A 1.5-kg ball is throw at 10 m/s. What is the balls momentum?

Answers

Answer 1

Answer : The momentum of ball is, 15 kg.m/s

Explanation :

Momentum : It is defined as the motion of a moving body. Or it is defined as the product of mass of velocity of an object.

Formula of momentum is:

where,  

p = momentum  = ?

m = mass  = 1.5 kg

v = velocity = 10 m/s

Now put all the given values in the above formula, we get:

Therefore, the momentum of ball is 15 kg.m/s


Related Questions


Aluminium is produced by the reduction of aluminium oxide
What is meant by the term reduction?

Answers

Answer:

Explanation:The word reduction in terms of chemistry means loss of Oxygen,Gain of hydrogen,Gain of electrons and loss of oxidation state.

Please mark me as brainiest.

Aluminium is extracted from aluminium oxide by electrolytic reduction.

What is reduction?

The process is termed as a reduction if

there is a loss of oxygen or an electronegative atom.there is a gain of hydrogen or an electropositive atom.loss of electrons.decrease in oxidation number.What is electrolytic reduction?

The electrolysis method used to obtain metals from molten chloride or oxides is known as electrolytic reduction.

What is the use of electrolytic reduction?

It is used in the extraction of highly electropositive metals.

To learn more about reduction and electrons here,

https://brainly.com/question/14698511

#SPJ2

When two objects are at the same temperature we say they are at

Answers

Answer:

equal temperatures

Explanation:

Does a ball rolling on an inclined plane have the same acceleration on the way up as it does on the way down?

Answers

Answer:

No, it does not.

Explanation:

According to the Law of Gravitation, something going down has more kinetic energy than something going up because it attracts pressure from around it when going down. When it goes up, it has less gravitational force and inertia also stops the ball from rolling upward. Therefore, without the amount of kinetic energy, it will not have the same amount of acceleration.


A series circuit is set up with an AA battery along with an mystery material and ammeter; however, there’s no current passing through.


A.Insulator
B.Conductor
C.Semiconductor



Answers

Answer:

A. Insulator

Explanation:

Since there is no current passing through at all.

5. A ball weighing 10 kg rolls 200 m down a frictionless incline with a 50 degree angle to the horizontal. If the ball’s initial velocity was 0 m/s, how much does the mechanical energy of the system change by the time the ball reaches its destination? A) It increased by 12%. B) It increases by 58%. C) It decreases by 12%. D) It does not change.

Answers

Answer:

D) It does not change

Explanation:

Since there is no friction in the inclined plane. Therefore, there is no loss in the total mechanical energy of the system. So according to the law of conservation of energy we can write:

Total Mechanical Energy at Start = Total Mechanical Energy at End + Frictional Loss

Total Mechanical Energy at Start = Total Mechanical Energy at End + 0

Total Mechanical Energy at Start = Total Mechanical Energy at End

It means there is no change in the total mechanical energy of the system.

Therefore, the correct option is:

D) It does not change

Which is one way to determine whether a reaction was a chemical reaction or a nuclear reaction?

Answers

Answer:

Check how much energy was released during the reaction or check for a change in total mass

What is the net force on a skydiver falling with a constant velocity of 0 m/s downward?

Answers

Since the velocity is constant then the there is 0 net force on him falling downward.

If a body of mass 2 kg is moving with a velocity of 30 m/s, then
on doubling its velocity the momentum becomes
a 30 kgm/s
b 90 kgm/s
C 120 kgm/s
d 60 kgm/s
HALPLPLPPLL

Answers

Answer:

d. 60

Explanation:

If a body of mass 2 kg is moving with a velocity of 30 m/s, then

on doubling its velocity the momentum becomes

a 30 kgm/s

b 90 kgm/s

C 120 kgm/s

d 60 kgm/s

HALPLPLPPLL

Answer:

120

Explanation:

The Nardo ring is a circular test track for cars. It has a circumference of 12.5 km. Cars travel around the track at a constant speed of 100 km/h. A car starts at the easternmost point of the ring and drives for 30 minutes at this speed.

Required:
a. What distance, in km, does the car travel?
b. What is the magnitude of the car's displacement, in km, from its initial position?
c. What is the speed of the car in m/s?

Answers

Answer: 50 km, 0, 27.78 m/s

Explanation:

Given

Circumference of the track is [tex]12.5\ km[/tex]

Speed of car is [tex]100\ km/h[/tex]

Car drives for [tex]30\ \text{minute}\ or\ 0.5\ hr[/tex]

(a)Distance traveled is

[tex]\Rightarrow D=100\times 0.5\\\Rightarrow D=50\ km[/tex]

(b)displacement of the car

It can be observed that 12.5 is a multiple of 50, that is, 50 km can be interpreted as 4 complete rounds of the track.

Therefore, the displacement of the car is zero.

(c)To convert kmph to m/s, multiply the entity by [tex]\frac{5}{18}[/tex]

[tex]\Rightarrow 100\times \dfrac{5}{18}\\\\\Rightarrow 27.78\ m/s[/tex]

135g of an unknown substance gains 9133 J of heat as it is heated from 25⁰C to 100⁰C. Using the chart below, determine the identity of the unknown substance.

Answers

Answer:

The unknown substance is Aluminum.

Explanation:

We'll begin by calculating the change in the temperature of substance. This can be obtained as follow:

Initial temperature (T₁) = 25 ⁰C

Final temperature (T₂) = 100 ⁰C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 100 – 25

ΔT = 75 ⁰C

Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:

Change in temperature (ΔT) = 75 ⁰C

Mass of the substance (M) = 135 g

Heat (Q) gained = 9133 J

Specific heat capacity (C) of substance =?

Q = MCΔT

9133 = 135 × C × 75

9133 = 10125 × C

Divide both side by 10125

C = 9133 / 10125

C = 0.902 J/gºC

Thus, the specific heat capacity of substance is 0.902 J/gºC

Comparing the specific heat capacity (i.e 0.902 J/gºC) of substance to those given in the table above, we can see clearly that the unknown substance is aluminum.

A 300-g chunk of ice (of density 0.900 g/cm3) is placed in a water bucket. A 20.0-g rock, with a volume of 2.00 cm3, is placed on top of the ice before water is filled to the top. When the ice melts and the rock drops to the bottom of the buckt, how much water spills out or needs to be added to maintain full level? Ignore the possible dependence of the densities of ice and water on temperature.

Answers

Answer:

18 cm³ of water

Explanation:

The correct procedure and explanation is in the picture attached. If you have any doubts, feel free to leave in the comments.

Hope this helps

Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg.m^2. The father exerts a force on the merry-go-round perpendicular to its radius to achieve an angular acceleration of 4.44 rad/s^2.

Required:
a. How long (in s) does it take the father to give the merry-go-round an angular velocity of 1.53 rad/s? (Assume the merry-go-round is initially at rest.)
b. How many revolutions must he go through to generate this velocity?
c. If he exerts a slowing force of 270 N at a radius of 1.20 m, how long (in s) would it take him to stop them?

Answers

Answer:

Explanation:

Given that:

the initial angular velocity [tex]\omega_o = 0[/tex]

angular acceleration [tex]\alpha[/tex] = 4.44 rad/s²

Using the formula:

[tex]\omega = \omega_o+ \alpha t[/tex]

Making t the subject of the formula:

[tex]t= \dfrac{\omega- \omega_o}{ \alpha }[/tex]

where;

[tex]\omega = 1.53 \ rad/s^2[/tex]

[tex]t= \dfrac{1.53-0}{4.44 }[/tex]

t = 0.345 s

b)

Using the formula:

[tex]\omega ^2 = \omega _o^2 + 2 \alpha \theta[/tex]

here;

[tex]\theta[/tex] = angular displacement

[tex]\theta = \dfrac{\omega^2 - \omega_o^2}{2 \alpha }[/tex]

[tex]\theta = \dfrac{(1.53)^2 -0^2}{2 (4.44) }[/tex]

[tex]\theta =0.264 \ rad[/tex]

Recall that:

2π rad = 1 revolution

Then;

0.264 rad = (x) revolution

[tex]x = \dfrac{0.264 \times 1}{2 \pi}[/tex]

x = 0.042 revolutions

c)

Here; force = 270 N

radius = 1.20 m

The torque = F * r

[tex]\tau = 270 \times 1.20 \\ \\ \tau = 324 \ Nm[/tex]

However;

From the moment of inertia;

[tex]Torque( \tau) = I \alpha \\ \\ Since( I \alpha) = 324 \ Nm. \\ \\ Then; \\ \\ \alpha= \dfrac{324}{I}[/tex]

given that;

I = 84.4 kg.m²

[tex]\alpha= \dfrac{324}{84.4} \\ \\ \alpha=3.84 \ rad/s^2[/tex]

For re-tardation; [tex]\alpha=-3.84 \ rad/s^2[/tex]

Using the equation

[tex]t= \dfrac{\omega- \omega_o}{ \alpha }[/tex]

[tex]t= \dfrac{0-1.53}{ -3.84 }[/tex]

[tex]t= \dfrac{1.53}{ 3.84 }[/tex]

t = 0.398s

The required time it takes= 0.398s

In a single-slit experiment, the slit width is 150 times the wavelength of the light.

What is the width (in mm) of the central maximum on a screen 2.6 m behind the slit?

I have tried:

y=[(1+1/2)(lambda)(2.6m)] / (150lambda)

to bring me to

y=[(1.5)(2.6)] \ (150)

giving me a y value in mm of 26

Answers

Smvkdnrr wud I row
B wit. How ir

How does a generator use the effect you noticed in the pickup coil to generate electrical energy? What energy transformations are taking place? Why does a generator make alternating current? What change would have to be made to make direct current?

Answers

Answer:

Movement of Electrons in opposite direction of the rotation of the pickup coil leads to the direction of Electrical energy ( Alternating current ).

Explanation:

For a Generator to generate electricity, Electrons that is found in the rotating coil of the Generator will experience some sort of force that makes them to start moving in a direction that is perpendicular to the direction of the rotating/pickup coil found in the Generator.

The conversion of mechanical energy (Rotation of the pickup coil ) to electrical energy takes place in the Generator

The generator makes an alternating current because electrons move in opposite direction of the rotating coil

In other to generate a Direct current using a generator we have to replace the slip rings with commutator.

Imagine you could travel to the moon where the acceleration due to gravity is 1.6 m/s^2. What would be the period of
a pendulum that is 1.0 m?
Show your work.

Answers

Answer:

4.9612 s

Explanation:

Applying,

T = 2π√(L/g)............... Equation 1

Where T = period of the pendulum, L = Lenght of the pendulum, g = acceleration due to gravity of the moon, π = pie.

From the question,

Given: L = 1 m, g = 1.6 m/s²

Constant: π = 3.14

Substitute these values into equation 1

T = 2×3.14×√(1/1.6)

T = 6.28√(0.625)

T = 6.28×0.79

T = 4.9612 s

What is the definition of Heat Transfer

Answers

Answer:

Heat transfer is an engineering discipline that concerns the generation, use, conversion, and exchange of heat (thermal energy) between physical systems.

Explanation:

Answer:

Heat transfer is a discipline of thermal engineering that concerns the generation, use, conversion, and exchange of thermal energy between physical systems. Heat transfer is classified into various mechanisms, such as thermal conduction, thermal convection, thermal radiation, and transfer of energy by phase changes.

Explanation:

hope that helps

The total resistance of a series circuit is 15.0 ohms what is the second resistance of the first resistance is 10.0 ohms?
A. less than 5.0 ohms
B. 5.0 ohms
C. 15 ohms
D. 25 ohms

Answers

I think the answer is B

A truck was carrying a substance in a tank. The molecules of that substance were moving away from each other. The truck parked overnight in a place where energy transferred out of the substance. In the morning, the substance was a gas. How were the molecules moving in the morning? Explain why the molecules were moving that way after energy was transferred out of them.

(Make it ask long as you need)
Or (short)

Answers

Answer:

In the morning the molecules were moving away from each other with a smaller speed than when the truck was carrying the substance.

Explanation:

So this helicopter pilot dropped me in the middle of an absolutely smooth frictionless
lake. He thought it was really funny. The only thing the pilot let me take is a bowling
ball. I tried to claw my way to the shore but was unable to get any horizontal force on
the super slippery zero friction ice. Explain how I can get to shore and why it will
work before I freeze to death. This test is about momentum. I wonder if my solution
has anything to do with that ...

Answers

Dang dude you are a soldier! Good job

The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. [beep] A single lap should be completed each time you hear this sound. [ding] Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over. The test will begin on the word start. On your mark, get ready, start.

explain why the lamp does not light when the input to the transformer is directed current​

Answers

Answer:

Direct current(DC) has no time varying field because current is constant as well as there is no relatively motion between coil and core(magnetic circuit) of the transformer. So there is no induced emf in secondary coil of the transformer. Tom Mounts, field engineer, and electronics technician.

Explanation:

can i have brainly if right

Direct current(DC) has no time varying field because current is constant as well as there is no relatively motion between coil and core(magnetic circuit) of the transformer. So there is no induced emf in secondary coil of the transformer.

A small spaceship whose mass is 1300 kg (including an astronaut) is drifting in outer space with negligible gravitational forces acting on it. If the astronaut turns on a 11 kW laser beam, what speed will the ship attain in 4.0 days because of the momentum carried away by the beam?

Answers

Answer:

Explanation:

Relation between energy and momentum is as follows .

E = h c / λ

E / c = h / λ

h /λ = momentum of a photon

momentum of a photon  = E /c

= 11 x 10³ / 3 x 10⁸

= 3.67 x 10⁻⁵

In 4 days no of photon

= 4 x 24 x 60 x 60 = 345600 .

momentum of photon released

3.67 x 10⁻⁵  x 345600 .

= 12.68 kg m/s

This momentum will be imparted to spaceship .

12.68 = mv

12 .68 = 1300 x v

v = .00975 m /s

= 9.75 mm /s

When 1.5 kg of mass turns into energy, how much energy is released? Find the equation, substitution, and number with units.

Answers

Explanation:

[tex]from \: einstein \: equation : \\ E = m {c}^{2} \\ E = 1.5 \times {(3 \times {10}^{8} )}^{2} \\ E = 1.35 \times {10}^{17} \: joules[/tex]

Which of the following is a problem with the estimated age of the universe?

There are stars in our galaxy that appear to be over 15 billion years old.

The universe is shrinking, which makes it is impossible to tell how old it is.

There should be more supergiants if the universe is really about ten billion years old.

There are planets in other galaxies that are less than five billion years old.

Answers

Answer:

There are stars in our galaxy that appear to be over 15 billion years old.

Explanation:

The age of the universe is the time past since the big ban event as based on observations of the early state of the universe. The comic problem with the universe is that it's estimated to be older since the time of the big bang. It also represents a contrast with objects in the galaxies such as stars, planets that could not have been present.

Based on the number on the fuse, what do you think is the maximum current allowed in this circuit?

Answers

Answer:

0.3 A

Explanation:

Build the circuit attached. Make sure the switch is turned off as you build the circuit. Set the Selected battery voltage to 10 volts.

A.      Based on the number on the fuse, what do you think is the maximum current allowed in this circuit?

Solution:

A fuse is a safety device which is used in circuits for preventing very high currents which can cause overloading or start a fire. A fuse is made up of a low resistance thin piece of metal such that the flow of high current can cause the metal to melt leading to an open circuit. A fuse lets current flow up to a maximum value before it melts and the circuit will be broken.

From the image attached, since the maximum rating of the fuse is 0.3 A, hence the maximum current that can flow through the circuit is 0.3 A.

You are designing an airplane propeller that is to turn at 2400 rpm (Fig. 9.13a). The forward airspeed of the plane is to be 75.0 m/s 75.0 m/s, and the speed of the propeller tips through the air must not exceed 270 m/s 270 m/s. (This is about 80% of the speed of sound in air. If the propeller tips moved faster, they would produce a lot of noise.) What is the maximum possible propeller radius?

Answers

Answer:

r = 1.07 m

Explanation:

The maximum radius of the propeller that can be allowed is given by the following formula:

[tex]v = r\omega\\\\r = \frac{v}{\omega}[/tex]

where,

r = maximum possible radius of the propeller = ?

v = maximum possible linear speed of the propeller = 270 m/s

ω = angular speed of the propeller = (2400 rpm)(2π rad/1 rev)(1 min/60 s)

ω = 251.33 rad/s

Therefore,

[tex]r = \frac{270\ m/s}{251.33\ rad/s}[/tex]

r = 1.07 m

At what rate is thermal energy being generated in the 2R-resistor when ε = 12 V and R = 3.0 Ω?​

Answers

Answer:

6 W

Explanation:

From the given information:

The resistance in Parallel for 2R is:

[tex]R_p = \dfrac{2R\times 2R}{2R+2R} \\ \\ R_p= R[/tex]

The equivalent resistance:

[tex]R_{eq} = R_p + R = 2R[/tex]

[tex]R_{eq} = 2(3)[/tex]

[tex]R_{eq} = 6 \ \ ohms[/tex]

The current through the circuit in R is:

[tex]= \dfrac{12}{R+R} \\ \\ = \dfrac{12}{2\times 3} \\ \\ = 2 A[/tex]

The current through the circuit in 2R is:

[tex]I_2R = (2A) \times \dfrac{2R}{2R+2R}[/tex]

[tex]I_2R = 2A \times \dfrac{1}{2} \\ \\ I_2R = 1A[/tex]

Finally, the thermal energy:

[tex]P_{2R} = (1)^2 (2R)[/tex]

[tex]P_{2R} = (1)^2 (2\times 3)[/tex]

[tex]P_{2R} = 6W[/tex]

which one hurry i need help pls dont get me wrong ..

Answers

Answer:

OPEN

Explanation:

An intentionally open circuit would be the circuit to the lights in the room that are turned off. There is no closed path available for the electricity to flow to the lights because the switch is in the "off" position which "opens" the path the electricity would normally flow through.

in a simple machine the input work is 187.5 N and output work is 125N. If load distance is 25 cm and effort distance is 75 cm calculate value of load and effort ​

Answers

Answer:

1. Laod = 500 N

2. Effort = 250 N

Explanation:

From the question given above, the following data were obtained:

Input work = 187.5 J

Output work = 125 J

Load distance = 25 cm

Effort distance = 75 cm

1. Determination of the load.

Output work = 125 J

Load distance = 25 cm = 25/100 = 0.25 m

Load =?

Output work = Load × Load distance

125 = Load × 0.25

Divide both side by 0.25

Load = 125 / 0.25

Laod = 500 N

2. Determination of the effort.

Input work = 187.5 J

Effort distance = 75 cm = 75/100 = 0.75 m

Effort =?

Input work = Effort × Effort distance

187.5 = Effort × 0.75

Divide both side by 0.75

Effort = 187.5 / 0.75

Effort = 250 N

HURRY ILL GIVE 15 POINTS
Carla draws two circuit diagrams that connect the same components in different ways as shown which statement about the circuit is correct?

Answers

Circuit A is correct

A loudspeaker, mounted on a tall pole, is engineered to emit 75% of its sound energy into the forward hemisphere, 25% toward the back. You measure an 85 dB sound intensity level when standing 3.5 m in front of and 2.5 m below the speaker. What is the speaker’s power output?

Answers

Answer:

"0.049 W" is the correct answer.

Explanation:

According to the given question,

[tex]r = \sqrt{(3.5)^2+(2.5)^2}[/tex]

  [tex]=\sqrt{8.5}[/tex]

[tex]SL=85[/tex]

As we know,

⇒  [tex]SL=10 \ log(\frac{I}{I_o} )[/tex]

     [tex]85=10 \ log(\frac{I}{10^{-12}} )[/tex]

      [tex]I=3.162\times 1^{-4} \ W/m^2[/tex]

Now,

⇒  [tex]P_{front} = I(2\pi r^2)[/tex]

               [tex]=(3.162\times 10^{-4})(2\pi\times 18.5)[/tex]

               [tex]=0.0368 \ W[/tex]

               [tex]=0.75 \ P[/tex]

or,

                [tex]=0.049 \ W[/tex]

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