Answer: The heat of combustion per gram of the material is 53.5 kJ
Explanation:
Let the heat released during reaction be q.
[tex]q=m\times c\times \Delta T[/tex]
[tex]q_{cal}[/tex] = Heat gained by calorimeter
Heat capacity of bomb calorimeter ,C = 38.29 kJ/°C
Change in temperature = ΔT = (27.04-23.61) °C = 3.43 °C
[tex]q_{cal}=C_{bomb}\times \Delta T=38.29\times 3.43=131.3kJ[/tex]
Total heat released during reaction is equal to total heat gained by bomb calorimeter.
[tex]q_{combustion}=-(q_{cal})[/tex]
[tex]q_{combustion}=-(131.3)J[/tex]
Thus 2.455 g of material releases 131.3 kJ of heat
1 g of material releases =[tex]\frac{131.3}{2.455}\times 1=53.5kJ[/tex] of heat
Thus the heat of combustion per gram of the material is 53.5 kJ
What number will go in the _?_ below to balance the equation?
3Gr3V2 + O3 --> 3GrO + __?__V
Question 1 options:
A. 1
B. 2
C. 3
D. 4
E. 5
F. 6
G. 9
Answer:
Option F 6 will be the answer.
1) 14.7 moles of Au react, how many grams of Au will that be?
2900 g Au
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableMolesStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 14.7 mol Au
[Solve] g Au
Step 2: Identify Conversion
[PT] Molar Mass of Au - 196.97 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 14.7 \ mol \ Au(\frac{196.97 \ g \ Au}{1 \ mol \ Au})[/tex][DA] Multiply [Cancel out units]: [tex]\displaystyle 2895.46 \ g \ Au[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
2895.46 g Au ≈ 2900 g Au
How many moles of F are in 8.25 grams of F?
0.434 mol F
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TablesMolesStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 8.25 g F
[Solve] moles F
Step 2: Identify Conversions
[PT] Molar Mass of F - 19.00 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 8.25 \ g \ F(\frac{1 \ mol \ F}{19.00 \ g \ F})[/tex][DA] Multiply [Cancel out units]: [tex]\displaystyle 0.434211 \ mol \ F[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.434211 mol F ≈ 0.434 mol F
What is occurring with the velocity between points D and E?
A velocity is decreasing
B. velocity is increasing
C. velocity is constant
D. velocity is zero
Answer:
a
Explanation:
the line is going down
To determine the highest angle the pendulum will swing to after the impact, we can apply the principle of conservation of momentum. Initially, the total momentum is zero since the pendulum is at rest.
After the impact, the total momentum remains zero because the block and embedded projectile move together as a single system.First, let's convert the weight units to a common system. The 5-pound rod is approximately 2.27 kg, and the 10-pound wooden block is around 4.54 kg. The projectile's weight is 0.3 oz, which is about 0.0085 kg.The momentum before the impact is zero, so the momentum after the impact must also be zero. This can be expressed as:(2.27 kg + 4.54 kg + 0.0085 kg) * V_final = 0Solving for V_final gives us V_final ≈ 0 ft/s. Since the velocity is zero after the impact, the pendulum will momentarily stop at its highest point.Therefore, the highest angle the pendulum will swing to after the impact is 0 degrees, or it will come to rest at the vertical position.
Learn more about momentum here :
https://brainly.com/question/30677308
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Chemical formula of copper (II) nitrate
Which of the following do omnivores eat?
A. only
B. plants and meat
C. meat only
D. they make their own food
Answer:
(B. Plants and meat)
Explanation:
Which yield comes from measurements obtained during a real experiment?
A) actual yield
B) theoretical yield
C) percent yield
Answer:
A) actual yield
Explanation:
Theoretical yield is the amount of product expected based on the stoichiomety.
Percent yield is the actual yield over the theoretical yield.
I just need my answers checked please be quick
Answer:
they are all right
Explanation:
Which of the following statements about maintaining a fitness program is ture?
Answer:
im sorry but you havent posted the pic
Explanation:
How many grams are in 7.32 x 1023 molecules of potassium carbonate (K2CO3)?
(I leave off the x10^23 because they both will divide out) Use your per
Given the decomposition of hydrogen peroxide, calculate the moles of oxygen gas produced from 4.20 mol of H2O2.
2H2O2(l)→2H2O(l)+O2(g)
Answer:
2.10 moles of O₂
Explanation:
2 H₂O₂ (l) → 2H₂O(l) + O₂(g)
In this reaction we say, that 2 moles of hydrogen peroxide can decompose to 2 moles of water and 1 mol of oyxgen.
So ratio is 2:1, according to stoichiometry.
If we apply a rule of three;
2 moles of hydrogen peroxide can decompose to 1 mol of oxygen
Then 4.20 moles of hydrogen peroxide may produced (4.20 . 1)/2 =
2.10 moles of O₂
Weather is caused by the:
mesosphere
stratosphere
troposphere
thermosphere
I WILL MARK BRAINLIST
When magnesium reacts with oxygen, magnesium atoms lose electrons.
What happens to magnesium in this reaction?
A. It is reduced.
B. It is oxidized.
C. It is decomposed.
D. It undergoes redox.
Answer:
B : it is oxidized .
Explanation:
The density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 18.2 g of CO2 according to the following chemical equation?
C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)
Answer: 12.1 ml of ethanol is needed
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} CO_2=\frac{18.2g}{44g/mol}=0.414moles[/tex]
[tex]C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(l)[/tex]
According to stoichiometry :
2 moles of [tex]CO_2[/tex] is produced by = 1 mole of [tex]C_2H_5OH[/tex]
Thus 0.414 moles of [tex]CO_2[/tex] is produced by=[tex]\frac{1}{2}\times 0.414=0.207moles[/tex] of [tex]C_2H_5OH[/tex]
Mass of [tex]C_2H_5OH=moles\times {\text {Molar mass}}=0.207moles\times 46.07g/mol=9.54g[/tex]
Volume of ethanol = [tex]\frac{\text {Mass of ethanol}}{\text {density of ethanol}}=\frac{9.54g}{0.789g/ml}=12.1ml[/tex]
12.1 ml of ethanol is needed to produce 18.2 g of [tex]CO_2[/tex]
Given the following chemical reaction equation:
3 Mg (s) + Al2O3 (s)------> 3 MgO (s) + 2 Al (s)
and 144g of MG and 150g of Al2O3 are reacted.
which chemical compound is the limiting reactant compound?
Answer:
Al₂O₃ is the limiting reactant
Explanation:
The limiting reagent or limiting reactant in a chemical reaction is a reactant that is totally used up when the chemical reaction is completed and subsequently, the reaction stops as no more products can be formed from the excess reactant.
Equation of the the reaction reaction is given below:
3 Mg (s) + Al₂O₃ (s) ----> 3 MgO (s) + 2 Al (s)
Mole ratio of reactants from the equation shows that 3 moles of magnesium metal is required to react with 1 mole of aluminum oxide.
Molar mass of magnesium metal, Mg = 24 g/mol
Molar mass of aluminum oxide, Al₂O₃ = (27 * 2 + 16 * 3) = 102 g/mol
from the equation of reaction, (24 * 3 g) 72 g of Mg reacts with 102 g of Al₂O₃
Given masses of reactants:
144 g of Mg = 144/24 6 moles of Mg
150 g of Al₂O₃ = 1.47 moles of Al₂O₃
Mole ratio of Mg to Al₂O₃ = 6/1.47 = 4.08 : 1
Therefore, magnesium is excess reactant while Al₂O₃ is the limiting reactant
Consider the following reaction:
Fe3+(aq) + SCN-(aq) ↔︎ [Fe(SCN)]2-(aq)
1)Explain what is meant by the term dynamic equilibrium.
2) Write the equilibrium expression for the reaction.
3) The numerical value of Kc at 298K is about 1000 for the reaction. What does this tell you about the position of the equilibrium at 298K?
Answer: In 1860s, Norwegian scientists C. M. Guldberg and P. Waage noted a peculiar relationship between the amounts of reactants and products in an equilibrium. Today, we call this observation the law of mass action. It relates the amounts of reactants and products at equilibrium for a chemical reaction. For a general chemical reaction occurring in solution, aA + bB ⇄ cC + dD the equilibrium constant, also known as Keq, is defined by the following expression: Keq = [C]c/[D]d where [A] is the molar concentration of species A at equilibrium, and so forth. The coefficients a, b, c, and d in the chemical equation become exponents in the expression for Keq. The Keq is a characteristic numerical value for a given reaction at a given temperature. That is, each chemical reaction has its own characteristic Keq. The concentration of each reactant and product in a chemical reaction at equilibrium is related; the concentrations cannot be random values, but they depend on each other. The numerator of the expression for Keq has the concentrations of every product (however many products there are), while the denominator of the expression for Keq has the concentrations of every reactant, leading to the common products over reactants definition for the Keq. Let us consider a simple example. Suppose we have this equilibrium: A ⇄ B .There is one reactant, one product, and the coefficients on each are just 1. The Keq expression for this equilibrium is Keq = [B]/[A]. Exponents of 1 on each concentration are understood. Suppose the numerical value of Keq for this chemical reaction is 2.0. If [B] = 4.0 M, then [A] must equal 2.0 M so that the value of the fraction equals 2.0: Keq = [B]/[A] = 4.0/2.0 =2.0 .By convention, the units are understood to be M and are omitted from the Keq expression. Suppose [B] were 6.0 M. For the Keq value to remain constant (it is, after all, called the equilibrium constant), then [A] would have to be 3.0 M at equilibrium: Keq = [B]/[A] = 60/3.0= 2.0 .If [A] were not equal to 3.0 M, the reaction would not be at equilibrium, and a net reaction would occur until that ratio was indeed 2.0. At that point, the reaction is at equilibrium, and any net change would cease. However, that the forward and reverse reactions do not stop because chemical equilibrium is dynamic.
During which changes of state do atoms that connot move past one another becomes free to move?
a. Vaporization and sublimation
b. boiling and deposition
c. sublimation and melting
d. condensation and melting
Answer:
c. sublimation and melting
Hope it helps...
Have a great day : )
Answer:
Option C is your answer
C. sublimation and melting
Explanation:
hope it helps u ^_^
have a great day/night
_Na+ Cl2 - -> _NaCl
A 2,4
B 1,2
C 3,3
D 2,2
Answer:
D 2,2
Explanation:
We can see that there are 2 chlorines on the reactant side so there has to be a 2 on the product side
Now we have Na + Cl2 --> 2NaCl
The problem now is that there are 2 sodiums on the product side so add a 2 to the Na on the reactant side
2Na + Cl2 --> 2NaCl
Now it's balanced!
Benzoic acid is a white crystalline powder used as a food preservative the compound contains 68.8% carbon, 5.0% hydrogen and 26.2% oxygen by mass what is the empirical formula
what is organic chemistry?
Answer:
Organic chemistry is the scientific study of the structure, properties, compositions, reactions and synthesis of organic compounds that by definition contains carbon.The organic compounds are molecules composed of carbon and hydrogen and it may contain any number of other elements.
Maybe this was your answer for your question.
You dissolve 0.47 g of potassium chloride (KCl) in 700 ml of water.
What is the molarity of the solution?
(From the periodic table: 1 mol K = 39.10 g; 1 mol Cl = 35.453 g)
Enter the value rounded to three decimal places with no units
Will give BRAINLEst
Answer:
0.009
Explanation:
Molarity, a measure of molar concentration of a substance is calculated thus;
Molarity = number of moles ÷ volume
According to the provided information, mass of KCl = 0.47g, volume of water = 700ml
Using mole = mass/molar mass
Molar Mass of KCl = 39.10 + 35.453
= 74.553g/mol
Mole = 0.47/74.55
Mole = 0.0063mol
Volume of water = 700ml = 700/1000 = 0.7L
Molarity = 0.006/0.7
Molarity = 0.00857
The value of molarity rounded to three decimal places (3 d.p) = 0.009
Name 2 diatomic molecules.
A sample of nitrogen gas has a temperature of 22.7oC when the volume of the container is 12.2L and it is under 150.4kPa of pressure. What temperature, in Kelvin, would the gas need to be in order to occupy a 9.7L container at 101.3kPa? Show all your work and round your answer to the hundredths place.
Answer:
The final temperature of the gas would need to be approximately 158.4 K
Explanation:
The details of the sample of nitrogen gas are;
The initial temperature of the nitrogen gas, T₁ = 22.7°C = 295.85 K
The initial volume occupied by the gas, V₁ = 12.2 L
The initial pressure of the gas, P₁ = 150.4 kPa
The final volume of the gas, V₂ = 9.7 L
The final pressure of the gas, P₂ = 101.3 kPa
Let 'T₂', represent the final temperature of the gas, by the ideal gas equation, we have;
[tex]\dfrac{P_1 \times V_1}{T_1} = \dfrac{P_2 \times V_2}{T_2}[/tex]
[tex]\therefore \ T_2 = \dfrac{P_2 \times V_2 \times T_1 }{P_1 \times V_1}[/tex]
Plugging in the values gives;
[tex]\therefore \ T_2 = \dfrac{101.3 \, kPa \times 9.7 \ L \times 295.85 K}{150.4 \ kPa \times 12.2 \ L} \approx 158.4327959 \ K[/tex]
The final temperature of the gas, T₂ ≈ 158.4 K
3. Calculate the energy in joules) of a photon with a wavelength of 3.66 X 104 hm (Infrared region) (Hint: Use Planck's equation)
104.3 x 10")
104.3 x 10-21,
1.043 X 1033
5.43 x 10 21
Answer:
5.43×10¯³² J
Explanation:
From the question given above, the following data were obtained:
Wavelength (λ) = 3.66×10⁴ hm
Energy (E) =?
Next, we shall convert 3.66×10⁴ hm to metre (m). This can be obtained as follow:
1 hm = 100 m
Therefore,
3.66×10⁴ hm = 3.66×10⁴ hm × 100 m / 1 hm
3.66×10⁴ hm = 3.66×10⁶ m
Next, we shall determine the frequency of the frequency of the photon. This can be obtained as follow:
Wavelength (λ) = 3.66×10⁶ m
Velocity (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 3.66×10⁶ × f
Divide both side by 3.66×10⁶
f = 3×10⁸ / 3.66×10⁶
f = 81.97 Hz
Finally, we shall determine the energy of the photon. This can be obtained as follow:
Frequency (f) = 81.97 Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 81.97
E = 5.43×10¯³² J
Therefore, the energy of the photon is 5.43×10¯³² J
Post-Lecture Assignment Chapter 06
Animation-Changes of State
< 1 of 23 >
When a solid is placed in a container and heat is applied, a phase change occurs. Watch the video and sort the parts of the curve based on whether the average energy of the molecules is changing, or is constant.
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The liquid is heated at the boiling point
The solid is heated at the melting
point
The liquid is heated to reach the
boiling point
The solid is heated to reach the
melting point
Average molecule energy change
Average molecule energy constant
Submit
Answer:
Can you send an image of the question, please?
Explanation:
When gases are treated as real, via use of the van der Waals equation, the actual volume occupied by gas molecules ________ the pressure exerted and the attractive forces between gas molecules ________ the pressure exerted, as compared to an ideal gas.
decreases, increases
does not affect, decreases
increases, decreases
does not affect, increases
increases, increases
Answer:
Increases, decreases
Explanation:
Give the theoretical yield, in moles, of CO2 from the reaction of 1.45 moles of C8H18 with 1.45 moles of O2.
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
Answer:
vuvbuvivovoivuighhghgig
When an ionic solid is added into a solvent, you can see that the ionic solid dissociates into its respective cations and anions. The solvent molecules immediately cluster around the ions. This is known as solvation. When the solvent is water, the solvation process is called hydration. Dissolution and hydration occur simultaneously, and salt is said to be dissolved in water. You can observe that some of the ions dissolved in the solution recrystallize or deposit to form the solid salt. When the rate of dissolution equals the rate of recrystallization (deposition), dynamic equilibrium is reached.
Rank from the first step to the last step.
a. hydration of anions
b. dissolution of salt into its cations and anions
c. hydration of cations
d. rate of dissolution is equal to the rate of deposition
e. hydrated cations and anions begin to deposit as a salt
Answer: See explanation
Explanation:
Based on the information given in the question, the ranking from the first step to the last step goes as follows:
1. Dissolution of salt into cations and anions
2. Hydration of anions
3. Hydration of cations
4. Dissolved cations and anions begin to deposit as a solid salt.
5. Rate of dissolution is equal to the rate of recrystallization.
What is the mass in grams of 1.00 x 10^12 lead (Pb)
atoms?
3.44 × 10⁻¹⁰ g Pb
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 1.00 × 10¹² atoms Pb
[Solve] grams Pb
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of Pb - 207.2 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 1.00 \cdot 10^{12} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})(\frac{207.2 \ g \ Pb}{1 \ mol \ Pb})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 3.44072 \cdot 10^{-10} \ g \ Pb[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
3.44072 × 10⁻¹⁰ g Pb ≈ 3.44 × 10⁻¹⁰ g Pb
Answer:
[tex]\boxed {\boxed {\sf 3.44 *10^{-10} \ g \ Pb}}[/tex]
Explanation:
1. Atoms to Moles
Use Avogadro's Number to convert atoms to moles. This number: 6.022*10²³, tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of lead.
[tex]\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]
Multiply by the given number of atoms.
[tex]1.00 *10^{12} \ atoms \ Pb *\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]
Flip the fraction so the atoms of lead cancel.
[tex]1.00 *10^{12} \ atoms \ Pb *\frac {1 \ mol \ Pb}{6.022*10^{23} \ atoms \ Pb}[/tex]
[tex]1.00 *10^{12}*\frac {1 \ mol \ Pb}{6.022*10^{23}}[/tex]
[tex]\frac {1.00 *10^{12}\ mol \ Pb}{6.022*10^{23}} = 1.66057788*10^{-12} \ mol \ Pb[/tex]
2. Moles to Grams
Use the molar mass to convert moles to grams. This can be found on the Periodic Table. For lead it is 207.2 grams per mole.
[tex]\frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]
Multiply by the number of moles we calculated.
[tex]1.66057788*10^{-12} \ mol \ Pb* \frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]
[tex]1.66057788*10^{-12}* \frac {207.2 \ g\ Pb}{ 1 }[/tex]
[tex]1.66057788*10^{-12}* {207.2 \ g\ Pb}= 3.44071737*10^{-10} \ g \ Pb[/tex]
3. Round
The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we calculated, it is the hundredth place. The 0 in the thousandth place tells us to leave the 4.
[tex]3.44 *10^{-10} \ g \ Pb[/tex]
Which of the following a true statement about igneous rocks?
A: Igneous rocks are only formed under a lot of heat and pressure. Some igneous rocks are formed below the surface others in oceans.
B: The properties of igneous rocks depend on the location in which they are formed.
C: Wind and water erosion can create igneous rocks.
Answer:
i think the answer is A....
Explanation:
Igneous rocks (from the Latin word for fire) form when hot, molten rock crystallizes and solidifies. The melt originates deep within the Earth near active plate boundaries or hot spots, then rises toward the surface.