A 2-year-old child is prescribed cyclosporine. The parent says the child doesn't like taking the liquid medication. Which statement by the nurse is most appropriate

Answer:

Explanation:

The answer is -2m/s²

1. Frequency

2. Reflected

3. Absorbed

4. Black

Answer:

A. The electrons from atom repel each other

Answer:

Scientific notation is the way that scientists easily handle very large numbers or very small numbers. For example, instead of writing 0.0000000056, we write 5.6 x 10-9. So, how does this work? We can think of 5.6 x 10-9 as the product of two numbers: 5.6 (the digit term) and 10-9 (the exponential term).

Explanation:

Answer:

a. 2.5 m/s

Explanation:

50 / 20 = 2.5 m/s

Answer:

vector quantity have both magnitude and direction but scalar quantities have only magnitude

Answer:

not suppoted

not supported

support

When a log of wood is put over the freshwater, the log start to float. Option B is correct.

Density:

It can be defined as the amount of substance per unit volume. It is usually denoted by D. It is measured in the [tex]\bold { kg/m^3}[/tex].

The less dense object always floats over the more dense substance.

For example- Here, The density of the log is 0.8 [tex]\bold{ cm^3}[/tex] and the density of the of water is 1.0 [tex]\bold{ cm^3}[/tex] .

Since, the density of the log is lesser than the density of the water.

Therefore, when a log of wood is put over the freshwater, the log start to float.

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Newton's second equation of motion :-

S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]

This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.

So let's see what pieces of information (bundles of equations) do we have with us, initially.

We have, a very primary equation with us,

dS/dt = v… (I)

(Considering motion in a straight line only)

And we also have the equation

dv/dt = a…(II)

Simply replacing the v in eqn (II) by eqn (I), we find

d2S/dt^2 = a…(III)

This is what we need to solve. It's easy.

You know,

d2S/dt^2 = d/dt(dS/dt) = a

⟹ dS/dt = ∫adt = at+c1

Since, dS/dt is the velocity of the particle,

Therefore, at t = 0, dS/dt|t = 0 = u

⟹ u = a∗0 + c1 = c1

⟹ c1 = u

Therefore, dS/dt = u + at

Thus, S = ∫(udt + atdt)

⟹ S = ut + 1/2at^2 +c^2

If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0

This makes S = S0 +ut + 1/2at^2

Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),

We get

S = ut + 1/2at^2

Hope it helps :)

Objects want to continue doing what they’re doing because they are “lazy.” This is called law of inertia.

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that state unless it is being acted upon by an external force. This law is also called the law of inertia because it depends on mass.

From the given question, we can fill gaps as follows;

Objects want to continue doing what they’re doing because they are “lazy.” This is called law of inertia.

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Answer:

Explanation:

Volume = Length x width x height

Multiply the length, width and, height to get the volume of the question.

Answer:

Every gas is made up of very small particles called molecules. Molecules of a gas are separated from each other by large distances so that volume is negligible as compared to total volume of gas. The force of gravitation on the molecules is also negligible.

Hope that helps. x

:

Answer:

Static= 600/(130*9.8)=0.47

Kinetic=475/(130*9.8)=0.37

Answer:

Letter A

Explanation:

Manganese dioxide- Mn02

Nitrogen Dioxide- n02

Strontium bromide- SrBr

Answer:

Momentum is directly proportional to the object's mass and also its velocity.

Explanation:

Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v.

During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

Since we know that every element have electrons in their atoms and every atom have vacant shells.

So during chemical reactions the elements fulfill their vacant shells and form bonds between each other it can be ionic or it can be covalent bond.

But when atoms breaks the bond their will be the positively or negatively charged electrons left in the atoms.

Hence During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

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Answer:

its B hope you have a good Day

The impulse of the boxers punch is 28 kgm/s.

The given parameters;

The impulse of the boxers punch is calculated as follows;

[tex]J = Ft[/tex]

where;

The magnitude of the impulse is calculated as follows;

[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]

Thus, the impulse of the boxers punch is 28 kgm/s.

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Without friction, the car cannot stop...

Answer:

d

Explanation:

Answer:the super villain would have the ability to control electricity and could take any Metal object or weapons that anyone points at him because he is magnetic

Explanation:

When mechanical waves interact with material, it transfer its energy to the material.

Mechanical waves are the type of waves that require a medium for transporting their energy from one region to another. Mechanical waves depend on particle interaction in order to transport their energy.

The amplitude and frequency of the wave are negatively affected due to the striking of mechanical waves with the material.

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Answer:

i have a screenshot just use mine https:/ss27

Explanation:

Explanation:

For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.

ΔU=Q−W

We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.

W=FΔx

W=3N×2m

W=6J

Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.

ΔU=Q−W

ΔU=10J−6J

ΔU=4J

Answer is 4J

i think this may help you very much

The force exerted by the explosion on the piston is 2.4 N.

The given parameters:

The force exerted on the piston by the explosion is calculated as follows;

F = PA

where;

A is the area of the piston in m²

The surface area of the piston in square meter is calculated as follows;

[tex]A = 80 \ cm^2 \times \frac{(1m)^2}{(100 \ cm)^2} \\\\A = 0.008 \ m^2[/tex]

The force exerted by the explosion on the piston is calculated as follows;

[tex]F = 300 \ (N/m^2)\ \times \ 0.008 \ (m^2)\\\\F = 2.4 \ N[/tex]

The complete question is here:

In a car engine, fuel is ignited within a cylinder to cause an explosion that moves a piston. If the explosion exerts 300 Pa of pressure on a piston with a surface area of 80 cm^2, what is the force exerted on the piston?

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[tex]\\ \sf\Rrightarrow s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\Rrightarrow s=0(19)+\dfrac{1}{2}a(19)^2[/tex]

[tex]\\ \sf\Rrightarrow 475=\dfrac{361a}{2}[/tex]

[tex]\\ \sf\Rrightarrow 950=361a[/tex]

[tex]\\ \sf\Rrightarrow a\approx 2.3m/s^2[/tex]

Answer:

Please translate this into Spanish! Sorry I can't :(

Explanation:

Disadvantages of Friction:

Friction produces unnecessary heat leading to the wastage of energy.

The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects.

Forest fires are caused due to the friction between tree branches.

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

The change in the energy applied to the car is calculated as;

[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]

The final speed of the car is calculated as follows;

[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]

Thus, the final speed of the car at the given conditions is 30.1 m/s.

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Answer:

The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²

Explanation: