The car's rate of centripetal acceleration in the circular path is 4.8 m/s².
The given parameters;
mass of the car, m = 2,000 kgvelocity of the car, v = 12 m/sradius of the circular path, r = 30 mThe centripetal acceleration of the car is calculated as follows;
[tex]a_c = \frac{v^2}{r}[/tex]
where;
v is the tangential speed of the carr is the radius of the circular pathSubstitute the given parameters and solve for the centripetal acceleration;
[tex]a_c = \frac{12^2}{30} \\\\a_c = 4.8 \ m/s^2[/tex]
Thus, the car's rate of centripetal acceleration is 4.8 m/s².
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How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.
Answer:
4.2s
Explanation:
Given parameters:
Power = 2190W
Mass of box = 1.47 x 10⁴g
distance = 6.34 x 10⁴mm
Unknown:
Time = ?
Solution:
Power is the rate at which work is done;
Mathematically;
Power = [tex]\frac{work done}{time}[/tex]
Time = [tex]\frac{work done}{power}[/tex]
Work done = weight x height
convert mass to kg;
100g = 1kg;
1.47 x 10⁴g = 14.7kg
convert the height to m;
1000mm = 1m
6.34 x 10⁴mm gives 63.4m
Work done = 14.7 x 9.8 x 63.4 = 9133.4J
Time taken = [tex]\frac{9133.4}{2190}[/tex] = 4.2s
What holds the metal ions together in a lattice?
A. covalent bonds
B. metallic bonds
C. hydrogen bonds
D. ionic bonds
Answer:
B. Metallic bonds.
If a car traveled 50 meters in 2 seconds, what will the velocity be? (Write the answer with a number, on decimal if needed, then a space and the units, for example 5.7 m/s)
Answer:
The answer is 25 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{50}{2} \\ [/tex]
We have the final answer as
25 m/sHope this helps you
At which temperature are the particles in a pencil moving faster: 20°C or 50°C?
Answer:
movement generates energy=heat so 50c should be it
A 16-V battery powers a series circuit that contains two lightbulbs The
voltage across the first lightbulb is 12-V
Complete question:
A 16-V battery powers a series circuit that contains two lightbulbs. The voltage across the first lightbulb is 12-V.
a. What fractional part of the circuit's total energy is transformed in the first lightbulb? Simply your answer.
b. What fractional part of the circuit's total energy is transformed in the second lightbulb? Simply your answer.
Answer:
(a) Fraction of energy of the first bulb in the total energy of circuit is 3/4
(b) Fraction of energy of the second bulb in the total energy of circuit is 1/4
Explanation:
Given;
total voltage across the series circuit, [tex]V_T[/tex] = 16 V
voltage across the first light bulb, V₁ = 12 V
The voltage across the second light bulb is given by;
V₂ = [tex]V_T[/tex] - V₁
V₂ = 16 V - 12 V
V₂ = 4 V
The total power across the circuit is given by;
P = I[tex]V_T[/tex]
P = 16I
Where;
I is the constant current in the circuit
(a)
power in the first light bulb is given by;
P₁ = 12I
Fraction of this power in the total energy of circuit is given by;
[tex]\frac{P_1}{P} = \frac{12I}{16I} = \frac{3}{4}[/tex]
(b)
power in the second light bulb is given by;
P₂ = 4I
Fraction of this power in the total energy of circuit is given by;
[tex]\frac{P_2}{P} = \frac{4I}{16I} = \frac{1}{4}[/tex]
HELP PLEASE I need to finish this asap
Answer:
I'm not 100% sure, but I think the answer would be the first one because there's a force pushing the object in every direction, so they would cancel eachother out and make the object stay in the same place.
Explanation:
pls vote brainliest
A 1,200 kg roller coaster car starts rolling up a slope at a speed of 15 m/s. What is the highest point it could reach?
Answer:
11.48 m
Explanation:
The following data were obtained from the question:
Mass (m) of the roller coaster = 1200 Kg
Initial velocity (u) = 15 m/s.
Final velocity (v) = 0 m/s (at highest point)
Acceleration due to gravity (g) = 9.8 m/s²
Highest point (h) =?
The highest point reached by the roller coaster can be obtained as illustrated below:
h = u²/2g
h = 15² / 2 × 9.8
h = 225/19.6
h = 11.48 m
Therefore, the highest point reached by the roller-coaster is 11.48 m
carter found the rock shown in the picture below near a river
Answer:
there's no picture
Explanation:
and what would the question be anyways?
Answer:
what is the question
Explanation:
If the brakes are applied and the speed of the car is reduced to 13 m/s in 14 s, determine the constant deceleration of the car.Express your answer to three significant figures and include the appropriate units. Assume ais negative if it acts in the opposite sense to the positive velocity.
Answer:
Explanation:
v = u + at
v is final velocity , u is initial velocity , a is acceleration and t is time .
here v = 0 , u = 13 m /s , t = 14 s
putting the values
0 = 13 + 14 a
a = 13 / 14 m /s²
= - .9286
= - 0.929 m /s²
Explain the procedures used and data recorded to identify a crystalline mineral based on its properties.
Answer:
By examining its external shape, color, hardness, etc.
Explanation:
A 60-kg woman runs up a staircase 15 m high (vertically) in 20 s.
Required:
a. How much power does she expend?
b. What is her horsepowerrating.
Answer:
(a) 441 W (b) 0.59 hP
Explanation:
Given that,
Mass of a woman, m = 60 kg
Height of a staircase, h = 15 m
Time, t = 20 s
(a) We need to find the power she expend. Work done per unit time is called power. It is given by :
[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{60\times 9.8\times 15}{20}\\\\P=441\ W[/tex]
( b) Since, 1 hP = 745.7 W
P = 0.59 hP
The Amazon rainforest has millions of trees down in South America. Pantanal, the largest wetland, or swamp, on Earth sits directly below the Amazon on a map. Explain this phenomenon using processes from the water cycle.
The subject is science just to let you know.
Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.
Answer:
Nine, Brazil, Venezuela
Explanation:
A steam catapult applies a very large force to supplement the engine thrust of a jet fighter as it takes off from an
aircraft carrier. The jet has a mass of 4000 kg and must reach its take off speed of 70 m/s at the end of the 220
m flight deck. What is the combined force of the catapult and engines? (Use the work-energy theorem)
Answer:
The combined force of the catapult and engines is 44545.455 newtons.
Explanation:
Let suppose that platform of the aircraft carrier is horizontal, such that changes in gravitational potential energy can be neglected. In addition, effects of non-conservative forces are neglected. By using Principle of Energy Conservation and Work-Energy Theorem we find that steam catapult-jet aircraft is represented by:
[tex]K_{1}+W_{1\rightarrow 2} = K_{2}[/tex] (1)
Where:
[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final translational kinetic energies of the jet fighter, measured in joules.
[tex]W_{1\rightarrow 2}[/tex] - Work done on the jet fighter due to the combined force of the catapult and engines, measured in joules.
By applying definitions of translational kinetic energy and work, we expand and simplify the equation above as follows:
[tex]F\cdot \Delta s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})[/tex]
[tex]F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot \Delta s}[/tex] (2)
Where:
[tex]F[/tex] - Combined force of the catapult and engines, measured in newtons.
[tex]m[/tex] - Mass of the jet fighter, measured in kilograms.
[tex]\Delta s[/tex] - Length of the catapult, measured in meters.
[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the jet aircraft, measured in meters per second.
If we know that [tex]m = 4000\,kg[/tex], [tex]v_{1} = 0\,\frac{m}{s}[/tex], [tex]v_{2} = 70\,\frac{m}{s}[/tex] and [tex]\Delta s = 220\,m[/tex], then the combined force of the catapult and engines is:
[tex]F = \frac{(4000\,kg)\cdot \left[\left(70\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (220\,m)}[/tex]
[tex]F = 44545.455\,N[/tex]
The combined force of the catapult and engines is 44545.455 newtons.
The combined force of the catapult and engines is 44,545.5 N.
The given parameters;
mass of the jet, = 4000 kgspeed of the jet, v = 70 m/slength of the deck, d = 220 mThe combined force of the catapult and engines is determined by applying work energy theorem as shown below;
[tex]W = \Delta E\\\\Fd = \frac{1}{2}m(v^2 -u^2) \\\\220F = \frac{1}{2}(4000)(70^2 - 0^2) \ \\\\220 F = 9,800,000\\\\F = \frac{9,800,000}{220} \\\\F = 44,545.5 \ N[/tex]
Thus, the combined force of the catapult and engines is 44,545.5 N.
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Based on the measured force between objects that are 10 meters apart, how can you find the force between objects that are any distance apart ?
Answer:
F' = 100 F/r²
Explanation:
The gravitational force of attraction between two objects is given by the Newton's Gravitational Formula. The Newton's Gravitational Formula is as follows:
F = Gm₁m₂/r²
where,
F = Force between objects
G = Universal Gravitational Constant
m₁ = mass of first object
m₂ = mass of second object
r = distance between objects = 10 m
Therefore,
F = Gm₁m₂/10²
Gm₁m₂ = 100F --------------------- equation (1)
Now, we consider these objects at any distance r apart. So, the force becomes:
F' = Gm₁m₂/r²
using equation (1), we get:
F' = 100 F/r²
So, if the force (F) between objects 10 m apart is known, we can find it at any distance from the above formula.
The force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]
According to the gravitational law, the force acting on an object is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Mathematically,
[tex]P=\frac{GMm}{r^2}[/tex]
M and m are the masses
r is the distance between the masses
If the force between objects that are 10 meters apart, hence;
[tex]P=\frac{GMm}{10^2}\\P=\frac{GMm}{100}\\GMm = 100P[/tex]
To find the force between objects that are any distance apart, we will use the same formula above to have;
[tex]P'=\frac{GMm}{r^2}\\[/tex]
Substitute the result above into the expression to have:
[tex]P'=\frac{100P}{r^2}[/tex]
Hence the force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]
Learn more on gravitational law here: https://brainly.com/question/11760568
A water molecule is made up of one oxygen and two hydrogen atoms. Why is water considered a pure substance?
Answer:
A mixture is when two or more substances combine physically together.
However, in water, two hydrogen atoms combine with one oxygen atom chemically, forming a new substance that has properties different from hydrogen alone or oxygen alone.
Explanation:
A solid keeps its shape due to which of the following factors?
Space between particles
Attractive forces between particles
The type of element in the solid
The container it is placed in
Answer:
c
Explanation:
because whatever elements are used like gas uses water evaporation so yeah
Answer:
(A) Space between particles!
Explanation:
Solids can hold their shape because their molecules are tightly packed together!
✞ Bye Have A Nice Day! ✞
How does temperature effect density and the flow of convection currents?
Answer:
Convection
Explanation:
Convection is heat transfer due to a density differential within a fluid. As water's temperature increases in the presence of a heat source, it will become less dense and rise. As it moves up and away from the heat source, it cools and becomes more dense and sinks.
if an object is moving with a velocity of 25m/s, an acceleration of 5m/s and has a travel time of 5s, what is the final velocity of the object?
V = at + V0
where v0 is the initial speed, a is the acceleration and t is the time.
So:
v = 5m/s^2*5s + 25m/s = 50 m/s
Two masses are to collide directly with each other. One has a mass of 5 kg and a velocity of 2 m/s. The other has a mass of 3 kg and a velocity of 1 m/2. The collision is perfectly inelastic. Find the velocity of the masses after the collision.
Answer:
v₃ = 1.625 [m/s]
Explanation:
To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.
Since the collision is inelastic, the two bodies are joined after the collision.
P = m*v [kg*m/s]
m = mass [kg]
v = velocity [m/s]
where:
P = lineal momentum [kg*m/s]
Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.
Pbefore = Pafter
(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃
where:
m₁ = mass one = 5 [kg]
v₁ = velocity of the mass one = 2 [m/s]
m₂ = mass two = 3 [kg]
v₂ = velocity of the mass two = 1 [m/s]
v₃ = velocity of the combined masses after the collision [m/s]
Now replacing we have:
(5*2) + (3*1) = (5 + 3)*v₃
10 + 3 = 8*v₃
v₃ = 13/8
v₃ = 1.625 [m/s]
The first group of planets that are made of rock and closest to the sun
Answer:
A terrestrial planet, telluric planet, or rocky planet is a planet that is composed primarily of silicate rocks or metals. Within the Solar System, the terrestrial planets are the inner planets closest to the Sun
True or False. A compound is formed when two or more elements are combined to make a
new substance with its own properties.
Anyone?
Answer:
I believe It's true. Since from memory I KNOW a compound is formed when elements are combined chemically.
Answer: correct
Explanation: a compound is 2 or more elements formed to make a completely new thing. For example, water is a compound. Why? Well, water is h20. What is h20? It’s Hydrogen and Oxygen. Oxygen is also a compound. Another example is CO2 (carbon dioxide) it’s made of carbon and oxygen, so it’s a compound! A element is just a pure substance. It’s not made up of other materials. It’s in its purest form.
a bowling ball hits two standing bowling pins at the same time. which of the following is true. assume that all collisions are elastic
Answer:
b?
Explanation:
things that affects the demand for electricity
QUESTION 13
Marci would describe almost a perfect person whenever her friends would ask her who she thought was
her ideal life partner. This "perfect" person would be ain)
O a prototype
b.reinforcer
oc. anagram
d. heuristic
A current of 15 Amps flows through a circuit with a resistance of 0.10 Ohms. What is the voltage?
A. 0.006 Volts
OB. 1.5 Volts
O C. 15 Volts
D. 150 Volts
Voltage = (current) x (resistance) (Ohm's law)
Voltage = (15 A) x (0.10 ohm)
Voltage = 1.5 volts (B)
Does electric and magnetic objects both have north and south poles
Explanation:
hope this answer was helpful
Calculate the velocity of an object moved around a circle with a radius of 1.65 m and an
acceleration of 3.5 m/s2.
Answer:
2.4m
Explanation:
Given parameters:
Radius of circle = 1.65m
Acceleration = 3.5m/s²
Unknown:
Velocity of the object = ?
Solution:
To solve this problem, we have to apply the formula of centripetal acceleration;
Centripetal acceleration = [tex]\frac{v^{2} }{r}[/tex]
v is the velocity
r is the radius
v² = centripetal acceleration x radius
Insert parameters and solve;
v² = 3.5 x 1.65
v = √5.775 = 2.4m
The velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
Given the data in the question;
Radius; [tex]r = 1.65m[/tex]Centripetal acceleration; [tex]a_c = 3.5m/s^2[/tex]Velocity; [tex]v = \ ?[/tex]
From the centripetal force equation, we use the expression for centripetal acceleration:
[tex]a_c = \frac{v^2}{r}[/tex]
Where [tex]a_c[/tex] is the centripetal acceleration, v is the velocity and r is radius.
We substitute our given values into the equation
[tex]3.5m/s^2 = \frac{v^2}{1.65m} \\\\v^2 = 3.5m/s^2\ *\ 1.65m\\\\v^2 = 5.775m^2/s^2\\\\v = \sqrt{5.775m^2/s^2} \\\\v = 2.4m/s[/tex]
Therefore, the velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
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When the wooden block is placed in the water and allowed to float to the top, what percentage of it is submerged
Answer:
This question is incomplete
Explanation:
This question is incomplete. However, what is described in the question is known as upthrust. Upthrust is an upward force on an object (in this case the wooden block) provided by the liquid (water) as a result of it displacing some of the liquid. Thus floating objects will normally displace some part of the liquid; making some part of it to be submerged in water.
The percentage of the submerged wooden block can be calculated as
length (in height) of the wood block submerged in water/total length (in height) of the wood × 100
The peripheral speed of the tooth of a 10-in.-diameter circular saw blade is 230 ft/s when the power to the saw is turned off. The speed of the tooth decreases at a constant rate, and the blade comes to rest in 17 s. Determine the time at which the total acceleration of the tooth is 130 ft/s2.
Answer:
The time is [tex]t_r =21.58 \ s[/tex]
Explanation:
From the question we are told that
The diameter of the circular saw is [tex]d = 10 \ in = \frac{10}{12} = 0.833 \ feet[/tex]
The peripheral speed is [tex]u = 230 \ ft/s[/tex]
The time taken for the blade to come to rest is t = 17 s
The total acceleration of the tooth considered is [tex]a = 130 \ ft/s^2[/tex]
Generally the radius of the blade is mathematically represented as
[tex]r = \frac{0.833}{2}= 0. 4165 \ feet[/tex]
Generally the tangential acceleration of the blade is mathematically represented as
[tex]a__{t}} = \frac{v - u}{t}[/tex]
Here v is the final velocity of the tooth of the blade which is zero since the blade came to rest
so
[tex]a__{t}} = \frac{0 - 230}{ 17}[/tex]
=> [tex]a__{t}} = - 13.53 \ ft/s^2[/tex]
Generally the total acceleration of the tooth of the blade is mathematically represented as
[tex]a = \sqrt{a_t^2 + a_r^2}[/tex]
Here [tex]a_r[/tex] is the radial acceleration , now making [tex]a_r[/tex] the subject of the formula we have that
[tex]130= \sqrt{13.56 ^2 + a_r^2}[/tex]
=> [tex]a_r = \sqrt{130^2 -(- 13.56)^2}[/tex]
=> [tex]a_r = 129.3 \ m/s^2[/tex]
Generally radial acceleration is mathematically represented as
[tex]a_r = \frac{v_r^2}{r}[/tex]
Here [tex]v_r[/tex] is the velocity at which the total acceleration is 130 ft/s2.
=> [tex]v_r = \sqrt{a_r * r }[/tex]
=> [tex]v_r = \sqrt{129.3 * 0.4165 }[/tex]
=> [tex]v_r = 7.34 \ m/s[/tex]
Generally the time at which the total acceleration is 130 ft/s2. is mathematically represented as
[tex]t_r = \frac{7.34 - 300}{a_t}[/tex]
=> [tex]t_r = \frac{7.34 - 300}{-13.56}[/tex]
=> [tex]t_r =21.58 \ s[/tex]
What is the density of the paint if the mass of a tin containing 5000 cm3 paint is 7 kg. If the mass of the empty tin, including the lid is 0.5 kg.
We are given:
Mass of the Paint bucket (with paint) = 7000 grams
Mass of the paint bucket (without paint) = 500 grams
Volume of Paint in the Bucket = 5000 cm³
Mass of Paint in the Bucket:
To get the mass of the paint in the bucket, we will subtract the mass of the bucket from the mass of the paint bucket (with paint)
Mass of Paint = Mass of Paint bucket (with paint) - Mass of the paint Bucket (without paint)
Mass of Paint = 7000 - 500
Mass of Paint = 6500 grams
Density of the Paint:
We know that density = Mass / Volume
Density of Paint = Mass of Paint / Volume occupied by Paint
Density of Paint = 6500/5000
Density of Paint = 1.3 grams / cm³