helpppp me please..
........
Answer:
The employer's monthly salary (X)
What values are stored in nums after the following code segment has been executed?
int[] nums = {50, 100, 150, 200, 250};
for (int n : nums)
{
n = n / nums[0];
}
[1, 2, 3, 4, 5]
[1, 1, 1, 1, 1]
[1, 100, 150, 200, 250]
[50, 100, 150, 200, 250]
An ArithmeticException is thrown.
Answer:
D.[50, 100, 150, 200, 250]
Explanation:
This is a trick question because the integer n is only a counter and does not affect the array nums. To change the actual array it would have to say...nums[n] = n/nums[0];
Computer programming 2
indicates the beginning and ending of your code written in HTML
Answer:
<body> ...</body>
indicates the beginning and ending of your code written in HTML
Explanation:
internet is an interconnected networks
o true
o false
Answer:
True.
Internet is an interconnected network.
Create the following SQL Server queries that access the Northwind database. Place them in a zip file and place the zip file in the "drop box" for Assignment 5. Name the queries Query 1-MP5, Query2-MP5, etc. Note: These problems all require aggregate processing with GROUP BY
1. For each employee, list the employee ID, employee first name, employee last name, and count of orders taken in 1996. Place the list in descending order by the number of orders.
2. For all orders shipped in July or August, 1996, list the order ID, company name, order date, and total cost of all items ordered. Place the list in descending order by the total cost
3. For all customers from the USA, list the customer ID, company name, state, count of orders, and total order amount. Do not consider the discount. Place the list in order by state and then customer ID.
4. Same as problem 3 but limit the list to all customers who placed 3 or more orders.
5. For all items in the Grains/Cereals category, list the product ID, product name, supplier name, and last date that the product was ordered. Order the list by supplier name and product name (Hint: Use MAX and be sure to include all necessary tables)
6. The product ID, product name, and count of distinct customers who ordered that product in 1996. Place the list in descending order by the count of customers.
Answer:
1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e
JOIN Orders o
ON e.EmployeeID = o.EmployeeID
WHERE YEAR(o.OrderDate) = '1996'
GROUP BY e.EmployeeID,e.FirstName,e.LastName
ORDER BY OrderByEmployee DESC
2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*
od.UnitPrice - od.Discount)) as TotalCost FROM Orders o
JOIN [Order Details] od
ON od.OrderID = o.OrderID
JOIN Customers c
ON o.CustomerID = c.CustomerID
WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and
YEAR(OrderDate) = 1996
GROUP BY o.OrderID,c.CustomerID, o.OrderDate
ORDER BY TotalCost DESC
3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c
JOIN Orders o
ON o.CustomerID = c.CustomerID
JOIN [Order Details] od
ON od.OrderID = o.OrderID
WHERE c.Country = 'USA'
GROUP BY c.CustomerID, c.CompanyName, c.City
ORDER BY c.City, c.CustomerID
4. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c
JOIN Orders o
ON o.CustomerID = c.CustomerID
JOIN [Order Details] od
ON od.OrderID = o.OrderID
WHERE c.Country = 'USA'
GROUP BY c.CustomerID, c.CompanyName, c.City
HAVING COUNT(o.OrderID) > 3
ORDER BY c.City, c.CustomerID
5. SELECT p.ProductID, p.ProductName, s.ContactName as SupplierName, MAX(o.OrderDate) as LastOrderDateOfProduct FROM Products p
JOIN Categories c
ON c.CategoryID = p.CategoryID
JOIN Suppliers s
ON s.SupplierID = p.SupplierID
JOIN [Order Details] od
ON od.ProductID = p.ProductID
JOIN Orders o
ON o.OrderID = od.OrderID
where c.CategoryName = 'Grains/Cereals'
GROUP BY p.ProductID, p.ProductName, s.ContactName
ORDER BY SupplierName, p.ProductName
6. SELECT p.ProductID, p.ProductName, Count(DISTINCT c.CustomerID ) as OrderByThisManyDistinctCustomer
FROM Products p
JOIN [Order Details] od
ON od.ProductID = p.ProductID
JOIN Orders o
ON o.OrderID = od.OrderID
JOIN Customers c
ON c.CustomerID = o.CustomerID
where YEAR(o.OrderDate) = 1996
GROUP BY p.ProductID, p.ProductName
Explanation:
The six query statements returns data from the SQL server Northwind database. Note that all the return data are grouped together, this is done with the 'GROUP BY' Sql clause.
What is digital transformation?
Answer:Digital Transformation is the adoption of digital technology to transform services or businesses, through replacing non-digital or manual processes with digital processes or replacing older digital technology with newer digital technology
Explanation:
Answer:
Explanation:
Digital transformation is the process of using digital technologies to transform existing traditional and non-digital business processes and services, or creating new ones, to meet with the evolving market and customer expectations, thus completely altering the way businesses are managed and operated, and how value is delivered to customers
Create a Department object which contains a name (String), budget (double), and an ArrayList of Employee objects. Each Employee object contains a FirstName (String). LastName(String), and an Address object. Each Address object contains a Street (String), Apartment (int), City (String), and State as a char array of length 2. The Apartment parameter is optional but the other three are mandatory! Ensure no Address object can be created that does not have them. Finally, create a test program that allows users to Add, Delete, Print, and Search the Employees of a Department.
Answer:
Explanation:
The following code is very long and is split into the 4 classes that were requested/mentioned in the question: Department, Employee, Address, and Test. Each one is its own object with its own constructor. Getters and Setters were not created since they were not requested and the constructor handles all of the variable creation. Address makes apartment variable optional by overloading the constructor with a new one if no argument is passed upon creation.
package sample;
import sample.Employee;
import java.util.ArrayList;
class Department {
String name = "";
double budget = 0;
ArrayList<Employee> employees = new ArrayList<>();
void Department(String name, double budget, ArrayList<Employee> employees) {
this.name = name;
this.budget = budget;
this.employees = employees;
}
}
------------------------------------------------------------------------------------------------------------
package sample;
public class Employee {
String FirstName, LastName;
Address address = new Address();
public void Employee(String FirstName, String LastName, Address address) {
this.FirstName = FirstName;
this.LastName = LastName;
this.address = address;
}
}
-------------------------------------------------------------------------------------------------------------
package sample;
class Address {
String Street, City;
int apartment;
char[] state;
public void Address(String street, String city, char[] state, int apartment) {
this.Street = street;
this.City = city;
this.state = state;
this.apartment = apartment;
}
public void Address(String street, String city, char[] state) {
this.Street = street;
this.City = city;
this.state = state;
this.apartment = 0;
}
}
-------------------------------------------------------------------------------------------------------------
package sample;
public class Test extends Department {
public void add(Department department, Employee employee) {
department.employees.add(employee);
}
public void delete(Department department, Employee employee) {
for (int x = 0; x < department.employees.size(); x++) {
if (department.employees.get(x) == employee) {
department.employees.remove(x);
}
}
}
public void Print(Department department, Employee employee) {
for (int x = 0; x < department.employees.size(); x++) {
if (department.employees.get(x) == employee) {
System.out.println(employee);
}
}
}
public void Search (Department department, Employee employee) {
for (int x = 0; x < department.employees.size(); x++) {
if (department.employees.get(x) == employee) {
System.out.println("Employee is located in index: " + x);
}
}
}
}
You are working for a company that is responsible for determining the winner of a prestigious international event, Men’s Synchronized Swimming. Scoring is done by eleven (11) international judges. They each submit a score in the range from 0 to 100. The highest and lowest scores are not counted. The remaining nine (9) scores are averaged and the median value is also determined. The participating team with the highest average score wins. In case of a tie, the highest median score, among the teams that are tied for first place, determines the winner.
Scoring data is be provided in the form of a text file. The scoring data for each team consists of two lines; the first line contains the team name; the second line contains the eleven (11) scores. You will not know ahead of time how many teams will participant. Your program will:
Prompt the user for the name and location of the scoring data file.
Process the sets of records in the file.
Read and store the team name in a string variable.
Read and store the scores in an array.
Display the team name followed by the complete set of scores on the next line.
Calculate and display to two decimal places the average of the nine qualifying scores, dropping the lowest and highest scores.
Determine and display the median value among the qualifying scores.
Display the count of the number of participating teams.
Display the winning team name and their average score. Indicate if they won by breaking a tie with a higher median score value.
A sample data file has been provided to allow you to test your program before submitting your work. Records in the sample data file look like this:
Sea Turtles
11 34 76 58 32 98 43.5 87 43 23 22
Tiger Sharks
85 55 10 99 35 5 65 75 8 95 22
The Angry Piranhas
30 10 80 0 100 40 60 50 20 90 70
The average score for the Sea Turtles was 46.5. The Angry Piranhas and the Tiger Sharks both had an average score of 50.0. The tiger sharks had a median value of 55.0, making them the winners of the competition.
You will define and use at least one function in your solution. As a suggestion, you should consider calling a function that sorts the array of judge’s score values into ascending order (lowest to highest). The advantage of doing this is that after being sorted, the lowest value is the first entry in your array and the highest value is the last entry in your array.
The average or arithmetic mean is a measure of central tendency. It is a single value that is intended to represent the collection of values. For this problem, you will only use nine of the values to determine the average. You will not include the highest score and the lowest score.
The median is another measure of central tendency. The median is often referred to as the middle value. In a set of values, half the values are less than the median and the other half are greater than the median. In a sorted array of five elements, the median is the third element. There are two values that are less then it and there are two values that are greater than it. In a sorted array of six values, the median is the simple average of the third and fourth values. In some cases, the median is a better representative value than the average.
You are encouraged to read the article entitled "Mixing getline with cin".
To receive full credit for this programming assignment, you must:
Use the correct file name.
Submit a program that executes correctly.
Interact effectively with the user.
Grading Guideline:
Correctly name the file submitted.
Create a comment containing the student’s full name.
Document the program with other meaningful comments.
Prompt the user for a file name and location.
Open, read, and process all the data in the input file.
Store the judge’s scores in an array.
Correctly display the team name and all scores.
Calculate and display the average score correctly.
Calculate and display the median score correctly.
Correctly count and display the number of competing teams.
Correctly determine and display the winning team and score.
Answer:
my sql
Explanation:
try with mysql
and database build
A sensitive manufacturing facility has recently noticed an abnormal number of assembly-line robot failures. Upon intensive investigation, the facility discovers many of the SCADA controllers have been infected by a new strain of malware that uses a zero-day flaw in the operating system. Which of the following types of malicious actors is MOST likely behind this attack?
A. A nation-state.
B. A political hacktivist.
C. An insider threat.
D. A competitor.
Answer:
A. A nation-state.
Explanation:
Given that a nation-state attack if successful is about having access to the different sector or industries of networks, then followed it by compromising, defrauding, altering (often for fraud purpose, or destroy information
Therefore, in this case, considering the information giving above, the type of malicious actor that is MOST likely behind this attack is "a Nation-State."
what is computer? different between RAM and ROM?
Answer:
RAM, which stand for RANDOM ACESS MEMORY and ROM whitch stand for READ ONLY MEMORY, are both present in your computer. RAM volatile memory that temporary store the file you are working on. ROM is a non volatile memory that permanently stores instruction for your COMPUTER.
Suppose you decide to use the number of times you see any of the area codes of the places Yanay has been to in 50 spam calls as your test statistic. Question 7. Write a function called simulate_visited_area_codes that generates exactly one simulated value of your test statistic under the null hypothesis. It should take no arguments and simulate 50 area codes under the assumption that the result of each area is sampled from the range 200-999 inclusive with equal probability. Your function should return the number of times you saw any of the area codes of the places Yanay has been to in those 50 spam calls. Hint: You may find the textbook section on the sample_proportions function to be useful. For model_proportions, under the null hypothesis, what's the chance of drawing one of the area codes Yanay has recently been to
Answer:
In Python:
import random
def simulate_visited_area_codes():
area_codes = []
for i in range(51):
num = random.randint(200,1000)
area_codes.append(num)
visited_codes = [289, 657, 786, 540]
count = 0
for i in range(51):
for j in range(len(visited_codes)):
if area_codes[i] == visited_codes[j]:
count+=1
return count
print("Visited Areas: "+str(simulate_visited_area_codes()))
Explanation:
So many incomplete details in your question, so I will fill in the gap (i.e. make assumptions)
The assumptions are:
The 50 area codes is stored in area_codes list; the codes are randomly generatedThe visited area codes is stored in visited_codes list, the list is initializes with [289, 657, 786, 540]The program and explanation is as follows: (comments are written in bold)
#This imports the random module
import random
#This defines the function
def simulate_visited_area_codes():
#Thie initializes area_codes to an empty list
area_codes = []
#This iterates from 1 to 50 and generate 50 random numbers to the area_codes list
for i in range(51):
num = random.randint(200,1000)
area_codes.append(num)
#This initializes the visited_code
visited_codes = [289, 657, 786, 540]
#This initializes count variable to 0
count = 0
#This iterates through the list and looks for matching code between the area_code and the visited_code lists
for i in range(51):
for j in range(len(visited_codes)):
if area_codes[i] == visited_codes[j]:
#The count variable is incremented by 1 for matching codes
count+=1
#This returns the count
return count
#The main begins here and prints the number of area code visited
print("Visited Areas: "+str(simulate_visited_area_codes()))
Simulate one or more responses from the distribution corresponding to a fitted model object.
The code is shown below:-
visited_test_statistics_under_null = make_array()
repetitions = 20000
for i in np.arange(repetitions):
new_sum_of_correct_area_code = simulate_visited_area_codes()
visited_test_statistics_under_null = np.append(visited_test_statistics_under_null, new_sum_of_correct_area_code)
visited_test_statistics_under_null( )
Learn more about the topic Simulate Function:
https://brainly.com/question/14492046
what is secondary memory?
Answer:
Secondary memory refers to storage devices, such as hard drives and solid state drives. It may also refer to removable storage media, such as USB flash drives, CDs, and DVDs. ... Additionally, secondary memory is non-volatile, meaning it retains its data with or without electrical power.
# 1) Complete the function to return the result of the conversion
def convert_distance(miles):
km = miles * 1.6 # approximately 1.6 km in 1 mile
my_trip_miles = 55
# 2) Convert my_trip_miles to kilometers by calling the function above
my_trip_km = ___
# 3) Fill in the blank to print the result of the conversion
print("The distance in kilometers is " + ___)
# 4) Calculate the round-trip in kilometers by doubling the result,
# and fill in the blank to print the result
print("The round-trip in kilometers is " + ___)
Answer:
See explanation
Explanation:
Replace the ____ with the expressions in bold and italics
1) return km
return km returns the result of the computation
2) = convert_distance(my_trip_miles)
convert_distance(my_trip_miles) calls the function and passes my_trip_miles to the function
3) + str(my_trip_km)
The above statement prints the returned value
4) +str(my_trip_km * 2)
The above statement prints the returned value multiplied by 2
what does command do
A disk has 4000 cylinders, each with 8 tracks of 512 blocks. A seek takes 1 msec per cylinder moved. If no attempt is made to put the blocks of a file close to each other, two blocks that are logically consecutive (i.e. follow one another in the file) will require an average seek, which takes 5 msec. If, however, the operating system makes an attempt to cluster related blocks, the mean interblock distance can be reduced to 2 cylinders and the seek time reduced to 100 microsec. How long does it take to read a 100 block file in both cases, if the rotational latency is 10 msec and the transfer time is 20 microsec per block
Answer:
The answer is below
Explanation:
a)
If the blocks of a file are not put together, that is for nonadjacent block of files to each other, the time (t) taken to read a 100 block file is:
t = (average seek + rotational latency + transfer time) * 100 block
Average seek = 5 msec, rotational latency = 10 msec and transfer time = 20 microsec = 0.02 msec
t = (5 + 10 + 0.02) * 100 = 1502 msec
b)
If the blocks of a file are put together, that is for adjacent block of files to each other, the time (t) taken to read a 100 block file is:
t = (seek time * mean interblock distance + rotational latency + transfer time) * 100 block
seek time = 100 microsec = 0.1 msec, rotational latency = 10 msec and transfer time = 20 microsec = 0.02 msec, mean interblock distance = 2 cylinders
t = (0.1*2 + 10 + 0.02) * 100 = 1022 msec
Suppose Alice and Bob have RSA public keys in a file on a server. They communicate regularly using authenticated, confidential messages. Eve wants to read the messages but is unable to crack the RSA private keys of Alice and Bob. However, she is able to break into the server and alter the file containing Alice's and Bob's public keys. a. How should Eve alter that file so that she can read confidential messages sent between Alice and Bob, and forge messages from either
Answer:
On the server, Eve could create and register her own version of Bob's and Alice's pairs of keys, then she can intercept the communication between Bob and Alice, decrypt the message and recalculate the hash, and also re-encrypting it all with her own version of Bob's and Alice's private and public keys.
Explanation:
Cryptography is the study of various methods to secure communication between two parties in the presence of a third known as adversaries.
Messages sent through communication mediums are encrypted to protect the confidentiality and integrity of their content. Using secure pins known as keys are used in some type of cryptography to encrypt and decrypt messages.
These keys are protected from adversaries and should be secured in servers.
Create an array of doubles to contain 5 values Prompt the user to enter 5 values that will be stored in the array. These values represent hours worked. Each element represents one day of work. Create 3 c-strings: full[40], first[20], last[20] Create a function parse_name(char full[], char first[], char last[]). This function will take a full name such as "Noah Zark" and separate "Noah" into the first c-string, and "Zark" into the last c-string. Create a function void create_timecard(double hours[], char first[], char last[]). This function will create (write to) a file called "timecard.txt". The file will contain the parsed first and last name, the hours, and a total of the hours. See the final file below. First Name: Noah
Solution :
[tex]$\#$[/tex]include [tex]$<stdio.h>$[/tex]
[tex]$\#$[/tex]include [tex]$<string.h>$[/tex]
void parse[tex]$\_$[/tex]name([tex]$char \ full[]$[/tex], char first[tex]$[],$[/tex] char last[tex]$[])$[/tex]
{
// to_get_this_function_working_immediately, _irst
// stub_it_out_as_below._When_you_have_everything_else
// working,_come_back_and_really_parse_full_name
// this always sets first name to "Noah"
int i, j = 0;
for(i = 0; full[i] != ' '; i++)
first[j++] = full[i];
first[j] = '\0';
// this always sets last name to "Zark"
j = 0;
strcpy(last, full+i+1);
// replace the above calls with the actual logic to separate
// full into two distinct pieces
}
int main()
{
char full[40], first[20], last[20];
double hours[5];
// ask the user to enter full name
printf("What is your name? ");
gets(full);
// parse the full name into first and last
parse_name(full, first, last);
// load the hours
for(int i = 0; i < 5; i++)
{
printf("Enter hours for day %d: ", i+1);
scanf("%lf", &hours[i]);
}
// create the time card
FILE* fp = fopen("timecard.txt", "w");
fprintf(fp, "First Name: %s\n", first);
fprintf(fp, "Last Name: %s\n", last);
double sum = 0.0;
for(int i = 0; i < 5; i++)
{
fprintf(fp, "Day %i: %.1lf\n", i+1, hours[i]);
sum += hours[i];
}
fprintf(fp, "Total: %.1f\n", sum);
printf("Timecard is ready. See timecard.txt\n");
return 0;
}
In cell F5, enter a formula using the PMT function. Insert a negative sign (-) after the equal sign in the formula to display the result as a positive amount. Use defined names for the rate, nper, and pv arguments as follows:
· rate argument: Divide the Rate by 12 to use the monthly interest rate.
· nper argument: Multiply the Term by 12 to specify the number of months as the periods.
· pv argument: Use the Loan_Amount as the present value of the loan.
2.In cell F6, enter a formula without using a function that multiplies 12 by the Term and the Monthly_Payment, and then subtracts the Loan_Amount to determine the total interest
3. in cell J5, enter another formula using the PV function. Use defined cell names for the rate, nper, and pmt arguments as follows:
· rate argument: Divide the Rate by 12 to use the monthly interest rate.
· nper argument: Subtract the year value in cell H5 from the Term, and then multiply the result by 12 to specify the number of months remaining to pay off the loan.
· pmt argument: Use the Monthly_Payment as a negative value to specify the payment amount per period.
Answer:
Open MS-Office Excel (a.) Define name for rate, nper and pv cells as Rate, Term and Loan_Payment. Select the cell then Menu > Formulas
Define a function below, count_over_100, which takes a list of numbers as an argument. Complete the function to count how many of the numbers in the list are greater than 100. The recommended approach for this: (1) create a variable to hold the current count and initialize it to zero, (2) use a for loop to process each element of the list, adding one to your current count if it fits the criteria, (3) return the count at the end.
Answer:
In Python:
def count_over_100(mylist):
kount = 0
for i in range(len(mylist)):
if mylist[i] > 100:
kount+=1
return kount
Explanation:
This defines the function
def count_over_100(mylist):
(1) This initializes kount to 0
kount = 0
(2) This iterates through the loop
for i in range(len(mylist)):
If current list element is greater tha 100, kount is incremented by 1
if mylist[i] > 100:
kount+=1
This returns kount
return kount
Objective
Make a function that solves the quadratic equation, outputting both values of X. You do not have to worry about imaginary numbers. That is, I will only use input that creates a real output (such as the example screenshots).
NOTE: A function that uses the C version of pass by reference is required to get full credit on this assignment. The C++ form of pass by reference will receive no credit.
Details
STEP 1
#include at the top of your file so that you can use the sqrt function. The sqrt function calculates the square root. For example:
int x = sqrt(9.0)
Will leave x with the value 3, which is the square root of 9.
STEP 2
Define a function THAT USES PASS BY REFERENCE to take in three double inputs and provides two double outputs. In the equations below I use a, b, and c as the double input names and x1 and x2 as the output names.
Inside this function solve the quadratic equation for both possible values of x:
X 1 = − b + b 2 − 4 a c 2 a
That is, X1 is equal to -b + sqrt(b * b - 4 * a * c) then divide all of that by 2 * a.
X 2 = − b − b 2 − 4 a c 2 a
That is, X2 is equal to -b - sqrt(b * b - 4 * a * c) then divide all of that by 2 * a.
Note the difference. One adds sqrt(b * b - 4 * a * c) and the other subtracts it.
This can be done in several lines of code if you want or you can attempt to perform the entire calculation in one line of code.
STEP 3
In the main function read in 3 inputs from the user. Pass these inputs to the quadratic equation function along with the pass by reference variables for the output. Print the results to the screen.
Advice
Your quadratic equation function does NOT need to account for imaginary numbers. Stick with the example inputs to test your code.
If you get NAN that means your equation has an imaginary solution. Do not worry about it. Try different inputs.
The calculation itself is a minor portion of this grade. The majority of the grade comes from implementing pass by reference so make sure you have that part correct.
b2 is simple enough that you do not need to call the pow() function to calculate the power. Instead multiply b * b.
You may want to calculate the numerator into one variable and the denominator into another. You don't have to solve the entire equation on one line (though that is possible).
Since you are using pass by reference you can make the QuadraticEquation function into a void function. It does not need to return anything since it is returning calculations via pointers.
Use scanf on one variable at a time. Don't forget to use double data types and %lf with scanf.
Answer:
In C
#include <stdio.h>
#include<math.h>
void myfunc(double *a, double *b, double *c) {
double x1, x2;
x1 = (-(*b) + sqrt((*b)*(*b)- 4*(*a)*(*c)))/(2*(*a));
x2 = (-(*b) - sqrt((*b)*(*b) - 4*(*a)*(*c)))/(2*(*a));
printf("x1 = %f\n",x1);
printf("x2 = %f\n",x2);}
int main () {
double a,b,c;
printf("a: "); scanf("%lf", &a);
printf("b: "); scanf("%lf", &b);
printf("c: "); scanf("%lf", &c);
myfunc(&a, &b, &c);
return 0;}
Explanation:
#include <stdio.h>
#include<math.h> --- This represents step 1
Step 2 begins here
This gets the values of a, b and c from main by reference
void myfunc(double *a, double *b, double *c) {
This declares x1 and x2
double x1, x2;
Calculate x1
x1 = (-(*b) + sqrt((*b)*(*b)- 4*(*a)*(*c)))/(2*(*a));
Calculate x2
x2 = (-(*b) - sqrt((*b)*(*b) - 4*(*a)*(*c)))/(2*(*a));
Print x1
printf("x1 = %f\n",x1);
Print x2
printf("x2 = %f\n",x2);}
Step 3 begins here
int main () {
Declare a, b and c as double
double a,b,c;
Get input for a, b and c
printf("a: "); scanf("%lf", &a);
printf("b: "); scanf("%lf", &b);
printf("c: "); scanf("%lf", &c);
Call the function to calculate and print x1 and x2
myfunc(&a, &b, &c);
return 0;}
What is picture ..............
Answer:
In its most general sense, a picture is a visual representation of something, especially in the form of a painting, drawing, photograph, or the like. A picture can also refer to a mental image, among other senses.
what is difference between computer and smartphone
Answer: One is smaller than the other.
In C++
Write a simple program to test your Circle class. The program must call every member function at least once. The program can do anything of your choice.
Answer:
int main() {
Circle* pCircle = new Circle(5.0f, 2, 3);
pCircle->up();
pCircle->down();
pCircle->left();
pCircle->right();
cout << "X: " << pCircle->getx() << endl;
cout << "Y: " << pCircle->gety() << endl;
cout << "Radius: " << pCircle->getRadius() << endl;
pCircle->print();
pCircle->update_radius(4.0f);
if (pCircle->isUnit()) {
cout << "is unit" << endl;
}
pCircle->move_x(10);
pCircle->move_y(10);
}
Explanation:
something like that?
8) What is the address of the first SFR (1/O Register)?
Answer:
The Register A is located at the address E0H in the SFR memory space. The Accumulator is used to hold the data for almost all the ALU Operations. Some of the operations where the Accumulator is used are: Arithmetic Operations like Addition, Subtraction, Multiplication etc.
Which field would best function as a primary key for a table that tracks orders?
OrderDate
CustomerType
OrderID
CustomerID
Answer:
Order ID
Explanation:
An order ID is a new ID for every order. Every number is unique, making it the beat way to find certain orders.
Answer:
C
Explanation:
(08.02 LC)
It is appropriate to leave sections of an application blank.
O True
O False
Explanation:
it is false because it is not appropriate
Do you think that dealing with big data demands high ethical regulations, accountability, and responsibility of the person as well as the company? Why
Answer:
i will help you waiting
Explanation:
Yes dealing with big data demands high ethical regulations, accountability and responsibility.
The answer is Yes because while dealing with big data, ethical regulations, accountability and responsibility must be strictly followed. Some of the principles that have to be followed are:
Confidentiality: The information contained in the data must be treated as highly confidential. Information must not be let out to a third party.Responsibility: The people responsible for handling the data must be good in analyzing big data. They should also have the required skills that are needed.Accountability: The service that is being provided has to be very good. This is due to the need to keep a positive work relationship.In conclusion, ethical guidelines and moral guidelines have to be followed while dealing with big data.
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Overheating of a computer can be easily prevented. Explain how
Write as many accurate and relevant statements about the following prompt as you can think of. You are free to use any of the resources provided to you. Drawings with descriptions of their meanings can be considered a response. A total of 5 correct responses will provide full credit for the assignment and incorrect responses will not effect the number of points received on the exercise.
Answer:
1. The structure is prone to hydrophobic interaction due to the presence of a hydrophobic side chain.
2. The amino acid side chain can form hydrogen bonds due to the presence of hydrogen and nitrogen.
3. It is the primary structure of proteins (polypeptides)
4. With the presence of sulfur in the amino acid, disulfide linkage can be formed.
5. Both structures are Cysteine and histidine side chains of amino acids.
Explanation:
Proteins are organic materials. The two structures are the primary structures of the primary protein molecule which is the amino acid. They can be found in both plants and animals as it promotes cellular regeneration of damaged tissues and cell and the development of organs in living things. It is also found naturally in other materials in our enviroment.