Answer:
950 torr
Explanation:
Step 1: Given data
Initial volume of the gas (V₁): 1.00 LInitial pressure of the gas (P₁): 760 torrFinal volume of the gas (V₂): 0.800 LFinal pressure of the gas (P₂): ?Step 2: Calculate the final pressure of the gas
If we assume ideal behavior and constant temperature, we can calculate the final pressure of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
P₂ = P₁ × V₁/V₂
P₂ = 760 torr × 1.00 L/0.800 L = 950 torr
3) How many grams of calcium hydroxide are necessary to create 49.5 mL of a 1.55 M solution?
Answer:
5.68g
Explanation:
how many lone pairs are on the central atom in GeH4?
Which carbohydrate strengthens plant cells?
A. glucose
B. glycogen
C. cellulose
D. lactose
Answer:
a
Explanation:
Answer:
c
Explanation:
edge
Chlorine gas and solid phosphorus combine to produce phosphorus trichloride gas.
Write a balanced chemical equation for this reaction.
I need help with chemistry :(
Answer:
How may we help kind sir
Explanation:
and if this was for points thanks
A student is given an antacid tablet that weighs 5.4630 g. The tablet is crushed and 4.3620 g of the antacid is added to 200. mL of simulated stomach acid. It is allowed to react and then filtered. It is found that 25.00 mL of this partially neutralized stomach acid required 13.6 mL of a NaOH solution to titrate it to a methyl red end point. It takes 27.7 mL of this NaOH solution to neutralize 25.00 mL of the original stomach acid. How much of the stomach acid (in mL) has been neutralized in the 25.00 mL sample that was titrated
Solution :
It is given that :
Weight of the antacid tablet = 5.4630 g
4.3620 gram of antacid is crushed and is added to the stomach acid of 200 mL and is reacted.
25 mL of the stomach acid that is partially neutralized required 13.6 mL of NaOH to be titrated for a red end point.
27.7 mL of [tex]$NaOH$[/tex] solution is equivalent to [tex]$25 \ mL$[/tex] of the original stomach acid. Therefore, 13.6 mL of NaOH will take x [tex]$\frac{25\text{ mL of original stomach acid}}{\text{27.7 mL of NaOH}}$[/tex]
= 12.27 ml of the original stomach acid.
Cells are made of cells true or false
false
cells are made up of nucleus and cytoplasm and it's contained within the cell membrane
Most cooking utensils are made up of aluminum because aluminum is _____
Explanation:
Cooking utensils, such as pots, pans and menu trays, are often made from aluminium because it is lightweight and conducts heat well, making it energy-efficient for heating and cooling. These properties also make it a preferred material for packaging.
Which of the following answers is true for the following statement?
The conjugate acid of a strong base is:
O aweak acid
O an amphiprotic acid
O a polyprotic acid
O a lousy (or very weak) acid
O a strong acid
it is either "aweak acid or a lousy (or very weak) acid"
Phosphorus is implanted into silicon. The implant parameters are a dose of 1015cm-2at an energy of 150keV.a)Find the depth of the peak of the implant profile and its value at that depth.b)If the wafer originally had 1016cm-3of boron uniformly distributed throughout, find the depth(s) at which the concentration of phosphorus is equal to the concentration of boron.
Answer:
a) ≈ 4.99 / cm^3
b) 0.515 um
Explanation:
Given data:
energy = 150 Kev
dose of 10^15 cm^-2
A) find the depth of the peak of the implant profile and its value at that depth
expression for implant profile = written below in the attached file
value of the peak depth ≈ 4.99 / cm^3
B ) determine the depth at which the concentration of phosphorus is equal concentration of boron
= 0.515 um
attached below is the detailed solution to the problem
2). H2S and SO2 as follows,(8pt)
H2S + SO2 ------>S + H2O
In a particular experiment, 7.95 g of sulfur is produced by the reaction of 7.5 g of H2S with 12.75 g of SO2.
What is the % yield of sulfur?
Answer: 75.7 % yield
Explanation:
The balanced chemical equation is:
[tex]2H_2S+SO_2\rightarrow 3S+2H_2O[/tex]
According to stoichiometry :
68.2 g of [tex]H_2S[/tex] will require = 64 g of [tex]SO_2[/tex]
Thus 7.5 g of [tex]H_2S[/tex] will require = [tex]\frac{64}{68.2}\times 7.5=7.0g[/tex] of [tex]SO_2[/tex]
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 68.2 g of give = 96 g of
Thus 7.5 g of [tex]H_2S[/tex] give =[tex]\frac{96}{68.2}\times 7.5=10.5g[/tex] of [tex]S[/tex]
% yield=[tex]\frac{\text{Actual yield}}{\text {Theoretical yield}}\times 100=\frac{7.95g}{10.5g}\times 100=75.7\%[/tex]
Thus 75.7 % yield is there.
How many moles are contained in 325 gram sample of ammonium dichromate (NH4)2Cr2O7
Answer:
Hyba odpowiedzi c. Hyba
Mole can be defined as the number of molar mass units of the compound in the sample. The moles of ammonium dichromate in 325 grams sample is 1.29 mol.
What is molar mass?The molar mass can be given as the mass of each atom in the formula unit. The molar mass of ammonium chromate is given as:
[tex]\rm (NH_4)_2Cr_2O_7=2(N)+4\;\times\;2(H)+2(Cr)+7(O)[/tex]
Substituting the mass of each atom to identify the molar mass of ammonium chromate:
[tex]\rm (NH_4)_2Cr_2O_7=2(14)+4\;\times\;2(1)+2(52)+7(16)\\ (NH_4)_2Cr_2O_7=28+8+104+112\\ (NH_4)_2Cr_2O_7=252 \;g/mol[/tex]
The molar mass of ammonium dichromate s 252 g/mol. The moles of the compound in 325 g is given as:
[tex]\rm Moles=\dfrac{mass}{molar\;mass} \\\\Moles=\dfrac{325\;g}{252\;g/mol}\\\\ Moles=1.29\;mol[/tex]
The moles of ammonium dichromate in the sample are 1.29 mol. Thus, option c is correct.
Learn more about moles, here:
https://brainly.com/question/15209553
In what type of reaction is water always a product
when hydrogen and oxygen combine then they form water as product
also in neutralization reaction water form as product
hope it helps
Water is always a product in a type of chemical reaction called a neutralization reaction.
A reaction is a process that involves the transformation of one or more substances into one or more different substances.
Neutralization reaction is type of reaction occurs when an acid and a base react together to form a salt and water. The general equation for a neutralization reaction is:
[tex]\rm acid + base \rightarrow salt + water[/tex]
In this type of reaction, the hydrogen ions ([tex]\rm H^+[/tex]) from the acid combine with the hydroxide ions ([tex]\rm OH^-[/tex]) from the base to form water ([tex]\rm H_2O[/tex]). The remaining ions from the acid and the base combine to form a salt.
Therefore, water is always a product in a neutralization reaction, which occurs when an acid and a base react together to form a salt and water.
Learn more about reaction here:
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A 9.56 sample of CuS is found to contain 6.35 g of copper what is the percent by mass of the copy and sulfur in this compound? (show your work)
Answer:
%Cu = 66.4%
%S = 33.6%
Explanation:
Step 1: Given data
Mass of CuS: 9.56 gMass of Cu: 6.35 gStep 2: Calculate the mass of S
The mass of CuS is equal to the sum of the masses of Cu and S.
mCuS = mCu + mS
mS = mCuS - mCu
mS = 9.56 g - 6.35 g = 3.21 g
Step 3: Calculate the percent by mass of each element
We will use the following expression.
%Element = mElement / mCompound × 100%
%Cu = mCu / mCuS × 100% = 6.35 g / 9.56 g × 100% = 66.4%
%S = mS / mCuS × 100% = 3.21 g / 9.56 g × 100% = 33.6%
(R)-Limonene is found in many citrus fruits, including oranges and lemons. Draw its structures and identify the relationship between them.
Answer:
we cant draw jn this
Explanation:
because it contin citric acid
What cell tissue helps carry messages? :
options:
muscular
nervous
connective
Answer:
Nervous
Explanation:
Nervous tissue is composed of two main cell types: neurons and glial cells. Neurons transmit nerve messages.
What pair of properties do all solids have?
Answer:
Has definite shape and volume
Solids have high melting point
Explanation:
what is the difference between zinc and magnesium
3.
Question
Many chemical warfare reagents readily convert into reactive 3-membered ring intermediates (although
maybe not the Joker's venom from the Batman comics). In turn, these intermediates can damage DNA by
what type of chemical reaction?
Your answer
O a. Elimination
O b. Sn1
OC. SN2
O d. None of the above
Answer:
I think it's letter B
Explanation:
Hope it helps correct if I'm wrong
If a ball rolling down a hill is half way between the top and bottom, how much potential energy does the ball have compared to kinetic energy?
Answer:
The gravitational potential energy and kinetic energy of this ball should be equal (assuming that there is no energy loss due to friction.)
Explanation:
The ball loses gravitational potential energy as it rolls down the hill. At the same time, the speed of the ball increases, such that the ball gains kinetic energy.
If there is no friction on this ball (and that the ball did not deshape,) all the gravitational potential energy that this ball lost would be converted to kinetic energy.
If the gravitational field strength [tex]g[/tex] is constant throughout, the gravitational potential energy of an object in that gravitational field would be proportional to its height.
If [tex]m[/tex] denote the mass of this ball, the gravitational potential energy ([tex]\rm GPE[/tex]) of this ball at height [tex]h[/tex] would be [tex]{\rm GPE} = (m \cdot g) \cdot h[/tex], which is proportional to [tex]h\![/tex].
The value of [tex]g[/tex] near the surface of the earth is indeed approximately constant (typically [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex].)
At halfway between the top and bottom of this hill, the height of this ball would be [tex](1/2)[/tex] of its initial value (the value when the ball was at the top of the hill.) Because the [tex]\rm GPE[/tex] of this ball is proportional to its height, at halfway down the hill, the [tex]\rm GPE\![/tex] of this ball would also be [tex](1/2)\![/tex] its initial value.
However, if there was no friction on this ball (and that the ball did not deshape,) that [tex](1/2)[/tex] of the initial [tex]\rm GPE\![/tex] of this ball was not lost. Rather, these [tex](1/2)\![/tex] of the initial [tex]\rm GPE[/tex] would have been converted to the kinetic energy ([tex]\rm KE[/tex]) of this ball.
Hence, when the ball is halfway down the hill:
[tex]\displaystyle \text{GPE halfway down the hill} = \frac{1}{2}\, \text{Initial GPE}[/tex].
[tex]\begin{aligned}& \text{KE halfway down the hill}\\ &= \text{Initial GPE} - \text{GPE halfway down the hill}\\ &= \text{Initial GPE} - \frac{1}{2}\, \text{initial GPE}\\ &= \frac{1}{2}\, \text{Initial GPE}\end{aligned}[/tex].
Therefore:
[tex]\begin{aligned}& \text{GPE halfway down the hill} \\ &= \frac{1}{2}\, \text{Initial GPE} \\ &= \text{KE halfway down the hill}\end{aligned}[/tex].
In other words, under these assumptions, when this ball is halfway down the hill, the gravitational potential energy and the kinetic energy of this ball would be equal.
The total pressure in a container is 37.9 psi. There are two gases in the container. Gas A exerts a pressure of 18.4 psi. What is the pressure of gas B?
Answer:
19.5
Explanation: using dalton law pt=p1+p2+p3...
the total pressure is 37.9 so to get pressure of gas b subtract pressure of gas a from total pressure.37.9-18.4 gas b equals 19.5
The lithosphere ______ part of the earth’s crust.
A. Gaseous
B. Solid
C. Water
D. Liquid
Answer:
The lithosphere solid part of the earth's crust
The volume of water in a graduated cylinder is 88 mL. After a small object is placed in the cylinder, the volume increases to 100 mL. What is the volume of the object? First give your answer in milliliters, then in cubic centimeters.
Answer:
12mL or 12 cubic centimeters.
Explanation:
The displacement of water is equal to the volume of the object.
100 mL - 88 mL = 12 mL
One milliliter is equal to one cubic centimeter.
Which combination will make a buffer?
A. NaOH and NaCl
B. KOH and KC1
C. HC1 and NaCl
D. CH3COOH and CH3COONa
Answer:
D
Explanation:
A buffer solution contains (1)a weak base and its salt, or (2) a weak acid and its salt.
So, the combination of the weak acid CH3COOH and its salt CH3COONa will make a buffer.
Answer:
D. CH3COOH and CH3COONa
Explanation:
A buffer is made of:
- a weak acid + its conjugate base
- a weak base + its conjugate acid
A. NaOH is a strong base
B. KOH is a strong base
C. HCl is a strong acid
TEST QUESTION FOR CHEMISTRY GENIUSES ONLY...
Answer:
HBr has an electronegativity difference of .76 because Hydrogen's electronegativity is 2.2 and the electronegativity of Bromide is 2.96, and by the chart, it has a polar-covalent bond
Hope this helps!
What volume, in mL, of 0.100 M NaOH is required to neutralize 35.0 mL of 0.102 M hydroiodic acid HI?
Answer:
35.7 mL NaOH
Explanation:
M1V1 = M2V2
M1 = 0.100 M NaOH
V1 = ?
M2 = 0.102 M HI
V2 = 35.0 mL
Solve for V1 --> V1 = M2V2/M1
V1 = (0.102 M)(35.0 mL) / (0.100 M) = 35.7 mL NaOH
Is the bond length in HCl the same as that in DCl? The wavenumbers of the J = 0 1 rotational transitions for H35Cl and 2H35Cl are 20.8784 and 10.7840 cm–1, respectively. Accurate atomic masses are H = 1.007825 amu, 2H = 2.0140 amu, and 35Cl = 34.96885 amu. Based on this information alone, can you conclude that the bond lengths are the same or different in the two molecules?
Is this statement true or false?
All gymnosperms lose their leaves in the winter.
Answer:
they do fall off of themselves
Answer:
True!
Explanation:
They usually fall off in the winter
6. The drawing shows Samir riding his mountain bike.
i) Draw a circle around the places on the drawing where there
should be a lot of friction.
ii) Explain why there should be a lot of friction in these places.
Answer:
You Need To Upload The Photo Then I Will Help You :)
Explanation:
2 NaOH + H2SO4 → 2 H2O + Na2SO4
How many grams of water are produced from 203.50 grams of H2S04?
Answer:
[tex]m_{H_2O}=74.8gH_2O[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible to realize there is a 1:2 mole ratio of sulfuric acid to water; thus, given the mass of the former and its molar mass (98.07 g/mol), it is possible to determine the mass of produced water as shown below:
[tex]m_{H_2O}=203.50gH_2SO_4*\frac{1molH_2SO_4}{98.07gH_2SO_4}*\frac{2molH_2O}{1molH_2SO_4} *\frac{18.02gH_2O}{1molH_2O}\\\\m_{H_2O}=74.8gH_2O[/tex]
Regards!