A 2MeV proton is moving perpendicular to a uniform magnetic field of 2.5T. the force of proton is

Answers

Answer 1

The force experienced by the 2MeV proton moving perpendicular to a uniform magnetic field of 2.5T can be calculated using the formula for magnetic force.

1. Determine the charge of the proton: A proton has a charge of +1.6 x [tex]10^{-19[/tex] Coulombs.

2. Calculate the velocity of the proton: The kinetic energy of the proton is given as 2MeV. Since 1 MeV is equal to 1.6 x [tex]10^{-13[/tex] Joules, the kinetic energy can be converted to Joules: 2 MeV = 2 x 1.6 x [tex]10^{-13[/tex] J = 3.2 x [tex]10^{-13[/tex] J.

The kinetic energy of a particle is given by the equation KE = (1/2)[tex]mv^2[/tex], where m is the mass and v is the velocity of the particle. The mass of a proton is approximately 1.67 x [tex]10^{-27[/tex] kg. Rearranging the equation, we can solve for v: v = sqrt((2 x KE) / m) = sqrt((2 x 3.2 x [tex]10^{-13[/tex] J) / (1.67 x [tex]10^{-27[/tex] kg)) ≈ 1.8 x [tex]10^7[/tex] m/s.

3. Calculate the magnetic force: The formula for the magnetic force on a charged particle moving through a magnetic field is given by the equation F = qvBsinθ, where q is the charge of the particle, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.

Since the proton is moving perpendicular to the magnetic field, θ = 90 degrees. Plugging in the values, we have F = (1.6 x [tex]10^{-19[/tex] C) x (1.8 x [tex]10^7[/tex]m/s) x (2.5 T) x sin(90°). The sine of 90 degrees is equal to 1, so the force can be simplified to F = (1.6 x [tex]10^{-19[/tex] C) x (1.8 x [tex]10^7[/tex] m/s) x (2.5 T) = 7.2 x [tex]10^{-12[/tex] N.

Therefore, the force experienced by the 2MeV proton moving perpendicular to the uniform magnetic field of 2.5T is approximately 7.2 x 10^-12 Newtons.

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Related Questions

A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Voltage


Depends on the amount of resistance
Depends on the amount of current
Is the measurement of electrical pressure
All of the above

Answers

Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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a compound having 44 total atoms consists of 11 atoms of element x and 33 atoms of element y find the % element x in the compound

A. 11%
B. 33%
C. 25%
D. 44%
E. 22%

Answers

The % element x in the compound is option c.25%.

To find the percentage of element X in the compound, we need to calculate the ratio of the number of atoms of element X to the total number of atoms in the compound and then convert it to a percentage.

Given:

Total number of atoms = 44

Number of atoms of element X = 11

To calculate the percentage, we can use the following formula:

Percentage of element X = (Number of atoms of element X / Total number of atoms) * 100

Substituting the given values, we get:

Percentage of element X = (11 / 44) * 100

Simplifying the equation, we have:

Percentage of element X = 0.25 * 100

Percentage of element X = 25%

Therefore, the percentage of element X in the compound is 25%.

The correct answer is option C. 25%.

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A rocket has been fired upward to launch a stellite in its orbit name two forces acting on the rocket immediately after leaving the launching pad

Answers

Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.

1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.

This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.

2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.

The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.

Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.

However, the thrust force continues to be the dominant force propelling the rocket upward.

It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.

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