A 15.0kg block is resting on a 2.5 m long board with a coefficient of static friction of 0.45. If one end of the board is slowly raised, at what angle will the block slip?

Answer:

Yes it is matter

Explanation:

In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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Answer:

τ = 0.009 Nm

Explanation:

The torque applied on the tooth can be given by the following formula:

[tex]\tau = Fd[/tex]

where,

τ = Torque on the tooth= ?

F = Force acting on tooth = 9 N

d = distance between force and tooth axis = 1 mm = 0.001 m

Therefore, using these values in the equation, we get:

[tex]\tau = (9\ N)(0.001\ m)[/tex]

τ = 0.009 Nm

Answer:

CELL DIVISION THAT INVOLVES MITOSIS AND CELL GROWTH DUE TO TAKING IN NUTRIENTS

Explanation:

Answer: Cell growth due to taking in nutrients and Cell growth due to fertilization​.

Explanation:

Answer:

[tex]CPD = 80[/tex]

[tex]PCD = 44[/tex]

Explanation:

Given

[tex]AB || CD[/tex]

[tex]BAD = 56[/tex]

[tex]CPA = 100[/tex]

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

[tex]CPA + CPD = 180[/tex] --- angle on a straight theorem

Substitute 100 for CPA

[tex]100 + CPD = 180[/tex]

Subtract 100 from both sides

[tex]100-100 + CPD = 180-100[/tex]

[tex]CPD = 80[/tex]

Next, we calculate PCD

We have that:

[tex]DAB= ADC = 56[/tex]  --alternate angle

In triangle PCD

[tex]PCD + CPD + PDC = 180[/tex] --- angles in a triangle

Where

[tex]PDC = ADC = 56[/tex]

So, we have:

[tex]PCD +80 + 56 = 180[/tex]

[tex]PCD +136 = 180[/tex]

Subtract 136 from both sides

[tex]PCD = 180 - 136[/tex]

[tex]PCD = 44[/tex]

Answer:

use a=v-u/t formula it will be correct

Answer:

i believe that they are or there's something out there

Explanation:

:)

Answer:

8

Explanation:

The energy levels is given as

E(n) = n² * h² / ( 8 * m * L²), where

n = 1, 2, 3, 4,... etc

At ground state energy (n = 1), therefore is E(g) = h² / (8 * m * L²).

We can then say that

E(n) = n² * Eg

Therefore, to have E = 64 Eg, we must have n² = 64. And for n² to be equal to 64, we find the square root of n

n = √64

n = 8

Essentially, the needed quantum number is 8

Answer: the cyclist traveling at 12.96 m/s

Explanation:

Given that;

diameter = 0.59 m

radius = 0.295 m

the wheel makes 7 rotations in a second,

in every rotation, it travels a distance of 2πr

so

total distance

= 7 × 2πr

= 7 × 2 × 3.14 × 0.295

= 12.96 m

Therefore velocity = 12.96 m/s

so the cyclist traveling at 12.96 m/s

Answer:

D mass of the iron rod

Explanation:

A) the length of the iron rod.

B) the thermal conductivity of iron.

C) the temperature difference between the ends of the rod.

D) the mass of the iron rod.

E) the duration of the time interval

The amount of heat that will flow through an iron rod whose two ends are maintained at different temperatures would depend on the thermal conductivity of the iron, the temperature difference between the two ends, the length of the iron rod, and the duration of flow of heat.

The thermal conductivity of any material is an indication of the ability of the materials to conduct heat. The higher the thermal conductivity, the higher the amount of heat a material can conduct within a specified period. Hence, the amount of heat that will flow through the iron rod depends on its thermal conductivity.

The temperature difference between two solid materials depends on the amount of heat that will flow across the materials by conduction. The higher the difference, the more the amount of heat that will flow. Hence, the amount of heat that would be conducted depends on the temperature difference between the two ends of the iron rod

The amount of heat that would move my conduction also depends on the distance that would be traveled by the heat. Due to heat loss to the surrounding, the shorter the distance, the more the heat and vice versa. Hence, the amount of heat that will flow through an iron rod depends on the length of the iron rod.

The duration of flow also dictates the amount of heat that will flow between two regions by conduction. The more the duration, the more the heat, provided that other conditions remain constant.

The only option that the amount of heat that would be conducted does not depend on is the mass of the iron rod.

The correct option is D.

Answer: c. 1.89 x 10^14 J

Explanation:

By Einstein's equation, we know that:

E = m*c^2

Where m is the mass-consumed in this case:

m = 2.10g

And we must rewrite this in Kg, knowing that:

1kg = 1000g

Then:

m = 2.10g = (2.10/1000) kg = 0.0021 kg

And c is the speed of light:

c = 3*10^8 m/s.

Then the energy will be:

E = 0.0021 kg*(3*10^8 m/s)^2 = 1.89*10^14 Joules.

The correct option is:

c. 1.89 x 10^14J

Answer:

[tex]Fr_k=152.88\ N[/tex]

Explanation:

Net Force

The net force is defined as the vector sum of all the forces acting on a body at a certain moment.

We should recall some basic concepts and equations to solve the problem.

If no external forces are applied in the vertical direction, the weight of the object and the normal force have the same magnitude and point to opposite directions.

The friction force is defined as:

[tex]Fr_k=\mu_k N[/tex]

[tex]Fr_s=\mu_s N[/tex]

Where the subindices k and s are referred as to the kinetic and static friction forces respectively.

The condition for the object to move is that the applied force is greater than the friction force.

The crate of oranges has a mass of 30 Kg, thus its weight is:

W = m.g = 30 * 9.8 = 294 N

The normal force is:

N = W = 294 N

The kinetic friction is calculated as:

[tex]Fr_k=0.52* 294[/tex]

[tex]\mathbf{Fr_k=152.88\ N}[/tex]

Answer:

So we can have energy  for electronics. It limits the flow of electric current

Explanation:

It’s in the answer!

Answer:

Basically, the function of a resistor is always to oppose the flow of current through it and the strength of this opposition is termed as its resistance.

Answer:

10 Pa

Explanation:

Pressure is defined as force per unit area.

Mathematically, P= F/A where  P is pressure, F is force and A is area.

Force, F = 60 N

Area, A = 2*3 = 6m²

P = 60/6 = 10 Pa

Answer:

It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit

Explanation:

What is a galvanometer?

A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.

A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant

Given that,

Mass of student 1, m₁ = 90 kg

Mass of student 2, m₂ = 60 kg

Speed of student 1, v₁ = 5 m/s

To find,

The velocity of the other student.

Solution,

Using the conservation of momentum to find the velocity of the other student. Let it is v₂.

[tex]m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\v_2=\dfrac{90\times 5}{60}\\\\=7.5\ m/s[/tex]

So, the velocity of the other student is 7.5 m/s.

Answer:

The value is [tex]L = 0.0073 \ H[/tex]      

Explanation:

From the question we are told that

    The number of turns is  [tex]N = 650 \ turns[/tex]

     The length is  [tex]l = 28 \ cm = 0.28 \ m[/tex]

      The radius of the cross-section is [tex]r = 3.5 \ cm = 0.035 \ m[/tex]

Generally the cross-sectional area  is mathematically represented as

       [tex]A = \pi * r^2[/tex]

=>    [tex]A = 3.142 * 0.035^2[/tex]

=>    [tex]A = 0.00384 \ m^2[/tex]

Generally the inductance is mathematically represented as

      [tex]L = \frac{N^2 * \mu _o * A }{ l}[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]

=>    [tex]L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}[/tex]

=>    [tex]L = 0.0073 \ H[/tex]      

Answer:

178.5 Hz

Explanation:

Given that a  car approaches a train station with a speed of 24 m/s. A stationary train at the station sounds its horn which has a frequency of 166 Hz. What frequency of sound is heard by the car's driver ?

Solution

Using doppler effect formula

F = f ( V/ V- v)

Where F = frequency of sound heard by the car

f = train frequency

V = speed of sound

v = car speed

F = 166 ( 343 ÷ ( 343 - 24 ) )

F = 166 ( 343 / 319 )

F = 166 × 1.0752

F = 178.489 Hz

F = 178.5 Hz

Therefore, the frequency of sound heard by the observer in the car is 178.5 Hz approximately.

Answer:

c.) 10 to 15 minutes

Explanation:

yw :)

Answer:

c.) 10 to 15 minutes

Explanation:

Answer: All UV can have harmful effects on biological matter (such as causing cancers) with the highest energies causing the most damage.

Explanation:

Answer:

Image B

Explanation:

although I'm not exactly sure, i've recently gotten this question as well. but model B demonstrates the force- distance trade off because you can see how in that image them distance is increased in the force is decreased with the object being shorter. hopefully this helps in some way

Answer:

0 j

Explanation:

The work done by the employee on the box at the given zero displacement is 0 J.

The given parameters;

The work done by the employee on the box is calculated as follows;

W = Fd

where;

Since the employee sits on the box without moving it, the distance moved by the box = 0

W = 500 x 0

W = 0 J

Thus, the work done by the employee on the box is 0 J.

Learn more about work done and displacement here: https://brainly.com/question/8635561

Answer:

T = 10 s

Explanation:

First, we need to find the frequency of the object as follows:

[tex]Frequency = f = \frac{Speed\ in\ rpm}{60}[/tex]

where,

Speed = Angular Speed = 6 rpm

Therefore,

[tex]f = \frac{6\ rpm}{60}\\\\f = 0.1\ Hz[/tex]

Now, for time period (T):

[tex]Time\ Period = T = \frac{1}{f}\\\\T = \frac{1}{0.1\ Hz}\\\\[/tex]

T = 10 s

Answer:

3.69 rad/s

Explanation:

From the question given above, the following data were obtained:

Period (T) = 1.7 s

Angular frequency (ω) =?

Thus, we can obtain the angular frequency (ω) by applying the following formula:

ω = 2π/T

Period (T) = 1.7 s

Pi (π) = 3.14

Angular frequency (ω) =?

ω = 2π/T

ω = 2 × 3.14 / 1.7

ω = 6.28 / 1.7

ω = 3.69 rad/s

Thus, the angular frequency of the motion is 3.69 rad/s

Answer:

The PE of the mass increased by 6,972.95 J

Explanation:

Gravitational Potential Energy

It's the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

We are given the mass of m=16 slug raised by a height h=10 ft. Both units will be converted to SI standard:

1 slug = 14.59 Kg, thus

16 slug = 16*14.59 Kg=233.44 Kg

1 ft = 0.3048 m, thus:

10 ft = 10*0.3048 m = 3.048 m

Thus, the PE of the mass increased by:

U = 233.44 * 9.8 * 3.048 = 6,972.95 J

the PE of the mass increased by 6,972.95 J

The potential energy will be "5120 ft.lb".

According to the question,

Mass,

Height,

As we know the formula,

→ [tex]U = mgh[/tex]

By substituting the values, we get

→     [tex]= 16\times 32\times 10[/tex]

→     [tex]= 5120 \ ft.lb[/tex]

Thus the response above is correct.

Learn more:

https://brainly.com/question/13347447

Answer:

The number of crate to be lifted is 27

Explanation:

Given;

mass of the crates, m = 25 kg

height in which the crate is lifted, h = 1.0 m

power output, P = 110 W

time to complete the task, t = 1 minutes = 60 s

The input energy is equal to the gravitational energy due to height the crate is lifted is given as;

E(input) = mgh

E(input)  = 25 x 9.8 x 1

E(input)  = 245 J

Output energy is given as;

E(output) = P x t

E(output) = 110 x 60

E(output) = 6600 J

Let the number of crate to be lifted = n

n x E(input)  = E(output)

n x 245 = 6600

n = 6600 / 245

n = 27 crates

Answer:

[tex]velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]

Max speed = [tex]\frac{15\, \pi}{4} \,\, \frac{m}{s}[/tex]

Max acceleration = [tex]\frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}[/tex]

Explanation:

Given the description of period and amplitude, the SHM could be described by:

[tex]f(x)=5\,sin(\frac{\pi}{4}x)[/tex]

and its angular velocity can be calculated doing the derivative:

[tex]f(x)=5\, \,sin(\frac{\pi}{4}x)\\f'(x)=5\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]

And therefore, the tangential velocity is calculated by multiplying this expression times the radius of the movement (3 m):

[tex]velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]  and is given in m/s.

Then the maximum speed is obtained when the cosine function becomes "1", and that gives:

Max speed = [tex]\frac{15\, \pi}{4} \,\, \frac{m}{s}[/tex]

The acceleration is found from the derivative of the velocity expression, and therefore given by:

[tex]acceleraton(x)=-15\,\frac{\pi^2}{16}\,sin(\frac{\pi}{4}x)[/tex]

and the maximum of the function will be obtained when the sine expression becomes "-1", which will render:

Max acceleration = [tex]\frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}[/tex]

Given that,

The rate of change of current = 3.2 A/s

Emf induced in the coil = 5.7 V

To find,

The magnitude of the mutual inductance of the two coils.

Solution,

The mutual inductance between the coils is given by the formula as follows :

[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]

So, the mutual inductance of the two coils is 1.78 H.

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

[tex](P_{1})-(P_{2})=P_{3}[/tex]

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

[tex](85) - 85 = P_{3}\\P_{3}= 0[/tex]

There is no movement of any of the balls, they remain at rest after the impact.

Answer:

The ratio of the new internal energy to the old is 4

Explanation:

let the old pressure of the gas = P₁

let the old volume of the gas = V₁

then, the new pressure of the gas = 2P₁

the new volume of the gas = 2V₁

The internal energy of the gas is given as;

PV = nRT

PV = k

P₁V₁ = P₂V₂

[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]

The ratio of the new internal energy to the old is 4