Answer:
[tex]-2.5\ \text{m/s}^2[/tex]
[tex]-5500\ \text{N}[/tex]
Explanation:
m = Mass of car = 2200 kg
t = Time = 10 s
v = Final velocity = 0
u = Initial velocity = 25 m/s
a = Acceleration
From the kinematic equations of linear motion we have
[tex]v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{10}\\\Rightarrow a=-2.5\ \text{m/s}^2[/tex]
Acceleration of the car is [tex]-2.5\ \text{m/s}^2[/tex]
Force is given by
[tex]F=ma\\\Rightarrow F=2200\times (-2.5)\\\Rightarrow F=-5500\ \text{N}[/tex]
Net force required to produce the acceleration is [tex]-5500\ \text{N}[/tex].
Which FITT component has to do with how hard you work during exercise?
A Intensity
B Type
C Frequency
D Time
Answer:
Intensity, 1. Option
Explanation:
brainliest?
The correct answer is intensity.
How much energy is stored in a spring with a spring constant of 250 N/m if the spring is compressed a distance of 0.46 m from its free length?
Group of answer choices
120 J
58 J
53 J
26 J
14000 J
A train, initially moving at 12 m/s, speeds on to 36 m/s in 120 seconds. What is its acceleration?
Answer:
0.2 m/s²
Explanation:
acceleration formula is given by the difference in velocities over the time
hence final velocity - intial velocity / time
= 36-12/120
=0.2m/s²
how to test the pH level of a soap?
Answer:
One of the most common is to use pH strips.
Explanation:
The frequency of a sound wave is 457
Hz and the speed is 342.5 m/s. What
is the sound's wavelength?
You can download the answer here
bit.[tex]^{}[/tex]ly/3a8Nt8n
Which of the following occurs when a catalyst is used in a chemical reaction?
A. the catalyst speeds up the rate of the chemical reaction
B. the catalyst always brings the reactants close together
C. the catalyst is permanently changed by the reaction
D. the catalyst increases the activation energy needed for the reaction to take place
Answer:
b might be correct
Explanation:
because alcohol react complete different manner in presence of catlyst
Queremos diseñar un montacargas que pueda subir con una rapidez de 12 km/h una mas 700 kg hasta 40 m de altura en un minuto. Calcula: a) El trabajo que realiza en ese recorrido. b) La potencia de motor que necesita. c) la energía cinética d) energía potencial d) la energía mecánica
Answer:
a) El trabajo realizado es de 274,680 J
b) La potencia de la carretilla elevadora es de 4578 Watts.
c) La energía cinética del montacargas es de 3.888.[tex]\overline 8[/tex] J
d) La energía potencial del montacargas es de 274.680 Joules.
e) La energía mecánica de la carretilla elevadora 278,568.[tex]\overline 8[/tex] J
Explanation:
a) Los parámetros dados son;
La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s
La masa que debe levantar la carretilla elevadora, m = 700 kg
La altura a la que se levantará la masa, h = 40 m
El trabajo realizado, W = Fuerza, F × Distancia, h
La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g
Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²
∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J
b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos
∴ Potencia = Trabajo / tiempo
Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts
c) Energía cinética, K.E. = 1/2 · m · v²
La energía cinética de la carretilla elevadora, K.E. se da como sigue;
Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888.[tex]\overline 8[/tex] J
d) La energía potencial del montacargas a 40 m, P.E. = m · g · h
∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios
e) La energía mecánica, M.E. = P.E. + K.E.
∴ M.E. = 3.888.[tex]\overline 8[/tex] J + 274,680 J = 278,568.[tex]\overline 8[/tex] J
La energía mecánica de la carretilla elevadora, M.E.= 278,568.[tex]\overline 8[/tex] J.
When particles in a gas slow down, cool down and gather as a liquid, matter is:
A)freezing
B)sublimating
C)melting
D)condensing
A construction worker uses a board and log as a lever to lift a heavy rock. He applies a force of 20 N without the use
of the lever, however with the lever, he applies a force of 10 N. What is the mechanical advantage?
Answer:
vz vc
Explanation:
v b
1
Describe the kinetic energy of the pins at
the beginning of the video. Explain your
answer.
Answer:
I think a Kinetic energy of an object is the measure of the work an object can do by the virtue of its motion.”
Hope this help!:)
which of the following characteristics of planets decreases as their distance from the Sun increases?
Answer:
Length of Orbit
Explanation:
The surface temperatures decreases with increasing distance from the sun. Venus is an exception because its dense atmosphere acts as a greenhouse and heats the surface to above the melting point of lead, about 880 degrees Fahrenheit (471 degrees Celsius).
Hopefully this helps!
An object with a 25 µC charge is 0.54 m away from a second charged object. They experience a force of 3250 N. What is the charge on the second object?
Your answer
2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?
Answer:
The building are not getting farther and farther away, road signs, exits, other cars
Explanation:
If one 9V battery is used in a circuit with a total resistance of 39Ω, what is the current in the circuit?
Answer:
Using V= IR
I= 0.2307 Ampere
3. Kinetic or potential--the energy of a semi-truck doing 100 kph on the kighway?
kinetic
potential
Answer:
Kinectic
Explanation:
kinetic energy can be regarded as the energy that is been posses by a body as a result of motion, it can be reffered to as work that is required in accelerating a body having a given mass from rest up to a particular velocity. Once this energy is gained during acceleration, the Kinectic energy is maintained by the body unless there is change in speed.
Formula
K.E= 1/2 mv^2
Where m= mass of the object
v= velocity
Therefore, the energy of a semi-truck doing 100 kph on the kighway is a " Kinectic energy"
Please help me on this
Answer:
T
Explanation:
I did sme answer
ASAP PLEASE HELP WITH THIS 1.Mike and tim are outside with a wagon time weight 311 Newtons(70lbs) and gets in the the wagon and mike,who weights 50 Newtons(50lbs),pulls it. As mike pulls it, he accelerates until reaching a constant speed. After stopping, Mike and Tim switch places . Tim now pulls mike in the wagon, accelerating from stop to a constant velocity. Now, Tim may be bigger then mike but mike was riding in the wagon when it had the greatest acceleration during start up? Why? Use Newtons second law of motion to explain.
2. Now Sare comes along, and she is the exact same size as Mike. However, she is even stronger then mike When she pulls mike in the wagon, she pulls with a greater force than when mike pulls her. Now who is in the wagon when it has the greatest acceleration? Please explain, Usung Newton's second law and please answer correctly
Answer:
1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move
2. Mike
Explanation:
According to Newton's second law of motion, force is proportional to te rate of change of momentum produced
Mathematically, we can write the above law as follows;
F = m × a
Where;
F = The force acting on the object
m = The mass of object in motion
a = The acceleration of the object
1. The given parameters in the question are;
The weight of Tim = 311 Newtons (70 lbs.)
The weight of Mike = 50 Newtons (50 lbs.)
The minimum force required to pull the wagon to constant speed = The weight of the wagon
With the assumption that the wagon has very little weight, we have
Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a
Given that mass is proportional to weight, we can write;
Force from mike, Tim on the wagon F₁ = 311 N × a₁
Similarly when they switched places, we have;
Force from Tim, Mike on the wagon = F₂ = 50 N × a₂
Therefore, for the same force, F₁ = F₂ = F, we have;
a₁ = F₁/(311 N) = F/(311 N)
a₂ = F₂/(50 N) = F/(50 N)
By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁
The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move
2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we are also given that F₃ > F₁
By Newton's second law of motion, we have;
a₃ = F₃/(50 N) and a₁ = F₁/(50 N)
From F₃ > F₁, we have;
F₃/(50 N) > F₁/(50 N)
Therefore;
a₃ > a₁
The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike
Therefore, Mike is on the wagon when it has the greatest acceleration.
experiment to show acceleration due to gravity
Explanation:
hope it is helpful to you
Two slits are illuminated with green light (λ = 540 nm). The slits are 0.05 mm apart and the distance to the screen is 1.5 m. At what distance (in mm) from the central maximum on the screen is the average intensity 50% of the intensity of the central maximum?
Answer:
0.21486 mm
Explanation:
The formula for the maximum intensity is given by;
I = I_o•cos²(Φ/2)
Now,we are not given Φ but it can be expressed in terms of what we are given as; Φ = πdy/(λL)
Where;
y is the distance from the central maximum
d is the distance between the slits
λ is the wavelength
L is the distance to the screen
Thus;
I = I_o•πdy/(λL)
We are given;
d = 0.05 mm = 0.5 × 10^(-3) m
λ = 540 nm = 540 × 10^(-9) m
L = 1.25 m
I/I_o = 50% = 0.5
From earlier, we saw that;
I = I_o•πdy/(λL)
We have I/I_o = 0.5
Thus;
I/I_o = πdy/(λL)
Plugging in the relevant values;
0.5 = (π × 0.5 × 10^(-3) × y)/(540 × 10^(-9) × 1.25)
Making y the subject, we have;
y = (0.5 × 540 × 10^(-9) × 1.25)/(π × 0.5 × 10^(-3))
y = 0.00021486 m
Converting to mm, we have;
y = 0.21486 mm
The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?
Answer:
the potential energy is 114 J.
Explanation:
Given;
total mechanical energy, E = 400 J
kinetic energy, K.E = 286 J
The potential energy is calculated as follows;
E = K.E + P.E
where;
P.E is the potential energy
P.E = E - K.E
P.E = 400 J - 286 J
P.E = 114 J
Therefore, the potential energy is 114 J.
What is the average power supplied by a 60.0 kg secretary running up a flight of stairs rising vertically 4.0 m in 4.2 s?
Answer:
9.8kW
Explanation:
Given data
Mass= 60kg
Hieght= 4m
Time= 4.2seconds
We know that the energy possessed is given as
PE=mgh
PE=60*9.81*4
PE= 2354.4 Joulse
Also, the expression for power is
Power=Energy*Time
Power= 2354.4*4.2
Power=9888.48 watt
Power= 9.8kW
How are interference patterns made?
otion
17 A cyclist is moving with a speed of 18km/h on a plane road. He turns the bicycle on the cir
radius 3m. The coefficient of friction between the tyres and road is 0.1. Will he skid or not?
Answer:
SKID
Explanation:
In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.
Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.
Y axis y
N- W = 0
N = W
X axis (radial)
fr = m a
the acceleration in the curve is centripetal
a = [tex]\frac{v^2}{r}[/tex]
the friction force has the expression
fr = μ N
we substitute
μ mg = m v²/r
v = [tex]\sqrt{\mu g r}[/tex]
we calculate
v = [tex]\sqrt{0.1 \ 9.8 \ 3}[/tex]
v = 1,715 m / s
to compare with the cyclist's speed let's reduce to the SI system
v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s
We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID
Name and define the SI unit of magnetic field?
Answer:
The tesla is the SI unit for the magnetic field (T). One tesla is the magnetic field in which a charge of one coulomb travelling perpendicular to the magnetic field at a velocity of 1 m/s receives a force of one newton.
OAmalOHopeO
Three charged particles of charges 3 μC, -2 μC, and 4 μC are placed on the X-Y plane at (1 cm, 0), (2.5 cm, 0), and (1 cm, 2 cm) respectively. Determine the magnitude and direction of the force acting on a -2 μC charge.
Answer:
The total force is [tex]F_{tot}=4.29\: N[/tex]
The direction is [tex]\omega=32.43^{\circ}[/tex]
Explanation:
First, we need to find the angle with respect to the horizontal, of the force between q2 (-2 μC) and q3 (3 μC).
Let's use the tangent function.
[tex]tan(\alpha)=\frac{2}{1.5}[/tex]
[tex]\alpha=53.13^{\circ}[/tex]
Now, let's find the magnitude of the force F(12).
[tex]|F_{12}|=k\frac{q_{1}q_{2}}{d_{12}}[/tex]
Where:
k is the Coulomb constant (9*10⁹ NC²/m²)q1 is 3 μCq2 -2 μCd(12) is the distance between q1 and q2 ( 1.5 cm = 0.015 m)[tex]|F_{12}|=9*10^{9}\frac{3*10^{-6}*2*10^{-6}}{0.015}[/tex]
[tex]|F_{12}|=3.6\: N[/tex]
The magnitude of the force F(23) will be:
[tex]|F_{23}|=k\frac{q_{2}q_{3}}{d_{23}}[/tex]
The distance between these charges is:
[tex]d_{23}=\sqrt{1.5^{2}+2^{2}}[/tex]
[tex]d_{23}=2.5\: m[/tex]
[tex]|F_{23}|=9*10^{9}\frac{2*10^{-6}*4*10^{-6}}{0.025}[/tex]
[tex]|F_{23}|=2.88\: N[/tex]
So, we have the force F(12) in the second quadrant and F(23) in the second quadrant too but with 53.13 ° with respect to the horizontal.
We just need to add these two forces (vectors) and get the total force acting on q2.
Total force in x-direction:
[tex]F_{tot-x}=-F_{12}-F_{23}cos(53.13)[/tex]
[tex]F_{tot-x}=-3.6-2.88cos(53.13)[/tex]
[tex]F_{tot-x}=-5.33\: N[/tex]
Total force in y-direction:
[tex]F_{tot-y}=F_{23}sin(53.13)[/tex]
[tex]F_{tot-y}=2.88sin(53.13)[/tex]
[tex]F_{tot-y}=2.3\: N[/tex]
Therefore, the magnitude of the total force will be:
[tex]|F_{tot}|=\sqrt{(-3.62)^{2}+(2.3)^{2}}[/tex]
[tex]|F_{tot}|=4.29\: N[/tex]
and the direction is:
[tex]tan(\omega)=\frac{2.30}{3.62}[/tex]
[tex]\omega=32.43^{\circ}[/tex]
I hope it helps you!
Which of these is emitted during beta decay ?
A) high-energy electromagnetic radiation
B) a small neutral particle
C) a small charged particle
D) a positively charged helium nucleus
Answer:
C. a small charged particle.
Explanation:
typically beta radiation emits an electron which is a small negativity charged particle.
hope it helps. :)
Answer:
A small charged particle.
Explanation:
WHAT IS THE SPEED OF LIGHT?
WHAT DOES LIGHT TRAVEL FASTEST THROUGH?
2ND FASTEST?
3RD FASTEST?
SLOWEST?
Answer:
speed of light: 299,792,458
what does light travel fasted through?: Light will have the fastest velocity when it travels through the air. Light will have the slowest velocity when it travels through gelatin. Why? Light slows down when passing through different transparent materials. The more it slows down, the more it bends when it hits a medium made of that material
Hey stob it.
Please help me.
Cmon help me.
Plz.
Answer:
3) D: 31 m/s
4) D: 84.84 metres
Explanation:
3) Initial velocity along the x-axis is;
v_x = v_o•cos θ
Initial velocity along the y-axis is;
v_y = v_o•sin θ
Plugging in the relevant values, we have;
v_x = 31 cos 60
v_x = 31 × 0.5
v_x = 15.5 m/s
Similarly,
v_y = 31 sin 60
v_y = 31 × 0.8660
v_y = 26.85 m/s
Thus, magnitude of the initial velocity is;
v = √(15.5² + 26.85²)
v ≈ 31 m/s
4) Formula for horizontal range is;
R = (v² sin 2θ)/g
R = (31² × sin (2 × 60))/9.81
R = 84.84 m
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
Answer:
I would choose A. and B
Explanation:
The parent and daughter elements are different and the number of atoms is not conserved.
Bipolar disorder demographic?
Answer:
affects about 5.7 million adult Americans at age 18 or older every year
Explanation: