a 10 kilogram steel ball is dropped from the top of a tower 100 meters high the kinetic energy of the ball just before it sttikes the ground is most nearly​

Answers

Answer 1

Explanation:

If we assume negligible air resistance and heat loss, we can assume that all of the Gravitational potential energy of the ball will turn into Kinetic energy as it falls toward the ground.

Therefore our Kinetic energy = mgh = (10kg)(9.81N/kg)(100m) = 9,810J.


Related Questions

WRITE A PARAGRAPH ABOUT PRESSURE

Answers

Answer:

pressure is a horrible thing to go through, it can lead to many bad side effects, like burn out and it can also lead to high blood pressure, head aches, heart problems, depression, anxiety, and many more damaging effects. Pressure can destroy someones mental health if not dealed worth properly

I hope this is okay! I'm not sure what pressure you meant

Which type of pressure are you referring to ?

what is it that makes a magnet different from a piece of iron that is not mangetic?​

Answers

Answer:

Under normal conditions, a magnetic material like iron doesn't behave like a magnet because the domains don't have a preferred direction of alignment. On the other hand, the domains of a magnet (or a magnetized iron) are all aligned in s specific direction.

help me with this please :((

Answers

Answer:

huh?

Explanation:

When two ocean plates come together, one ocean plate __________________
under the other, causing a chain of ________________ __________________
to form.

Answers

Answer:

A subduction zone is also generated when two oceanic plates collide — the older plate is forced under the younger one — and it leads to the formation of chains of volcanic islands known as island arcs.

Explanation:

It takes a crane 59s to lift a flagstone using 342 W of power. How much work is done on the flagstone? ​

Answers

Answer: The work done on the flagstone is 20178 J

Explanation:

Power is the rate at which work is done . It is equal to the amount of work done divided by the time it takes to do the work.

[tex]Work=Power\times time[/tex]

Given : work = ?

Power = 342 W = 342J/s

Time = 59 s

[tex]Work=342J/s\times 59s=20178J[/tex]

Thus the work done on the flagstone is 20178 J

- During a certain period, the angular position of a rotating object is given by: = − + , where  is in radian and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the rotating object at = Sec.

Answers

The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by [tex]$\theta =2t^2 +10t+5$[/tex], where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, [tex]$\theta =2t^2 +10t+5$[/tex]

∴ Angular speed is   [tex]$\omega = \frac{d \theta}{dt}$[/tex]

                                 ω = 10 + 4t

And angular acceleration is [tex]$\alpha = \frac{d \omega}{dt}$[/tex]

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(0)^2 +10(0)+5$[/tex]

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

b). At time, t = 3.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(3)^2 +10(3)+5$[/tex]

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

                                   

                                           

Read this quotation:

"… my father, the King, is old and feeble. He has only me to help him take care of his people. This terrible dragon has driven them from their homes, carried away their cattle, and ruined their crops."

Which character says these words?


St. George


the Princess in "Robin Hood and the Golden Arrow"


the Princess in "The Last of the Dragons"


the Princess in "St. George and the Dragon"

Answers

Answer:

the Princess in "St. George and the Dragon"

Answer:

The princess in st. George and the dragon

Explanation:

Have a good day

HELP! WILL GIVE BRAINLIST!!!
- What effect do oceans have on the climate?
a. Oceans produce extreme cold.
b. Oceans moderate temperatures and climate.
c. Oceans have little effect climate.
d. Oceans create extreme temperatures.

Answers

The answer is for this is C

Answer:

b. Oceans moderate temperatures and climate.

Explanation:

i had this on my quiz and it was right =]

A 75kg bicyclist (including the bicycle), initially at rest at the top of a hill, coasts down the hill, reaching a speed of 14.6m/s at the bottom of the hill. The distance and height of the hill are shown. Neglect any friction impeding the motion and the rotational energy of the wheels. List the energy types at the initial and final time and whether work and loss (due to non-conservative forces) occur as well as the corresponding amounts of energy.

Answers

The energy type at the initial time is potential energy and the energy at the final time or position is kinetic energy.

What is the law of conservation of energy?

The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.

Based on the law of conservation of mechanical energy, the formula for the change in the kinetic energy and the potential energy of the bicyclist is given as;

K.Ei + P.Ei = K.Ef + P.Ef

where;

K.Ei is the initial kinetic energy of the bicyclistK.Ef is the final kinetic energy of the bicyclistP.Ei is the initial potential energy of the bicyclistP.Ef is the final potential energy of the bicyclist

The kinetic energy of the bicyclist increases with increase in the velocity of the bicyclist while the potential energy increases with increase in the height of the bicyclist.

At the initial position when the bicyclist is at rest, the kinetic energy is zero, so the only energy at the initial position is potential energy because the height is maximum.

In addition, at the final position, the velocity of the bicyclist is maximum and the height is zero, so the only energy at the final position is kinetic energy.

Learn more about conservation of energy here: https://brainly.com/question/166559

#SPJ1

A fish swimming at a rate of .6 m/s notices a huge shark. Three seconds later, the fish is swimming at a speed of 3 m/s. What is the fish's acceleration?

0.8 m/s/s
-0.8 m/s/s
12.5 m/s/s
-12.5 m/s/s

Answers

Answer:

C

Explanation:

???

i think

draw position time graph when speed is increasing​

Answers

Explanation:

We need to draw position-time graph when the speed is increasing.

The slope of position-time graph gives the speed of an object.

Position means distance covered.

When the speed of an object is increasing with time. It means it is moving with increasing speed.

The attached figure shows the position -time graph when speed is increasing​.

Can u anser 5,6 on the picture

Answers

Answer: Number 6 is Periods

Explanation:

Hurricane or typhoons occur when large areas of the open ocean soak up heat from the sun t or f​

Answers

Answer: true

Explanation:

a squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy

What is the squirrels mass

Answers

Answer:

yeet yeet yeet yeet

Explanation:

Kinetic energy (K.E):-

So, the Mass of the Squirrel is 0.51 Kg (or) 510 grams.

A squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy.

What is the squirrel’s mass?

Answer: 0.51 kg

An object at rest has no net force acting on it.
True or False​

Answers

That’s True bc an unbalanced force would need to keep and object in motion at a constant velocity.

Answer:

True

Explanation:

The object is at rest, which means it's not moving, so there is no net force on it, according to Newton's First Law.

If the velocity of an object changed from 30 m/s to 60 m/s over a period of 10 seconds what would the average acceleration be ?

Answers

3 meters per second squared (3 m/s2)

As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
seconds. Calculate the acceleration of the horse.

Answers

As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
seconds. Calculate the acceleration of the horse.
Can anybody help ?

Describe what happens to the moving boat when the oars are out of the water and the forward thrust is zero

Answers

Answer:

The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.

13. Austin rode his bike 10 m/s for two minutes. How far did he travel? A. 200 meters B. 1200 meters C. 1000 meters D. 20 meters​

Answers

Answer:

B. 1200

Explanation:

60 sec in one min in 2 min there will be 120 sec. 10x120=1200

Two soccer players run toward each other. One player has a mass of 85 kg
and runs west with a speed of 8 m/s, while the other has a mass of 105 kg
and runs east with a speed of 7 m/s. What is the total momentum of the
system made up of the two players?

Answers

Answer:

Total momentum, p = 55 kg-m/s

It is given that,

Mass of player 1, m₁ = 85 kg

Mass of player 2, m₂ = 105 kg

Speed of player 1, v₁ = -8 m/s (west)

Speed of player 2, v₂ = 7 m/s (east)

Momentum is equal to the product of mass and velocity. For this system, momentum is given by :

p=m_1v_1+m_2v_2p=m

1

v

1

+m

2

v

2

p=85\ kg\times (-8\ m/s)+105\ kg\times 7\ m/sp=85 kg×(−8 m/s)+105 kg×7 m/s

p = 55 kg-m/s

The total momentum of the system made up of the two players is 55 kg-m/s.

Answer:

p = 55 kg * m/s east

Explanation:

The answer above explains it neatly, but leaves the direction out of the answer. The player heading east has more momentum, so the net momentum of the system is east.

An object that falls and accelerates solely as a result of gravity is said to be in
(2 points)
A. terminal velocity
B. free fall
C. air resistance
D. terminal acceleration

Answers

I think the answer is c

show your work. john uses a 25N force to push a boulder off a cliff that is 312m tall. What is the work done on the boulder?​

Answers

Answer:7800

work=force x distance

Force in Newtons

Distance in Meters

Work in Joules

A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?

Answers

Answer:

either its 12 or 0.402

Explanation:

You bought a helium balloon for a friend’s winter birthday. The outside temperature was -34 degrees C. The store was at a comfortable 298K. The volume of the balloon immediately after the store clerk filled it was 6 liters. What was the volume after you brought it outside? Show your work. Make sure to include units.

Answers

Answer:

4.81 L

Explanation:

From the question given above, we obtained the following information:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = – 34 °C

Final Volume (V₂) =?

Next, we shall convert – 34 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = – 34 °C

T(K) = – 34 + 273

T(K) = 239 K

Thus, –34 °C is equivalent to 239 K

Finally, we shall determine the final volume of the balloon as follow:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = 239 K

Final Volume (V₂) =?

V₁ / T₁ = V₂ / T₂

6 / 298 = V₂ / 239

Cross multiply

298 × V₂ = 6 × 239

298 × V₂ = 1434

Divide both side by 298

V₂ = 1434 / 298

V₂ = 4.81 L

Thus, the volume of the balloon when it was brought outside the store was 4.81 L.

a metallic cube whose each side is 10 cm is subjected to a shearing force of 100 kg. The top force is displaced through 0.25 cm with respect to the bottom. calculate the shearing stress strain and modulus​

Answers

Answer:

9.8×104Nm−2,0.025,3.92×106Nm−2

Solution :

Here, L=10cm=10×10−2m

F=100kgf=100×9.8N

ΔL=0.25cm=0.25×10−2m,

Shearing stress =FL2=100×9.8(10×10−2) Sheraing strain =ΔLL=0.25×10−210×10−2 = 0.025 Shear Modulus of elasticity, G=Shearing stressShearing strain=9.8×1040.025

=3.92×106Nm−2

Explanation:

Physical values in the real world have two components: magnitude and

Answers

Answer:

Dimension.

Explanation:

12. A baseball player throws a ball. While the 700.0-g ball is in the pitcher’s hand, there is a force of 125 N on it. What is the acceleration of the ball?

Answers

Answer:

F=ma

125N=.7*a solve for a.

Explanation:

A 0.15 kg ball is moving with a velocity of
35 m/s. Find the momentum of the ball.

Answers

Answer:

5.25 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.15 × 35

We have the final answer as

5.25 kg.m/s

Hope this helps you

(HELP PLEASE)What are some reasons people produce synthetic materials?

Answers

Answer:

Explanation:

Synthetic fabrics, such as nylon and polyester, are produced entirely from chemicals. Natural fabrics, such as cotton, silk, and wool are made of fibres from plants and animals. Synthetic fabrics are useful because they have very different or enhanced (improved) properties in comparison to natural materials.

Shows a car travelling around a bend in the road. The car is travelling at a constant speed. There is a resultant force acting on the car. This resultant force is called the centripetal force. (i) In which direction, A, B, C or D, does the centripetal force act on the car? Tick ( ) one box. A B C D (1) (ii) State the name of the force that provides the centripetal force.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete but the missing figure is in the attachment below.

When an object is travelling around a circular path, there is a force that tends to draw that object towards the center of the circular path and keep the object moving in the curved path, that force is called the centripetal force. From this description, it can be deduced that the direction of the centripetal force that acts on the car (in the attachment below) is D.

The name of the force that provides this centripetal force is frictional force. This is the force that prevents the car from slipping off the road; keeping it moving in the curved path.

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