Answer:
12 mol CO₂
General Formulas and Concepts:
Atomic Structure
CompoundsMolesMole RatioStoichiometry
Analyzing reactions rxnUsing Dimensional AnalysisExplanation:
Step 1: Define
Identify
[rxn] 6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
[Given] 2 mol C₆H₁₂O₆
[Solve] mol CO₂
Step 2: Identify Conversions
[rxn] 6CO₂ → C₆H₁₂O₆
Step 3: Convert
[DA] Set up: [tex]\displaystyle 2 \ mol \ C_6H_{12}O_6(\frac{6 \ mol \ CO_2}{1 \ mol \ C_6H_{12}O_6})[/tex][DA] Multiply [Cancel out units]: [tex]\displaystyle 12 \ mol \ CO_2[/tex]What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g
Answer:
[tex]V'=1040ml[/tex]
Explanation:
From the question we are told that:
Initial Volume [tex]V_1=10.5mL[/tex]
Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]
Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]
Generally the equation for Acidity &Volume Relationship is mathematically given by
[tex]N_1V_1=N_2V_2[/tex]
Therefore
[tex]V_2=\frac{N_1V_2}{N_2}[/tex]
[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]
Therefore
Change in Water volume is
[tex]V'=V_2-V_1[/tex]
[tex]V'=1050ml-10ml[/tex]
[tex]V'=1040ml[/tex]
A diamond can make permanent marks on glass. It can also cut glass. Most other materſals cannot do this.Which property of a diamond allows it to make cuts or marks on glass? a. Hardness b. Heaviness c. Roughness d. transparency
Which sequence contains elements listed from most reactive
to least reactive?
Answer:
Transition metals, alkali metals, alkaline earth metals Transition metals - Middle of the periodic chart, only average reactivity. alkali metals - As mentioned above, very reactive. Bad choice, going from lower reactivity to higher reactivity.
Hope this answer is right!
PLEASE HELP ME SOLVE THIS.Thank you so much!
Answer: The coefficients for the given reaction species are 1, 6, 2, 3.
Explanation:
The given reaction equation is as follows.
[tex]Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}[/tex]
Now, the two half-reactions can be written as follows.
Reduction half-reaction: [tex]Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}[/tex]
This will be balanced as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O[/tex] ... (1)
Oxidation half-reaction: [tex]Cl^{-} \rightarrow Cl_{2} + 1e^{-}[/tex]
This will be balanced as follows.
[tex]6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}[/tex] ... (2)
Adding both equation (1) and (2) we will get the resulting equation as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O[/tex]
Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the metal (M). Please provide your answer in 2 decimal places.
a. How many moles of oxygen atoms are found in 4.00 g of O2?
b. How many atoms of hydrogen are found in 0.400 mol of H2S?
c. How many hydrogen atomsare present in 0.235 g of NH3?
Answer:
See solution.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:
[tex]\% M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\% =\frac{m_M}{m_M+32.00}*100 \%[/tex]
Thus, we solve for the molar mass of the metal to obtain:
[tex]59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol[/tex]
For the subsequent problems, we proceed as follows:
a.
[tex]4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2[/tex]
b.
[tex]0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH[/tex]
c.
[tex]0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH[/tex]
Regards!
Given that vat contains 9600 kg of milk, what is the mass of mg of the milk that vat contains?
Answer:
9.6x10⁹ mg
Explanation:
In order to solve this problem we need to convert 9600 kg into mg.
First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:
9600 kg * [tex]\frac{1000g}{1kg}[/tex] = 9.6x10⁶ g
Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:
9.6x10⁶ g * [tex]\frac{1000mg}{1g}[/tex] = 9.6x10⁹ mg
The mass of milk miligrams is 9.6x10⁹.
The ideal gas law is PV = nRT.
Use 8.31 for R. (8.31 Lx kPa / Kx mol)
What is the temperature of 3.0 moles of a gas that is in a closed container of
volume 9L, and has a pressure of 85kPa?
1. 3.4 kelvin
2. 0.03 kelvin
3. 30.7 kelvin
4. 28.6 kelvin
Answer: 30.66945 kelvin
Explanation:
An aqueous salt solution is 15.0% mass sodium chloride. How many grams of salt are in 250.0 grams of this solution? Use correct
significant figures.
Answer:
37.5 g NaCl
Explanation:
Step 1: Given data
Concentration of NaCl: 15.0% m/mMass of the solution: 250.0 gStep 2: Calculate how many grams of NaCl are in 250.0 g of solution
The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.
250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl
g Calculate the moles of methanol in a first distillate that has a total volume of 0.5 mL and contains 23.4% methanol. The density of methanol is 0.791 g/mL, and the molar weight of methanol is 32.04 g/mol. 2.9 x10-3 mol Methanol 9.3 x10-3 mol Methanol 1.17 x 10-2 mol Methanol None of the above
Answer:
2.9 × 10⁻³ mol
Explanation:
Step 1: Calculate the volume of methanol
0.5 mL of distillate contains 23.4% methanol.
0.5 mL × 23.4% = 0.117 mL
Step 2: Calculate the mass corresponding to 0.117 mL of methanol
The density of methanol is 0.791 g/mL.
0.117 mL × 0.791 g/mL = 0.0925 g
Step 3: Calculate the moles corresponding to 0.0925 g of methanol
The molar weight of methanol is 32.04 g/mol.
0.0925 g × 1 mol/32.04 g ≈ 2.9 × 10⁻³ mol
Which one of the mixtures would most likely produce a chemical reaction?
F2 + At- OR At2 + F-
Answer:
F₂ + At⁻
Explanation:
Astatine is the only Halogen that does not exist as a diatomic molecule. One Astatine atom would have a charge of 1⁻. Fluorine is the most electronegative element, and therefore very reactive and commonly forms a diatomic molecule.
Based on a specific example of titration method. How do titration methods play a role in agriculture industry?
Answer:
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
Answer:
How is titration used in the industry?
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
What is the molar mass of a substance
A) the mass in grams of one mole of a substance
B) the number of particles in one gram of a substance
C) the number of moles in one gram of a substance
D) the mass in grams of one particle of a substance
thank you :)
Answer:
A) the mass in grams of one mole of a substance.
Explanation:
The molar mass of a substance is the mass in grams of 1 mole of the substance. As shown in this video, we can obtain a substance's molar mass by summing the molar masses of its component atoms. We can then use the calculated molar mass to convert between mass and number of moles of the substance.
11. Which of these conditions would decrease the rate of photosynthesis in a plant?
A. above average precipitation
B. Changing the daylight hours from 14 hrs to 10 hrs
C. Changing the CO2 concentration from 380 ppm to 410 ppm
D. All of these choices
Answer:
B. Changing the daylight hours from 14 hrs to 10 hrs
Explanation:
what is the formula for trioxocarbonate (IV)
Answer:
[tex]CO_3^{2-}[/tex]
Explanation:
Trioxocarbonate (iv) salts result from the reaction of trioxocarbonate(iv) acid with metals and metal oxides.
All sodium, potassium, and ammonium of trioxocarbonate(iv) salts appearas to be soluble, while all others are insoluble.
Apart from Na and K, all trioxocarbonate (iv) salts breakdown to release CO2 when heated.
The formula for Trioxocarbonate (iv) is: [tex]CO_3^{2-}[/tex]
So, we can have Sodium trioxocarbonate as [tex]Na_2CO_3[/tex] and sodium hydrogen trioxocarbonate (iv) [tex]NaHCO_3[/tex]
How many grams of oxygen are present in 93.98 g of CO2?
Answer:
There are about 68.33 grams of oxygen present in 93.98 g of CO2.
Which compounds, on heating with an excess of concentrated sulfuric acid, produce only one product with molecular formula C7H10? [choices on the picture]
Answer:
1 and 2
Explanation:
When Concentrated H2SO4 reacted with the alcohols, they produce cycloalkenes. This is a mechanism known as dehydration of alcohols with an acid catalyst. This is because concentrated H2SO4 acts as a great oxidizing agent. In the process, the alcohols are heated to a high temperature with an excess of pure sulfuric acid. By passing the gases through a sodium hydroxide solution, the carbon dioxide and sulfur dioxide produced by reactive species are eliminated. The reaction mechanism shown in the image below indicates that only compounds 1 and 2 produce only one product.
Explain the science of water pressure
"At sea level, the air that surrounds us presses down on our bodies at 14.7 pounds per square inch . (gooxgle) "
Basically the deeper you go under the water, whether that be a pool or the sea the pressure will increase because of the weight of the water above you. Which causes greater force.
Calculate the pKa of hypochlorous acid (HClO, a weak acid). A 0.015 M solution of hypochlorous acid has a pH of 4.64.
Answer:
"7.46" is the correct answer.
Explanation:
Given that:
[tex]pH=4.64[/tex]
[tex]C=0.015 \ M[/tex]
The equation:
⇒ [tex]HA \rightleftharpoons H^++A^-[/tex]
HA = C - Cα
H⁺ = Cα
A⁻ = Cα
now,
⇒ [tex]pH=-log(H^+)[/tex]
[tex]=-log(C \alpha)[/tex]
[tex]=4.64[/tex]
[tex]C \alpha = 2.3\times 10^-5 \ M[/tex]
As we know,
⇒ [tex]K_a=C \alpha^2[/tex]
[tex]=(\frac{C \alpha}{C} )^2\times C[/tex]
[tex]=\frac{(2.3\times 10^{-5})^2}{0.015}[/tex]
[tex]=3.5\times 10^{-8}[/tex]
hence,
⇒ [tex]pK_a=-log(K_a)[/tex]
[tex]=7.46[/tex]
Two hundred forty-eight milliliters of an acid with an unknown concentration are titrated with a base that has a
concentration of 1.4 M. The indicator changed color when 82 milliliters of base were added. What is the concentration of
the unknown acid?
O 0.46 M
4.2 M
Answer:0.46
Explanation:
Calculate the lattice energy of CuBr(s) using a Born–Haber cycle.
Data:
Enthalpy of sublimation of Cu(s) = 337.7 kJ/mol
1st ionization energy of Cu(g) = 745 kJ/mol
Enthalpy of vaporization of Br2(l) = 29.96 kJ/mol
If a swimming pool contains 2850 kg liters of water how many gallons of water does it contain
Which of these statements are true? Select all that apply.
The AH+ for Br2() is 0 kJ/mol.
The AH; for Hel) is 0 kJ/mol.
The AH+ for Hg() is 0 kJ/mol.
The AHp for Cl2(g) is 0 kJ/mol.
The AH; for N261) is 0 kJ/mol.
Answer:
The AH+ for Br2() is 0 kJ/mol.
The AH+ for Hg() is 0 kJ/mol.
The AH; for N261) is 0 kJ/mol.
Explanation:
The statements 1,3,4 and 5 are true.
What is meant by enthalpy ?Enthalpy is defined as a thermodynamic quantity, which can be considered equal to the total heat of the system.
Here,
1) The enthalpy of formation of Br₂ (cr, l) is 0 kJ/mol.
So, the statement is true.
2) The enthalpy of formation of He(l) is not zero.
So, the statement is false.
3) The enthalpy of formation of Hg(l) is 0 kJ/mol.
So, the statement is true.
4) The enthalpy of formation of Cl₂(g) is 0 kJ/mol.
So, the statement is true.
5) The enthalpy of formation of N₂ is 0 kJ/mol.
So, the statement is true.
Hence,
The statements 1,3,4 and 5 are true.
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Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures PA and inside the flasks are measured.
a. PA will be greater than
b. PA will be less than PB
c. PA will be equal to PB
d. It's impossible to predict whether PA or will be greater without more information.
The question is incomplete, the complete question is:
Liquid A is known to have a lower viscosity and lower vapor pressure than Liquid B. Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures [tex]p_A[/tex] and [tex]p_B[/tex] inside the flasks are measured.
a. [tex]p_A[/tex] will be greater than
b. [tex]p_A[/tex] will be less than [tex]p_B[/tex]
c. [tex]p_A[/tex] will be equal to [tex]p_B[/tex]
d. It's impossible to predict whether [tex]p_A[/tex] or will be greater without more information.
Answer: The correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
Explanation:
Vapor pressure is defined as the equilibrium pressure which is exerted by the vapor phase to be in thermodynamic equilibrium with its condensed state (liquid phase) in a closed system at a given temperature.
We are given:
Vapor pressure of A < Vapor pressure of B
This means that a lesser number of gaseous molecules will form over its surface and thus, will experience lower pressure.
Thus, [tex]p_A<p_B[/tex]
Hence, the correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
Ayuda plissss es para hoy
alimientos procesados:
cereales, queso ,verduras enlatadas, un pan bocadillos salados, como patatas fritas, panecillos de salchicha, tartas y empanadas productos cárnicos, como tocino, salchicha, jamón, salami y paté comidas para microondas o comidas preparadas pasteles y galletas bebidas, como leche o refrescos
alimientos naturales
1. Pescado · 2. Brócoli o cualquiera de las verduras crucíferas · 3. Remolacha · 4. Espinacas y otras verduras de hoja verde · 5. Col rizada · 6. Mantequilla de maní · 7. Almendras.pechugas de pollo, Cordero, Salmón, Camarón,Aceite de coco,Nueces y semillas
Answer:
what
Explanation:
Which bodies of water in the list are found to the west of the Philippines?
Answer:
South China sea
Explanation:
To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).
3 enzimas presentes en nuestro organismo e indique en que procesos actúan
Answer:
ATP asa, Helicasa, Proteasa, ARN polimerasa
Explanation:
Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.
Al momento de referirse a ellas, se utiliza la terminación asa.
ATPasa → Sintetizando ATP para el funcionamiento celular
Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.
Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.
ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.
first law of the thermodynamic indicates.?
Answer:
The first law of thermodynamics states that energy can neither be created nor destroyed, only altered in form. For any system, energy transfer is associated with mass crossing the control boundary, external work, or heat transfer across the boundary. These produce a change of stored energy within the control volume.
Explanation:
1. Write the structural formulas and give IUPAC names for all isorneric alcohols of molecular formula
С4Н9OH
Explanation:
Butanol (С4Н9OH)
Structural formula is :-
CH3-CH2-CH2-CH2-OH
Draw the R enantiomer of CFClBrI as a 3-D (wedge and dotted line) structure and as a Fischer projection (putting the I at the top and the F to the right). Be able to draw Fischer projections for other simple compounds with a single chiral carbon.
The 3D structure of R- CFClBrI is drawn using wedges and dotted line with I in the top and F right to I and Fischer projection is drawn using lines for bonds where C is placed at center and I in the top with F right to it.
What is an enantiomer?An enantiomer is a spatial isomer of a compound having different spatial configuration but the same formula. Enantiomers are non-superimposable mirror images of each other.
In R- enantiomer, the elements are arranges in a way that on numbering in clockwise direction, the priority of group decreases from 1 to 2 to 3 and follows. The highest priority group is numbered first.
If the count 1..2..3 goes in anti-clockwise direction, then the enantiomer is termed as S. In 3D projection, wedges and dotted lines are used for representing bonds.
In Fischer projection, lines are used for bonds as shown in the uploaded image. Where the chiral carbon is shown in center and other groups are allotted as per the R or S configuration.
Therefore, the 3D image and Fischer projection of CFClBrI is drawn as in the image uploaded.
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If a light beam strikes a shiny object at a 90-degree angle, to what are the angle of incidence and the angle of reflection equal?
Answer:
Angle of incidence = angle of reflection = 0
Explanation:
Given that,
A light beam strikes a shiny object at a 90-degree angle.
The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.
Here, the beam strikes normally. So, the angle of incidence is 0.
A/c to the law of reflection,
Angle of incidence = angle of reflection
So, the angle of reflection is also equal to 0.