A 3kg cat falls out of a window that is 10m above the ground and lands
safely in the grass. Calculate the velocity at which the cat hit the ground.

Answer:

The diameter of the hole is 5.6164 μm

Explanation:

Given the data in the question;

wavelength λ = 633 nm = 633 × 10⁻⁹ m

L = 4.0 M

width of the central maximum D = 1.1 cm.

Now,

Y = D / 2

Y = 1.1 / 2 = 0.55 cm

So diameter of the aperture will be;

α = 1.22λ / ( Y / L )

we substitute in our values;

α = ( 1.22 × (633 × 10⁻⁹ m)) / ( 0.55 / 4.0 )

α = 0.00000077226 / 0.1375

α = 5.6164 × 10⁻⁶ m

α = ( 5.6164 × 10⁻⁶ × 10⁶ ) μm

α = 5.6164 μm

Therefore, the diameter of the hole is 5.6164 μm

Answer:

49 kg is the mass of the couch.

Explanation:

GPE = mgh

9800 = m * 10 * 20

9800 = 200m

m = (9800/20) = 49 m

Thenks and mark me brainliest :))

Answer:

60xtime x cost per unit

Explanation:

...

Answer:

the medium through which it travels

Explanation:

Answer: [tex]13.4\ m/s[/tex]

Explanation:

Given

The frequency of the source is [tex]f_o=960\ Hz[/tex]

Change in frequency is [tex]75\ Hz[/tex]

Speed of sound [tex]c=343\ m/s[/tex]

Suppose [tex]v[/tex] is the velocity of the observer

Doppler frequency is given by

[tex]f'=f_o\left(\dfrac{c\pm v_o}{c\pm v_s}\right)[/tex]

Here, the source is at rest

While approaching source, frequency is

[tex]f_1=f_o\left(\dfrac{c+v}{c}\right)\quad \ldots(i)[/tex]

While leaving, frequency is

[tex]f_2=f_o\left(\dfrac{c-v}{c}\right)\quad \ldots(ii)[/tex]

The difference in the frequency is

[tex]\Rightarrow f_1-f_2=75\\\\\Rightarrow f_o\left(\dfrac{c+v}{c}\right)-f_o\left(\dfrac{c-v}{c}\right)=75\\\\\Rightarrow f_o\left(\dfrac{2v}{c}\right)=75\\\\\Rightarrow v=\dfrac{75\times 343}{2\times 960}\\\\\Rightarrow v=13.39\approx 13.4\ m/s[/tex]

Answer:

D

Explanation:

yes. The shortest object is traveling the fastest.

No,their lengths be used to rank the objects according to their speeds. Because the length of the object is depended on the frame of reference of the observer. Option A is correct.

A frame of reference is a mathematical and physical coordinate system whose origin, direction, and scale are given by a collection of reference points.

Because the length of each item is determined by the observer's frame of reference, If an observer is stationary yet traveling at near light speed, he will feel length contraction.

Otherwise, the length of the items should not alter for everyday pace.A spectator sees four identical objects flying at almost the speed of light.

No,their lengths be used to rank the objects according to their speeds. Because the length of the object is depended on the frame of reference of the observer.

Hence,option A is correct.

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Answer:

F = 51.3°

Explanation:

The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

[tex]F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\[/tex]

where,

W = Weight of Wagon = 150 N

θ = Angle of Inclinition = 20°

Therefore,

[tex]F = (150\ N)Sin\ 20^o[/tex]

F = 51.3°

Answer:

a. 7.96 W/m² b. i. 0.205 V/m ii. 0.68 nT

Explanation:

(Part a) Calculate I, the intensity of the light incident on your book?

Intensity, I = Power, P/Area,A

I = P/A where P = 100 W and A = 4πr² where r = distance of source from book = 1 m.

So, I = P/A

= 100 W/4π(1 m)²

= 25/π W/m²

= 7.96 W/m²

(Part b) Find Eo and Bo, the amplitude of the electric and the magnetic fields of the EM waves emitted by the lamp.

i. Eo the amplitude of the electric field

Intensity, I = E²/cμ₀ where E = r.m.s value of electric field, c = speed of light = 3 × 10⁸ m/s and μ₀ = permeability of free space = 4π × 10⁻⁷ H/m

Thus, E =  √(I/cμ₀)

substituting the values of the variables into the equation, we have

E =  √(I/cμ₀)

E =  √(7.96 W/m²/[3 × 10⁸ m/s × 4π × 10⁻⁷ H/m])

E =  √(7.96 W/m²/120π H/s)

E =  √(0.0211 Ws/Hm²)

E = 0.145 V/m

Now E = E₀/√2 where E₀ = maximum value of electric field

So, E₀ = √2E

= √2 × 0.145 V/m

= 0.205 V/m

ii. Bo the amplitude of the magnetic field

Since c =  E₀/B₀ where c = speed of light = 3 × 10⁸ m/s

B₀ = E₀/c

= 0.205 V/m ÷ 3 × 10⁸ m/s

= 0.068 × 10⁻⁸ T

= 0.68 × 10⁻⁹ T

= 0.68 nT

Answer: 3.13 m

Explanation:

Given

mas of the ball is m=10 kg

The ball rolls down a vertical distance of 5 m

Spring constant of spring is [tex]k=100\ N/m[/tex]

Here, the potential energy of the ball converted into kinetic energy which in turn converts into elastic potential energy

[tex]\Rightarrow mgh=\frac{1}{2}kx^2\quad [\text{x=compression in the spring}]\\\\\Rightarrow 10\times 9.8\times 5=\frac{1}{2}\cdot 100\cdot x^2\\\Rightarrow x=\sqrt{9.8}\\\Rightarrow x=3.13\ m[/tex]

Thus, the spring compresses by 3.13 m.

Answer: 2120 N is correct

Explanation: correct answer for acellus

Answer:

Some of the copper wire needs to be exposed so that the battery can make a good electrical connection. ... You need to do this because the direction of a magnet field depends on the direction of the electric current creating it. The movement of electric charges creates a magnetic field.

Explanation:

In an electromagnet, it must the wire be connected to the battery for the magnet to work the current is flowing through into the wire once it is introduced.

The magnetic field is defined as the field the magnetic materials generate or when an electric charge moves in a field region that generates the magnetic field.

As we know, the electricity is often used to generate a magnetic field in electromagnets.

The current is flowing through into the wire once it is introduced, from either a battery or maybe another source of electricity. The looped wire is magnetized as if it were a magnetic material as a function of the magnetic field created around it.

Thus, in an electromagnet, it must the wire be connected to the battery for the magnet to work the current is flowing through into the wire once it is introduced.

Learn more about the magnetic field here:

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Answer:

0.34 m/s^2

Explanation:

force=mass × acceleration

400 =1200 × acceleration

acceleration=400/1200

=0.34 m/s^2

Answer:

Explanation:

Given that:

To Calculate:

We know that:

We have:

Finding its density:

⟶ Density = 270/360

⟶ Density = 0.75

Hence,

Answer:

an armature a permanent magnet brushes slip rings

Explanation:

Answer:

armature, permanent magnet, brushes, slip rings on edge:-)

Explanation:

Answer:

true

Explanation:

Buoyancy is an upwards force measured in Newtons is true.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Upthrust, often known as buoyancy, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth.

Buoyancy is an upwards force measured in Newtons is true.

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Answer:

a = 0.1962 m/s^2

Explanation:

The magnitude of kinetic friction exerted is given by

[tex]F_k=\mu_kN[/tex]

Where, μ_k= coefficient of kinetic friction= 0.02 and N = reaction force = mg

Where m= mass = 30 Kg and, g is acceleration due to gravity =9.81 m/s^2

F_k=0.02×30×9.81 =5.886 N

Now, since, there is no applied force this kinetic friction force will cause acceleration of the child

⇒ ma = F_k

here, a is the acceleration

⇒30a = 5.886

⇒ a = 0.1962 m/s^2

Answer:

Speed acquired (Final velocity) = 12 m/s

Distance travelled = 720 meter

Explanation:

Given:

Uniform acceleration = 0.1 m/s²

Initial velocity = 0 m/s

Time taken = 2 minutes = 2 x 60 = 120 second

Find:

(a)  Speed acquired (Final velocity)

(b) Distance travelled

Computation:

v = u + at

v = 0 + 0.1(120)

Speed acquired (Final velocity) = 12 m/s

Distance travelled = ut + (1/2)(a)(t²)

Distance travelled = (0)(120) + (1/2)(0.1)(120²)

Distance travelled = (1/2)(0.1)(14400)

Distance travelled = 720 meter

Given :

A gerbil wheel has a radius of 3.2 inches. The gerbil can spin the wheel at a rate of 35 rotations per minute.

To Find :

The angular speed of the wheel in degrees per minute and the linear speed of wheel in inches per minute.

Solution :

Angular speed is given by :

[tex]\omega = 25\ rpm \\\\\omega = 25\times 360^o \ per \ minute\\\\\omega = 9000^o \ per \ minute[/tex]

Now, velocity is given by :

[tex]v = Radius\times \dfrac{RPM}{60\ sec/min}\times 2\pi\ rad/rev\\\\v = 3.2 \times \dfrac{35}{60}\times 2\pi\\\\v = 11.73\ m/s[/tex]

Hence, this is the required solution.

Answer: there is simply no way that she can improve her chances of finding such a quasar; such discoveries are completely random

Explanation:

Answer: 1.4 m

Explanation:

Given

Mass of siblings are 25kg and 35 kg who sits at 2.5 m and 1 m left to pivot.

Suppose the 70 kg mass sits at a distance x from the pivot towards right.

Torque applied by two siblings must cancel the torque of 70 kg mass i.e.

[tex]\Rightarrow 25\times 2.5+35\times1=70x\\\Rightarrow 62.5+35=70x\\\\\Rightarrow x=\dfrac{97.5}{70}\\\\\Rightarrow x=1.392\approx 1.4\ m[/tex]

Answer:

Step 1: A Bill Is Born

Anyone may draft a bill; however, only members of Congress can introduce legislation, and, by doing so, become the sponsor(s). The president, a member of the cabinet or the head of a federal agency can also propose legislation, although a member of Congress must introduce it.

Step 2: Committee Action

As soon as a bill is introduced, it is referred to a committee. At this point the bill is examined carefully and its chances for passage are first determined. If the committee does not act on a bill, the bill is effectively "dead."

Step 3: Subcommittee Review

Often, bills are referred to a subcommittee for study and hearings. Hearings provide the opportunity to put on the record the views of the executive branch, experts, other public officials and supporters, and opponents of the legislation.

Step 4: Mark up

When the hearings are completed, the subcommittee may meet to "mark up" the bill; that is, make changes and amendments prior to recommending the bill to the full committee. If a subcommittee votes not to report legislation to the full committee, the bill dies. If the committee votes for the bill, it is sent to the floor.

Step 5: Committee Action to Report a Bill

After receiving a subcommittee's report on a bill the full committee votes on its recommendation to the House or Senate. This procedure is called "ordering a bill reported."

Step 6: Voting

After the debate and the approval of any amendments, the bill is passed or defeated by the members voting.

Step 7: Referral to Other Chamber

When the House or Senate passes a bill, it is referred to the other chamber, where it usually follows the same route through committee and floor action. This chamber may approve the bill as received, reject it, ignore it, or change it.

Step 8: Conference Committee Action

When the actions of the other chamber significantly alter the bill, a conference committee is formed to reconcile the differences between the House and Senate versions. If the conferees are unable to reach agreement, the legislation dies. If agreement is reached, a conference report is prepared describing the committee members' recommendations for changes. Both the House and Senate must approve the conference report

Step 9: Final Action

After both the House and Senate have approved a bill in identical form, it is sent to the president. If the president approves of the legislation, he signs it and it becomes law. Or, if the president takes no action for ten days, while Congress is in session, it automatically becomes law.If the president opposes the bill he can veto it; or if he takes no action after the Congress has adjourned its second session, it is a "pocket veto" and the legislation dies.

Step 10: Overriding a Veto

If the president vetoes a bill, Congress may attempt to "override the veto." If both the Senate and the House pass the bill by a two-thirds majority, the president's veto is overruled and the bill becomes a law.

Explanation:

good luck!

Answer:

A, Passive Solar.

Explanation:

Explanation:

the answer is 1835N that how best I can help

Answer:

b ❤❤❤❤❤❤❤❤❤ yes

Explanation:

yes b❤❤❤❤❤❤❤❤❤❤❤

Answer:

False

Explanation:

Answer:

it means a cell has 4.5Volt of electromtive force.

Answer:

She will be going at 11.01 m/s when she reaches the bottom.      

Explanation:

We can find the speed at the bottom by equating the total work with the change in energy:

[tex] W = E_{f} - E_{i} [/tex]   (1)

There is no energy conservation because there is a force of friction on her way down.  

By entering [tex]W = -F_{\mu}*d[/tex], where [tex]F_{\mu}[/tex] is the force of friction (is negative because it is in the opposite direction of motion) and d is the displacement, into equation (1) we have:

[tex]-F_{\mu}*d = E_{f} - E_{i}[/tex]  

In the initial state, we have kinetic and potential energy and in the final state, we have only kinetic energy.

[tex]-F_{\mu}*d = \frac{1}{2}mv_{f}^{2} - (\frac{1}{2}mv_{i}^{2} + mgh)[/tex]  

Where:

m: is the total mass = 40 kg

[tex]v_{f}[/tex]: is the final speed =?

[tex]v_{i}[/tex]: is the intial speed = 5 m/s

g: is the gravity = 9.81 m/s²

h: is the height = 10 m

[tex] -20 N*100 m = \frac{1}{2}40 kg*v_{f}^{2} - \frac{1}{2}*40 kg*(5 m/s)^{2} - 40 kg*9.81 m/s^{2}*10 m [/tex]    

By solving the above equation for [tex]v_{f}[/tex] we have:

[tex] v_{f} = 11.01 m/s [/tex]      

Therefore, she will be going at 11.01 m/s when she reaches the bottom.                                    

I hope it helps you!                      

Answer:

Elastic Potential Energy

If an object is at rest on a compressed spring, the compressed spring contains elastic potential energy.

Explanation:

It's the one that stores a spring when it is compressed or stretched.

Greetings.

Answer:

awareness and honesty toward others

Answer:

B,C,D

Explanation:

Ap3X

Answer: Higher.

Explanation: The doppler effect essentially. "The Doppler effect can be described as the effect produced by a moving source of waves in which there is an apparent upward shift in frequency for observers towards whom the source is approaching and an apparent downward shift in frequency for observers from whom the source is receding."