A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?

When NaOH is added to water, it separates into Na+ and OH-. The hydroxyls make it more basic.

A basic solution is an aqueous solution containing more OH⁻ ions than H⁺ ions.

When NaOH as a solute is mixed into the solvent like water, it separates NaOH into Na+ and OH-. The sodium ions Na⁺ have little effect on the solution, but the hydroxyls OH⁻ ions makes the solution more basic.

Thus, NaOH form a basic solution by the presence of OH⁻ ions  into it.

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Using law of conservation of momentum

[tex]\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3[/tex]

[tex]\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3[/tex]

[tex]\\ \sf\Rrightarrow 7500-21000=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow -13500=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow v_3=-3m/s[/tex]

The feeling can either be positive or negative.

A positive feeling can occur when one performs very well in the given home. Also, a positive feeling can come from a high level of satisfaction in the homework. When you complete your homework on time using the recommended steps, you will be sure to do well on the homework.

In other hand, a negative feeling may result from poor performance in the homework. In ability to complete the homework or missing some steps in the homework can increase your level of trepidation even before seeing your score.

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Happy Holidays!

We can use the following equation to solve for the gravitational force:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

[tex]F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}[/tex]

Answer:

e = k q / r² then,

e = 9×10^9 * 1×10^-6 / 50² = 3.6 N/C

hope this helps ❤.

Hi there!

[tex]\large\boxed{\text{Angular acceleration.}}[/tex]

For a rigid body rotating about a fixed axis, its angular characteristics ⇒ angular acceleration and velocity are constant throughout.

However, its LINEAR velocities/accelerations differ because of the following relationships:

v = ωr

a = αr

Thus, a point closer to the axis of rotation has a smaller linear velocity or acceleration compared to a point along the edge.

Answer:

2 miles

Explanation:

Answer:

Atomic mass

Explanation:

Answer:

atomic mass

Click thanks if thankc if this helped

Answer:

There are many forces involved in the game of football. These are: Force of Gravity, Normal Force, Force of Friction, and Applied Force. Force of Gravity applies to football when the football is thrown or kicked, when a player jumps in the air to avoid a tackle or catch a ball, and is constantly being applied.

Explanation:

How physics is used in football?

When you throw a football across the yard to your friend, you are using physics. You make adjustments for all the factors, such as distance, wind and the weight of the ball. The farther away your friend is, the harder you have to throw the ball, or the steeper the angle of your throw.

Answer:

Vertebrate zoology

Explanation:

Have a great day!

Explanation:

What we know:

Sa + Sb = 350 km

Ta + Tb = 4h

S = Vt

With these equations above we can write a system of equations and find Tb, as you see in the picture(s).

After having Tb you can easily find Ta and then Sa and Sb. Hopefully it was clear.

Answer:

Doubling the large mass

Explanation:

By doubling the mass you will get more gravational force

Answer: This problem may arise when your father never bought a shoe before. A male is bad at buying accesories and guessing the size, so the mother should have bought a pair of shoes. Or it can also be that your father has a short term memory or that he never knew the size of your feets. The feet might also have irregular growth for which it grows more than the normal size but such cases are rare to be seen.

You can prevent this by going with your father and selecting the shoe of your size. Or you can simply send your mother to buy it for you instead. Or another perfect choice could be is that you just dont ever send your father to buy anything for you or just never buy a pair of shoes. Wear the shoes that you always did or buy it yourself since your the one who is supposed to know the size of your feets. Another possible solution could be that you can make use of the money by gifitng them to someone close to you.

Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

[tex] \tan(x) = \frac{opp}{adj} [/tex]

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]

[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]

Now we take the arctan or inverse tan of 1/2.

[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]

Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.

The western and southern component have a negative displacement as shown in the graph.

Let the southern component be -x

The western component is half of -x = -x/2

Since the angle is with the south, the trigonometric ratio to be used to find the angle is:

Tan θ = -×/2 /-x

Tan θ = 1/2

θ = tan^-1(0.5)

θ = 26.6°

Therefore, angle of the wind with the south is 26.57°.

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Answer:

potential energy = mgh = 300 × 10 × 6m = 18000 joule or 18 kilo joule.

Explanation:

Answer:

5) A 200n

F net=0n

6) B 50n

F net=0n

7) C 200n

F net= 900n, up

8) D 80n

F net=60n,left

9) E 300n

F net=60n,left

10)???

11) G 20n

F net=30n,Right

__________________________________

All the answers is hard

correct me if i'm wrong

Answer:

I believe its A: Sports biomechanics.

Answer:

We are required to analyze the conservation of kinetic energy in a perfectly inelastic collision.

kinetic energy:K=1/2mv²

momentum:p=mv

Explanation:

Using the equations for final velocity in terms of masses and initial velocity for a perfectly inelastic collision, work out the final kinetic energy. Calculate the initial kinetic energy and show that kinetic energy is not conserved. Use variables, no numbers

You need to follow law of conservation of energy

We know

You may use momentum formula mass×velocity

In both you need to form equations then solve for final velocity

Answer:

The inductive time  constant is just T = L / R

T = 10E-3 henry/ 10 ohm = 10E-2 sec = .1 sec  

(.01 / 10 = .1)

Total displacement:-

[tex]\\ \sf\Rrightarrow 10-30=20m[/tex]

Total distance

[tex]\\ \sf\Rrightarrow 10+30=40m[/tex]

The correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.

Force with which the sledgehammer hits the wall = 1000 N

Thus, the force exerted by the sledgehammer on the wall = -1000 N

Thus, the correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

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Answer:

Slinky is the correct answer.

[tex]\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Question \; :- }}}}}}}[/tex]

An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec² in the forward direction. What is the net force acting on the automobile?

_________________________________________

[tex]\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given\; :- }}}}}}}[/tex]

_________________________________________

[tex]\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}[/tex]

_________________________________________

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Concept \: and \: Formula \: Used \; :- }}}}}}}[/tex]

➯ Force is defined as the product of the mass of the body and its acceleration.

[tex] \bigstar \: \small{ \fbox {\textsf {\textbf{F = ma}}}}[/tex]

Where :

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Substituting \: the\: Given\: Values :- }}}}}}}[/tex]

[tex]⇝ \: \: \small \textsf {\textbf{ F = (1250 × 4) N }}[/tex]

[tex]⇝ \: \: \small \textsf {\textbf{ F = 5000 N }}[/tex]

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Therefore \; :- }}}}}}}[/tex]

❝ The net force acting on the automobile is 5000 N. ❞

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Answer:

1. around 22m

Explanation:

Annie traveled 9 meters during that time. Her average acceleration was -8 m/s².

Annie's initial speed was 12 m/s.

Her final speed was 0 m/s.

The time it took her to stop was 1.5 seconds.

Therefore, the distance she traveled during that time is:

distance = (initial speed + final speed)/2 * time

= (12 m/s + 0 m/s)/2 * 1.5 seconds

= 9 meters

Annie's average acceleration is calculated by dividing her change in velocity by time it took for that change to occur.

In this case, her change in velocity is from 12 m/s to 0 m/s, which is a decrease of 12 m/s.

The time it took for this change to occur is 1.5 seconds.

Therefore, Annie's average acceleration is:

acceleration = change in velocity / time

= -12 m/s / 1.5 seconds

= -8 m/s²

The negative sign indicates that Annie was slowing down.

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Answer:

hottest plant: vensus, close to the sun

coldest plant: Neptune, farthest from the sun

Explanation:

Answer:

-8

5.092×10

Explanation:

given,

distance (d) =15m

mass (M1) =350kg

mass(M2) = 492kg

Gravitational constant (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×350×492)÷15^2

= (1.14857×10^-5)÷225

= 5.092×10^-8

The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:

a)  we have four sections;

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  [tex]d_{total}[/tex]= 16 m

e) maximum speed  is:      v = 6 m / s

Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.

        v = v₀ + a t

        y = v₀ t + ½ a t²

where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.

In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:

Let's answer the different questions about the system.

a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;

b) The acceleration is the first 8 s

          v = v₀ + a t

          [tex]a = \frac{v-v_o}{\Delta t}[/tex]  

          [tex]a = \frac{2-0}{8-0}[/tex]  

          a = 0.25 m / s²

c) The maximum acceleration is when the slope is maximum.

          [tex]a = \frac{6-2}{ 14-10}[/tex]  

          a = 1 m / s²

Therefore the acceleration is maximum in the section between 10 and 14 s

d) The total displacement is the sum of the displacements of each section.

         [tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]  

We look for every displacement.

       d₁ = v₀ + ½ a₁ Δt²

       d₁ = 0 + ½ 0.25 8²

       d₁ = 8 m

In the second section the velocity is constant

         d₂ = v₂ Δt₂

         d₂ = 2 (10-8)

         d₂ = 4 m

The third section.

    d₃ = v₀ + ½ a t²

    d₃ = 2 + ½ 1 (14-10) ²

    d₃ = 10 m

The distance of the fourth section.

we look for acceleration

          a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]  

          a₄ = [tex]\frac{0-6}{18-14}[/tex]  

          a₄ = -1.5 m / s²

          d₄ = 6 + ½ (-1.5) (1814) ²

          d₄ = -6 m

The total displacement is;

          [tex]d_{total}[/tex] = 8 + 4 + 10 -6

          [tex]d_{total}[/tex] = 16 m

e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to

          v = 6 m / s

In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:

  a)  we have four sections;

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  [tex]d_{total}[/tex]= 16 m

e) maximum speed  is:      v = 6 m / s

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