Answer:
D. 3:7Step-by-step explanation:
1 dollar = 30 cents tax + 70 cents net income
The ratio of taxes to net income:
30 : 70 = 3 : 7Correct choice is D
If 30cents are out then net income=100-30=70
ratio:-
[tex]\\ \rm\Rrightarrow \dfrac{30}{70}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{3}{7}[/tex]
[tex]\\ \rm\Rrightarrow 3:7[/tex]
construct thruth table for each of the following Statement
Rhonda I just got home from
in figure , EF=1 and FC=2 What is the length of AC?
Step-by-step explanation:
ae=ec
ec=1+2=3
then ae=3
Answer:
6-most likely (AC=6)
Step-by-step explanation:
Because the 2 sides, AE and EC *look the same. Also you can look at the opposite sides.
*This is what I think
Choose the best answer to the following question. Explain your reasoning with one or more complete sentences. At 11:00 you place a single bacterium in a bottle, and at 11:01 it divides into 2 bacteria, which at 11:02 divide into 4 bacteria, and so on. How many bacteria will be in the bottle at 11:30?
Answer:
we could work this out by geometric sequence
Step-by-step explanation:
G1=2, G2=4, we have a formula,Gn=G1r^n-1
G2=G1 (r)^1, 4=2r, r=2
G30=G1 (2)^29=1,073,741,824 bacterium
A house m by m is surrounded by a walkway m wide. 27 9 1.8 a) Find the area of the region covered by the house and the walkway. b) Find the area of the walkway.
Answer:
A. 385.56 square meters.
B. 142.56 square meters.
Step-by-step explanation:
A house 27m by 9m is surrounded by a walkway 1.8m wide.
a) Find the area of the region covered by the house and the walkway.
b) Find the area of the walkway.
Let
Length of the house=l=27m
Width of the house=w=9m
Wideness of the walkway=x=1.8m
Area of the region covered by the house and the walkway
=( L + 2*x) * (w + 2*x)
= (27+2*1.8)*(9+2*1.8)
=(27+3.6)*(9+3.6)
=(30.6)*(12.6)
=385.56 square meters.
b) Area of the walkway
= (L + 2*x)*(w + 2*x) - l*w
= (27+2*1.8)*(9+2*1.8) - 27*9
=(27+3.6)*(9+3.6) - 243
=(30.6)*(12.6) - 243
=385.56 - 243
=142.56 square meters.
What is the surface area?
9 ft
6 ft
3 ft
square feet
Answer:
the answer to this question is equal to 162
Simplify: y^-3
a) 3/y
b) - 1/y^3
c) -3y
d) 1/y^3
Answer:
1/y^3
Step-by-step explanation:
We know that a^-b = 1/a^b
y ^-3 = 1/y^3
A taste test asks people from Texas and California which pasta they prefer, brand A or brand B. The table shows the results. A person is randomly selected from those tested. What is the probability that the person is from Texas, given that the person prefers Brand B? PLEASE HELP! I'll name you Brainliest if you're answer is the best!
Answer:
A
Step-by-step explanation:
It would be A because there are 45 people in Texas that prefer brand B. There are 105 people in total that prefer brand B. 45/105 is .42857... so rounded it would be .43, therefore A. I hope this helps.
Answer:
A
Step-by-step explanation:
Please answer ASAP PLEASE!
Answer/Step-by-step explanation:
The inequality, x ≤ 7, has solutions that includes values that is equal to 1 or less than 7.
This can be represented on a number line as shown in the number line graphed in the attachment below.
A full circle or shaded "o" indicates that the number 7 is included in the solution.
The arrow points from 7 to the left, telling us that the value of x are all numbers from 7 and below.
The mass of a species of mouse commonly found in houses is normally distributed with a mean of 20.2 grams with a standard deviation of 0.18 grams. Enter your responses as a decimal with 4 decimal places. (a) What is the probability that a randomly chosen mouse has a mass of less than 19.99 grams?
Answer:
12.1%
Step-by-step explanation:
Given that:
Mean (μ) = 20.2 grams and standard deviation (σ) = 0.18 grams.
The z score is a score used to determine the number of standard deviations by which the raw score is above or below the mean. A positive z score means that the raw score is above the mean and a negative z score means that the raw score is below the mean. It is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
a) For x < 19.99 g:
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{19.99-20.2}{0.18} \\\\z=-1.17[/tex]
From the normal distribution table, P(x < 19.99) = P(z < -1.17) = 0.1210 = 12.1%
The probability that a randomly chosen mouse has a mass of less than 19.99 grams is 12.1%
A train goes at a speed of 70km / h. If it remains constant at that speed, how many km will it travel in 60 minutes?
Answer:
Total distance travel by train = 70 km
Step-by-step explanation:
Given:
Speed of train = 70 km/h
Total time taken = 60 min = 60 / 60 = 1 hour
Find:
Total distance travel by train
Computation:
Distance = Speed × Time
Total distance travel by train = Speed of train × Total time taken
Total distance travel by train = 70 × 1
Total distance travel by train = 70 km
Last year, Leila had $30,000 to invest. She invested some of it in an account that paid 6% simple interest per year, and she invested the rest in an account that paid 5% simple interest per year. After one year, she received a total of $1580 in interest. How much did she invest in each account?
Answer:
6%: $8,0005%: $22,000Step-by-step explanation:
Let x represent the amount invested at 6%. Then 30000-x is the amount invested at 5%. Leila's total earnings for the year are ...
0.06x +0.05(30000-x) = 1580
0.01x +1500 = 1580 . . . . . . . . . . . . simplify
0.01x = 80 . . . . . . . . . . . subtract 1500
x = 8000 . . . . . . . . . . . . multiply by 100
Leila invested $8000 at 6% and $22000 at 5%.
A ball is thrown straight up into the air from an initial height of 5 feet at time t = 0. The height, in feet, of the ball above the ground is given by h(t), where t is measured in seconds for 0 ≤ t ≤ 15. Based on the values of t and h(t) given in the table, for which value of t would the speed of the ball most likely be the greatest?
t (seconds) 0 3 6 9 12 15
h(t) (feet) 5 12 15 11 6 0
Select one:
a. 2 seconds
b. 5 seconds
c. 9 seconds
d. 15 seconds
Answer:
5 seconds
Step-by-step explanation:
The speed of an object is the rate of distance over time. The value of time (t) at the greatest speed of the ball is at 2 seconds
First, we calculate the speed using:
[tex]Speed = \frac{h(t)}{t}[/tex] --- i.e. distance/time
At t = 0, h(t) = 5
So;
[tex]Speed = \frac{5}{0} = unde fine d[/tex]
At t = 3, h(t) = 12
[tex]Speed = \frac{12}{3} = 4[/tex]
At t = 6, h(t) = 15
[tex]Speed = \frac{15}{6} = 2.5[/tex]
At t = 9, h(t) = 11
[tex]Speed = \frac{11}{9} = 1.2[/tex]
At t = 12, h(t) = 6
[tex]Speed = \frac{6}{12} = 0.5[/tex]
At t = 15, h(t) = 0
[tex]Speed = \frac{0}{15} = 0[/tex]
By comparing the above values, we notice that as time and height increases, the value of speed reduces.
This means that the greatest value of speed will be at the least value of time (t).
From the given options, the least value of time is at:
[tex]t = 2[/tex]
Hence, the value of time (t) at the greatest speed of the ball is at 2 seconds
Read more about speed at:
https://brainly.com/question/7359669
The age of some lecturers are 42,54,50,54,50,42,46,46,48 and 48 calculate the mean age and standard deviation
Answer:
Mean age: 48
Standard deviation: 4
Step-by-step explanation:
a) Mean
The formula for Mean = Sum of terms/ Number of terms
Number of terms
= 42 + 54 + 50 + 54 + 50 + 42 + 46 + 46 + 48+ 48/ 10
= 480/10
= 48
The mean age is 48
b) Standard deviation
The formula for Standard deviation =
√(x - Mean)²/n
Where n = number of terms
Standard deviation =
√[(42 - 48)² + (54 - 48)² + (50 - 48)² +(54 - 48)² + (50 - 48)² +(42 - 48)² + (46 - 48)² + (46 - 48)² + (48 - 48)² + (48 - 48)² / 10]
= √-6² + 6² + 2² + 6² + 2² + -6² + -2² + -2² + 0² + 0²/10
=√36 + 36 + 4 + 36 + 4 + 36 + 4 + 4 + 0 + 0/ 10
=√160/10
= √16
= 4
The standard deviation of the ages is 4
15. What is the next number in this series?
6, 11, 9, 14, 12,
a. 17
b. 10
C. 18
d. 16
Answer:
a. 17
Step-by-step explanation:
The pattern is add 5 then subtract 2
If f(x) = x2 + 9x – 14 and g(x) = x2 – x + 3, find (f – g)(x).
Answer:
10x-17
Step-by-step explanation:
f(x) = x^2 + 9x – 14
g(x) = x^2 – x + 3
(f – g)(x)=x^2 + 9x – 14 - (x^2 – x + 3)
Distribute the minus sign
(f – g)(x)=x^2 + 9x – 14 - x^2 + x - 3
Combine like terms
=10x-17
Apply the square root property of equality.
x + =
Answer:
Step-by-step explanation:
Answer:
+ 1/16 = +- 2/3
A refrigeration system at your company uses temperature sensors fixed to read Celsius (0C) values, but the system operators in your control room understand only the Fahrenheit scale. You have been asked to make a Fahrenheit (°F) label for the high temperature alarm, which is set to ring whenever the system temperature rises above -10°C. What Fahrenheit value should you write on the label?
Answer:
14 °F
Step-by-step explanation:
To answer this problem, we will use the known celsius to fahrenheit conversion formula.
[Celsius * (9/5)] + 32 = Fahrenheit
Now we just plug in the value of celsius:
[-10 * (9/5)] + 32 = Fahrenheit
[ -2 * 9 ] + 32 = Fahrenheit
[ -18 ] + 32 = Fahrenheit
14 = Fahrenheit
So you should right 14(°F) on the label.
Cheers.
What fraction of a pound is an ounce?
Answer:
1/16
Step-by-step explanation:
there are 16 ounces in a pound
Answer:
1/16 pounds
Step-by-step explanation:
Please help me to find out the answer
9514 1404 393
Answer:
80.99 m
Step-by-step explanation:
The hypotenuse of the triangle is given, and the desired side length is the one adjacent to the angle marked. The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
Multiplying by the hypotenuse, we find ...
RY = (82 m)cos(9°) ≈ 80.99 m
How many variables terms are in the expression 3xcube y+5xsquare+y+9
Answer: Please Give Me Brainliest, Thank You!
2
Step-by-step explanation:
There are two variables here, X and Y
Find the first six partial sums S1, S2, S3, S4, S5, S6 of the sequence whose nth term is given. 1 2 , 1 22 , 1 23 , 1 24 , . .
Answer:
the first partial sum [tex]\mathbf{S_1= \dfrac{1}{2}}[/tex]
the second partial sum [tex]\mathbf{S_2= \dfrac{3}{4} }[/tex]
the third partial sum [tex]\mathbf{S_3= \dfrac{7}{8}}[/tex]
the fourth partial sum [tex]\mathbf{S_4= \dfrac{15}{16}}[/tex]
the fifth partial sum [tex]\mathbf{S_5= \dfrac{31}{32}}[/tex]
the sixth partial sum [tex]\mathbf{S_6= \dfrac{63}{64}}[/tex]
Step-by-step explanation:
The term of the sequence are given as : [tex]\dfrac{1}{2}[/tex], [tex]\dfrac{1}{2^2}[/tex], [tex]\dfrac{1}{2^3}[/tex], [tex]\dfrac{1}{2^4 }[/tex] , . . .
The nth term for this sequence is , [tex]\mathtt{a_n =( \dfrac{1}{2})^n}[/tex]
The nth partial sum of the sequence for [tex]\mathtt{a_1,a_2,a_3.... a_n}[/tex] is [tex]\mathtt{S_n}[/tex]
where;
[tex]\mathtt{S_n = a_1 +a_2+a_3+ ...+a_n}[/tex]
The first partial sum is: [tex]\mathtt{S_1= a_1}[/tex]
[tex]\mathtt{S_1= (\dfrac{1}{2})^1}[/tex]
[tex]\mathbf{S_1= \dfrac{1}{2}}[/tex]
Therefore, the first partial sum [tex]\mathbf{S_1= \dfrac{1}{2}}[/tex]
The second partial sum is: [tex]\mathtt{S_2= a_1+a_2}[/tex]
[tex]\mathtt{S_2= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2}[/tex]
[tex]\mathtt{S_2= \dfrac{1}{2} + \dfrac{1}{4}}[/tex]
[tex]\mathtt{S_2= \dfrac{2+1}{4} }[/tex]
[tex]\mathbf{S_2= \dfrac{3}{4} }[/tex]
Therefore, the second partial sum [tex]\mathbf{S_2= \dfrac{3}{4} }[/tex]
The third partial sum is : [tex]\mathtt{S_3= a_1+a_2+a_3}[/tex]
[tex]\mathtt{S_3= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3 }[/tex]
[tex]\mathtt{S_3= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}}[/tex]
[tex]\mathtt{S_3= \dfrac{4+2+1}{8}}[/tex]
[tex]\mathbf{S_3= \dfrac{7}{8}}[/tex]
Therefore, the third partial sum [tex]\mathbf{S_3= \dfrac{7}{8}}[/tex]
The fourth partial sum : [tex]\mathtt{S_4= a_1+a_2+a_3+a_4}[/tex]
[tex]\mathtt{S_4= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 }[/tex]
[tex]\mathtt{S_4= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}}[/tex]
[tex]\mathtt{S_4= \dfrac{8+4+2+1}{16}}[/tex]
[tex]\mathbf{S_4= \dfrac{15}{16}}[/tex]
Therefore, the fourth partial sum [tex]\mathbf{S_4= \dfrac{15}{16}}[/tex]
The fifth partial sum : [tex]\mathtt{S_5= a_1+a_2+a_3+a_4+a_5}[/tex]
[tex]\mathtt{S_5= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 +(\dfrac{1}{2})^5 }[/tex]
[tex]\mathtt{S_5= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}}[/tex]
[tex]\mathtt{S_5= \dfrac{16+8+4+2+1}{32}}[/tex]
[tex]\mathbf{S_5= \dfrac{31}{32}}[/tex]
Therefore, the fifth partial sum [tex]\mathbf{S_5= \dfrac{31}{32}}[/tex]
The sixth partial sum: [tex]\mathtt{S_5= a_1+a_2+a_3+a_4+a_5+a_6}[/tex]
[tex]\mathtt{S_6= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 +(\dfrac{1}{2})^5 +(\dfrac{1}{2})^6 }[/tex]
[tex]\mathtt{S_6= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64} }[/tex]
[tex]\mathtt{S_6= \dfrac{32+16+8+4+2+1}{64}}[/tex]
[tex]\mathbf{S_6= \dfrac{63}{64}}[/tex]
Therefore, the sixth partial sum [tex]\mathbf{S_6= \dfrac{63}{64}}[/tex]
What number represents the same amount as 8 hundreds + 10 tens + 0 ones? i was told 810 is incorrect
Answer:
900
Step-by-step explanation:
You have 10 tens not 1 ten
8 * 100 + 10 * 10 + 0*1
800 + 100 + 0
900
Answer:
[tex]900[/tex]
Step-by-step explanation:
[tex]8 \times 100 + 10 \times 10 + 0 \times 1 \\ 800 + 100 + 0 \\ = 900[/tex]
(20/2 + 4)/2
^^^ I NEED A EQUATION LIKE THAT BUT FOR IT TO EQUAL 16
Answer:
Here are a few examples.
(30/2 + 1)/2
(26/2 + 3)/2
(28/2 + 2)/2
coordinates of England
Answer:
52.3555 north
1.1745 west
I will be honest I'm having a major brain fart.. What's the line called and what's it do again? it's separating numbers.. Looks like this
29
---
3
I know I'm stupid for this one... I've been up for 30 hours studying and now I can't remember this.. I need sleep but can't till i figure this out now...
Answer:
fraction bar. separates numerator and denominator in a fraction
Answer:
basically a dividing symbol, but specifically used for fractions
Step-by-step explanation:
After running 3/4 of a mile tess has only run 1/3 how long is the race in miles but I want to know how you did it
a student ran out of time on a multiple choice exam and randomly guess the answers for two problems each problem have four answer choices ABCD and only one correct answer what is the probability that he answered neither of the problems correctly
Answer:
The probability that he answered neither of the problems correctly is 0.0625.
Step-by-step explanation:
We are given that a student ran out of time on a multiple-choice exam and randomly guess the answers for two problems each problem have four answer choices ABCD and only one correct answer.
Let X = Number of problems correctly answered by a student.
The above situation can be represented through binomial distribution;
[tex]P(X=r)=\binom{n}{r}\times p^{r}\times (1-p)^{n-r};x=0,1,2,3,....[/tex]
where, n = number of trials (samples) taken = 2 problems
r = number of success = neither of the problems are correct
p = probability of success which in our question is probability that
a student answer correctly, i.e; p = [tex]\frac{1}{4}[/tex] = 0.75.
So, X ~ Binom(n = 2, p = 0.75)
Now, the probability that he answered neither of the problems correctly is given by = P(X = 0)
P(X = 0) = [tex]\binom{2}{0}\times 0.75^{0}\times (1-0.75)^{2-0}[/tex]
= [tex]1 \times 1\times 0.25^{2}[/tex]
= 0.0625
Billy has x marbles. Write an expression for the number of marbles the following have… a) Charlie has 5 more than Billy b) Danny has 8 fewer than Billy c) Eric has three times as many as Billy
Answer:
Charlie: 5 + xDanny: x - 8Eric: x × 3Heights of men on a baseball team have a bell-shaped distribution with a mean of and a standard deviation of . Using the empirical rule, what is the approximate percentage of the men between the following values? a.166 cm and 202 cm b. 172cm and 196cm
Let assume that the mean is 184 and the standard deviation is 6
Heights of men on a baseball team have a bell-shaped distribution with a mean 184 of and a standard deviation of 6 . Using the empirical rule, what is the approximate percentage of the men between the following values? a.166 cm and 202 cm b. 172 cm and 196cm
Answer:
P(156<X<202) = 99.7%
P(172<X<196) = 95.5%
Step-by-step explanation:
Given that :
Heights of men on a baseball team have a bell-shaped distribution with a mean of and a standard deviation of . Using the empirical rule, what is the approximate percentage of the men between the following values? a.166 cm and 202 cm b. 172 cm and 196cm
For a.
Using the empirical rule, what is the approximate percentage of the men between the following values 166 cm and 202 cm.
the z score can be determined by using the formula:
[tex]z = \dfrac{X - \mu}{\sigma}[/tex]
[tex]z(166) = \dfrac{166-184}{6}[/tex]
[tex]z(166) = \dfrac{-18}{6}[/tex]
z(166) = -3
[tex]z(202) = \dfrac{202-184}{6}[/tex]
[tex]z(202) = \dfrac{18}{6}[/tex]
z(202) = 3
P(156<X<202) = P( μ - 3σ < X < μ + 3σ )
P(156<X<202) = P( - 3 < Z < 3)
P(156<X<202) = P( Z < 3) - P(Z < -3)
P(156<X<202) = 0.99865- 0.001349
P(156<X<202) = 0.997301
P(156<X<202) = 99.7%
For b.
b. 172 cm and 196cm
[tex]z = \dfrac{X - \mu}{\sigma}[/tex]
[tex]z(172) = \dfrac{172-184}{6}[/tex]
[tex]z(172) = \dfrac{-12}{6}[/tex]
z(172) = -2
[tex]z(196) = \dfrac{196-184}{6}[/tex]
[tex]z(196) = \dfrac{12}{6}[/tex]
z(196) = 2
P(172<X<196) = P( μ - 2σ < X < μ + 2σ )
P(172<X<196) = P( - 2 < Z < 2)
P(172<X<196) = P( Z < 2) - P(Z < -2)
P(172<X<196) = 0.9772 - 0.02275
P(172<X<196) = 0.95445
P(172<X<196) = 95.5%
Can someone please help me solve the equation?
Answer:
B opition is right
Step-by-step explanation:
The domina a function of