Answer:
3.53 s
Explanation:
From the question given above, the following data were obtained:
Force (F) = 125 N
Spring constant (K) = 39.6 N/m
Period (T) =?
Next, we shall determine the mass of the object. This can be obtained as follow:
Force (F) = 125 N
Acceleration due to gravity (g) = 10 m/s²
Mass (m) =?
F = m × g
125 = m × 10
Divide both side by 10
m = 125 / 10
m = 12.5 Kg
Finally, we shall determine the period of vibration. This can be obtained as follow:
Mass (m) = 12.5 Kg
Spring constant (K) = 39.6 N/m
Pi (π) = 3.14
Period (T) =?
T = 2π√(m/K)
T = 2 × 3.14 × √(12.5/39.6)
T = 6.28 × √(12.5/39.6)
T = 3.53 s
Thus, the period of vibration is 3.53 s
Write the balanced equation for the formation of benzoic acid from the Grignard reagent. Include all reagents and products but not solvents.
Answer:
The correct answer is - C6H5MgBr + CO2 → C7H6O2 (without solvent)
Explanation:
Grignard reagents are the reagents formed by the chemical reaction between magnesium with an alkenyl or alkyl halide which are represented by the chemical formula RMgX where X stands for the halogen, and R is an alkyl or aryl group. These alkyl or aryl groups are based on the benzene ring.
The nature of these reagents are nucleophilic react with electrophiles such as epoxides or carbonyl groups. The formation of benzoic acid is possible with the reaction of the Grignard reagent with the carbon dioxide In H3O+ to form benzoic acid with MgBrOH.
C6H5MgBr + CO2 → C7H6O2
How many carbon atoms are there in 200 molecules of C3H2O?
O 1.20 x 1026
0 3.61 x 1026
200
600
Answer:
[tex]\boxed {\boxed {\sf 600 \ atoms \ of \ carbon}}[/tex]
Explanation:
We are given this compound with the formula: C₃H₂O
According the subscripts, 1 molecule contains 3 carbon atoms, 2 hydrogen atoms, and 1 oxygen atom.
We can make a ratio. There are 3 carbon atoms for every 1 molecule of C₃H₂O.
[tex]\frac { 3 \ atoms \ C }{1 \ molecule C_3H_2O}[/tex]
Since we want to calculate the number of atoms in 200 molecules, we can multiply the ratio by 200.
[tex]200 \ molecules \ C_3H_2O*\frac { 3 \ atoms \ C }{1 \ molecule C_3H_2O}[/tex]
[tex]200*\frac { 3 \ atoms \ C }{1 }[/tex]
[tex]600 \ atoms \ C[/tex]
200 molecules of C₃H₂O contains 600 atoms of carbon.
Determine whether each described process is endothermic or exothermic.
Wood burns in a fireplace Choose...
Ice melts into liquid water Choose...
Solid dissolves into solution, making ice pack feel cold Choose...
A process with a calculated positive q Choose...
A process with a calculated negative q Choose...
Acid and base are mixed, making test tube feel hot Choose...
Answer:
Following are the responses to the given choices:
Explanation:
Air woods is a smoking process as it releases heat.Incasereaction produces reaction energy, the response is then exothermic, while absorbs react energy, therefore the response is exothermic.Heat is essential for melting ice. Correspondingly, ice melts into liquid water as well as other reactions stop.Feel cold due to fuel absorption. That ice pack thus feels cold and brings another micro reaction to the stop.Unless the reaction's heat is positive, that process is endothermal.The reaction is exothermic unless the heat from the reaction is bad.Feel hot due to its loosening energy. A test tubefeelhot is, thus, an exothermic reaction.Ionic compounds form ________ from a repeating pattern of ions.
O fibers
O rough edges
O a sticky surface
O crystals
Answer:
crystals
It's in my science book, my class just finished this chapter.
A buffer solution contains 0.20 mol of propionic acid (CH3CH2COOH) and 0.25 mol of sodium propionate (CH3CH2COONa) in 1.50 dm3.
What is the pH of this buffer?
Enter your answer using two decimal places.
Answer:
I don't know how to do it the subject
Most acids are strong acids.
A. True
B. False
Answer:
False, There are only a few strong acids, so many people choose to memorize them. All the other acids are weak
Explanation:
Part
A certain gas is present in a 110 L cylinder at 2.0 atm pressure. If the pressure is increased to 4.0 atm, the volume of the gas
decreases to 5.5 L. Find the two constants k. the initial value of k, and kr, the final value of k, to verify whether the gas obeys Boyle's
law.
Express your answers to two significant figures separated by a comma.
View Available Hint(s)
ΤΟ
ΑΣΦ
t
2) ?
k ke =
Submit
Answer:
See explanation
Explanation:
Recall that from Boyle's law;
Volume is inversely proportional to pressure at constant temperature
V α 1/P
V = k/P
k = PV
Hence, for Boyle's law, PV = constant
In the first case;
P = 2.0 atm , V= 110 L
PV = 110 * 2.0 = 220
In the second case;
P = 4.0 atm , V= 5.5 L
PV = 4.0 * 5.5 = 22
Since PV is not constant in both cases, the gas does not obey Boyle's law.
True or False:
The geocentric model of the solar system is correct.
Answer:
True
Explanation:
What is the atomic structure for antimony
Answer:
Hmm
Explanation:
Elemental antimony adults a layer structure (space group R3m No.166) in which layers consist of fused, ruffled, six-membered rings. The nearest and the next nearest neighbors form and irregular octahedral complex, with the 3 atoms in each layer slightly closer than 3 atoms in the next
Electric configuration : 4d^10 5s^2 5p^3
How many millimeters of mercury are in 0.334 atm?
Answer:
253.83996
Explanation:
multiple the pressure value by 760
CH3CH2OH + 302 → 2C02 + 3H2O
What would be the limiting reactant in the reaction if 1 mole of
oxygen gas and 1 mole of ethanol (CH3CH2OH) reacted with
each other?
Answer:
Oxygen Gas
Explanation:
The balanced equation shows us the reactant ratio of the reaction.
This means that for every one mole of CH3CH2OH, we need 3 moles of O2 to react with it. Because we need more O2, (3x as much) than ethanol and we have the same given amount (1 mole of each), the oxygen will be the limiting reagent. (1 mole of oxygen would only require 1/3 moles of ethanol to react).
Hope this helped!
On analysis of 3.4 mg of an organic compound, 8.03 g of CO2 and 3.34 g of H2O were obtained. The percentage composition of carbon and hydrogen in the compound are.......................... respectively
Answer: The percentage composition of carbon and hydrogen in the compound are 64.4 % and 10.9 % respectively
Explanation:
Mass of [tex]CO_2[/tex] = 8.03 g
Mass of [tex]H_2O[/tex]= 3.34 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 8.03 g of carbon dioxide, =[tex]\frac{12}{44}\times 8.03=2.19g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 3.34 g of water, =[tex]\frac{2}{18}\times 3.34=0.371g[/tex] of hydrogen will be contained.
Mass of oxygen in the compound = (3.4) - (2.19+0.371) = 0.839 g
percent composition of C =[tex] \frac{\text{mass of C}}{\text{ Total mass}}\times 100= \frac{2.19}{3.4}\times 1000=64.4\%[/tex]
percent composition of H =[tex] \frac{\text{mass of H}}{\text{ Total mass}}\times 100= \frac{0.371}{3.4}\times 1000=10.9\%[/tex]
Thus the percentage composition of carbon and hydrogen in the compound are 64.4 % and 10.9 % respectively
The oceanic crust is mostly associated with the —————.
A. Thermosphere
B. Hydrosphere
C. Asthenosphere
D. Volcanoesphere
E. Atmosphere
1. Chlorofluorocarbons (CFCs) A carbon-chlorine bond in the CFC molecule can be broken by sunlight, leaving a highly reactive free radical which then goes on to destroy the surrounding ozone molecules. The energy of a C-Cl bond is 328 kJ/mole. Calculate the wavelength of light needed to break a bond in a single molecule. In which region of the spectrum (infrared, visible, UV) does this wavelength fall
Answer: The wavelength for this photon is 365 nm. The wavelength corresponds to UV region.
Explanation:
The relationship between wavelength and energy of the wave follows the equation:
[tex]E=\frac{Nhc}{\lambda}[/tex]
E= energy
N = avogadros number
[tex]\lambda [/tex] = wavelength of the wave
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]328\times 10^3J=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8m/s}{\lambda}[/tex]
[tex]\lambda=3.65\times 10^{-7}m=365nm[/tex] [tex]1m=10^9nm[/tex]
Thus wavelength for this photon is 365 nm. The wavelength of 365 nm corresponds to UV region.
What is the reaction order with respect to [A]
Answer:
it is the 1st order
Explanation:
i took that one and its the first order
What product(s) would be formed when these are the reactants? C5H12 + O2 (limited)
Answer:
Carbon dioxide and water I believe because it is a combustion reaction
Which of these statements BEST describes a possible environmental
consequence in constructing a large-scale wind farm to generate
electricity?
A Wind farms alter the regional climate.
B. Wind farms can disrupt migrating wildlife.
C. Wind farms use a renewable energy source.
D. Wind farms generate direct current electricity.
Answer:
Option B. is correct
Explanation:
Wind turbines collect the kinetic energy of wind using the turbine blades. The blades turn an electric generator as they are connected to a drive shaft, which in turn produces electricity.
These turbine blades can disrupt flying wildlife including bats and birds.
So,
wind farms can disrupt migrating wildlife.
Option B. is correct.
1.20 x 10^22 molecules NaOH to gram
Answer:
[tex]\boxed {\boxed {\sf 0.797 \ g \ NaOH}}[/tex]
Explanation:
1. Convert Molecules to Moles
First, we must convert molecules to moles using Avogadro's Number: 6.022*10²³. This tells us the number of particles in 1 mole of a substance. In this case, the particles are molecules of sodium hydroxide.
[tex]\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}[/tex]
Multiply by the given number of molecules.
[tex]1.20*10^{22} \ molecules \ NaOH *\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}[/tex]
Flip the fraction so the molecules cancel out.
[tex]1.20*10^{22} \ molecules \ NaOH *\frac {1 \ mol \ NaOH} {6.022*10^{23} \ molecules \ NaOH}}[/tex]
[tex]1.20*10^{22} *\frac {1 \ mol \ NaOH} {6.022*10^{23}}}[/tex]
[tex]\frac {1.20*10^{22} \ mol \ NaOH} {6.022*10^{23}}}[/tex]
[tex]0.0199269345732 \ mol \ NaOH[/tex]
2. Convert Moles to Grams
Next, we convert moles to grams using the molar mass.
We must calculate the molar mass using the values on the Periodic Table. Look up each individual element.
Na: 22.9897693 g/mol O: 15.999 g/mol H: 1.008 g/molSince the formula has no subscripts, we can simply add the molar masses.
NaOH: 22.9897693+15.999+1.008=39.9967693 g/molUse this as a ratio.
[tex]\frac {39.9967693 \ g \ NaOH }{1 \ mol \ NaOH}[/tex]
Multiply by the number of moles we calculated.
[tex]0.0199269345732 \ mol \ NaOH*\frac {39.9967693 \ g \ NaOH }{1 \ mol \ NaOH}[/tex]
The moles of sodium hydroxide cancel.
[tex]0.0199269345732 *\frac {39.9967693 \ g \ NaOH }{1}[/tex]
[tex]0.0199269345732 *39.9967693 \ g \ NaOH[/tex]
[tex]0.79701300498 \ g \ NaOH[/tex]
The original measurement of molecules has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 0 tells us to leave the 7 in the hundredth place.
[tex]0.797 \ g \ NaOH[/tex]
1.20*10²² molecules of sodium hydroxide is approximately 0.797 grams.
select two correct answers
Answer:
a and b
Explanation:
Opals are formed when water in oceans dribble through the Earth, picking up silica from sandstone along the way. And really, that only happens when the ocean water touches the land.
take it before its gone
what is the freezing point of glucose?
Answer:
In Fahrenheit it is 294.8°F and in Celsius it is 146°C.
If the Sun suddenly lost all of its gravity, which statement would best describe how the planets would move?
a
The planets would stop moving.
b
The planets would all collide into each other.
c
The planets would travel in a straight line.
d
The planets would continue moving in a circular path.
Answer:
It's B
Explanation:
It's the sun's gravitational pull that keeps our planets revolving around it and as soon as it's gone it's a high chance of it being a pinball machine and everything colliding into each other.
Write the balanced NET IONIC equation for the reaction that occurs when ammonium bromide and sodium hydroxide are combined. This reaction is classified as fill in the blank 6 . A. Strong Acid Strong Base B. Weak Acid Strong Base C. Strong Acid Weak Base D. Weak Acid Weak Base The extent of this reaction is: fill in the blank 7 . A. ... Below 50% B. ... 50% C. ... Above 50% D. ... 100%
Answer:
c
Explanation:
What makes the human thumb so special?
Answer:
The thumb alone is controlled by nine separate muscles; The hand has been used as a symbol of protection since ancient times; The human hand is different to the hands or paws of other animals, because it has fingers and a thumb that can work together. Each finger has 3 bones and the thumb has two bones
Explanation:
nothing. lol .-. o.O
Reaction 1: Solid sodium hydroxide dissolves in water to form an aqueous solution of ions. ????????????H(????) → ????????+(????????) + ????H −(????????) + x1????????
Reaction 2: Solid sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????????H(????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x2????????
Reaction 3: An aqueous solution of sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????+(????????) + ????H −(????????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x3????J
Procedure Reaction
1 a. In the glassware menu, take out a 50 mL graduated cylinder and a foam cup. From the tools menu, take out the scale. From the solutions stockroom, move the distilled water and solid NaOH onto the workbench.
b. Transfer 50.0 mL of water to the foam cup. To do this, drag the carboy of water onto the graduated cylinder. (Before you release the mouse button, the cursor will show a "plus sign" to indicate that it is the recipient). A transfer textbar will appear, enter "50.0" mL and click on pour. (You will notice that the graduated cylinder now reads 50.0 mL).
c. Weigh about 1 gram of solid sodium hydroxide pellets, NaOH(s), directly into the foam cup and record its mass to the nearest 0.01 gram. To do this, place the foam cup on the balance so it registers a mass, then click the "Tare" button. Drag the NaOH bottle onto the foam cup. (When you release the mouse, the bottle will be tipped to show that it is in the pour mode). Next, type "1.00" grams into the transfer bar and then click pour. Note that the balance now reads the mass of the transferred NaOH. You may now take the cup off of the scale.
d. Click on the graduated cylinder, record its temperature and then drag it onto the foam cup. (When you release the mouse, the graduated cylinder will be tipped to show that it is in pour mode.) Enter "50.0" mL in the transfer bar and then click pour. Record the highest temperature. e. Remove the foam cup and graduated cylinder from the workbench. (Right click on the item and select "remove.")
Reaction 2
a. Take the 0.5 M HCl from the strong acids cabinet and a fresh foam cup and a fresh 50 mL graduated cylinder from the glassware menu and place them on the workbench. The procedure for Reaction 2 is the same as for Reaction 1 except that 50.0 mL of 0.50 M hydrochloric acid solution is used in place of the water. After measuring 50.0 mL of the HCl solution into the graduated cylinder, proceed as before with steps b-e of the procedure for Reaction 1.
Reaction 3
a. Take out a 25 mL graduated cylinder, a fresh foam cup, the 1.0 M HCl and the 1.0 M NaOH. (If you are running out of room on the workbench, you may remove the previously used chemicals.) Use the graduated cylinder to measure and transfer 25.0 mL of 1.0 M HCl into the foam cup. Pour an equal volume of 1.0 M sodium hydroxide solution into a clean graduated cylinder.
b. Record the temperature of each solution to the nearest 0.1 oC. Pour the sodium hydroxide solution into the foam cup and record the highest temperature obtained during the reaction.
Data and Analysis
Reaction 1Reaction 2Reaction 3
Mass of solution* (g) 1.03g 1.03g
Initial temperature(°C) 25oC 25OC 25OC
Maximum temperature (°C) 30.3oC 37oC 31.7oC
Temperature change (∆T)
Heat energy q (kJ)
Moles of NaOH
Molar heat of reaction (-q/mol) also known as Enthalpy change,
DH (kJ/mol)
The conversion of more than one substance reactant into one or more distinct substances, products, and subsequent discussion can be characterized as follows:
Reaction Calculation:Calculating the Reaction 1:
[tex]NaOH\ (s) \rightarrow Na^+ \ (aq) + OH^- \ (aq) + X_1\ \ KJ ......................... (1)[/tex]
[tex]NaOH[/tex] mass = [tex]1\ g[/tex]
[tex]H_2O[/tex] mass = [tex]50 \ mL = 50\ g[/tex]
water heat of [tex]s_p[/tex] = [tex]4.186\ \frac{ J}{ g\ ^{\circ}C}[/tex]
[tex]\Delta T[/tex] = final temp - initial temp [tex]= 30.3 - 25 = 5.3^{\circ} \ C\\[/tex]
Therefore
Calculating the releasing heat
= mass × sp heat × [tex]\Delta T[/tex]
= 50 × 4.186 × 5.3 J
= 1109.3 J
Calculating the [tex]NaOH[/tex] mass [tex]= 1\ g = \frac{1}{ 40}\ mole= 0.025 \ mole[/tex]
Calculating the releasing heat per mole:
[tex]\to NaOH = \frac{1109.3}{ 0.025} = 44372\ J = 44.4\ KJ[/tex]
Thus
[tex]\to X_1 = 44.4\ KJ[/tex]
Calculating the Reaction 2:
[tex]NaOH \ (s) + H^+\ (aq) + Cl^- \ (aq) \rightarrow Na^+ \ (aq) + Cl^- \ (aq) + H_2O + X_2 \ KJ\\[/tex]
Calculating the net ionic from the equation:
[tex]NaOH\ (s) + H^+\ (aq) \rightarrow Na^+ \ (aq) + H_2O \ (l) + X_2 \ KJ ................................... (2)[/tex]
Calculating the [tex]NaOH[/tex] mass:
[tex]= 1\ g = \frac{1 }{ 40} = 0.025\ mole[/tex]
Calculating the [tex]HCl[/tex] mass:
[tex]= 50\ mL = 50\ g[/tex] [ density = 1 approx]
sp heat of the solution [tex]= 4.186 \frac{J}{g\ ^{\circ}C}[/tex] [ assume the sp heat same as water]
[tex]\Delta T[/tex] = final temp - initial temp [tex]= 36.97 - 25 = 11.97^{\circ} \ C[/tex]
Calculating the releasing heat:
= mass × sp heat × [tex]\Delta T[/tex]
= 50 × 4.186 × 11.97 J
= 2505.3 J
Calculating the releasing heat per mole in [tex]NaOH[/tex]:
[tex]= \frac{ 2505.3 }{ 0.025} = 100212\ J = 100.2 KJ[/tex]
Thus
[tex]X_2 = 100.2 \ KJ[/tex]
Calculating the Reaction 3:
[tex]Na^+ \ (aq) + OH^-\ (aq) + H^+ \ (aq) + Cl^- \ (aq) \rightarrow Na^+\ (aq) + Cl^-\ (aq) + H_2O + X_3\ KJ[/tex]
Calculating the net ionic in the given equation
[tex]H^+ + OH\rightarrow H_2O\ (l) + X_3\ KJ .............................................................. (3)[/tex]
Calculating the volume of [tex]NaOH[/tex]:
[tex]= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole[/tex]
Calculating the volume of HCl:
[tex]= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole[/tex]
Calculating the total volume
[tex]= 50 \ mL = 50\ g[/tex] { density = 1]
Calculating the sp heat in the solution
[tex]= 4.186 \frac{J}{ g \ ^{\circ} C}[/tex] [ assumed the sp heat is the same as water]
[tex]\Delta T[/tex] = final temp - initial temp [tex]= 31.7- 25 = 6.7^{\circ}\ C[/tex]
Calculating the releasing heat
= mass × sp heat × [tex]\Delta T[/tex]
= 50 × 4.186 × 6.7 J
= 1402.3 J
Calculating the releasing heat per mole in [tex]NaOH[/tex]:
[tex]=\frac{1402.3 }{ 0.025} \ J\\\\= 56092\ J\\\\= 56,09\ KJ[/tex]
Therefore
[tex]X_3 = 56.09 \ KJ\\\\X_1 = 44.4\ KJ\\\\X_2 = 100.2\ KJ\\\\X_3 = 56.09\ KJ\\\\X_2 - [ X_1+ X_3 ] = 100.2 - [44.4 + 56.09]\ = 100.2 - 100.49= -0.29[/tex]
So, the difference is equal to zero.
[tex]\to X_2 = X_1 + X_3[/tex]
This is due to the fact that if we add the reaction (1) and (3) we get the reaction (2)
Calculating the difference percentage:
[tex]= [\frac{0.29 }{100.2} ] \times 100 = 0.29\%[/tex]
The number of joules released in reaction 1 would be 4 times what is released in the calculation if we used 4 g of [tex]NaOH[/tex].
[tex]\to 4 \times 1109.3\ J = 4437.2 \ J\\\\[/tex]
Calculating the [tex]NaOH[/tex] moles [tex]= \frac{4}{40} = 0.1[/tex]
[tex]\to X_1 = \frac{4437.2}{ 0.1} = 44372 \ J = 44.4\ KJ[/tex]
As a result, it has no bearing on the solution's molar heat.
Find out more about the reaction here:
brainly.com/question/17434463
Please help I will give you brainly
Observe the activity in your classroom. You can observe people, objects, and parts of your actual classroom as you
begin to notice changes in matter. Collect data for two examples of changes in matter. Use the Changes in Matter
observation questions to determine if your examples are physical or chemical changes.
Your answer should include the following: two examples, the type of change for each, and how the examples were
formed. You can use this format:
Example 1
Type of Change:
How examples were formed:
Please help me
Answer: Microphones are a type of transducer - a device which converts energy from one form to another. Microphones convert acoustical energy (sound waves) into electrical energy (the audio signal). Different types of microphone have different ways of converting energy but they all share one thing in common! Furthermore, Example 1: Crushing a can.
Type of change:
Developmental – May be either planned or emergent; it is first order, or incremental. ...
Transitional – Seeks to achieve a known desired state that is different from the existing one. ...
Transformational – Is radical or second order in nature.
Heat in the amount of 100 kJ is transferred directly from a hot reservoir at 1400 K (TH) to a cold reservoir at 600 K. Calculate the entropy change of the two reservoirs. The entropy change of the two reservoirs is kJ/K. Is the increase of entropy principle satisfied
Answer:
ΔS = - 0.125 Kj/K decreased entropy
Explanation:
From ΔH = TΔS => ΔS = ΔH/T
= 100Kj/(600K - 1400K) = - 188Kj/800K = - 0.125 Kj/K
Entropy in the cooler flask would have 'decreased' (i.e.; more ordered state) at 600K.
Below is a diagram of a man pushing a furniture to the left with 100N of force. Which of the following statements is incorrect?
A.) The furniture does not move if the force of friction is 100N to the right.
B.) The force exerted by the man on the furniture is equal to the force exerted by the furniture on the man.
C.) The force of friction must be lower than 100N for the cabinet to move.
D.) The force exerted by the man and the force of friction must be balanced in order to accelerate it to the left.
Answer:
If I'm not mistake it should be D
Explanation:
Please inform me if im right or wrong.
How much work is done by a person who lifts a weight 2 meters off of the ground by using a force of 55 Newtons?
O 27.5 Joules
O 57 Joules
53 Joules
O 110 Joules
Answer:
D. 110 Joules
Explanation:
Work = Force x Distance
The given force here is 55 Newtons, and the distance the object moved against the force is 2 meters.
Therefore 2 x 55 = 110 Joules of Work.
Hope this helped!
How many grams of Ca metal are produced by the electrolysis of molten CaBr2 using a current of 10.0 amp for 2.44 hour??
Answer:
17.95 g
Explanation:
The electrolysis of CaBr₂ → Ca²⁺ + 2Br⁻
Ca₂⁺ + 2e⁻ → Ca
Recall that:
Charge (Q) = current (I) × time (t)
Q = 10.0 × 2.4 × 3600
Q = 86400 C
Number of moles of electron = [tex]\dfrac{charge \ Q}{faraday's \ constant}[/tex]
[tex]=\dfrac{86400}{96485} \\ \\ =0.8955 \ mol[/tex]
No of moles of Ca = [tex]\dfrac{1}{2} \times 0.8955[/tex]
= 0.44775 moles
Mass of Ca = no of moles × molar mass of Ca
= 0.44775 mol × 40.08 g/mol
= 17.95 g