72 drops were 1ml for stearic acid
the container was 8.5 cm wide and filled with hexane
Trial 1 was 20 drops
Trial 2 was 21
trial 3 was 16
The concentration of steric solution in hexane was :1.64*10^-4 g/ml
Area of single molecule of steric acid is: 0.21 mn^2
Molar mass of steric acid is: 284 g/mol
-What is the moles of stearic acid used?
-What is the number of stearic acid used to make the lens?
-how many molecules of stearic acid would there be if its it was 1 mole of stearic acid on that lense?

Answers

Answer 1

CaseAnswer:

-Mole of stearic acid used = 1.3*10^-3 mol

-Molecules of stearic acid there would be in 1 mole of stearic acid = 7.994*10^20 molecules

Explanation:

Know information from the problem are:

Mass concentration of C18H32O2 = 1.6x10^-4 g/ml, Molar mass of C18H32O2 = 284 g/mol.

Unit factor from drops to ml is 72 drops = 1ml. Therefore, for every drop, n, given, there would be n drops (1ml/ 72drops). The problem tells that stearic acid was added to hexane and that the addition process was done three-time with different amounts of drops. Think of this as releasing a substance from a burette during titration. If we convert the drops into millimeters, we would have 20 drops (1ml/72drops)= 0.28 ml, 21 drops (1ml/72drops)= 0.29 ml, and 16 drops (1ml/72drops)= 0.22 ml. [We need these volumes to determine the mass of stearic acid from mass concentration given.]

Unknown informations are:

V (volume in ml) =?

The mole of stearic acid used =?

Strategy

To calculate the mole of stearic acid used, we need the mass of stearic acid from the mass concentration. To get this we need a volume. Notice that those volumes (drops) are not the same ( it is safe to say that there is an error in the readings, as they were done independently). Therefore, we would find two or three values whose difference is smaller ( there is a little error). Subtract the smaller number from the larger number till you get a smaller difference ( do this for all three values).

The set of numbers with the smallest difference is 0.29 - 0.28=0.014, our concordant value.

Solutions

Now we us this set of numbers, 0.29-0.28, to determine an average volume :

V = (0.29-0.28)/2 (ml)

V= 0.285 ml

Now we can calculate the mass of stearic acid from the mass concentration:

m = C*V; m is the mass, C is the concentration in g/ ml, and V is the volume in ml.

m = (1.64*10^-4 g/ml)*(0.285 ml)

m = 4.674*10^-5 g

The mole of stearic acid used:

n = m/MM l; n is the mole of stearic acid, m is the mass of stearic acid, and MM is the molar mass of stearic acid.

n = 4.674*10^-5 g (284 g/mol)

n = 1.3274*10^-3

How many molecules of stearic acid would there be if it was 1 mol of stearic acid?

1 mol = 6.02214*10^23 molecule

Therefore, a conversion fraction would be:

6.02214*10^23 molecule/ 1 mol

Solution

Molecules of stearic acid in 1 mol =

1.3274*10^-3 mol (6.02214*10^23 molecule/ 1 mol)

= 7.994*10^20 molecules in 1 mol of C18H16O2


Related Questions


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Answers

Answer:

1.0 L

Explanation:

Use the ideal gas law PV=nRT where P is pressure = 1100 kPa, V is the volume you are calculating, n is the number of moles which can be calculated by dimensional analysis and the periodic table, R is the ideal gas constant in this case R=8.314 kPa L/K mol, and T is the temperature in kelvins. See attached image for work through. 1.0 L is the answer with two sig figs.

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Answers

Answer:

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Answers

Answer:

7.61 liters

Explanation:

From the question,

Applying Charles law formula,

V₁/T₁ = V₂/T₂...................... Equation 1

Where P₁ = initial volume of of air, V₂ = Final volume of air, T₁ = Initial Temperature of air, T₂ = Final Temperature of air.

make V₂ the subject of the equation

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b
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Answers

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தமிழ் வாழ்க ​

Answers

Answer:

Modal means the one that occurs most often (averages: mode). In maths, the mode is one of the most common ways to describe a set of data. ... The modal class is, therefore, the group with the highest frequency.

Answer:

Modal means the one that occurs most often (averages: mode). In maths, the mode is one of the most common ways to describe a set of data. ... The modal class is, therefore, the group with the highest frequency. For example: if you counted the number of pencils in different pencil cases and you decided to group them.

Explanation:

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D.4

Answers

Answer: 1. 5
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How can the strength of an acid be determined using titration? (100 POINTS!)

Answers

Answer:

Explanation:

A titration in general is used to determine the concentration of something with a solution of known solution. For acid, a base solution of known concentration is added slowly. The end-point is determined by using a pH indicator. When the acid is neutralized at the end, note the amount of base solution used and the strength of acid can be calculated.

Note that the quantity of base solution utilised and the acid strength can be estimated after the acid has been neutralised.

What is titration?

Titration is a method of chemical analysis where the quantity of a sample's constituents is established by adding a precisely measured amount of something else with which the component that is wanted will react in a specific, known proportion.

A burette, which is essentially a long, graded measurement tube with a stopper and a tube for injection at its bottom end, is used to gradually administer a standard solution of titrating reagent, and titrant, to a specified concentration. When the point of equal value is achieved, the addition is terminated. Note that the quantity of base solution utilised and the acid strength can be estimated after the acid has been neutralised.

Therefore, note that the quantity of base solution utilised and the acid strength can be estimated after the acid has been neutralised.

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Use the balanced equation from #13 to answer the following:

Calculate how many moles of SO2 can be produced with when given 75 grams of CS2.


Now calculate how many moles of SO2 can be produced with when given 96 grams of O2.




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Answers

Answer:

1. 9600 moles

2. 4096 moles

Explanation:

CS2 + 3 O2=> CO2 + 2 SO2

1. The ratio for CS2: SO2 is :

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If there are 75g of CS2 then there are:

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Moles = mass × Mr

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2. The ratio for O2 : SO2 is:

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A3.00 mol sample of CO2 (g) is in a rigid 6.00 L container at 400.°C.

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Answers

Answer:

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Answers

Answer:

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Explanation:

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Answers

Answer:

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Answers

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No links.
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Answers

Explanation:

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Answers

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2 moles of CH₃OH are burned by 3 moles of O₂

For 2.5 moles of CH₃OH are burned by x moles of O₂

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Answers

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Answers

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