A 0.100 kg limestone cube is released from rest, and proceeds to slide down a frictionless ramp. At the bottom of the ramp, the limestone cube makes an elastic collision with a steel cube whose mass is 0.200 kg, which is initially at rest. At what vertical height should the limestone cube be placed such that the steel cube has a velocity of 1.50 m/s after the collision

Answers

Answer 1

Answer:

the height at which the limestone cube must be placed is 0.23 m.

Explanation:

Given;

mass of limestone cube, m₁ = 0.1 kg

initial velocity of the limestone cube, u₁ = 0

mass of steel cube, m₂ = 0.2 kg

initial velocity of the steel cube, u₂ = 0

final velocity of the steel cube, v₂ = 1.5 m/s

Apply the principle of conservation of energy to determine the height of the limestone cube.

Potential energy of the limestone cube at top = Kinetic energy of steel cube at base

m₁gh = ¹/₂m₂v₂²

where;

h is the height at which the limestone cube is placed

[tex]h = \frac{m_2v_2^2}{2m_1g} \\\\h = \frac{0.2\times 1.5 ^2}{2 \times 0.1 \times 9.8} \\\\h =0.23 \ m[/tex]

Therefore, the height at which the limestone cube must be placed is 0.23 m.


Related Questions

Can someone help me with this one please I need help I will mark brainless

Answers

Answer:

Your answer is A) 3.33ft/min E

Explanation:

i know this because i know to find the velocity you have to divide distance and time. So for this question your distance=10 and your time=3.

The state of the atmosphere at a particular time and place is called the ————-.

Answers

Answer:

= weather

Explanation:

A temperature scale has an upper fixed point of 260mm and the lower fixed point of 50mm.what will be the reading on this scale when the thermometer read 125°F​

Answers

Answer:

the reading on the scale is 158.5 mm.

Explanation:

Given;

upper fixed point of the temperature scale, x₁ = 260 mm

lower  fixed point of the temperature scale, x₂ = 50 mm

upper temperature scale, T₁ = 212 °F

lower temperature scale, T₂ = 32 °F

thermometer reading, t = 125 °F, let the reading on the scale = x

Interpolate as follows to determine the value of "x"

[tex]\frac{X_1 - X}{X_1-X_2} = \frac{T_1-t}{T_1-T_2} \\\\\frac{260-X}{260-50} = \frac{212-125}{212-32} \\\\\frac{260 -X}{210} =\frac{87}{180} \\\\180(260-X) = 87(210)\\\\46800 -180 X = 18270 \\\\180X = 46800-18270\\\\180X = 28530\\\\X = \frac{28530}{180} \\\\X = 158.5 \ mm[/tex]

Therefore, the reading on the scale is 158.5 mm.

When light wave strike a red object, what happens to the light waves of all colors except red?

Answers

Answer:

the object absorbs all light except for red. the red light is reflected back into your eyes, which is why it looks red.

What happens if you are riding your bike and hit something (like a curb) with the front wheel

Answers

You would flip forward or to the side

What is the amount of thermal energy needed to make 5 kg of ice at - 10 °C to
steam at 100 °C? (Heat of fusion of Ice is 3.34 x 10 j/kg, specific heat capacity of
ice is 2.09 x 10 3 J/kg °C, Specific heat capacity of water is 4.186 x 10 ? J/kg° C,
Heat of vaporization of water 2.26 x 10 J/kg)

Answers

Answer:

The amount of thermal energy needed is 15167500 joules.

Explanation:

By First Law of Thermodynamics, we see that amount of thermal energy ([tex]Q[/tex]), in joules, is equal to the change in internal energy. From statement we understand that change in internal energy consisting in two latent components ([tex]U_{l,ice}[/tex], [tex]U_{l,steam}[/tex]), in joules, and two sensible component ([tex]U_{s,w}[/tex]), in joules, that is:

[tex]Q = U_{l,ice} + U_{s, w} + U_{s,ice} + U_{l,steam}[/tex] (1)

By definitions of Sensible and Latent Heat, we expanded the formula:

[tex]Q = m\cdot (h_{f,w}+h_{v,w}+c_{ice}\cdot \Delta T_{ice}+c_{w}\cdot \Delta T_{w})[/tex] (2)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]h_{f,w}[/tex] - Latent heat of fussion of water, in joules per kilogram.

[tex]h_{v,w}[/tex] - Latent heat of vaporization of water, in joules per kilogram.

[tex]c_{ice}[/tex] - Specific heat of ice, in joules per kilogram per degree Celsius.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram per degree Celsius.

[tex]\Delta T_{ice}[/tex] - Change in temperature of ice, measured in degrees Celsius.

[tex]\Delta T_{w}[/tex] - Change in temperature of water, measured in degrees Celsius.

If we know that [tex]m = 5\,kg[/tex], [tex]h_{f,w} = 3.34\times 10^{5}\,\frac{J}{kg}[/tex], [tex]h_{v,w} = 2.26\times 10^{6}\,\frac{J}{kg}[/tex], [tex]c_{ice} = 2.090\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]c_{w} = 4.186\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]\Delta T_{ice} = 10\,^{\circ}C[/tex] and [tex]\Delta T_{w} = 100\,^{\circ}C[/tex], then the amount of thermal energy is:

[tex]Q = 15167500\,J[/tex]

The amount of thermal energy needed is 15167500 joules.

Someone that knows physics and can explain please help.
(IF YOU DO NOT KNOW DO NOT ANSWER IM NOT TRYING TO BE PICKY JUST TIRED OF PEOPLE GIVING RANDOM ANSWERS)

Answers

Answer:

500uF

Explanation:

On the graph C (Charge/Coulomb) increases by .005 each measurement and the Voltage by 10. Capacitance= Charge/Potential difference. .005/10 =.0005 which is written as 500uF. This works since if u simply work it backwards, 1uF is 1 millionth of a Coulomb times that by 500 which gives .0005 then by 10 for Voltage and then u get the original charge.

So the answer is 500uF.

What is the process by which water particles move through a membrane?
active transport
homeostasis
osmosis
cell division
photosynthesis

Answers

The answer is active transport
Answer: Active transport

How many joules of gravitational potential energy does a person have after they went up stairs that are 10 meters tall? Assume the person has a mass of 60 kilograms. And assume this takes place on earth.

Answers

Answer:

P = 5880 J

Explanation:

Given that,

The mass of a person, m = 60 kg

The height of the stairs, h = 10 m

We need to find the gravitational potential energy of the person. The formula is as follows :

[tex]P=mgh[/tex]

Substitute all the values,

[tex]P=60\times 9.8\times 10\\\\P=5880\ J[/tex]

So, the required gravitational potential energy is equal to 5880 J.

As a result of friction, the angular speed of a wheel c hanges with time according to d θ d t = ω0 e −σ t , where ω0 and σ are constants. The angular speed changes from an initial angular speed of 2.88 rad/s to 1.38 rad/s in 3.92 s. (a) Determine the magnitude of the angular acceleration after 1.88 s. Answer in units of rad/s 2 . (b) How many revolutions does the wheel make after 2.6 s ? Answer in units of rev. (c) Find the number of revolutions it makes before coming to rest.

Answers

poste en français s’il vous plaît

1. Budding is a way that some very tiny organisms can reproduce.

True
False
____________________________________

Male-female reproduction needs two parent cells to begin.

True
False

Answers

Answer:1.. true 2 false

Explanation:

In regards to the respiratory system; all of the following are true except

Answers

Could you please provide the options? :)

Electromagnetic waves used in cell phones are called

a. radio waves
b.microwaves
c. Gamma rays
d. Ultraviolet rays

Answers

Answer:

A.Radio waves

Explanation:

*15 points*
How much louder is the sound of heavy street traffic (60dB) than the sound of normal conversation(40dB)?

A. 20 times louder
B. 100 times louder
C. 240 times louder
D. 2 times louder

Answers

The sound of heavy street traffic is 100 times louder than the sound of normal conversation.

What is street traffic?

Street traffic is the movement of vehicles and pedestrians in a designated public space, such as a street or alley. Traffic is generally regulated by signs, signals, and lane markings. It is important to obey these rules, as they are intended to keep pedestrians and drivers safe. Street traffic can involve many types of vehicles, including cars, buses, motorcycles, bicycles, and trucks.

The sound of heavy street traffic is 60dB, while the sound of normal conversation is 40dB. This means the sound of the heavy street traffic is 20dB louder than the sound of a normal conversation. To calculate the difference in loudness, we need to take the difference in decibels and raise it to the power 10. This means that the sound of heavy street traffic is 100 times louder than the sound of normal conversation.

To learn more about street traffic
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In which of the following is convection the main type of heat transfer?
O A. Gas and vacuum
B. Solid and liquid
O C. Liquid and gas
O D. Solid and vacuum

Answers

Convection is the primary mode of heat transfer in liquids and gases.

The correct answer is option C.

Convection is a process of heat transfer that occurs in fluids (liquids and gases) due to the movement of the fluid itself. It involves the transfer of heat energy through the bulk movement of the fluid particles. This mechanism is different from conduction, which is the direct transfer of heat through molecular collisions, and radiation, which is the transfer of heat through electromagnetic waves.

In the case of liquids and gases, convection occurs when a temperature difference exists within the fluid. The heated regions of the fluid become less dense and rise, while the cooler regions sink. This creates a continuous circulation of the fluid, known as convection currents, which transfer heat from one location to another.

Option A, Gas and vacuum, does not involve the presence of a fluid medium, so convection cannot occur. In a vacuum, heat transfer primarily occurs through radiation. Option B, Solid and liquid, includes the possibility of conduction in solids but not convection. Option D, Solid and vacuum, does not involve any fluid medium, so convection is not applicable.

Therefore, option C, Liquid and gas, is the correct choice where convection is the main type of heat transfer. In liquids and gases, convection plays a significant role in heat transfer processes, such as the movement of heat in boiling water, air currents in a room, and oceanic circulation patterns.

For more such information on: Convection

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A car wheel turns through 12pi in 10.7s calculate the angular speed of the wheel

Answers

Answer:

The answer should be D..

Explanation:

what makes 60% of your arm and what makes the other 40%

Answers

60% is all the muscles and 40% is tendons

consider an electromagnetic wave of frequency f=3x10^6 Hz. does this radiation belong to the visible range to the ultraviolet or to the infrared of radio waves ?why?

Answers

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

44e

called.
4) The object that changes its position relative to a fixed point with time is called ...
3) Theratiobetweentotaldisplacementandtotaltimeisсalled..
5) The motion that repeats itself in equal intervals of time is called
6) If the body moves at uniform velocity its acceleration is equal to
7) Acceleration of an object's motion when it changes its velocity with unequal
amounts in equal time is called.
8) When an object started motion from rest, its initial velocity is equal to
9) When a body moves with uniform velocity its initial velocity and its final velocity
are ....
10If an object is thrown upwards its horizontal range reached by it is​

Answers

Answer:

4) Object in motion

5) Velocity

6) 0 m/s²

7) non - uniform acceleration

8) 0 m/s

9) Equal

10) distance covered by the object along the horizontal plane before it reaches the same vertical position from which it started.

Explanation:

4) Object in motion

5) Ratio between displacement and time is velocity. Displacement is in metres(m) and time is in seconds(s). Thus, displacement/time is in m/s which is velocity.

6) Acceleration = 0 m/s² since it loves with uniform velocity and therefore doesn't accelerate.

7) Since the object changes its velocity with unequal amounts in equal time, the acceleration is called non - uniform acceleration since the acceleration will differ at different points.

8) Initial velocity of an object that starts motion from rest is zero.

9) They are equal since velocity is uniform.

10) The horizontal range will be distance covered by the object along the horizontal plane before it reaches the same vertical position from which it started.

You've always wondered about the acceleration of the elevators in the 101 story high Empire State Building. One day, while visiting New York, you take your bathroom scale into the elevator and stand on it. The scale reads 177 lb as the door closes. As the elevator moves upward the scale reading varies between a minimum value of 138 lb and a maximum value of 227 lb as the elevator travels 101 floors.
a. What is the magnitude of the acceleration as the elevator starts upward?
b. What is the magnitude of the acceleration as the elevator brakes to a stop?

Answers

Answer:

a) 2.8 m/s2

b) 2.2 m/s2

Explanation:

The lecture on the bathroom scale is equal to the normal force that the scale exerts on you, and is directed upward.There is another force acting on you, which is gravity.This force (which we call weight) is the product of the mass times the acceleration due to gravity, g, and is directed downward, opposite to the normal force.When the elevator  is at rest, no acceleration takes place, so according Newton's 2nd Law, no net force must be exerted on you.In this condition, the normal force Fn₀ must be equal to the weight:[tex]F_{no} = m * g = 177 lb (1)[/tex]Since the normal force takes any value needed to satisfy Newton's 2nd law, the two extreme lectures can be expressed as follows, in terms of  the two forces acting on you while the elevator is moving upward:

       [tex]F_{n1} = m * (g +a_{1}) = 227 lb (2)[/tex]

      [tex]F_{n2} = m * (g +a_{2}) = 138 lb (3)[/tex]

Replacing m by 177lb/g (a given), and rearranging, we can solve (1) for a₁, as follows:

       [tex]a_{1} = (\frac{227lb}{177lb} *g) - g = 0.28*g = 0.28*9.8m/s2 = 2.8 m/s2 (4)[/tex]

As it can be seen, the normal force takes a larger value in order to be compliant with the upward acceleration that opposes to gravity.In the same way, we can find the magnitude of the downward acceleration when the elevator brakes to a stop, from (3):

       [tex]a_{2} = (\frac{138lb}{177lb} *g) - g = -0.22*g =- 0.22*9.8m/s2 = -2.2 m/s2 (5)[/tex]

In this case, the normal force takes a lower value than at rest, due to the acceleration has the same direction as gravity.

Plants are known as producers because they can make their own food. Which of the following provides a list of basic needs a plant must have for photosynthesis to happen?

A.
water and oxygen in the air

B.
soil, energy from the sun, and oxygen in the air

C.
energy from the sun, carbon dioxide in the air, water

D.
soil, carbon dioxide in the air, energy from the sun

HELP PLEASE

Answers

Answer:

C .energy from the sun, carbon dioxide in the air, water

hope my answer helps

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What is the name for a compound formed with covalent bonds?

Answers

Answer:

These are called molecular compounds. ex. organic compounds like lipids or proteins.

If distance between two charges increased 5 times then force between them

Answers

decreased 5 times

Explanation: if the force increases 5 times between them would decrease 5 times

Why is radiant energy classified as Kinetic energy

Answers

Answer:

Radiant energy is a type of kinetic energy, referring to energy that travels by waves or particles. The energy is created through electromagnetic waves and is most commonly experienced by humans in the form of heat.

Answer:

Explanation:

Radiant energy is a type of kinetic energy, referring to energy that travels by waves or particles. The energy is created through electromagnetic waves and is most commonly experienced by humans in the form of heat. Radio signals: Similar to x-rays, radio waves also travel in the form of waves.

15. Which tectonic boundary would have many normal faults associated
with it?
A. Convergent
B. Divergent
C. Transform

Answers

Answer: A. Convergent

A 105-kg rubber mat is pushed on a dry concrete floor. What is the coefficient of static friction, if the force required to start the mat sliding is 1030 N?

Answers

Answer:

[tex]\mu=1[/tex]

Explanation:

Given that,

Mass of a rubber mat, m = 105 kg

We need to find the coefficient of static friction, if the force required to start the mat sliding is 1030 N.

The applied force is given by :

[tex]F=\mu mg\\\\\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{1030}{105\times 9.8}\\\\\mu=1[/tex]

So, the required coefficient of static friction is equal to 1.

A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its speed is 3 m/s. But 2.5 seconds later, at the bottom of the slope, its speed is 25 m/s. What is its average acceleration?

Answers

Answer:

the average acceleration is 8.8 m/s^2

Explanation:

The computation of the average acceleration is shown below;

As we know that

a = (v − u) ÷ t

where

a denotes average acceleration

v denotes the speed at the bottom of the slope

u denotes the speed at down the slop

t denotes time

= (25 - 3) ÷ 2.5

= 8.8 m/s^2

hence, the average acceleration is 8.8 m/s^2

A U-tube with a cross-sectional area of 1.00 cm2 is open to the atmosphere at both ends. Water is poured into the tube until the water rises part-way along the straight sides, and then 5.00 cm3 of oil is poured into one end. As a result, the top surface of the oil ends up 0.550 cm higher than the water surface on the other side of the U. What is the density of the oil

Answers

Answer:

0.89 g/cm^3 = 890 kg/m^3

Explanation:

Cross sectional area of U-tube ( A ) = 1.00 cm^2

volume of oil ( V )  = 5.00 cm^3

change between top surface = 0.550 cm

height of oil = 5 cm  ( volume / area )

height of water = 5 - 0.550 = 4.45 cm

pressure at the oil-water junction = Pressure on the second side of the U-tube at same level

Po * g * Hoil = Pw * g * Hwater

Po * 5 = 1 * 4.45

∴ Density of oil ( Po ) = 4.45 / 5  g/cm^3 = 0.89 g/cm^3

The system needs an ordinary friction-based brake to bring the train to a full stop. Explain why the magnetic brake is not very efficient when the train is moving slowly. The system needs an ordinary friction-based brake to bring the train to a full stop. Explain why the magnetic brake is not very efficient when the train is moving slowly. The slower the train is moving, the greater are the changes of the magnetic flux, thus the eddy currents become stronger. The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker. The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become stronger. The slower the train is moving, the greater are the changes of the magnetic flux, thus the eddy currents become weaker.

Answers

Answer:

The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker.

Explanation:

A magnetic brakes is not a very efficient way of braking when a train is moving slowly because at low speeds, the changes in the magnetic flux are very less and so it causes the eddy current to become weaker.

Let us find the drag force which is proportional to the velocity of two conducting plates.

The EMF that is induced in the eddy currents are : [tex]$E=v(B \times L)$[/tex]

The force which is due to the induced magnetic field is, [tex]$F=l(L \times B)$[/tex]

Therefore, [tex]$F=\frac{E}{R} \times (L \times B)$[/tex]

                 [tex]$F=\frac{v(B \times L)}{R} \times (L \times B)$[/tex]

Here, force is directly proportional to the velocity of the two conducting plates.

Therefore, we can say that when the speed of the train is low, the magnetic flux changes are less and thus the eddy currents are weaker.  

How much work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s?
50 J,
12.5 J,
25 J,
49 J​

Answers

Answer:

The correct option is (b).

Explanation:

We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.

We know that, the work done is equal to the kinetic energy of an object i.e.

[tex]W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J[/tex]

So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.

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