Answer: The empirical formula and the molecular formula of the organic compound is [tex]CHO[/tex] and [tex]C_4H_4O_4[/tex] respectively.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of [tex]CO_2[/tex] = 21.71 g
Mass of [tex]H_2O[/tex]= 5.926 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 21.71 g of carbon dioxide, =[tex]\frac{12}{44}\times 21.71=5.921g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 5.926 g of water, =[tex]\frac{2}{18}\times 5.926=0.658g[/tex] of hydrogen will be contained.
Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53 g
Mass of C = 5.921 g
Mass of H = 0.658 g
Mass of O = 10.53 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles[/tex]
Mass of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.493}{0.493}=1[/tex]
For H =[tex]\frac{0.658}{0.493}=1[/tex]
For O=[tex]\frac{0.658}{0.493}=1[/tex]
The ratio of C : H: O = 1: 1: 1
Hence the empirical formula is [tex]CHO[/tex].
empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29
Molecular mass = 104.1 g/mol
[tex]n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4[/tex]
Thus molecular formula = [tex]n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4[/tex]
Identify an alkene and carboxylic acid using primary observations
If the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation. It is not a carboxylic acid if it does not react with sodium carbonate. A substance is not an alkene or a carboxylic acid if it does not decolorize bromine water and is not acidic.
What is the flowchart for identification of an alkene and carboxylic acid?The following flowchart can be used to recognize an alkene and a carboxylic acid:
1. Start with the hypothetical unknown substance.
2. Use bromine water to test the substance.
a. An alkene is a substance that discolors bromine water.
b. Move on to the following stage if the compound does not lighten bromine water.
3. Use universal indicator paper or litmus paper to test the chemical.
a. The substance might be a carboxylic acid if it is acidic and causes the paper to turn red.
b. Go to the following step if the chemical is not acidic.
4. Use sodium carbonate to evaluate the substance.
a. A substance is a carboxylic acid if it reacts with sodium carbonate to release carbon dioxide gas.
b. The chemical is not a compound if it does not react with sodium carbonate.
Therefore, if the unknown substance decolorize bromine water, it is an alkene. If it does not, litmus paper is used to test it. If the paper turns red, then the substance may be a carboxylic acid, and the reaction with sodium carbonate serves as additional confirmation.
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Your question is incomplete, most probably the complete question is:
TASK 2 - Pass 2B.P4 Identify an alkene and carboxylic acid using primary observations. To achieve 2B.P4, learners should follow guidance to identify an alkene and a carboxylic acid (for example, ethanoic acid) from primary observations. Learners will be expected to identify an alkene in the way described in 1B.4. For ethanoic acid this is by its pH and its reaction with sodium carbonate. The guidance given to the learners could be in the form of a flowchart.
Environments have changed over millions of years. Which of these would be best for a scientist to study when investigating these environmental changes?
A. volcanic deposits
B. weather forecasts
C. fossil records
D. ocean currents (There is no science subject so ima put mathematics)
Answer:
c
Explanation:
fossil records
How many moles are in 8.7 x 104 atoms of oxygen?
This is a freebie for anyone for one get the crown
Answer:
hhh
Explanation:
What are two main ways that water is being polluted or wasted
Answer:
Chemical waste from factories is sometimes dumped into rivers and lakes, or directly into the ground. Pesticides (chemicals that kill insects) applied to farmland enter surface water and groundwater, often in large quantities. Leaks from underground storage tanks for liquids like gasoline go directly into groundwater.
Explanation:
Hope it helps! Correct me if I am wrong!
Im sure about my answer!
If you dont mind can you please mark me as brainlest?
PLZZZ HELP CHEMISTRY QUESTION DOWN BELOW IMAGE SHOWWN BELOW
Which two changes would make this reaction product-favored? 3H2 + N2 ⇄ 2NH3 + energy  A. Decreasing the pressure  B. Increasing the temperature  C. Increasing the pressure  D. Reducing the temperature
Answer:C and D
Explanation:Just did it
Increasing the pressure and Decreasing the temperature are the two changes would make this reaction product-favored.
What is Equilibrium ?It is a state when a reaction is reversible and both forward and reverse reaction occur simultaneously at the same rate .
In the process of manufacture of Ammonia , both forward and reverse reaction are taking place
N₂(g) + 3H₂ (g) → 2NH₃ (g)
2NH₃(g) → N₂ (g) + 3H₂ (g)
when these reaction occur at same rate , the state is called equilibrium and is represented by
N₂ (g) + 3H₂(g) ⇔ 2NH₃(g) +Heat
As we can see from the equation , heat is produced in the forward reaction so if we increase the temperature the reverse reaction will be favored ,
On decreasing temperature the reaction will become product favored .
While on increasing the Pressure the manufacture of Ammonia increases.
Therefore Option C and Option D are the two changes would make this reaction product-favored.
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A chromophore is:______
a. an unsaturated organic functional group that absorbs ultraviolet or visible radiation.
b. a biochemical species, such as NADH, that strongly absorbs ultraviolet or visible radiation.
c. an ion or complex of elements from the first two transition series that absorbs visible radiation.
d. a molecule that contains an electron-donor group bonded to an electron-acceptor. When radiation is absorbed, an electron is transferred from the donor to an orbital of the acceptor.
a. an unsaturated organic functional group that absorbs ultraviolet or visible radiation.
Hope this helps :D
explain why silver chloride cannot be used as an electrolyte
Answer:
This is because .It doesn't reacts with dilute acid .It is a coinage metal.
Complete the following double displacement reactions
KOH + H 2 SO 4
NaOH + HCl
Al 2 (SO 4 ) 3 + NaOH
BaCl 2 + Na 2 SO 4
PbSO 4 + Na 2 CO 3
Answer:
2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O
NaOH + HCl ⇒ NaCl + H₂O
Al₂(SO₄)₃ + 6 NaOH ⇒ 3 Na₂SO₄ + 2 Al(OH)₃
BaCl₂ + Na₂SO₄ ⇒ BaSO₄ + 2 NaCl
PbSO₄ + Na₂CO₃ ⇒ PbCO₃ + Na₂SO₄
Explanation:
In double displacement reactions, both reactants exchange their cations and anions.
2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O
NaOH + HCl ⇒ NaCl + H₂O
Al₂(SO₄)₃ + 6 NaOH ⇒ 3 Na₂SO₄ + 2 Al(OH)₃
BaCl₂ + Na₂SO₄ ⇒ BaSO₄ + 2 NaCl
PbSO₄ + Na₂CO₃ ⇒ PbCO₃ + Na₂SO₄
Describe two signs that show that a chemical reaction happens when magnesium
burns in air.
Answer:
When magnesium burns in air, the oxygen in the air reacts with magnesium metal to produce magnesium oxide.
Magnesium burns in oxygen present in the air to produce magnesium.
Can somebody please help me!!!
Answer:
force are called roll
Explanation:
force your answer give me five Points
Answer:
friction
Explanation:
The other terms honestly just don't make any sense in this context. Round objects experience less friction, since they have less of their surface touching the ground at a time. Imagine a bowling bowl: only a small part of the ball is ever touching the ground at one instant. Now imagine a waffle: almost all of the surface is touching the ground.
Human blood contains a buffer of carbonic acid (H_2 CO_3) and bicarbonate anion (HC〖O_3〗^-) in order to maintain blood pH between 7.35 and 7.45, as a value higher than 7.8 or lower than 6.8 can lead to death. In this buffer, hydronium and bicarbonate anion are in equilibrium with carbonic acid. Furthermore, the carbonic acid in the first equilibrium can decompose into CO_2 gas and water, resulting in a second equilibrium system between carbonic acid and water. Because CO_2 is an important component of the blood buffer, its regulation in the body, as well as that of O_2 , is extremely important. The effect of this can be important when the human body is subjected to strenuous condition.
Carbonic acid buffer:
H_2 CO_3 (aq)+ H_2 O(l) ↔H_3 O^+ (aq)+HC〖O_3〗^- (aq)
1. Write the equilibrium constant expression K_c for the carbonic acid buffer in the blood.
Kc = [H3O+][HCO3-] / [H2CO3]
Remember that Kc is products over reactants. Also, you do not include liquid water in a Kc expression, since liquid water has no concentration.
Based on the picture of the map, why does Buenos Aries have a higher ocean surface temperature than Cape Town even though they have the same latitude?
Water which has soaked into the ground is known as
Methanol has a melting point of -97 degrees celsius and a boiling point of 65 degrees celsius. What phase is methanol in at 80 degrees celsius? (Solid, Gas, or Liquid?)
How many moles of carbon dioxide gas occupy a volume of
81.3 L at 204 kPa and a temperature of 95.0 °C?
mol CO2
Answer:
5.42
Explanation:
I used a calculator
Answer: 5.42 mol CO2
Explanation: Uses idea gas law
True or False: With a given number of moles of solvent, the solution will always have the same concentration
Answer:
Its true
Explanation:
Hope it helps, have a great day!!!
What solid figure has two bases, but no lateral faces?
cylinder
rectangular prism
triangular prism
cone
Answer:
it is cylinder as it has two bases but no lateral faces.
briefly describe how the pH of a colourless solution could be measured using a universal indicator
Answer:
Universal indicator can show us how strongly acidic or alkaline a solution is, not just that the solution is acidic or alkaline. This is measured using the pH scale , which runs from pH 0 to pH 14.
Explanation:
~Hope this helps
HELP ME PLEASE ITS DUE TODAY
Answer:
Explanation:
S2Si
O2
C2H4
N2
CBr4
S2
I think these are correct
what is reduction potential?
Answer:
A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.
Explanation:
When magma goes down into the lower part of the mantie where it is recycled and may come right back up the ocean ridge is called..
Identify the following for an atom with 8 protons, 8 electrons, and 7 neutrons.
a. Atomic number:
b. Mass number:
c. Nuclear Notation:
d. Hyphen Notation:
please help
Answer:
i thinks its a. but iam not sure
Which describes how technology has changed society?
A. There is less food available to people.
B. People live longer than they used to
O C. It is more difficult to move goods
O d. It is hard for people to communicate
Answer:
B. People live longer than they used to
Explanation:
None of the other answers are correct.
Write the IUPAC names of the given carboxylic acids. A molecule has the condensed formula C H 3 C H 2 C H (O C H 3) C H 2 C O O H. IUPAC name: A six membered hydrocarbon ring with three double bonds. The group C O O H is attached to ring carbon one, and a chlorine atom is attached to ring carbon four. IUPAC name:
Answer:
The correct answer is -
3-methoxypentanoic acid, and
4-chlorobenzoic acid
Explanation:
1. condensed formula of the molecule is -
CH3CH2CH(OCH3)CH2COOH and the number of the carbons would be count from the end of carboxylic acid. So, the counting as given in the image, it shows there are 5 carbon so it is Penta and has methyl group on fourth carbon so 4-methyl, therefore, its IUPAC name will be - 4-methyl pentanoic acid
2. similarly for the molecule with COOH group attached with ring carbon and chlorine is represented as in the image and it shows a benzene ring and COOH group is present at C1 and chlorine is in C4 so the name would be 4-chlorobenzoic acid.
The International Union of Pure and Applied Chemistry (commonly abbreviated to IUPAC) recommends a systematic approach for the nomenclature of organic compounds, which is referred to as the IUPAC nomenclature of organic compounds. Here the IUPAC names are 4-methyl pentanoic acid and 4-chlorobenzoic acid.
In essence, the condensed structural formula is a system for writing organic compounds in a single line of text.
1. CH₃CH₂CH(OCH₃)CH₂COOH and the number of the carbons would be counted from the end of carboxylic acid. So, the counting as given in the image shows there are 5 carbon so it is Penta and has methyl group on the fourth carbon so 4-methyl, therefore, its IUPAC name will be - 4-methyl pentanoic acid
2. Similarly the molecule with COOH group attached with ring carbon and chlorine is represented as in the image and it shows a benzene ring and COOH group is present at C-1 and chlorine is in C-4 so the name would be 4-chlorobenzoic acid.
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how many oxygen molecules in 2.3x10-⁸g of molecular oxygen
Answer:
6.321 × 10^22
Explanation:
Mass of Oxygen =
3.36
g
Molar mass of oxygen (
O
2
) = 16 x 2 =
32
g
m
o
l
−
Total molecules in oxygen = Mass in grams/Molar mass x
N
A
=
3.36
32
x
6.02
x
10
23
=
6.321
x
10
22
Note:
N
A
(Avagadro's number) =
6.02
x
10
23
Hope it helps...
A liquid medicine is labeled as having 5% active ingredient, by volume. If
the dosage of the medicine is 50 mL, how much of the active ingredient is
to be ingested? *
Answer:
2.5 mL
Explanation:
Step 1: Given data
Concentration of the active ingredient (C): 5% v/vVolume of the medicine (V): 50 mLStep 2: Calculate the amount of the active ingredient in the medicine
The concentration of the active ingredient is 5% v/v, that is, there are 5 mL of the active ingredient per 100 mL of the medicine. The volume of the active ingredient is 50 mL of the medicine is:
50 mL Med × 5 mL AI/100 mL Med = 2.5 mL AI
How many grams are in 5 moles of calcium fluoride (CaF2)?
Answer:
1 moles Calcium Fluoride = 78.0748064 gram using the molecular weight calculator and the molar mass of CaF2.
A student mixes 50.0 mL of 1.00 M Ba(OH)2 with 72.8 mL of 0.375 M H2SO4.
a)Calculate the mass of BaSO4 formed.
b)Calculate the pH of the mixed solution.
Answer:
The correct answer should be 12.72 pH of the mixed solution and 9.94g mass of solid BASO4 formed.
The molecules of Ba(OH)2 are : 1.00M x 0.05L = 0.05 ( moles )
The molecules of H2SO4 are : 0.494M x 0.0864L = 0.0426816
Ba(OH)2 + H2SO4 ----> BaSO4 + 2 H2O
0.0426816<--- 0.0426816
The mixed solution is Ba(OH)2 with 0.05 - 0.0426816 = 0.0073184
The concentration of mixed solution is : 0.0073184 : ( 0.05 + 0.0864 ) = 0.054 M
The pH of mixed solution is 14 - -log[0.054] = 14 - 1.27 = 12.73 PH
And the mass of BaSO4 is 0.0426816 x ( 137 + 32 + 16 x 4 ) = 9.94 gams.