C. 100 W
D. 25 W
Explanation:
A nichrome (ρ = 100x10-8 Ωm) wire has a diameter of 0.40 mm. ... A power line with a resistance of 2 ohms has a current of 80 A in it
1/8 Watt 50 kΩ resistor has 70 V applied.
A 50 Ω resistor in a circuit has a current flowing through it of 2.0 A then the power dissipated by the resistor is 200 Watt. Therefore the correct option is B.
What is power?The rate of doing work is known as power. The Si unit of power is the watt.
Power =work/time
The mathematical expression for the power is as follows
P = VI
where P is the power
V is the voltage
I is current passing through the circuit
The expression of power can be represented in many different forms by using the ohms law
As we know from Ohm's law that V= IR
Power = VI
by substituting V=IR in place of the voltage in power formula
P = I²R
As given in the problem a 50 Ω resistor in a circuit has a current flowing through it of 2.0 A so by substituting the values of the current and the resistance in the formula of power
P = 2²×50
= 200 Watt
Therefore the correct answer is B.
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Ples helppp meeeeee this is timedd
Answer:
50 km/h
Explanation:
From the graph, we can deduce the following parameters;
Distance = 20, 40, 60, 80, 100 km
Time = 0.5, 1.0, 1.5, 2.0 hours
To find the average velocity of the car over the first 2.00 hours.
First of all, we would determine the total distance and time.
Total distance = 20 + 40 + 60 + 80 + 100 = 300 km
Total time = 0.5 + 1.0 + 1.5 + 2.0 = 5
Average velocity = distance/time
Average velocity = 100/2
Average velocity = 50 km/h
In which direction of the wave motion do longitude waves transfer energy ?
Answer:
Hello There!!
Explanation:
The answer is O parallel.
hope this helps,have a great day!!
~Pinky~
2. Why is it necessary for rotation to occur within a
generator?
Answer:
ON
Explanation:
Locate your computer's Power button.
Press and hold that button until your computer shuts down.
Wait until you hear the computer's fans shut off, and your screen goes completely black.
Wait a few seconds before pressing and holding the power button to initiate your computer's normal startup.
a stone is thrown vertically upward with an initial velocity of 14m/sc negleting in air resistance find (a)Maximum height reached and (b)Time taken before it reached the ground
Answer:
1/2 m v^2 = m g H conservation of energy
H = (v^2 / (2 * g))^1/2 = (14^2 / 19.6)^1/2 = 10 m
H = 1/2 g t^2 time to fall 10 m
t = (2 * H / g)^1/2 = (20 / 9.8)^1/2 = 1.43 sec
Total time in air = 2 * 1.43 = 2.86
You can also use 2 a S = V0^2 since final velocity = 1.43 * 9.8 m/s = 14 m / s
and 2 a S = 2 * 9.8 * 10 = 196 m^2 / s^2 which is V0 squared