A 10.0 kg block is released from rest down a 30° ramp.
It slides 6.0m along the ramp against a frictional force
of 16N. What is its speed after sliding 6.0m along the ramp?
*SOLVE USING ENERGY

The speed or the tangential velocity of the satellite to keep it in its orbit is  3,073.5 meters per second.

The gravitational force between two objects is given by:

F = GMm/r²

Where:

G = constant of gravity = 6.674 x 10⁻¹¹ N.m²/kg²

M, m = mass of each object

r = distance between objects

Parameters given in the problem:

M = 5.972 x 10²⁴ kg

m = 750 kg

r = 6371 + 35,800 = 42,171 km = 42,171,000 m

Hence,

F = 6.674 x 10⁻¹¹ x 5.972 x 10²⁴ x 750 / 42,171,000²

   = 168.1 N

This is equal to centripetal force:

F = m  . v² / r

168.1  = 750 .  v² /  42,171,000

v² = 9,446,304

v = 3,073.5 m/s

Hence, the tangential velocity of the satellite to keep it in its orbit is  3,073.5 m/s

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The rate of the distance from planar to radar is 150m.

=300 sin30

= 300 x 0.5

=150m

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Answer:

ur gay

Explanation:

i said so

Hence there exist no solution for such angular position, in other words there is no fourth order maximum fringe.

The distance between the two consecutive peaks or troughs of a wave is known as its wavelength. It is calculated in the wave's direction.

The angular position of the bright fringes in the double slit interference is given by the following relation

[tex]m\lambda=d\sin\funcapply\left(\theta_m\right)[/tex]

Where,

m: Is the dazzling fringe's order, m.

[tex]\lambda :[/tex]580-nm (Is the wavelength of the incident light on the double slit.)

d: 0.100mm (Is the distance between the centers of the two slits.)

[tex]\theta_m:[/tex] is the angle at which the mth fringe is located.

[tex]\begin{aligned}\theta_4 & =\sin ^{-1}\left(\frac{4 \lambda}{d}\right) \\& =\sin ^{-1}\left(\frac{4 \times 580 \times 10^{-9}}{1.00 \times 10^{-4}}\right)\end{aligned}[/tex]

    [tex]=\sin ^{-1}(0.02)\\=1.14[/tex]

Where, the sine function can never have a value greater than 1 , hence there exist no solution for such angular position

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Consider the light spectrum. The maximum Doppler shift for spectral lines from stars is a few hundred km/s. The lines of even the nearest quasars are significantly more redshifted.

Describe the spectrum of light.

The term "light spectrum" refers to the range of various wavelengths that a light source emits. Light is measured in nanometers (nm). Each nanometer corresponds to a wavelength of light or a band of light energy. Visible light is the portion of the spectrum between 380 and 780 nanometers (nm).

What kind of light spectrum does that entail?

The frequency of the light determines the hue of the light in the visible spectrum. A rainbow or the split light from a prism always has the same visible spectrum.

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Answer:

Inductance or mutual inductance

Energy produced in one circuit induces energy in another

(such as high voltage produced by a coil from input by say, a 12V battery)

The molar mass of the gas is

43.008 g/mol

Avogadro stated that "Equal volumes of all gases at the same temperature and pressure contain the same number of molecules". Hence at standard temperature and pressure 1 mole of a gas occupies 22.4 liters of volume.

1 mol = 22.4 liters

Given a gas with 1 L and mass of 1.92 g at STP

Number of moles = 1 L / (22.4 L/mol) = 0.0446 mol

The molar mass = mass of gas / number of moles

molar mass = 1.92 g / 0.0446 mol

molar mass = 43.008 g/mol

Hence, molar mass of the gas is

43.008 g/mol

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The frequency of the second overtone if the fundamental frequency is 308 Hz is equal to 1540 Hz.

An overtone can be described as any resonant frequency above the fundamental frequency of a sound. Overtones can be defined as all pitches higher than the lowest pitch within an individual sound. While the fundamental can be described as usually heard most prominently, overtones are present in any pitch except a true sine wave.

The lowest normal frequency is called the fundamental frequency, while the higher frequencies are known as overtones.

Given, the fundamental frequency, f₀ = 30 8 Hz

The relationship between the fundamental frequency and the second overtone is given by

f₂ = 5 f₀

f₂ = 5 × 308 = 1540 Hz

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The screwdriver being described above has a mechanical advantage of 65 N. Accordingly, this straightforward device would exert 65N of force on the can's lid for every 20N of force applied to the screwdriver.

A screwdriver's handle can have its torque increased by increasing the diameter of the handle. The force exerted by a person's hand on the handle must be farther away from the screwdriver's shaft in order to increase the torque that is applied to the screw by the tool.

The mechanical advantage and force that a screw can exert for a given applied force increase as the distance between its threads decreases. However, since most real screws have high levels of friction, the mechanical advantage they provide is less than that predicted by the previous equation.

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Answer:

A carton of mass 50-kg slides across an icy surface at a speed of 4 m/s. Conclusion : The momentum of a carton of given mass moving with a particular velocity is 200 kg−m/s .

The image is inverted and real because the question tells us that the image was formed on a screen.

When the rays come together, a true image is created. A virtual image is always formed above the principal axis, therefore it is always upright, as opposed to a real image, which is always formed below the principal axis and is always inverted.

An image that can be projected onto a screen is a real image. Behind the lens, a virtual image appears to emerge.

The image is inverted, magnified, and real for an object that is between one and two focal lengths from the lens.

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So work done by non-conservative forces = -0.868 joules.

As per the data given in the question,

It is given that:

Weight of leaf = 0.017 Kg = 17 grams.

Initial height was 5.3 m

Speed on landing was 1.3 m/s,

So, to find the total non conservative work we will apply the work-energy theorem

The work-energy theorem states that the net work done on a system is equal to the change in kinetic energy, or that the work done by the sum of all forces acting on a particle equals the change in kinetic energy of the particle.

So, the value of energy lost [tex]=-\left(mgh-\frac{1}{2} m v^2\right)[/tex]

[tex]=-\left(17 \times 10^{-3} \times 9.8 \times 5.3-\frac{1}{2} \times 17 \times 10^{-3} \times(1-3)^2\right) \\& =-\left(882.98 \times 10^{-3}-14.365 \times 10^{-3}\right) \\& =-0.868 \mathrm{~J}[/tex]

Forces = -0.868 joules.

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The mohorovicic discontinuity is the Boundary where the crust gives way to the mantle

What is Mohorovicic discontinuity ?

The line separating the Earth's crust and mantle is known as the Moho discontinuity. Because it was found by a Croatian scientist named Andreaja Mohorovicic, it retains that name. Within the (lithospheric) plate, this boundary denotes a change in seismic wave velocity from the crust to the uppermost mantle. The surface that separates the earth's crust from its mantle, located roughly 24 to 30 miles (40 to 50 km) below the continents and 6-7 miles (10 to 12 km) below the ocean floor.

According to the above definition

We get to know that

The mohorovicic discontinuity is the Boundary where the crust gives way to the mantle

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When you punch the pack of ice, you notice that cold pack rapidly becomes quite cold. This is because, chemical reaction took place absorbing thermal energy from the pack.

Chemical reactions that absorb energy are called endothermic. In an endothermic reactions, more energy is absorbed when the bonds in the reactants are broken than it is released when new bonds are formed.

The process in making the cold pack is the physical act of dissolving. When ammonium nitrate is dissolved in water, that process is endothermic and thus producing the cold pack. All the reaction absorb energy, for example thermal energy from heat for its activation.

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The precept of the conservation of momentum dictates that because the stone enters the water and pushes a number of the water downwards, the stone is compelled upwards.

There are 3 unique axes in any delivery, known as longitudinal, transverse, and vertical axes. The movements around them are called the roll, pitch, and yaw respectively.in order for the boat to move, the force of the wind pushes at the sail and reasons the boat to move.

Start something shifting, deliver impetus to something, as in A press convention set the brand new assignment in motion. it is also put as set the wheels in motion, as in permit's set the wheels in motion for the brand new library wing. This idiom dates from approximately 1800.

The answer is C, the force is a result of the interaction between the oars and the water the boat is visiting. that is the force that actions the boat forward.

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Their speed after collision is 2.5.

What is the reason for this?

An ice skater with a mass of 50 kg is moving at a speed of 6m/s.

The ice skater with 50 kg mass collides with a second stationary skater whose mass is 70 kg.

These skaters cling together after the collision and they also move without friction.

Their speed after the collision would be as follows:

Formula: mv = mv

from above information, we know that

Mass of first skater is m= 50 kg

Speed of first skater v= 6m/s

Mass of second skater is m= 70 kg

Speed after collision v=?

mv = mv

50 x 6 = (50 + 70) v

v = 50 x 6 / 120 = 2.5

So therefore, their speed after collision would be 2.5.

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Both balls have the same final speed.

Based on Newton's second law of motion,

force = momentum/time change

Momentum change = force time

(force time)/mass = change in speed

When two 1.0 kg stationary cue balls are struck by cue sticks with equal force and time.

Therefore both stationary cube balls will have the same final speed.

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The acceleration of block B is 0.5 and tension is 42.8 lb.

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

mass = 40 lb

u_k = 0.15.

P = 50 lb

theta = 10

Length of the rope

L=s + s+ Constant + s,

differentiate with respect to time

0=2a,+a,

a = 2a, (magnitude only)

a=0.5

At equilibrium, V = 0

N =40 + 8

N  = 48 lb

K=μk

f, =0.15%48 = 7.2 1b

D Alembert principle

Σ F x = ma

P-T-T-f₁ = (40+8/32.2)a

50 - 2T - 7.2 = 1.4907a

2T +1.4907a, = 42.8

2T +1.4907x0.5a, = 42.8 lb

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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The force with which the man presses the knife against the stone is 2.96 N.

Given that,

Diameter of the stone d = 45 cm = 0.45 m

Radius r = 45/2 cm = 22.5 cm = 0.225 m

Initial angular velocity ω₀ = 200 rpm = 200* 2π/6 rad/s = 20.94 rad/s

Final angular velocity ωf = (1 - 0.1)* 200 rpm = 180 rpm = 180* 2π/6 rad/s = 18.85 rad/s

Mass of the stone m = 25 kg

Coefficient of kinetic friction μ*k = 0.2

Time t = 10 s

Part a:

By using the equation of motion with uniform angular acceleration we will find out the angular acceleration of grindstone:

ω* f = ω₀ + α*t

⇒ α = ( ω* f - ω₀) / t = (18.85 rad/s - 20.94 rad/s)/ (10s) = -0.21 rad/s²

Negative sign shows that the wheel is decelerating.

Part b:

Consider the rim of grindstone as a solid disk, therefore the moment of inertia

I = 0.5*m*r² = 0.5*25* (0.225)²

We know that, Torque = Force* perpendicular distance

τ = (μ*k*F)*r ----(1)

Also:

τ = I* α = 0.5*25* 0.225²* 0.21 = 0.133 N-m

F = 0.133/(0.2*0.225) = 2.96 N

Thus, the force with which the man presses the knife against the stone is 2.96N.

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The time it takes for it to travel through the air is 5m / 343 m/s = 14.57 msec.

We know that it travels faster through the metal, so if the difference is 11, then tm = 11–14.57 ms

which means the speed through the metal is 5/0.00066 = 7575 m/s

But this is not a good answer, as the speed of sound in the air can vary over a large range. And the difference between 11 and 11.66 ms is small.

For example, the 343 number is at 20ºC. At 25ºC it is 346 m/s, which has a travel time of 11.55 ms, and when you subtract, you get 0.55 ms, or a speed of 7330 m/s. So it depends on the exact temperature, which you did not define.

Temperature is a measure of hot or cold expressed on one of several scales including Fahrenheit and Celsius. Temperature indicates the direction in which heat energy spontaneously flows. Temperature is a measure of how hot or cold something is Specifically.

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Optional equipment includes an alternate static source.

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A spherical asteroid with a radius of 823 km has an escape speed of 4 103 m/s.

Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational force acting on it. Its symbol is "g," and its unit is m/s2. Gravitational acceleration is a vector quantity, having a magnitude and a direction.

(a) The given values are

[tex]$$r=500 \mathrm{~km}$$[/tex]

[tex]$$\Rightarrow a=3.0 \mathrm{~ms}^{-2}$$[/tex]

[tex]$$\Rightarrow v=1000 \mathrm{~ms}^{-1}$$[/tex]

[tex]$$\Rightarrow h=1000 \mathrm{~km}$$[/tex]

We know that the formula for gravitational acceleration is given as

[tex]$$a_g=\frac{G M}{r^2}$$[/tex]

And the formula for the escape velocity is given by

[tex]$$v=\sqrt{\frac{2 G M}{r}}$$[/tex]

Substituting for gravitational acceleration in the above formula we get

[tex]& \Rightarrow v=\sqrt{\frac{2 a_g r^2}{r}} \\[/tex]

[tex]& \Rightarrow v=\sqrt{2 a_g r}[/tex]

Substituting the given values for the radius and gravitational acceleration.

[tex]$$\Rightarrow v=\sqrt{2(3.0)\left(500 \times 10^3\right)}$$[/tex]

[tex]& \therefore v=1.732 \times 10^3 \mathrm{~ms}^{-1}[/tex]

The complete question is,
(a) What is the escape speed on a spherical asteroid whose radius is 5 (lind whose gravitational acceleration at the surface is 3.0 [tex]\mathrm{~ms}^{-2}$[/tex]

(b) How far from the surface will a particle go if it leaves the asteroid's surface with a radial speed of[tex]$1000 \mathrm{~ms}^{-1}$[/tex]

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Answer:

Electric field on the surface of the ball 28 kV/m

Explanation:

Given:

R = 15 cm = 0.15 m

q = 7.0·10⁻⁸ C

________________

E - ?

Electric field on the surface of the ball:

E = k·q / R²

E = 9·10⁹·7.0·10⁻⁸ / (0.15)² ≈ 28 000 V/m    or   E = 28 kV/m

Answer:7.99

Explanation:

The statement predicts magnetic flux toward being 37.82*10⁻⁷ Wb, 131.73*10⁻⁷ Wb and 131.73*10⁻⁷ Wb

It typically sits between the engine and the ignition module of your car. When the automobile key is turned, solenoids (also known as start solenoids or starter relay) operate by combining big electric pulses from your vehicle's charge with smaller electrical impulses from ignition system.

(a). Flux is given by

Ф= BACosФ

μ₀ηIL² cos0

= 4*π*10⁻⁷*1370*3.11*0.0275²

=  37.82*10⁻⁷ Wb

(b). Here diameter and length are equal

Ф = BACosФ

    = μ₀ηI(π(L/2)²)cos 0

    = 4*π*10⁻⁷*1370*3.11*3.14*(0.028)²

    = 131.73*10⁻⁷ Wb

(c). Here as length is greater than diameter the flux will be same as flux    on solenoid        

Ф = 131.73*10⁻⁷ Wb

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The complete question is-

A single-turn square loop of side L is centered on the axis of a long solenoid. In addition, the plane of the square loop is perpendicular to the axis of the solenoid. The solenoid has 1370 turns per meter and a diameter of 7.70 cm, and carries a current of 5.11 A.

Part A: Find the magnetic flux through the loop when L= 2.75 cm .

Part B: Find the magnetic flux through the loop when L= 5.60 cm .

Part C: Find the magnetic flux through the loop when L= 13.5 cm .

The percentage decrease in the tension of the dulcimer string vibration is 99.09%.

Current vibration = 247 Hz

Required vibration = 260 Hz

We know that'

= V = vμ

= √ (T/μ)

Combining the two equations of two different vibrations'

= (T₁ / T₂) = (v₁/v₂)²

The percentage decrease is =

= [ 1 - (T₁ / T₂) ] X 100%

= [ 1 -  (v₁/v₂)² ] X 100%

= [ 1 -  (247/260)² ] X 100%

= [ 1 - 0.009025] X 100 %

= 99.09 %

The string with is supposed to vibrate at 260 Hz is vibrating at 247 Hz, thus the percentage decrease required to reduce the tension so that it vibrates at correct frequency is 99.09%.

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The Total work done lifting the bucket to the top of the building is 405 kg m

What is work?
Work in physics is the energy that is transmitted to or from a object when a force is applied along a displacement. In its simplest form, it equals the goods of the force's magnitude and the distance travelled for a constant force directed in the same direction as the motion. When a force is applied, it is said to have a component that points inside the direction of a displacement of the application point.

The work done lifting the bucket to the top of the building can be calculated by multiplying the force of the weight of the bucket by the distance it is moved. In this case, the force is equal to the mass of the bucket and sand, which is 30 kg, and the distance is 15 m. So, the work done is:
Work = Force x Distance

    = 30 kg x 15 m

    = 450 kg m
However, as the bucket is leaking sand, the mass of the bucket and sand is decreasing as it is being lifted. The mass of the bucket and sand at the top of the building will be less than 30 kg and the amount of work done will be less than 450 kg m.

To calculate the work done lifting the bucket to the top of the building, we need to calculate the mass of the bucket and sand at the top of the building. We can do this by subtracting the amount of sand lost from the initial mass of the bucket and sand. As the bucket leaks 0.1 kg of sand each meter it is lifted, the mass of the bucket and sand at the top of the building can be calculated as:
Mass at top of building = 30 kg - 0.1 kg x 15 m
                       = 27 kg

Now, we can calculate the work done lifting the bucket to the top of the building by multiplying the force of the weight of the bucket and sand at the top of the building by the distance it is moved. In this case, the force is equal to the mass of the bucket and sand at the top of the building, which is 27 kg, and the distance is 15 m. So, the work done is:
Work = Force x Distance

    = 27 kg x 15 m

    = 405 kg m

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In surface waves, circular motion refers to particle motion. The particles that make up the majority of the medium are present in both transverse and longitudinal waves.

And travel both perpendicularly to the direction of the transported energy and parallel to it. Surface waves have particle motion that is neither longitudinal wave nor transverse waves. Motion is the phenomenon whereby an item shifts in relation to time. Motion is quantitatively characterized in terms of the body's change in position with respect to the observer's frame of reference as well as the velocity, acceleration, and speed of the body. Each material particle vibrates in a longitudinal wave about its usual rest position.

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A: The  momentum of the first player be 450  kg.m/s.

The  momentum of the second player be 800 kg.m/s.

B:  The total momentum of the football players be 1250  kg.m/s.

C: The velocity of the football players after the collision be 7.14 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

One has a mass of 75 kg and is moving at 6 m/s.

The second has a mass of 100 kg and is moving at 8 m/s

So, momentum of the first player = mass * velocity

= 75×6 kg.m/s

= 450  kg.m/s.

The momentum of the second player = mass * velocity

= 100×8  kg.m/s

= 800 kg.m/s.

If the two football players collide, the total momentum of the football players be =  450  kg.m/s + 800 kg.m/s = 1250  kg.m/s.

The velocity of the football players after the collision be = total momentum/total mass =  1250  kg.m/s./(75+100)kg = 7.14 m/s.

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A horizontal ideal spring with a spring constant of k is linked to a mass m object that is at rest on a frictionless surface. By lowering m, the system's oscillation frequency can be raised.

What is an example of frequency?

The number of times that a specific data value occurs is its frequency. A data value's frequency is represented by the letter f. In the event that five students achieve The grade A was said to have a frequency of five, much like in science.

What does frequency serve to accomplish?

The frequency, a crucial factor in science and engineering, describes the temporal rate of change observed in oscillatory and periodic phenomena, including mechanical vibrations, audio signals (sound), radio waves, and light.

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