7. Han's cell phone plan costs $200 to start. Then there is a $50 charge each month. a. What is the total cost (start up fee and monthly charge) to use the cell phone plan for 1 month? b. What is the total cost for x months?c.Graph the cost of the cell phone plan over a period of two years using month as the units of time be sure to label your axes and scale them by labeling each grid line with a number.d.Is there a portions relationship between time and the cost of the cell phone plan.e. Draw a line a parallel to the line you graphed that goes through the point(0,350) suppose that this line represents the pricing plan for another company.What is the startup fee and monthly cost for this plan?

Answers

Answer 1

Answer:

a. $250

b. The total cost for x month is $200 + $50 × x

c. Please see the attached graph

d. Yes, there is a proportional relationship between time and the cost of the cell phone plan

e. $350

Step-by-step explanation:

The given parameters are;

The costs to start on the cell phone cell = $200

The charge each month = $50

a. The total cost to use the cell phone plan for 1 month = Start up fee + Monthly charge = $200 + $50 = $250

b. The total cost for x month, c = $200 + $50 × x

c. Please see the attached graph

d. Yes, there is a proportional relationship between time and the cost of the cell phone plan

e. The line parallel to the line graphed that goes to the point (0, 350), is given as follows;

y = m·x + c

Where;

m = 50

y - 350 = 50 × (x - 0)

y = 50·x + 350

The startup fee is given by the total cost at x = 0, when the monthly fee is excluded, which gives;

c = 50 × 0 + 350 = 350

The startup fee for the pricing plan = $350.

7. Han's Cell Phone Plan Costs $200 To Start. Then There Is A $50 Charge Each Month. A. What Is The Total
7. Han's Cell Phone Plan Costs $200 To Start. Then There Is A $50 Charge Each Month. A. What Is The Total
Answer 2

The startup fee and monthly cost for this plan according to the question is :

Part a:

The total cost to use the cell phone plan for 1 month = Start up fee + Monthly charge

Total Cost = $200 + $50 Total Cost = $250 The total cost to use the cell phone plan for 1 month is $250.

Part b:

The total cost for x month, c = $200 + $50 × x The total cost for x month is $200 + $50 × x c.

Please see the attached graph

Part c:

Yes, there is a proportional relationship between time and the cost of the cell phone plan .

Part e:

The line parallel to the line graphed that goes to the point (0, 350), is given as follows;

y = m·x + c

Where;

m = 50 y - 350 = 50 × (x - 0) y = 50·x + 350

The startup fee is given by the total cost at x = 0, when the monthly fee is excluded, which gives;

c = 50 × 0 + 350 = 350

Yes, there is a proportional relationship between time and the cost of the cell phone plan e. $350

The given parameters are; The costs to start on the cell phone cell = $200 The charge each month = $50

The startup fee for the pricing plan = $350.

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y=-2x-1

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Kaycee wrote the proportion StartFraction 12 over 3 EndFraction = StartFraction 9 over c EndFraction for this situation. Identify the error and give two ways to write the proportion correctly.

Answers

Answer:

Marco earned $2.25.

Step-by-step explanation:

1. If Marco sold 12 cups of lemonade for 3$, we would divide 12 cups and how much he earned from the 12 cups (3$). 12/3 = 4

2. By the end of the day, Marco earned $9. So, 4 cups = 1$. To break it down, 1$ = 100 cents and 100 cents divided by 4 is 25 cents.  Cups to Cost. ( 4 : 1 ) and/or ( 1 : 0.25 )

3. 8 cups = 2$ plus 1 cup (0.25) = 2.25.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Answer:

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Step-by-step explanation:

This was the example answer

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Justin has a crate that is 8 feet long 2 feet wide and 3 feet tall decide weather each of the crate sizes described below has the same volume as Justin's crate

Answers

Complete question is;

Justin has a crate that is 8 feet long, 2 feet wide, and 3 feet tall. Decide whether each of the crate sizes described below has the same volume as Justin’s crate.

a. 9 feet long, 1 foot wide, 4 feet tall

b. 8 feet long, 2 feet wide, 2 feet tall

c. 4 feet long, 4 feet wide, 3 feet tall

d. 8 feet long, 3 feet wide, 3 feet tall

e. 6 feet long, 2 feet wide, 4 feet tall Answer:

Options C & E have the same volume as Justin's crate.

Step-by-step explanation:

We are told Justin has a crate that is 8 feet long, 2 feet wide, and 3 feet tall.

Thus, original volume is;

V_o = 8 × 2 × 3 = 48 ft³

A) For a dimension of 9 feet long, 1 foot wide, 4 feet tall , volume is;

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B) For a dimension of 8 feet long, 2 feet wide, 2 feet tall, volume is;

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C) For a dimension of 4 feet long, 4 feet wide, 3 feet tall, volume is;

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E) For a dimension of 6 feet long, 2 feet wide, 4 feet tall, volume is;

V_e = 6 × 2 × 4 = 48 ft³

Looking at all the options, the only ones that given a volume equal to Justin's original volume are options C & E.

Write an equation that represents the question below...​

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Answer:

first use your brain

Step-by-step explanation:

step by step you have to learn first

Answer:

30

Step-by-step explanation:

15 x 2 = 30

he was q5 feet ahead so in another hour he will be 30 feet

HELP ASAP!!
Adam sold 6 of wrapping paper and 9 wrapping paper for a total of $219. Jane sold 12 wrapping paper and 13 rolls of SHINY wrapping paper for a total of $353. Find the cost each of one roll of PLAIN wrapping paper and one roll of SHINY wrapping paper .

Answers

Answer:

The answer is $14.6 for the plain paper and $14.12

Step-by-step explanation:

I think i'm probably wrong but 6+9= 15 so 219 divided by 15 is 14.6 so thats answer 1 and 12+13=25 and 353 divided by 25 is 14.12

:p sorry if im incorrect

Answer: The first answer for 6 of wrapping paper and 9 wrapping paper is $7.30. The second answer for 12 wrapping paper and 13 rolls of SHINY wrapping paper is $4.38.

Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

hipe this helps :]

Answer:

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Answers

Answer:

The greatest common factor of 128 and 192 is 64, because 64 is the highest number that is divisible by both numbers.

The greatest common factor of 128 and 192 is 64 because 64 is the highest number that is divisible by both numbers.

What is the greatest common factor?

The greatest common factor is the largest positive number which can be divided into given numbers evenly.

In mathematics, the largest positive integer that divides each of the integers is known as the greatest common divisor of two or more integers that are not all equal to zero. The greatest common divisor of two integers is x and y.

Given that the two numbers are 128 and 192. The greatest common factor is the largest number which is divided into both numbers.

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PLZ HELP ASP 25 Points
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Answers

Answer:

it is proportional

Step-by-step explanation:

if you plug it in a graph the equation would be y = 1400x + 150

where y is the total cost of rent x is the unknown amount of months 1400 is how much it is a month and the 150 is the extra fee

Question in picture solve

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

X+y=8

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Please consider marking brainliest! :)

Using the principle of proportional relationship, it will take 20 cows 7.2 days.

Setting up the relationship thus :

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Hence, for 20 cows, it will take;

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3 laps a minute.

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

Answers on edge 2021

Please hurry up and help me thanks

Answers

Answer:

Line 1: m = 2

Line 2: m = 2

The lines are parallel.

Step-by-step explanation:

First, ensure both lines are in the slope-intercept form given as y = mx + b. where m is the slope of the line.

If the slope of both lines are the same, they are parallel.

If the slope of one is the negative reciprocal of the other, they are perpendicular.

If the slope of both lines are different and one is neither the reciprocal of the other, then they are neither parallel nor perpendicular.

✍️Line 1, y = 2x + 5, is already in the slope-intercept form.

✅The slope of Line 1 is 2

✍️Line 2, y - 3 = 2(x + 15), is in point-slope.

We can decide to rewrite in the slope-intercept form or directly determine the slope as it is given. The slope is 2. But to be sure, let's rewrite as y = mx + b.

y - 3 = 2(x + 15)

y - 3 = 2x + 30

Add 3 to both sides

y = 2x + 33

✅As we can see, the slope of line 2 is 2.

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Answers

Answer: 80

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1What is the simple interest on #25 000 for 3years at 5% per annum?.

#28 750

#3 750

#2 875

#375


Answers

Answer:

3750

Step-by-step explanation:

Simple interest (I) is calculated as

I = [tex]\frac{PRT}{100}[/tex] ( P is the principal, R is rate of interest and T time in years )

Here P = 25000, R = 5 and T = 3 , thus

I = [tex]\frac{25000(5)(3)}{100}[/tex]

  = [tex]\frac{375000}{100}[/tex]

  = 3750

A square has side length (2x+3)in. What is the area of the square

Answers

Answer:

the area would be "4x2+9+12x"

sorry if this doesn't help :(

Step-by-step explanation:

Answer:

Answer given in the photo

DUE TODAY PLEASE HELP!
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Answer: 12. X = 14

Step-by-step explanation:

10x + 17 = 87 + 5x

10x = 70 + 5x

5x = 70

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Albert’s father is 24 years older than Albert. In 8 years, his father will be twice as old as Albert. How old is Albert now? How old is his father?

Answers

Answer:

Albert is 24. Albert's father is 48

Step-by-step explanation:

Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an initial population Upper P 0 requires n units of time to​ triple, then the function ​P(t)equals Upper P 0 (3 )Superscript StartFraction t Over n EndFraction models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

Answers

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than [tex]A(t)=A_{0}e^{kt}[/tex]. for example, if an initial population P₀ requires n units of time to triple, then the function [tex]P(t)=P_{0}(3)^{\frac{t}{n} }[/tex] models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form [tex]P(t)=P_{0}(3)^{\frac{t}{n} }[/tex] that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form [tex]A(t)=A_{0}e^{kt}[/tex].

Answer: a) [tex]P(t)=50(3)^{\frac{t}{30} }[/tex]

              b) P(t) = 280 insects

              c) t = 74 days

             d) [tex]A(t)=50e^{0.037t}[/tex]

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

[tex]P(t)=50(3)^{\frac{t}{30} }[/tex]

b) In t = 47 days:

[tex]P(t)=50(3)^{\frac{t}{30} }[/tex]

[tex]P(47)=50(3)^{\frac{47}{30} }[/tex]

[tex]P(47)=50(3)^{1.567}[/tex]

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

[tex]750=50(3)^{\frac{t}{30} }[/tex]

[tex]\frac{750}{50}=(3)^{\frac{t}{30} }[/tex]

[tex](3)^{\frac{t}{n} }=15[/tex]

Using the property Power Rule of logarithm:

[tex]log(3)^{\frac{t}{30} }=log15[/tex]

[tex]\frac{t}{30}log(3)=log15[/tex]

[tex]t=\frac{log15}{log3} .30[/tex]

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

[tex]A(t)=A_{0}e^{kt}[/tex]

[tex]3A_{0}=A_{0}e^{30k}[/tex]

[tex]3=e^{30k}[/tex]

Use Power Rule again:

[tex]ln3=ln(e^{30k})[/tex]

[tex]ln3=30k[/tex]

[tex]k=\frac{ln3}{30}[/tex]

k = 0.037

Equation for exponential growth will be:

[tex]A(t)=50e^{0.037t}[/tex]

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