83. A sailboat travels south at 12.0 km/h with respect to the
water against a current 15.0° south of east at 4.0 km/h.
What is the boat's velocity?

Answers

Answer 1

Answer:

The magnitude of the boat's velocity is 8.21 km/h.

Explanation:

We can find the boat's velocity as follows:

[tex] \Epsilon V_{x} = V_{w_{x}} + V_{b_{y}} [/tex]            

[tex] \Epsilon V_{y} = V_{w_{y}} + V_{b_{y}} [/tex]

Where:

[tex]V_{w_{x}}[/tex] and [tex]V_{w_{y}}[/tex] are the components of the velocity of the water in the x and y-direction

[tex]V_{b_{x}}[/tex] and [tex]V_{b_{y}}[/tex] are the components of the velocity of the boat in the x and y-direction

Since the angle is 15° we have:

[tex] \Epsilon V_{x} = -4.0 km/h*sin(15) + 0 = -1.04 km/h [/tex]  

[tex] \Epsilon V_{y} = 4.0 km/h*cos(15) - 12.0 km/h = -8.14 km/h [/tex]

Now, the velocity of the boat is:  

[tex] V = \sqrt{V_{x}^{2} + V_{y}^{2}} = \sqrt{(-1.04 km/h)^{2} + (-8.14 km/h)^{2}} = 8.21 km/h [/tex]

Therefore, the magnitude of the boat's velocity is 8.21 km/h.

I hope it helps you!


Related Questions

Suppose the Sun is 1.29025 X 108 km from
Earth.
The speed of light is 2.99792 x 108 m/s.
How long does it take for its light to reach
us?
Answer in units of min.

Answers

Answer:

It takes the Sun's light 7.17 minutes to reach us.

Explanation:

We can calculate the time that takes the light to reach us by using the following equation:

[tex] t = \frac{d}{c} [/tex]    

Where:

d: is the distance = 1.29025x10⁸ km = 1.29025x10¹¹ m

c: si the speed of light = 2.99792x10⁸ m/s  

Hence, the time is:

[tex] t = \frac{d}{c} = \frac{1.29025 \cdot 10^{11} m}{2.99792 \cdot 10^{8} m/s} = 430.38 s = 7.17 min [/tex]

Therefore, it takes the Sun's light 7.17 minutes to reach us.

I hope it helps you!

mary travelled 70mph due north
this is an example of
Acceleration
distance
speed
velocity

Answers

Velocity because It is defined as the change in the position with respect to the time. Velocity is a vector quantity that means it depends on the magnitude and direction of an object. The S.I unit of velocity is, m/s

Acceleration : It is defined as the rate of change of velocity of an object wit respect to the time. Acceleration is a vector quantity that means it depends on the magnitude and direction of an object. The S.I unit of acceleration is, m/s to the power of 2

Distance : It is defined as the how far an object has traveled in time. Distance is a scalar quantity that means it is depends on the magnitude of an object only. The S.I unit of distance is, m

Speed : It is defined as the distance traveled by an object in unit time. Speed is also a scalar quantity. The S.I unit of speed is, m/s

Mary traveled 70 miles/hour due north. This is an example of velocity. 70 miles/hour tell us about the magnitude of the object and north tell us about the direction of an object.
Hence, the correct option is, velocity.







If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain using Newton's second law

Answers

Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

Answer:

the bike

Explanation:

it has less mass than the motorcycle so so it would have more acceleration

does anyone have the same thing for the brainly app
mine said "this operation couldn't complete" an does anyone know how to fix it

i am on iphone

Answers

Answer:

PICK ONE

Explanation:

Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?

Answers

Answer:

The net charge on each sphere is -1.5 q

Explanation:

Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again

The given parameters of the conducting spheres meant to touch are;

The net charge on the first sphere, Q₁ = +5.0 q

The net charge on the second sphere, Q₂ = -8.0 q

The net charge on each sphere after touching and then separated, 'Q', is given as follows;

[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]

Therefore, by substituting the known values of the variables, we have;

[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]

The net charge on each sphere, Q = -1.5 q.

The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q

What is charge?

Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again

The given parameters of the conducting spheres meant to touch are;

The net charge on the first sphere, Q₁ = +5.0 q

The net charge on the second sphere, Q₂ = -8.0 q

The net charge on each sphere after touching and then separated, 'Q', is given as follows;

[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]

Therefore, by substituting the known values of the variables, we have;

[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]

Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q

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The first charge is pulling on the second. Is the second pulling on the first? Explain your reasoning

Answers

Answer:

law of action and reaction.

Explanation:

In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.

In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.

Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body

An electric force is an attractive or repulsive interaction. Newton's laws of motion define how it affects things, just like any other force. Yes, the second pulling on the first.

How does Newton's third law explain in terms of electricity?

An electric force is an attractive or repulsive interaction between any two charged things. Newton's laws of motion define how it affects things, just like any other force.

The motion of objects under the influence of such a force or combination of forces is studied using Newton's laws.

The analysis generally starts with the creation of a free-body diagram in which the kind and direction of the various forces are represented by vector arrows.

Newton's laws of motion define how it affects things, just like any other force. Hence Yes, the second pulling on the first.

To learn more about Newton's third law refer to the link;

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If the small piston has an area of .004 square
meters and Bob pushes down on it with 225 N of
force, how much weight can he lift on the car
side of the system, if that piston's area is 3.5
square meters?

Answers

F₂ = 1.723 x 10⁸ N

Further explanation

Given

Area of small piston : 0.004 m²

Area of large piston : 3.5 m²

Force 225 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

225/0.004 m² = F₂/3.5² m²

F₂ = 1.723 x 10⁸ N

A surfer paddles to where the waves are sinusoidal with crests 14 m apart. He bobs a vertical distance 3.6 m from trough to crest, which takes 1.5 s. Find the wave speed, & describe the wave.

Answers

Answer:

v = 9.34 m/s

Explanation:

Given that,

The distance between crests, [tex]\lambda=14\ m[/tex]

The vertical distance from trough to crest = 3.6 m

Time taken, t = 1.5 s

The amplitude of wave = vertical distance from trough to crest /2

= 3.6/2

= 1.8 m

The speed of the wave is given by :

[tex]v=f\times \lambda\\\\=\dfrac{\lambda}{T}\\\\=\dfrac{14}{1.5}\\\\=9.34\ m/s[/tex]

So, the speed of the wave is 9.34 m/s.

The height of a transverse waves is known as its?

Answers

Answer:

amplitude

Explanation:

wave is a called the crest, and the low point is called the trough. For longitudinal waves, the compressions and rarefactions are analogous to the crests and troughs of transverse waves. The distance between successive crests or troughs is called the wavelength. The height of a wave is the amplitude.…

If a man with
with long-sighted eye want to
a' text book, what shoðld be the distance between
book and the lens? Give reason​

Answers

Lots of factors play a role. Firstly if he is presbyopic he won't be able to read without specs at normal reading distances. Many years ago a chap by the name of Donders published a table which shows a linear relationship between age and ability to focus. The ready made reader market relies on his findings to suggest the power you need for reading at different ages. Secondly if he is far sighted (needing correction at distance to see clearly) it will also influence his ability to see close. For example +3.00D distance Rx at an age of 40 years will be very different than the same prescription at age 20 years due to his ability to accommodate. My suggestion is to have comprehensive eye exam to find out what you need at the specific working distance (computer or laptop or book reading all have different reading distances).

PLS ANSWER FAST WILL GIVE BRAINLEST!!!


Calculate the missing variables using the necessary formula and rules using "FORCE"

A water filled balloon with an overall mass of 1 kg undergoes an acceleration of 2m/s2. How much force is being applied to the ballon?

Answers

Answer:

2 Newtons

Explanation:

[tex]F = ma[/tex]

Therefore, your mass would be 1kg and your acceleration would be 2m/s/s

Plug the numbers into the equation:

[tex](1kg)(2m/s/s)[/tex]

which will equal

[tex]2 Newtons[/tex]

John slides down a hill at a 4 m height initially at rest. If all energy is conserved and friction is excluded, what is John's velocity at the bottom of the ramp?

Answers

The velocity at the bottom : v = 8.85 m/s

Further explanation

Given

height of the hill = 4 m

Required

The velocity at the bottom

Solution

The law of conservation energy :

ME₁=ME₂

(PE+KE)₁ = (PE+KE)₂

initially at rest⇒vo=0⇒KE₁=0

At the bottom⇒h=0⇒PE₂=0

So the equation becomes :

PE₁=KE₂

mgh=1/2.mv²

gh = 1/2v²

[tex]\tt v=\sqrt{2gh}[/tex]

v = √2x9.8x4

v = 8.85 m/s

A merry-go-round accelerating uniformly from rest achieves itsoperating speed of 2.5rpm in five revolution.


A) What is the magnitude of its angluar acceleration(rad/s^2)?

B) How many seconds does it take the merry-go-round to reachits operating speed?

Answers

Answer:

(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²

(B) Time of motion 240.2 s

Explanation:

Given;

final angular speed, ωf = 2.5 RPM

angular distance, θ = 5 rev = 5 x 2π = 10π rad

initial angular speed, ωi = 0

final angular speed in rad/s;

[tex]\omega_f = \frac{2.5 \ rev}{min} \times \ \frac{2\pi}{1 \ rev} \times \ \frac{1 \min}{60 s} = 0.2618 \ rad/s \\[/tex]

(A) the magnitude of its angular acceleration(rad/s^2);

[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\(0.2618)^2 = 0 + (2\times 10\pi)\alpha\\\\0.0685 = 20\pi \alpha\\\\\alpha = \frac{0.0685}{20\pi} \\\\\alpha = 1.09\times 10^{-3} \ rad/s^2[/tex]

(B) Time of motion;

[tex]\omega_f = \omega_i + \alpha t\\\\0.2618 = 0 + 1.09\times 10^{-3} t\\\\t = \frac{0.2618}{1.09\times 10^{-3}} \\\\t = 240.2 \ s[/tex]

Which of the following technologies would produce the most energy in light
waves?
A. Infrared sensor on a DVD player
B. Wireless communications transmitter
C. Microwave industrial drying equipment
D. Compact fluorescent lightbulb

Answers

Answer:

D. Compact fluorescent lightbulb

Explanation:

Compact fluorescent lightbulb

A compact fluorescent light bulb would produce the most energy in light

waves, therefore the correct option is D.

What is electromagnetic radiation?

Electromagnetic radiation is a type of energy radiation produced by the propagation of electromagnetic waves that are produced for natural as well as anthropogenic reasons. This radiation does not need any kind of medium to propagate. The electromagnetic wave has components of light as well as heat in them.

Different kinds of electromagnetic radiation have varied levels of energy for example solar radiation is also a form of electromagnetic radiation and gamma radiation is electromagnetic radiation with very high energy.

Most energy in the form of the light wave is produced by the Compact fluorescent lightbulb, therefore the correct option is D.

Learn more about electromagnetic radiation

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if a 50.0-kg mass weighs 554 n on the planet saturn, calculate saturn’s radius

Answers

Answer:

17.35 × 10^(-6) m

Explanation:

Mass; m = 50 kg

Weight; W = 554 N

Now, we know that;

W = mg

Thus; 554 = 50g

g = 554/50

g = 11.08 m/s²

Also, we know that;

mg = GMm/r²

g = GM/r²

Making t the subject gives;

r = √(GM/g)

G has a constant value of 6.67 × 10^(-11) Nm²/kg²

r = √(6.67 × 10^(-11) × 50/11.08)

r = 17.35 × 10^(-6) m

The radius of the saturn is [tex]\bold {17.35 x 10^{-6 }m}[/tex] if  a 50.0-kg mass weighs 554 N.

From Newton's second law,

W = mg  

554 = 50 x g  

g = 554/50  

g = 11.08 m/s²  

Now, Newton's law of gravitation  

[tex]\bold {F=G{\dfrac{m_1m_2}{r^2}}}[/tex]

Where,

F = force

G = gravitational constant = 6.67 x 10^-11 N.m²/kg²

m1 & m2= mass  = M = 50 kg

r = distance between centers of the masses

Put the values and solve it for r,  

[tex]\bold {r = \sqrt {(6.67 x10^{-11} \times \dfrac {50}{11.08}}}\\\\\bold {r = 17.35 x 10^{-6 }m}[/tex]

Therefore, the radius of the saturn is [tex]\bold {17.35 x 10^{-6 }m}[/tex] if  a 50.0-kg mass weighs 554 N.

To know more about Newton's law of gravitation

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Julieta kicks a 0.2 kg soccer ball already rolling in the same direction at 2.5 m/s. The ball leaves her foot at a speed of 20 m/s after the kick

Answers

Answer:

3.5kgm/s

Explanation:

We can calculate the momentum of Julieta

momentum = m(v-u)

Momentum = 0.2(20-2.5)

Momentum = 0.2(17.5)

Momentum = 3.5

Hence the momentum of Julieta is 3.5kgm/s

What is the mathematical relationship between height, mass, gravity, and gravitational potential energy?

Answers

The change in gravitational potential energy, ΔPEg, is ΔPEg = mgh, with h being the increase in height and g the acceleration due to gravity. The gravitational potential energy of an object near Earth's surface is due to its position in the mass-Earth system.

Suman with a mass of 45kg climbs in 3m heigh ladder in 10 seconds. Calculate her power. Plz help me​

Answers

Answer:

work done=fdcosø

f=mg=450N

d=+3m

ø=180

450×3×cos(180°) power=work done/

time taken

1350×-1 p=135watts

Sometimes, a crackling sound is heard while taking off a sweater during winters. Explain

Answers

Answer:

it is somewhat frozen

Explanation:


5.Which graph above shows an object's acceleration? 1pt
6. Why did you choose that graph in question above (explain why)? 1pt

Answers

5. B shoes an objects acceleration

6. B is the answer because a position time graph shoes velocity; hence v=change in x/t

PLS ANSWER FAST WILL GIVE BRAINLYEST TIMED TEST!!!!


use the equation solving a= F divided by M

Also use metres per second squared [m/s2]


A Spring balance is used to launch a 0.05 kg foam ball with a force of 5N. What acceleration is produced?

Answers

using a=f/m u get 100 bc 5/.05 =100m/s

Which vector has an x-component with a length of 3?
А. С.
B. d
C. a
D. b

Answers

Answer:

B.d

mark me as brainlist

Answer:

D. b

Explanation:

the endpoint of vector b is at 3, which means the length is 3

A 10 kg bowling ball would require what force to accelerate down an alley at a rate of 3 m/s2? what is the net force? ​

Answers

Answer:

a. Force = 30N

b. Fnet = 128N

Explanation:

Given the following data;

Mass = 10 kg

Acceleration = 3m/s²

a. To find the force;

Force = mass * acceleration

Substituting into the equation, we have

Force = 10 * 3

Force = 30N

b. To find the net force;

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

Fnet is the net force. Fapp is the applied force. Fg is the force due to gravitation.

We know that acceleration due to gravity is equal to 9.8m/s²

To find the gravitational force;

We know that acceleration due to gravity, g = 9.8m/s²

Fg = mg = 10*9.8 = 98N

Substituting into the equation, we have;

Fnet = 30 + 98

Fnet = 128N

5. Which organisms are used to manufacture human insulin?
A. algae
B. amoebas
C. bacteria
D. protozoans

Answers

The answer is going to be C, Bacteria. Therefore the organisms that are used to manufacture human insulin would be bacteria.

The organism that is used to manufacture human insulin is known as the bacteria E. Coli. Thus, the correct option for this question is C.

What is the function of human insulin?

The function of human insulin is to maintain the blood sugar level by converting the active form of sugar which is glucose into the stored form of glycogen in order to maintain the blood sugar level.

In this modern era of science and technology, recombinant human insulin is mainly synthesized or produced with the help of organisms like E. Coli which is classified in the category of bacteria, and Saccharomyces cerevisiae which is classified in the category of unicellular fungus.

Therefore, the organism that is used to manufacture human insulin is known as the bacteria E. Coli. Thus, the correct option for this question is C.

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You weigh 580 N on Earth. If you were to go to Mars, where its gravitational pull is 3 . 7 11 m /s 2 , what would you weigh? (Hint: gravity on Earth is 9.8 m /s 2 .

Answers

Answer:

59.18 kg

Explanation:

use f=ma

f= 580 N

a = 9.8 m/s 2

weigh(m) doesn't change only force(F) changes

Answer: 219.6N

Explanation:

Find the mass of this person by dividing his weight by the accelleration. Remember, F=ma

580 = m*9.8

m = 59.18kg

Then multiply the mass by the new gravitational acceleration on Mars.

59.18*3.711 = 219.6N

A student is preparing to take a bath when she realizes the hot water tap in the bathroom is not working. The student goes to the kitchen and prepares 10 of 100°C water to mix with 10 L of 10°C water.

Answers

Answer:

(10 L)(100° C) + (90 L)(10°) = (100 L)T

1,000 + 900 = 100T

1,900 = 100T

100T = 1,900

T = 1,900/100

Explanation:

Need help ASAP
Thanks + BRAINLIST only for correct answer

1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves

2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above

3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna

Answers

Answer:

Explanation:

1.electric

2.radio wave

3.broadcast

Hope it helped you.

Part C
How many combined bits of storage are there on the two tablets?

Answers

Answer:

IVE BEEN TRYNA FIND THE ANSWER FOR THE PAST HOUR T-T

Explanation:

Answer:

3.2 x10^11 bits of storage

Explanation:

A 1600 kg car with the brakes applied comes to a stop in 4.20 seconds. During these 4.20 seconds the force of friction slowing down the car is 3900 N. What is the change in momentum of the car?

Answers

Answer:

The change in momentum of the car is 16380.8 kg.m/s

Explanation:

Given;

mass of the car, m = 1600 kg

time of motion, t = 4.20s

force of friction on the car, F = 3900 N

final velocity of the car after the brakes were applied, v = 0

The initial velocity of the car during the motion is calculated as;

[tex]F = ma = \frac{mu}{t} \\\\mu = Ft\\\\u = \frac{Ft}{m} \\\\u = \frac{3900\times 4.2}{1600} \\\\u = 10.238 \ m/s[/tex]

The change in momentum of the car is calculated as;

ΔP = mu

ΔP = 1600 x 10.238

ΔP = 16380.8 kg.m/s

What is the best example of a compound machine A ax. B ramp. C car D screw

Answers

Answer: I believe the answer is C

Explanation:

Cars are composed of hundreds of simple machines

The answer to this question is C.) Car,
hopes this helps, and if you can, pls mark me brainliest :D
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