Answer:
I don't know the answer.
Explanation:
Im not smart <3
Why do you think spacecraft that carry instruments to collect data about objects in space are called probes?
Answer:
my mind cant comprehend a shing word u just said
Explanation:
The probes collect data, they capture the movement in space, therefore, spacecraft that carry instruments to collect data about objects in space are called probes, So the given statement is correct.
What are Probes?
Any conductor that is placed into a plasma and gathers current is a probe. Measurements of the current on the probe as a function of the bias potential given to the probe can be used to identify a plasma's properties.
Such probes affect their surroundings while directly detecting electron and ion flows in the plasma. Any conductive material (wire, foil, chamber walls, etc.) can serve as a plasma probe; nevertheless, precise control over the probe's size, shape, and substance is necessary to achieve detectable plasma levels. Astronauts are not present aboard probes. Scientists can analyze the data the probes relay back to Earth. Sputnik 1 was the first spacecraft to launch.
Because probes probably collect data, they capture the movement in space, therefore, spacecraft that carry instruments to collect data about objects in space are called probes.
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Q. A runner has a momentum of 670 kg m/s and is traveling at a
velocity of 9 m/s. What is his mass?
Answer:
m = 74.44 kg
Explanation:
p = m × v
670 = m × 9
9m = 670
m = 670/9
m = 74.44 kg
Momentum of an body is defined as the product of mass and velocity.It s unit is kgm/sec.The value of mass will be 74.44 kg.
What is momentum?The measurement of mass in motion is called momentum. Momentum is equal to its mass multiplied by its velocity. Mathematically it is given as;
Momentum = Mass x Velocity
The given data in the problem will be
p is the momentum of runner=670 kgm/sec.
v is the velocity =9m/sec.
m is the mass =?
[tex]\rm p =mv\\\\\rm m =\frac{p}{v} \\\\\rm m =\frac{670}{9} \\\\\rm m =74.44 kg[/tex]
Hence the value of mass will be 74.44 kg.
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A satellite is in orbit 36000km above the surface of the earth. Its angular velocity is 7.27*10^-5 rad/s. What is the velocity of the satellite? (The radius of the earth is 6400km.)
Answer:
v = 3.08 km/s
Explanation:
Given that,
The angular velocity of the satellite = [tex]\omega=7.27\times 10^{-5} rad/s[/tex]
A satellite is in orbit 36000km above the surface of the earth.
The radius of the earth is 6400 km
Let v is the velocity of the satellite. It can be calculated as :
[tex]v=r\omega\\\\v=(36000\times 10^3+6400\times 10^3)\times 7.27\times 10^{-5}\\\\v=3082.48\ m/s\\\\v=3.08\ km/s[/tex]
So, the velocity of the satellite is 3.08 km/s.
A car with a mass of 1,400 kg is traveling at a speed of 40 m/s. What is its momentum?
Answer:
56000kgm/s
Explanation:
Momentum = Mass * Velocity (both in standard unit)
Therefore, the car's momentum = 1400 * 40 = 56000kgm/s (or 56000Ns)
What are some of the similar features of position vs time and velocity vs time
C) If your displacement is 19.3m and your final position is 31.8m, what was your initial position?
Answer:12.5
Explanation: Subtract
0.0135 kg of steam at 100°C is
cooled, which turns it into water at
50.0°C. How much heat has been
removed? (Remember, it has to
change phase before cooling
down.)
Boil Pt (°C)
Material Melt Pt (°C) 4 0/kg)
Water
0
3.33.105
L(/kg) c (J/(kg*C))
2.26.106 4186
100
(Unit = J)
Answer:
33333.35 kg
Explanation:
I got it right on Acellus, rounded to 33300 sigfigs
When 0.0135 kg of steam at 100°C is cooled, turns it into water at 50.0°C. Then 33,342.45 J of heat has been removed.
What is latent heat?Latent heat is the heat absorbed or released by a substance during a change in its physical state without a corresponding change in temperature. This means that the heat energy is being used to break or form intermolecular bonds between the particles in the substance, rather than raising or lowering the temperature. Examples of processes that involve latent heat include melting, freezing, vaporization, and condensation. The amount of heat required or released during these phase transitions is dependent on the substance and the amount of material undergoing the change.
Here in the question,
To solve this problem, we need to use the formula for the heat required to change the phase of a substance, which is given by:
Q = m * L
where Q is the heat required, m is the mass of the substance, and L is the specific latent heat of the substance.
In this case, we need to find the heat required to change 0.0135 kg of steam at 100°C to water at 100°C, and then cool it down to 50°C.
First, we need to find the heat required to change the phase of the steam to water at 100°C. Using the table given, we can see that the specific latent heat of vaporization for water is 2.26 × 10^6 J/kg. So the heat required to change 0.0135 kg of steam to water at 100°C is:
Q1 = m * L = 0.0135 kg * 2.26 × 10^6 J/kg = 30,510 J
Next, we need to find the heat required to cool the water from 100°C to 50°C. Using the specific heat capacity of water, which is 4186 J/(kg°C), we can calculate the heat required as:
Q2 = m * c * ΔT = 0.0135 kg * 4186 J/(kg°C) * (100°C - 50°C) = 2832.45 J
The total heat removed is the sum of the heat required to change the phase of the steam and the heat required to cool the water:
Q = Q1 + Q2 = 30,510 J + 2832.45 J = 33,342.45 J =33.34245 kJ.
Therefore, 33,342.45 J of heat has been removed.
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How far will a car travel in half an hour at
30 mph?
Answer:
The car will travel the distance of 15 miles
S= D/T
therefore
D=ST
D = Distance
S = Speed (30 mph)
T = Time (0.5 Hours)
D = 30 * 0.5 = 15
A particle with charge q on the negative x axis and a second particle with charge 2q on the positive x axis are each a distance d from the origin. Where should a third particle with charge 3q be placed so that the magnitude of the electric field at the origin is zero? (Use any variable or symbol stated above as necessary.)
Answer:
The charge 3q must be placed at a distance of 1.73d away from the origin.
Explanation:
The electric field at the origin due to q at distance, d from the origin is E = q/4πε₀d².
The electric field at the origin due to 2q at distance, d from the origin is E' = -2q/4πε₀d². (It is negative since it its directed towards the negative x-axis)
Now, the net electric field at the origin due to both charges is thus E" = E + E' = q/4πε₀d² + (-2q/4πε₀d²) = q/4πε₀d² - 2q/4πε₀d² = -q/4πε₀d².
The electric field due to 3q at a distance x from the origin is E₁ = 3q/4πε₀x².
Now, the net electric field E' must cancel out E₁ so that the electric field at the origin is zero.
So, E' + E₁ = 0
E' = -E₁
-q/4πε₀d² = -3q/4πε₀x²
1/d² = 3/x²
taking inverse of both sides, we have
x²/3 = d²
multiplying both sides by 3, we have
x² = 3d²
taking square root of both sides, we have
x = (√3)d
x = ±1.73d
So, the charge 3q must be placed at a distance of 1.73d away from the origin.
Find the acceleration of a 600 kg car that experiences an impulse of 18,000 kgm/s in 0.05 seconds.
I need help with this question, i don’t understand it
Answer:
what?
Explanation:
Answer:
600m/s²
Explanation:
Given parameters:
Mass of car = 600kg
Impulse = 18000kgm/s
Time = 0.05s
Unknown:
Acceleration = ?
Solution:
To solve this problem, let us find the force that cause the impact first;
Impulse = Force x time
Force = [tex]\frac{impulse}{time}[/tex] = [tex]\frac{18000}{0.05}[/tex] = 360000N
So;
Force = mass x acceleration
Acceleration = [tex]\frac{Force }{mass}[/tex] = [tex]\frac{360000}{600}[/tex]
Acceleration = 600m/s²
HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN
A shopping cart is going 2.0 m/s and comes to a complete stop after 4 seconds. What was the cart's acceleration?
8 m/s2
-0.5 m/s2
0.5 m/s2
-8 m/s2
Answer:
0.5 m/s2
Explanation:
accelration formula : final velocty - starting velocity divided by time
A rescue pilot drops a survival kit while her plane is flying at an ultitude of 2500m with a forward velocity of 95m. If the air friction is disregarded, how far advance of the starving explorer’s drop zone should she release the package?
Answer:
Approximately [tex]2.1\; \rm km[/tex], assuming that [tex]g = -9.8\; \rm m \cdot s^{-2}[/tex].
Explanation:
Let [tex]t[/tex] denote the time required for the package to reach the ground. Let [tex]h(\text{initial})[/tex] and [tex]h(\text{final})[/tex] denote the initial and final height of this package.
[tex]\displaystyle h(\text{final}) = \frac{1}{2}\, g\, t^2 + h(\text{initial})[/tex].
For this package:
Initial height: [tex]h(\text{initial}) = 2500\; \rm m[/tex].Final height: [tex]h(\text{final}) = 0\; \rm m[/tex] (the package would be on the ground.)Solve for [tex]t[/tex], the time required for the package to reach the ground after being released.
[tex]\displaystyle t^{2} = \frac{2\, (h(\text{final}) - h(\text{initial}))}{g}[/tex].
[tex]\begin{aligned} t &= \sqrt{\frac{2\, (h(\text{final}) - h(\text{initial}))}{g} \\ &\approx \sqrt{\frac{2\times (0\; \rm m - 2500\; \rm m)}{(-9.8\; \rm m \cdot s^{-2})}} \approx 22.588\; \rm s\end{aligned}[/tex].
Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at [tex]95\; \rm m \cdot s^{-1}[/tex].) From calculations above, the package would travel forward at that speed for about [tex]22.588\; \rm s[/tex]. That corresponds to approximately:[tex]95\; \rm m \cdot s^{-1} \times 22.588\; \rm s \approx 2.1 \times 10^{3}\; \rm m = 2.1\; \rm km[/tex].
Hence, the package would land approximately [tex]2.1\; \rm km[/tex] in front of where the plane released the package.
The bottom of a ladder must be placed 4 feet from a wall. The ladder is 12 feet long. How far above the ground does the ladder touch the wall? Estimate your answer to the nearest tenth.
Answer:
Height of wall (Perpendicular) = 11.31 ft (Approx)
Explanation:
Given:
Base Distance (Base) = 4 feet
Height of ladder (Hypotenuse) = 12 feet
Find:
Height of wall (Perpendicular)
Computation:
Perpendicular = √Hypotenuse² - Base²
Height of wall (Perpendicular) = √12² - 4²
Height of wall (Perpendicular) = √144 - 16
Height of wall (Perpendicular) = √128
Height of wall (Perpendicular) = 11.31 ft (Approx)
Which part of the electromagnetic spectrum is nearest to radio waves?
X-rays
microwaves
gamma rays
ultraviolet light
Answer:
i believe it is the microwaves that is closest to the radio waves.
Explanation:
The microwaves are the part of the electromagnetic spectrum is nearest to radio waves.
What is meant by electromagnetic spectrum?The range of all EM radiation arranged from high to low frequency (short to long wavelength) according to their frequency or wavelength. is known as the electromagnetic spectrum (EM).
Here,
The visible light from a bulb in your home and the radio waves from a radio station are two examples of electromagnetic radiation. Radiation is energy that travels and disperses as it does.
The properties of the electromagnetic spectrum include the ways in which signals can propagate and how much data they can carry. Signals delivered at higher frequencies typically propagate more quickly but can carry more data in a given amount of space.
The electromagnetic spectrum begins with the lowest frequency radio waves and moves up in frequency and down in wavelength from there. Radio waves are followed by visible light, infrared radiation, and lastly microwaves.
Hence,
The microwaves are the part of the electromagnetic spectrum is nearest to radio waves.
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A closed cylindrical tank of radius 3.5 m and height 2m is made from
a sheet of metal. How much sheet of metal is required ?
Explanation:
Total surface area of cylinder:
[tex]2\pi \times r(h + r) \\ 2 \times \pi \times 3.5(3.5 + 2) \\ 2\pi \times 19.25 = 120.951317 \\ 120.95 \: {cm}^{2} [/tex]
sheet of metal required = 120.95 cm^2
Explanation:
Answer:
Given :-
A closed cylindrical tank of radius 3.5 m and height 2 m is made from a sheet of metal.
To Find :-
How much sheet of metal is required.
Formula Used :-
[tex]{\red{\boxed{\large{\bold{T.S.A\: of\: cylinder\: =\: 2{\pi}r(r + h)}}}}}[/tex]
where,
r = Radius
h = Height
Solution :-
Given :
Radius = 3.5 m
Height = 2 m
According to the question by using the formula we get,
⇒ [tex]\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5(3.5 + 2)[/tex]
⇒ [tex]\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5(5.5)[/tex]
⇒ [tex]\sf T.S.A =\: 2 \times \dfrac{22}{7} \times 3.5 \times 5.5T.S.A=2×722×3.5×5.5
⇒ \sf T.S.A =\: 2 \times \dfrac{22}{7} \times 19.25[/tex]
⇒ [tex]\sf T.S.A =\: 2 \times 60.5[/tex]
➠ [tex]\sf\bold{\purple{T.S.A =\: 121\: {m}^{2}}}[/tex]
∴ 121 m² of sheet of metal is required.
At what point in this sequence of events is potential energy
being converted to kinetic energy?
A. When the spring is recoiling B. When the spring is fully stretched. C. When the spring is fully recoiled. D. When the spring is stretching
Answer:
your answer is C
Explanation:
the spring when fully recoiled is at maximum PE and will then convert to KE
1. A brick and a peanut are dropped of the roof of a house at the same time, which
object hits the ground first? (Ignore air resistance).
Answer:
It would be the brick since the mass and the weight is greater than the peanut I might be wrong on this but thats the best answer i can give
Explanation:
What do plasma cells produce ?
Show the steps im confused.
The answer is 14 m/s
Answer:
14 m/s
Explanation:
KE=1/2mv^2
5880J= 1/2(60kg)v^2
5880J=(30)(V^2)
5880/30=V^2
196=v^2
square root of 196 is 14
A person walks 60 meters in 1 minute. Then walks 30 meters in 2 minutes. What is thier average speed over the 3 minute walk?
Can someone help me with this last question
Is gravitational energy a form of kinetic energy or potential energy? Why do you think that?
Please help due today!!
Answer:
When something is lifted, work is done on the object against the pull of gravity. This work is converted to a form of potential energy called gravitational potential energy. When the item falls towards Earth like an apple from a tree, gravitational potential energy is converted into kinetic energy.
Refer to your Expeditions in Reading book for a complete version of this text.
Based on “Solar Power for Public Buildings,” which answer best states the author’s position on the use of solar power in California?
A The use of solar energy will double the pollution produced in California.
B The state’s tap water will be purer if processed in solar-powered plants.
C Increasing the use of solar power will positively impact the environment.
D Solar panels remove most of the toxic chemicals found in the atmosphere.
Answer:
d
Explanation:
Answer:
D. Solar panels remove most of the toxic chemicals found in the atmosphere.
People do not believe it is possible to use the sun's energy to create electricity.
Explanation:
I did the test.
Which electromagnetic waves have the shortest wavelength and the highest frequency?
waves
Answer: Gamma rays (violet) have the shortest wavelengths and the highest frequencies.
Explanation: The wavelength of the gamma rays is less than 0.01 nanometers. The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength.
The electromagnetic waves have the shortest wavelength and the highest frequency is Gamma rays (violet).
What are gamma rays?Gamma radiation, from gamma rays (γ), is a type of electromagnetic radiation usually produced by radioactive elements. Gamma rays, due to their high energy, are able to penetrate matter more deeply than alpha or beta radiation.
Gamma ray is a type of high frequency electromagnetic radiation usually produced by radioactive elements.
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help me!
Bill left a hammer out in the rain all day. The next morning it had rust on it.
Oxygen and a metal chemically combine to form rust. What is rust an example of?
O a mixture
• a solution
an element
a compound
Answer:D.Compound
Explanation: internet
Can some one please explain how to read this and what the answer would be?
Answer:
4 to 5
Explanation:
What is the momentum of a car that is 12000 g and is traveling at 45 m/s? (LOOK AT THE UNITS)
a)
267 kg*m/s
b)
540000 kg*m/s
c)
540 kg*m/s
d)
.27 kg*m/s
e)
54000kg*m/s
Answer:
e
Explanation:
Plss help with my science
Answer:
rotates, axis,not sure,day, not sure, night, revolves, not sure, hemisphere, towards, summer, away, winter
Explanation:
i single and thiccccc hmu
Answer:
wtfffff
Explanation:
wtffffff
Problem 5. A bullet leaves a rifle with a velocity of 452 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.93 m. Determine the acceleration of the bullet.
Answer:
1.1 x 10⁵m/s²
Explanation:
Given parameters:
Velocity = 452m/s
distance = 0.93m
Unknown:
Acceleration of the bullet = ?
Solution:
To solve this problem, we use one of the kinematics equation which is given below:
V² = U² + 2aS
V is the final velocity
U is the initial velocity = 0m/s
a is the unknown acceleration
S is the distance traveled
So;
452² = 0² + (2 x a x 0.93)
204304 = 1.86a
a = 1.1 x 10⁵m/s²