9. Find the measure of angle
a
36°
57°

si existen pero que tipo de números? porque si existen

Step-by-step explanation:

35A) arc AC = 360-(100+110+80)=

360-290 = 70°

35B) L D = ½× 70 = 35°

35C) L AEC = ½(100+70)=½×170= 85°

35D) L P = ½(100-70) = ½×30 = 15°

Answer:

let y=x²+9²

dy/dx=dx²/dx+d9²/dx

=[tex]2 x^{2-1}+0[/tex]

=2x is a required answer.

Answer:

Answer is 36.

You can simply get this by writing and expression for it

25/100 x w=9

25w/100=9

w= 9x100/25

w=36.

Answer:

36

Step-by-step explanation:

9/w=25/100

cross multiplication:

9*100=25w

900=25w

900=25w / 25

36=w

Answer: 500 mcg/mL

Step-by-step explanation: 0.5 mg/mL = ___________ mcg/mL

0.5 mg/mL(1000)

500 mcg/mL

Answer:

500 mcg / mL

Step-by-step explanation:

this is the ansa when u do 0.5 mg/mL = ___________ mcg/mL

Answer:

trick:

1 hour = 60 minutes

ex if said to convert 25 minutes to hour so

1 hour/60=1minutes

multiply both sides with 25

25 x 1hour/60=25minutes

5/12 hours=25 minutes

just like that for hour

Answer:

D

Step-by-step explanation:

Answer:

3960 minutes

Step-by-step explanation:

From;

0.693/t1/2 = 2.303/t log No/N

t1/2 = half life of 90Y

No = initial activity of 90Y =  8.9 x 10^5 disintegrations per minute

N= activity of 90Y after time t = 2.6 x 10^4 disintegrations per minute

t = time taken

Since the time elapsed is 20,235 minutes, we substitute into the formula above.

0.693/t1/2 = 2.303/20235 log 8.9 x 10^5/2.6 x 10^4

0.693/t1/2 =  1.75 * 10^-4

t1/2 = 0.693/ 1.75 * 10^-4

t1/2 = 3960 minutes

9514 1404 393

Answer:

Step-by-step explanation:

Let n represent the number. Then half the number is n/2. We are told that ...

  n = n/2 +10 . . . . the number equals half the number plus 10

  n/2 = 10 . . . . . . .subtract n/2

  n = 20 . . . . . . . . multiply by 2

The number is 20.

Answer:

Step-by-step explanation:

Answer:

$92

Step-by-step explanation:

Find the profit by plugging in 10 as c and 7 as p into the expression:

5c + 6p

5(10) + 6(7)

50 + 42

= 92

So, the bakery will make $92

Given:

The rule of input and output function is:

[tex]25-g[/tex]

To find:

The answer if we put 19.

Solution:

Consider the input and output function is:

[tex]f(g)=25-g[/tex]

Substitute [tex]g=19[/tex], we get

[tex]f(19)=25-19[/tex]

[tex]f(19)=6[/tex]

Therefore, the required answer is 6.

Answer:

The null hypothesis must be rejected

Step-by-step explanation:

Here the P value is less than 0.05

which means that the test results are statistically significant and there are sufficient evidence to reject the null hypothesis and accept the alternative hypothesis.

Hence, the null hypothesis must be rejected.

Step-by-step explanation:

you can get simply V= ABh πr^2 h π3.14^2 x 17.9 then you get the answer Ihope I can help you

Answer:

P = 1104

a - Side

Step-by-step explanation:

P = 1104

a - Side

Answer:

P=1140

Step-by-step explanation:

P=1140 BANANA SORRY THE ANSWER I DONT HAVE IT BUT HAVE A GOOD DAY

Answer:

16

Step-by-step explanation:

I don't know  how to explain but it is 16

Answer:

Since the Width (W) of the rectangle is not given, the answer would be Length (L) = 240/W

Step-by-step explanation:

A = L*W

240 = L*W

240/W = L

Answer:

[tex]forth \: line \: - 5x - 3x + 3 = 6 \\ - 8x + 3 = 6 \\ - 8x = 3 \\ x = \frac{3}{ - 8} [/tex]

Answer:

17

Step-by-step explanation:

8.5 / 0.5

x = 8.66 ft

Step-by-step explanation:

cos 30 = adj/hyp = x/10

---> x = (10 ft)cos30

= 8.66 ft

about 78.54

V=π·5^2·1 = 78.54

Answer:

Find the volume of the cylinder.

[tex]\star \: \: \purple{Volume_{(cylinder)} = \pi {r}^{2} h}[/tex]

[tex]\star \: \: \purple{Volume_{(cylinder)} = 3.14 \times ( {5)}^{2} \times 1 }[/tex]

[tex]\star \: \: \purple{Volume_{(cylinder)} =3.14 \times 25 \times 1 }[/tex]

[tex]\star \: \: \purple{Volume_{(cylinder)} =78.50 \: in {}^{3} }[/tex]

Find the volume of a cylinder with the same radius and double the height.

[tex]\star \: \: \purple{Volume_{(cylinder)} = \pi {r}^{2} h}[/tex]

[tex]\star \: \: \purple{Volume_{(cylinder)} = 3.14 \times {(5)}^{2} \times 2}[/tex]

[tex]\star \: \: \purple{Volume_{(cylinder)} = 3.14 \times 25 \times 2}[/tex]

[tex]\star \: \: \purple{Volume_{(cylinder)} = 157 \: in {}^{3} }[/tex]

Answer:

The probability that the sampled fraction of voters favoring the bond issue will not differ from the true fraction by more than 0.08 is 0.7698

Step-by-step explanation:

Given  

n = 64

p = 0.20

X/n -p < 0.06

x-np <0.06n

x-np <0.06 * 64  

x-np <3.84

Z score  

= (x-np)/sqrt (np(1-p))

= -3.84/ sqrt (64*0.20*0.80)

= -1.20

P (x/n-p<0.06) = P(-1.2<z<1.20) = 1-2*0.1151 = 0.7698

Answer:

A. 169 is the correct answer

Answer:

Objective Minimize 10x1 +15x2 + 12x3+18x4+15x5+ 21x6

The central total cost $ 17586 due to the number of central undergraduate students 1458 is very high.

The total minimum cost would $ 17586 +$260+ $300= $ 18146

Step-by-step explanation:

Let

X1 = # of undergraduate students from the East region,

X2 = # of graduate students from the East region,

X3 = # of undergraduate students from the Central region,

X4 = # of graduate students from the Central region,

X5 = # of undergraduate students from the West region, and

X6 = # of graduate students from the West region.

Then  the cost functions are

y1= 10x1 +15x2

y2= 12x3+18x4

y3= 15x5+ 21x6

According to the given conditions

The constraints are

x1 +x2 + x3+x4+ x5+ x6 ≥ 1500------- A

15X2 +18X4+21X6 ≥ 400---------B

21X6 ≥ 100

X6 ≥ 100/21

X6 ≥ 4.76

Taking

X6= 5

10X1 ≤ 500

X1 ≤ 500/10

X1≤ 5

18X4 ≥ 75

X4 ≥ 75/18

X4 ≥ 4.167

Taking

X4= 5

Putting the values

15X5+ 21X6 ≥ 300

15X5+ 21(5) ≥ 300

15X5+ 105 ≥ 300

15X5 ≥ 300-105

15X5 ≥ 195

X5 ≥ 195/15

X5 ≥ 13

Putting value of X6 and X4 in B

15X2 +18X4+21X6 ≥ 400

15X2 +18(5)+21(5) ≥ 400

15X2 +195 ≥ 400

15X2  ≥ 400-195

15X2  ≥ 205

X2  ≥ 205/15

X2  ≥ 13.67

Taking X2= 14

Now putting the values in the cost equations to check whether the conditions are satisfied.

y1= 10x1 +15x2

y1= 10 (5) + 15(14)= 50 + 210= $ 260

y3= 15x5+ 21x6

y3= 15 (13) + 21(5)

y3= 195+105= $ 300

x1 +x2 + x3+x4+ x5+ x6 ≥ 1500

5+14+x3+5+13+5≥ 1500

x3≥ 1500-42

x3≥ 1458

y2= 12x3+18x4

y2= 12 (1458)  + 18 (5)

y2= 17496 +90

y2= $ 17586

The cost can be minimized if the number of students from

                                 Undergraduate         Graduate

East Region              X1≤ 5                            X2  ≥ 13.67

Central                      X3≥ 1458                   X4 ≥ 4.167

West                          X5 ≥ 13                          X6 ≥ 4.76

This will result in the required number of students that is 1500

Constraints:

East Undergraduate must not be greater than 5

East Graduate must not be less than 13

Central Undergraduate must  be greater than 1458

Central Graduate must  be greater than 4

West Undergraduate must  be greater than 13

West Graduate must  be greater than 4

The central total cost $ 17586 due to the number of central undergraduate students 1458 is very high.

The east region has a least cost of $260 and west region has a cost of $300.

The total minimum cost would $ 17586 +$260+ $300= $ 18146

Answer:

Step-by-step explanation:

Answer:

$6.36

Step-by-step explanation:

3 pies require 3/2 cups of lemon juice

16 tablespoons = 1 cup

need 24 tablespoons of lemon juice

need 12 lemons at $0.53 each

total cost = 12 x 0.53 = $6.36

answer:

x = 64

step-by-step explanation:

so we know that, 180 + 26 + x + 90 = 360°

180 + 26 + x + 90 = 360°

296 + x = 360

x = 64°

Answer:

B. g(x)= |x| + 5

Step-by-step explanation:

-5 represents a vertical shift down, so that narrows it down to either A or B. A shows a shift across the horizontal (X) axis, so it must be B.