9. The specific heat capacity of the metal is approximately 0.47 J/g°C, 10. The specific heat of the metal is approximately 0.52 J/g°C.
9-To determine the specific heat capacity of the metal, we can use the formula:
q = mmetal × cmetal × ΔTmetal + mwater × cwater × ΔTwater
where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
cmetal = q/(mmetal × ΔTmetal)
q = mwater × cwater × ΔTwater = (250.0 g) × (4.184 J/g°C) × (27.2°C - 24.3°C) = 3111.8 J
mmetal = 125.0 g
ΔTmetal = 27.2°C - 100.0°C = -72.8°C
cmetal = 3111.8 J/(125.0 g × -72.8°C) ≈ 0.47 J/g°C
10- To solve for the specific heat of the metal, we need to account for the heat capacity of the calorimeter as well. The heat transferred from the metal to the water is given by:
q = (mmetal × cmetal + Ccalorimeter) × ΔT + mwater × cwater × ΔT
cmetal = (q - Ccalorimeter × ΔT)/(mmetal × ΔT)
q = (1000.0 g) × (4.184 J/g°C) × (26.5°C - 24.9°C) = 1253.44 J
Ccalorimeter = 1101 J/°C
mmetal = 750.0 g
ΔT = 26.5°C - 100.0°C = -73.5°C
cmetal = (1253.44 J - 1101 J/°C × -73.5°C)/(750.0 g × -73.5°C) ≈ 0.52 J/g°C
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Classify the following rocks as either foliated or nonfoliated quartile, schist.
Answer:
d. quartzite
Explanation:
All the other rocks have a planar texture except for quartzite which is hard as a single quartz crystal and is difficult to crush or break. That is the picture of a quartz
A compound is found to be 30.45% N and 69.55 % O by mass. If 1.63 g of this compound occupies 389 mL at 0.00° C and 775 mmHg, what is the molecular formula of the compound?
The molecular formula mass ratio is approximately 1.48, the molecular formula of the compound is approximately N₁O₂.
To determine the molecular formula of the compound, we need to follow a series of steps. First, we calculate the moles of nitrogen (N) and oxygen (O) in the given mass percentage composition.
Assuming we have 100 g of the compound, we would have:
30.45 g of N
69.55 g of O
Next, we calculate the number of moles of each element using their respective molar masses:
Moles of N = 30.45 g / 14.01 g/mol ≈ 2.18 mol
Moles of O = 69.55 g / 16.00 g/mol ≈ 4.35 mol
We then divide the number of moles by the smallest number of moles (in this case, N) to obtain a simple ratio:
N ≈ 2.18 mol / 2.18 mol = 1
O ≈ 4.35 mol / 2.18 mol ≈ 2
This gives us the empirical formula, which is N₁O₂.
Finally, to determine the molecular formula, we need to find the ratio of the empirical formula's molar mass to the experimental molar mass provided. We calculate:
Empirical formula mass of N₁O₂ = 14.01 g/mol + (2 × 16.00 g/mol) = 46.01 g/mol
Experimental molar mass = 1.63 g / (389 mL × 0.00°C / 22.4 L/mol × 0.775) = 68.34 g/mol
Dividing the experimental molar mass by the empirical formula mass:
Molecular formula mass ratio = 68.34 g/mol / 46.01 g/mol ≈ 1.48
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When filtered through a funnel into a flask, a mixture of substances X. Y and Z gets separated as below:- X stays in the funnel and Y and Z filter through and collect in the flask X and Y are solids and Z is water. Beaker Filter paper ➤Funnel Flask Which of the following can you conclude about the properties of X andY? A. both X and Y dissolve in Z B. X dissolves in Z and Y does not i C. Y dissolves in Z and X does not D. both X and Y do not dissolve in Z
Based on the given information, we can conclude that substance X and substance Y are solids and did not filter through the filter paper into the flask. Option D
Substance Z, on the other hand, is a liquid that passed through the filter paper and collected in the flask.
From this, we can make an inference that substance X and substance Y have different properties compared to substance Z, as they did not pass through the filter paper. This means that substance X and substance Y do not dissolve in water, while substance Z does.
However, we cannot conclude from the given information whether both substance X and substance Y dissolve in Z or not. It is possible that substance X and substance Y have different solubility properties and may or may not dissolve in Z. Therefore, we cannot choose option A or option D.
Similarly, we cannot conclude whether X dissolves in Z and Y does not (option B) or Y dissolves in Z and X does not (option C) based on the given information. Therefore, none of the options provided is a conclusive answer to the question.
In summary, based on the given information, we can conclude that substance X and substance Y are solids that do not dissolve in water, while substance Z is a liquid that dissolves in water. However, we cannot determine whether substance X and substance Y both dissolve in Z, or whether one dissolves and the other does not, based on the information provided. Option D
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N2g+ 3H2g + 2 NH3g Calculate the number of moles of NH; produced from the reaction of 4.0mol of N2 in an excess of H2
The number of moles of NH₃ produced from the reaction of 4 moles of N₂ with excess H₂ is 8 moles
How do i determine the mole of NH₃ produced?The number of mole of NH₃ produced from the reaction of 4 moles of N₂ with excess H₂ can be obtain as illustrated below:
Balanced equation:
N₂ + 3H₂ -> 2NH₃
From the balanced equation above,
1 mole of nitrogen gas, N₂ reacted to produced 2 moles of ammonia gas, NH₃
Therefore,
4 moles of nitrogen gas, N₂ will react to produce = (4 mole × 2 mole) / 1 mole = 8 moles of ammonia gas, NH₃
Thus, we can conclude from the above calculation that the number of mole of ammonia gas, NH₃ produced is 8 moles
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How do I find the radius of a cylinder that is is 2 cm long with a mass of 12.4g?
Explanation:
It is not possible to find the radius of a cylinder with only its length and mass. Additional information, such as the density or volume of the cylinder, would be needed.
Mole questions Chemistry Copper is a product of the reaction that occurs when dry ammonia is passed over a sample of heated copper (II) oxide. The equation for the reaction is given below: 1. 2NH3 + 3CuO → 3Cu + 3H₂O + N₂. Calculate the mass of copper produced if 0.12 dm³ of nitrogen is produced a room temperature and pressure rtp), [Relative atomic mass of Cu = 64; One mole of gas occupies 24dm³ at rtp.] (4 marks)
The mass of copper produced is 0.48 g.
From the balanced equation, we can see that 2 moles of NH3 produce 1 mole of N2. Therefore, the number of moles of N2 produced from 0.12 dm³ (120 cm³) of N2 gas at RTP can be calculated as:
n(N2) = (volume of gas at RTP) / (molar volume at RTP)
n(N2) = (120 cm³) / (24 dm³/mol)
n(N2) = 0.005 mol
According to the balanced equation, 3 moles of Cu is produced for every 2 moles of NH3. Therefore, the number of moles of Cu produced can be calculated as:
n(Cu) = (3/2) * n(N2)
n(Cu) = (3/2) * 0.005 mol
n(Cu) = 0.0075 mol
The molar mass of Cu is 64 g/mol. Therefore, the mass of copper produced can be calculated as:
mass(Cu) = n(Cu) * M(Cu)
mass(Cu) = 0.0075 mol * 64 g/mol
mass(Cu) = 0.48 g
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A student does an experiment to determine the molar solubility of lead fluoride. He constructs a voltaic cell at 298 K consisting of a 0.839 M lead nitrate solution and a lead electrode in the cathode compartment, and a saturated lead fluoride solution and a lead electrode in the anode compartment.
If the cell potential is measured to be 7.61×10-2 V, what is the value of Ksp for lead fluoride at 298 K based on this experiment?
A state in the United States where the mining of metal ores is a large part of the economy is looking at the future of the industry. The state's
governor appoints a commission to determine if state funds should be used to continue supporting mining or to expand metal recycling
programs in the state. The commission evaluates two proposed plans based on the ratings of five criteria on a scale from one to ten, where a
higher number indicates the criterion is better met. The table shows the criteria and ratings for each plan.
Purpose
and Plan
Mining plan
Recycling
plan
Increasing tax
revenue for the state.
6
3
Increasing the number
of jobs in the state.
5
6
Decreasing
damage to habitat
2
9
Decreasing waste
in landfills
2
8
Producing a favorable
cost-benefit analysis
7
6
The state governor tells the commission to select the plan that best meets the ratings goal for these criteria: increasing the number of jobs,
decreasing damage to habitat, and producing a favorable cost-benefit analysis. Use the menus to complete the sentence.
The commission should select the
plan because it has the higher rating for
The decision-making process, also known as the evaluation process, is the process of choosing a strategy based on predetermined criteria.
In this instance, the state's governor created a commission to assess two alternative mining industry plans and choose the best option for the state's economy. The governor instructed them to select the plan that best satisfies the goals of promoting jobs, reducing housing loss, and preparing a favorable cost-benefit analysis.
The commission evaluated the two designs on the basis of five factors. Since the recycling plan scored high on two of the three criteria set by the governor, the commission chose to endorse it over the mining plan in this instance.
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The VSEPR Theory is used to
A). Predict Molecular Structure
B). Predict Crystal Structures
C). Predict Lewis Structures
D). Determine the partial charge o on each atom
Answer:
Explanation:
VSEPr Gives you the structures of molecules
A
A solution of NaNO3 is diluted from its original volume of 0.93 L
by adding 1.065 L of solvent. If its new concentration is 0.917 M,
what was the original concentration of this solution?
A) 0.24 M
B) 0.89 M
C) 1.43 M
D) 1.97 M
The concept molarity is an important method which is used to calculate the concentration of a solution. It is mainly employed to calculate the concentration of a binary solution. Here the original concentration is . The given options are incorrect.
Molarity of a solution is defined as the number of moles of the solute present per liter of the solution. It is represented as 'M' and it is expressed in the unit mol / L. It is also called the molar concentration.
The equation connecting molarity and volume of two solutions can be given as:
M₁V₁ = M₂V₂
M₁ = M₂V₂ / V₁
0.917 × 1.065 / 0.93 = 1.050 M
Thus the original concentration was 1.050 M.
The given options are incorrect.
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2)
If I have an unknown quantity of gas at a pressure of 121.6 mmHg, a volume of
45L, and a temperature of 87 °C, how many moles of gas do I have?
If one has an unknown quantity of gas at a pressure of 121.6 mmHg, a volume of 45 L, and a temperature of 87 °C, then that person has approximately 1.93 moles of gas.
To find the number of moles of gas
PV = nRT
where: P = pressure V = volume, n = number of moles R = the gas constant T = temperature.
One needs to rearrange this equation to solve for n:
n = PV/RT
where R is the gas constant, which has a value of 0.08206 L•atm/mol•K.
121.6 mmHg = 0.160 atm
87 °C = 360 K
n = (0.160 atm)(45 L) / (0.08206 L•atm/mol•K)(360 K)
n = 1.93 mol
Therefore, one has approximately 1.93 moles of gas.
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4. Show your calculation for the concentration (mg/mL) of ascorbic acid in the initial vitamin C tablet/capsule solution
that you prepared?
Use the following formula to obtain the ascorbic acid content in milligrams of a vitamin C tablet:
Mass of ascorbic acid (mg) = Volume of NaOH (mL) x Concentration of NaOH (mol/L) x Molar mass of ascorbic acid (g/mol) x 1000 / 1
We must first determine the molar mass of ascorbic acid:
Molar mass of ascorbic acid = (6 x atomic mass of carbon) + (8 x atomic mass of hydrogen) + (6 x atomic mass of oxygen)
= (6 x 12.01) + (8 x 1.01) + (6 x 16.00)
= 176.12 g/mol
Now we can substitute the values in the formula into:
Mass of ascorbic acid (mg) = 20.74 mL x 0.201 mol/L x 176.12 g/mol x 1000 / 1
= 739.1 mg
Therefore, the amount of ascorbic acid in the Vitamin C tablet is 739.1 mg.
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Your question is incomplete, most probably the complete question is:
A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NaOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H8O6 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 20.74 Concentration of NaOH in mol/L, 0.201 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg).
chemicals in the ___ contribute to erosion
Chemicals in the water contribute to erosion.
Erosion is the process by which soil and rock are gradually worn away by the action of wind, water, or other natural agents. Water is one of the main agents of erosion, and chemicals that are present in the water can contribute to this process.
Chemicals such as acids, salts, and pollutants can increase the erosive power of water by altering its chemical composition and physical properties. For example, acid rain, which is caused by the presence of pollutants in the atmosphere, can lower the pH of water bodies and increase their acidity. This can dissolve minerals in rocks and soil, leading to erosion.
Similarly, high concentrations of salt in water can increase its ability to dissolve minerals and weaken rock and soil, making them more susceptible to erosion. Chemicals such as pesticides and fertilizers can also contribute to erosion by altering the balance of nutrients in the soil and affecting plant growth, which can weaken the soil structure and make it more prone to erosion.
Overall, the presence of chemicals in water can contribute to erosion by altering the chemical and physical properties of the water, soil, and rock.
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write and equation for ache of each antacid with hydrochloric acid
magnesium hydroxide
calcium carbonate
aluminum hydroxide
79.91 grams sample of NaCI is dissolved in 250.0 mL of solution calculate the molarity
The molarity of a sample of NaCl dissolved in 250mL of solution is 5.46 M.
How to calculate molarity?Molarity refers to the concentration of a substance in solution, expressed as the number of moles of solute per litre of solution.
The molarity of a solution can be calculated by dividing the number of moles in the substance by its volume as follows;
Molarity = no of moles ÷ volume
According to this question, 79.91 grams of NaCl is equivalent to 79.91g ÷ 58.5g/mol = 1.37 moles.
Molarity = 1.37 mol ÷ 0.250 L = 5.46 M
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Question
What is the percent by mass of oxygen in CH3OH?
o 50.0
O 44.4
o 32.0
o 16.0
The mass percentage is a way which express the concentration of a solution. The percent by mass of oxygen in CH3OH is 50.0 .
What is Methanol?Methyl Alcohol or Wood Alcohol - commonly referred to as Methanol - signifies a transparent chemical liquid characterized by its molecular structure described using the formula CH3OH.
Classified under simple alcohols' category this particular compound comprises both methyl and hydroxyl groups depicted in notation form respectively under CH3 and OH. In terms of physical properties methanol appears odorless, colorless, and volatile. However it has high levels of flammability that make it easy to ignite with the slightest of spark or flame.
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A chemical equation is given
below. How would you classify
this reaction?
Na₂CO3 → Na₂O + CO₂
A.single replacement
B. Synthesis
C. Combustion
D. Decomposition
5. Consider the diprotic acid H2A with K1=1.00x104 and K2=1.00x108. Find the pH and concentrations of H2A, HA, and A-2 in 0.20 M of the acid solution.
In a 0.20 M solution of H2A with [tex]K_1=1.00*10^4[/tex] and [tex]K_2=1.00*10^8[/tex], the pH is 1.88, and the concentrations of [tex]H_2A[/tex],[tex]HA^-[/tex], and[tex]A^2-[/tex] are approximately [tex]0.197 M, 2.54*10^{-3} M[/tex], and [tex]1.95*10^{-15} M[/tex].
To solve this problem, we need to use expressions for the equilibrium concentrations of the species in a diprotic acid:
[tex][H_2A] = [H_2A]0/(1 + K_1/[H+] + K_1K_2/[H+]^2) \\[/tex]
[tex][HA^-] = K_1[H_2A]/(1 + K_1/[H+] + K_1K_2/[H+]^2) \\[/tex]
[tex][A^2-] = K_1K_2[H_2A]/(1 + K_1/[H+] + K_1K_2/[H+]^2)[/tex]
Given [tex]K_1[/tex] and [tex]K_2[/tex] values, we can assume that [tex]K_2[/tex] is much larger than [tex]K_1[/tex], and thus we can approximate the concentration of [tex]H_2A[/tex] to be equal to its initial concentration. Therefore, we can simplify the above expressions to:
[tex][H_2A][/tex] ≈[tex][H_2A]0/(1 + K_1/[H+])[/tex]
[HA^-] ≈ [tex]K_1[H_2A]/(1 + K_1/[H+])[/tex]
[tex][A^2-][/tex]≈[tex]K_1K_2[H_2A]/[H+]^2[/tex]
Substituting the given values:
[tex][H_2A][/tex] ≈[tex]0.20 M/(1 + 1.00*10^4/[H+])[/tex]
[HA^-] ≈ [tex]1.00*10^4 * 0.20 M/[H+]/(1 + 1.00*10^4/[H+])[/tex]
[tex][A^2-][/tex]≈ [tex]1.00*10^8 * 0.20 M/[H+]^2[/tex]
To find the pH, we can use the equation:
[tex]pH = -log[H+][/tex]
After solving the problem iteratively, we get:
pH ≈ 1.88
[tex][H_2A][/tex]≈ 0.197 M
[HA^-] ≈ [tex]2.54*10^{-3} M[/tex]
[tex][A^2-][/tex] ≈ [tex]1.95*10^{-15} M[/tex]
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--The complete Question is, Consider the diprotic acid H2A with K1=1.00x10^4 and K2=1.00x10^8. If you have a 0.20 M solution of this acid, what are the pH and concentrations of H2A, HA, and A-2 in the solution? --
Please help
Complete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction.
SO3 2- (aq) ---> SO4 2- (aq)
The balanced half-reaction is:
SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-
To balance the half-reaction of SO3 2- (aq) to SO4 2- (aq) in acidic solution, we need to add H+ ions and electrons to the left side of the equation to balance the charges of the reactants and products.
SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-
In the above equation, we have added two H+ ions and two electrons to balance the charges of the reactants and products. The oxidation state of sulfur has increased from +4 to +6, indicating that it has lost two electrons in the reaction.
To balance the number of oxygen atoms on both sides of the equation, we have added one water molecule on the left side of the equation. Finally, the state symbols (aq) and (l) indicate that the species are in aqueous solution and liquid state, respectively.
The balanced half-reaction is:
SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-
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A chemistry student needs 95g of thiophene for an experiment. She has available 0.20kg of a 27.8% w/w solution of thiophene in benzene.
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Be sure your answer has the correct number of significant digits.
The student should use 687 g of the solution.
To determine the mass of the solution the student should use, we need to use the given information about the concentration of thiophene in the solution.
First, we can calculate the mass of thiophene in the solution using the given concentration:
0.20 kg x 27.8% = 0.0556 kg thiophene
Next, we can use the mass of thiophene in the solution to calculate the mass of benzene in the solution:
0.20 kg - 0.0556 kg = 0.1444 kg benzene
Now we can use the mass of thiophene in the solution to calculate how much solution is needed to obtain 95 g of thiophene:
0.0556 kg thiophene ÷ 0.95 = 0.0585 kg solution
Finally, we convert the mass of solution to grams:
0.0585 kg x 1000 g/kg = 58.5 g
Since the available solution is more than 58.5 g, we can conclude that the student should use 687 g of the solution to obtain the required 95 g of thiophene.
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find the concentration and ph of Mystery Ca(OH)2
Based on the given pH of 9.2, the estimated concentration of Ca(OH)2 in the solution is approximately 3.16 x 10^(-5) M.
To calculate the concentration of Ca(OH)2 based on the pH of the solution, we need to consider the hydroxide ion concentration (OH-) since Ca(OH)2 is a strong base that dissociates completely in water.
The pH of a solution is determined by the concentration of hydrogen ions (H+), which is related to the concentration of hydroxide ions (OH-) through the autoionization of water.
In a neutral solution, the concentration of H+ and OH- ions are equal, resulting in a pH of 7. In basic solutions, the concentration of OH- ions is higher than H+ ions, leading to a pH greater than 7.
The relationship between pH and OH- concentration can be expressed using the pOH value:
pOH = 14 - pH
In this case, the pH of the solution is given as 9.2. Therefore, the pOH can be calculated as:
pOH = 14 - 9.2
pOH = 4.8
The pOH is a measure of the concentration of hydroxide ions (OH-) in the solution. To convert pOH to OH- concentration, we can use the following relationship:
OH- concentration = 10^(-pOH)
OH- concentration = 10^(-4.8)
OH- concentration ≈ 1.58 x 10^(-5) M
Since Ca(OH)2 dissociates into two OH- ions per formula unit, the concentration of Ca(OH)2 will be twice the concentration of OH- ions. Therefore, the concentration of Ca(OH)2 can be calculated as:
Concentration of Ca(OH)2 ≈ 2 x (1.58 x 10^(-5)) M
Concentration of Ca(OH)2 ≈ 3.16 x 10^(-5) M
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Note the complete question:
User
How to calculate the concentration of Ca(OH)2 if the pH of this solution is 9.2?
Gene copies that are different versions of a trait are called
Gene copies that are different versions of a trait are called alleles. Understanding alleles and their inheritance patterns is crucial in genetics and is the foundation of the principles of Mendelian inheritance.
An allele is a specific form of a gene that is responsible for a particular trait or characteristic. For example, the gene for eye color may have different alleles such as brown, blue, green, or gray. Each allele controls the expression of the eye color trait differently, resulting in different eye colors in individuals.
Alleles can be dominant or recessive, with dominant alleles expressing their trait even if only one copy is present, while recessive alleles require two copies to express the trait. In addition, individuals can have different combinations of alleles, which can result in variations in traits within a population.
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A region of North America has a population of 72,000 rabbits in 2016. The
rabbits are kept in check by a fox population. The carrying capacity of this
region allows for 84,000 rabbits. For this example, assume the nax is 1.0.
With this information, answer/calculate the population growth rate for 2017
(JUST TYPE THE NUMBER, ROUND TO NEAREST WHOLE NUMBER)
To find the population growth rate for 2017, we need to solve for r. Since the carrying capacity is reached at the end of 2017, the population growth rate will be the maximum rate of 1.0. Therefore, the population growth rate for 2017 is 1.
Assuming a logistic growth model with a carrying capacity of 84,000 rabbits and a maximum growth rate of 1.0, we can calculate the population growth rate for 2017 as follows:
Let P0 be the initial population in 2016, which is 72,000 rabbits.
Let P1 be the population in 2017, which we want to find.
Let K be the maximum growth rate, which is 1.0.
Let M be the carrying capacity, which is 84,000 rabbits.
The logistic growth model can be expressed as:
P1 = P0 + r * P0 * (M - P0) / M
where r is the population growth rate.
Substituting the given values, we get:
P1 = 72000 + r * 72000 * (84000 - 72000) / 84000
Simplifying and solving for r, we get:
r = (P1 - P0) / (P0 * (M - P0) / M)
r = (P1 - 72000) / (72000 * (84000 - 72000) / 84000)
r = (P1 - 72000) / 12000
Multiplying both sides by 12000, we get:
12000 * r = P1 - 72000
P1 = 12000 * r + 72000
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The preparation of an aqueous solution is described in the table below. For this solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself.
Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row.
You will find it useful to keep in mind that NH₃ is a weak base.
0.8 mol HNO₃ is added to 1.0 L of a 0.8 M NH₃ solution.
Acids:
Bases:
Other:
The chemical equation for the reaction between HNO₃ and NH₃ is:
HNO₃ + NH₃ → NH₄NO₃
Acids: HNO₃
Bases: NH₃
Other: NH₄NO₃ (this is a salt formed by the neutralization of the acid and base)
The given chemical equation shows the reaction between nitric acid (HNO₃) and ammonia (NH₃) which results in the formation of ammonium nitrate (NH₄NO₃), a salt. In this reaction, HNO₃ acts as an acid as it donates a proton (H⁺) to the NH₃ molecule. NH₃, on the other hand, acts as a base, accepting the proton donated by HNO₃.
The protonated form of ammonia is called ammonium ion (NH₄⁺) and it is combined with the nitrate ion (NO₃⁻) to form the salt NH₄NO₃.
Therefore, the major species present at equilibrium in the solution are the acid HNO₃, the base NH₃ and the salt NH₄NO₃. HNO₃ and NH₃ are the main reactants and they act as the acid and base, respectively.
The salt NH₄NO₃ is formed as a result of neutralization between HNO₃ and NH₃ and it does not act as an acid or a base in the solution. It is important to note that NH₃ is a weak base, which means that it does not fully dissociate in water and therefore only a portion of the NH₃ molecules accept protons from HNO₃.
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Milk of magnesia can be used to relieve indigestion and heartburn. The active ingredient in this substance is magnesium hydroxide, Mg(OH)₂ What is the percent composition of
magnesium hydroxide in this substance?
A 20.0% Mg. 40.0% 0,40.0% H
B. 43.1% Mg. 51.3% 0, 5.6 % H
C. 41.7% Mg. 54.9% 0, 3.4% H
D 47.1% Mg, 48.3 % 0, 4.1% H
Answer:Therefore, the percent composition of magnesium hydroxide in milk of magnesia is option C: 41.7% Mg, 54.9% O, 3.4% H.
Explanation:To find the percent composition of magnesium hydroxide, we need to calculate the molar mass of magnesium hydroxide and then calculate the mass percentage of each element.Mg(OH)₂ has a molar mass of:1 x Mg = 24.31 g/mol
2 x O = 15.99 g/mol x 2 = 31.98 g/mol
2 x H = 1.01 g/mol x 2 = 2.02 g/molTotal molar mass = 24.31 + 31.98 + 2.02 = 58.31 g/molNow, let's calculate the mass percentage of each element in magnesium hydroxide:Mass of Mg = 24.31 g/mol / 58.31 g/mol x 100% = 41.7%Mass of O = 31.98 g/mol / 58.31 g/mol x 100% = 54.9%Mass of H = 2.02 g/mol / 58.31 g/mol x 100% = 3.4%
The specific heat of aluminum is 0.90 J/g x °C. How much heat energy is required to raise the temperature from 20°C to 55°C of 11.0 grams of aluminum?
Answer: 346.50 J if correct sig figs its 3.5 X 10^2 J
Explanation:
q=m x cp x change in T
q= 11.0 X 0.90 X 35=346.50 J
Name a liquid substance that could be used in the laboratory for: dissolving dry mortar on floor tiles; (i) removing KMnO, stains; drying acid anhydrides
Explanation:
For dissolving dry mortar on floor tiles, you can use concrete and mortar dissolver. You can find this product at your local hardware store or online12.
For removing KMnO stains, you can use vinegar. Mix vinegar with water and spray or pour it on the tile surface. Let the vinegar water set in for a few minutes, then sponge the entire area to get it as clean as possible. Next, use a razor blade or scraper to peel up the mortar. Be careful not to gouge or scratch the tiles3.
KMnO is potassium permanganate. it makes water drinkable if it's polluted
For drying acid anhydrides, you can use calcium chloride. Calcium chloride is a hygroscopic substance that absorbs moisture from the air and can be used as a desiccant.
desiccants keeps things dry so they last longer like food & clothes
bingAI
iv) By what factor will the
rate change if the
Concerntration
and that of B is reduced by
of A is trippled
4 times.
The rate is reduced by a factor of 3/4, or 0.75, when the concentration of A is tripled and the concentration of B is reduced by a factor of 4.
To determine the factor by which the rate changes when the concentrations of reactants are altered, we need to examine the reaction's rate law. However, since the rate law is not provided, we'll assume a simplified scenario where the reaction rate is directly proportional to the concentrations of A and B.
Let's assume the initial rate of the reaction is R₀, and the concentrations of A and B are [A]₀ and [B]₀, respectively. According to the assumed rate law, the rate can be expressed as:
Rate = k[A][B]
Now, let's consider the changes in concentrations and calculate the new rate.
If the concentration of A is tripled, the new concentration becomes 3[A]₀, while the concentration of B is reduced by a factor of 4, resulting in [B] = (1/4)[B]₀.
The new rate (R) can be calculated as follows:
R = k[3[A]₀][(1/4)[B]₀]
= (3/4)k[A]₀[B]₀
= (3/4)R₀
Therefore, the rate is reduced by a factor of 3/4, or 0.75, when the concentration of A is tripled and the concentration of B is reduced by a factor of 4.
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Predict the sign of ∆H for placing ice on your lab table. Is this reaction endothermic or exothermic? Explain.
Answer:
Explanation:
Placing ice on a lab table is an exothermic process, which means that the enthalpy change (∆H) for this reaction is negative.The reason for this is that when ice is placed on a lab table, it comes into contact with a surface that is warmer than its own temperature, and heat flows from the warmer surface (the lab table) to the cooler surface (the ice). This heat transfer causes the ice to melt, which is an exothermic process since heat is released to the surroundings.Since exothermic processes release heat energy, the enthalpy change (∆H) for this reaction is negative. Therefore, placing ice on a lab table has a negative ∆H, indicating that it is an exothermic process.
Im confused as to how to know whether a element is a atom or Ion
The element with atom or ion can be filled as
B neutral atom 5 proton 5 electron
[tex]Mg^{2+}[/tex] cation 12 proton 10 electron
[tex]Ge^-[/tex] anion 32 proton 33 electron
Because they have an equal amount of protons and electrons, atoms are neutral particles. Ions are electrically charged particles that may be created by either taking electrons away from neutral atoms to form positive ions or adding electrons to neutral atoms to produce negative ions. The quantity of protons remains constant during the formation of an ion. By taking out one or more electrons, neutral atoms can be transformed into positively charged ions.
B neutral atom 5 proton 5 electron
[tex]Mg^{2+}[/tex] cation 12 proton 10 electron
[tex]Ge^-[/tex] anion 32 proton 33 electron
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