-6/5 - (-3/8)
Help please




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Answer:

9a + 3b + 6c

Step-by-step explanation:

4a-6b+9c + 5a+9b-3c

4a + (-6b) + 9c + 5a + 9b + (-3c)

(4a + 5a) + (-6b+9b) + (9c-3c)

9a + 3b + 6c

Answer:

the person below is correct I believe

Step-by-step explanation:

hope this helped have a good rest of your night :)❤

Answer:

the ansewer is 56

Step-by-step explanation:

Answer:

b = 24 ft

h = 10 ft

Step-by-step explanation:

120 = ½hb

120 = ½h(3h - 6)

240 = h(3h - 6)

240 = 3h² - 6h

 80 = h² - 2h

    0 = h² - 2h - 80

    0 = (h - 10)(h + 8)

    h = 10 ft or -8 ft

 we ignore -8 as it makes no sense for a triangle side length.

b = 3(10) - 6 = 24 ft

Answer:

w = win

Step-by-step explanation:

w=13

Answer:

w = 13

Step-by-step explanation:

16w - w = 15w

15w - 12w = 3w

3w - 2w = w

w = 13

Answer:

$1.33

Step-by-step explanation:

32-20 = 12

12/9 = $1.33

Answer:

To find the area of a square with the scale factor of 3, you multiply the side lengths by 3, so (3*L)*(3*W)= Area of your square.

Step-by-step explanation: I hope that this helps, ask questions in the comments below.(if you have any).

The area of the imagined square will be 90 units² by increased with a scale factor of 3.

You must specify the extent of the shape's enlargement when describing one.

The scale factor is the ratio of two dimensions such that one figure is large and another is small.

As per the imagined square with dimensions of 10 units.

Applied the scale factor 3 in the length of the square(since it has only one dimension).

10 x 3 = 30 units.

Thus, each side of the square will be 30 units in length.

Hence "By adding a scale factor of 3, the envisioned square's area will expand to 90 units²".

To learn more about scale factors,

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Answer:

Fertilizer A = 20, Fertilizer B = 56

Step-by-step explanation:

Step 1: Set up the equations

Nitrogen: 8x + 5y ≥ 440

Phosphorous: 2x + 5y ≥ 260

Potassium: 4x + 5y ≥ 360

Step 2: Find the vertices

It is easiest to graph the equations to find the vertices. (see attachment).  You can also solve each system of equations to find the intersected points.

The following satisfy the "greater than or equal to" requirement:

(0, 88) → y-intercept of Nitrogen equation

(20, 56) → intersection of Nitrogen and Potassium equations

(50, 32) → intersection of Phosphorous and Potassium

(130, 0) → x-intercept of Potassium

Step 3: Use vertices in cost function C(x) to find the minimum

C(x) = $30x + $20y

(0, 88): $30(0) + $20(88) = $1760

(20, 56): $30(20) + $20(56) = $1720    ← This is the minimum!

(50, 32): $30(50) + $20(32) = $2140

(130, 0): $30(130) + $20(0) = $3900

The minimum cost occurs when 20 bags of Fertilizer A and 56 bags of Fertilizer B are purchased.  

Answer:

5

Step-by-step explanation:

The answer is 60/12 becuase we can simfly both of theese mixed numbers into an improper fraction, wich will be 4/3*15/4. We do the multiplication, and we get 60/12. 60/12 can be simplifed to 5 becuase 60 divided by 12 is 5

Step-by-step explanation:

It is represented by ,

=> y ≥ 1/4x -1

Answer:

The ribbon costs 1.25 per meter

Step-by-step explanation:

5/4=1.25

ANSWER :

0 / 15 = 0 + 0/15 = 0

Answer 12

Step-by-step explanation:

A shipment of 12 microwave ovens contains three defective units. A vending company has ordered four units, and because each has identical packaging, the selection will be random. What is the probability that (a) all four units are good, (b) exactly two units are good, and (c) at least two units are good?

 I hope that helped?

Answer:

i will clear you.

Step-by-step explanation:

Given:-

Marbels we have =30

when we add marbels =5

Now,

or,30+5

The left pic :

[tex]x = 46 \times \cos(70°) [/tex]

[tex]x = 46 \times 0.342[/tex]

[tex]x = 15.732[/tex]

_____________________________________________

The right pic :

[tex] \tan(18°) = \frac{15}{x} \\ [/tex]

[tex]0.325 = \frac{15}{x} \\ [/tex]

Thus :

[tex]x = \frac{15}{0.325} \\ [/tex]

[tex]x = 46.1538[/tex]

There u go ...

Have a great day ❤

Answer:

c

Step-by-step explanation:

In Line 4, she forgot to take the negative square root, because squaring both 8 and −8 equals 64.

60

Step-by-step explanation:

(-47)-(-107)

(-47)-1(-107)

-47+107

=60

Since you have the answers, I'll just show the steps on how to get there.

============================================================

Problem 19

[tex](1+4i)^2\\\\(1+4i)(1+4i)\\\\1*1 + 1*4i + 4i*1 + 4i*4i\\\\1 + 4i + 4i + 16i^2\\\\1 + 4i + 4i + 16(-1)\\\\1 + 4i + 4i-16\\\\(1-16) + (4i+4i)\\\\(1-16) + (4+4)i\\\\-15 + 8i\\\\[/tex]

Keep in mind that [tex]i = \sqrt{-1}[/tex] by definition. Squaring both sides leads to [tex]i^2 = -1[/tex]

In the second step, I used the idea that x^2 = x*x. Right after that, I used the FOIL rule to expand everything out.

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Problem 21

We could follow the same idea as problem 19, but I'll use a different approach.

[tex](A+B)^2 = A^2+2AB+B^2\\\\(3+i)^2 = 3^2 + 2*3*i + i^2\\\\(3+i)^2 = 9 + 6i - 1\\\\(3+i)^2 = 8 + 6i\\\\[/tex]

The formula on the first line is the perfect square binomial formula.

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Problem 23

The FOIL rule can be used if you want, but I'll use the difference of squares rule instead.

[tex](m+n)(m-n) = m^2 - n^2\\\\(3+5i)(3-5i) = (3)^2 - (5i)^2\\\\(3+5i)(3-5i) = 9 - 25i^2\\\\(3+5i)(3-5i) = 9 - 25(-1)\\\\(3+5i)(3-5i) = 9 + 25\\\\(3+5i)(3-5i) = 34\\\\[/tex]

It turns out that multiplying any complex number of the form a+bi with its conjugate a-bi will result in a purely real number (that has no imaginary part). More specifically: [tex](a+bi)(a-bi) = a^2+b^2[/tex]

============================================================

Problem 25

We could use the difference of squares rule again, but I'll show a different approach. This time using the distribution rule. The FOIL rule could also be used if you wanted.

[tex](6+7i)(6-7i)\\\\x(6-7i)\\\\6x-7xi\\\\6(x)-7i(x)\\\\6(6+7i)-7i(6+7i)\\\\6(6)+6(7i)-7i(6)-7i(7i)\\\\36+42i-42i-49i^2\\\\36-49(-1)\\\\36+49\\\\85\\\\[/tex]

I used x = 6+7i and the substitution property to help distribute. Lines 3 and 6 are where distribution is applied.

Answer:

y = 10

Step-by-step explanation:

y = (-2)(x) + 4

y = (-2)(-3) + 4

y = 6 + 4

y = 10

Answer:

a b d e

Step-by-step explanation:

i just took the test and got a hundred

Equations A, B, and E are true, i.e 66: 10 = 6.6, 660: 10° = 66, 6: 100 = 0.06​.

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

Make sure your equation is correct by comparing the values on either side of the equals sign to create a true equation. A true equation must have the same numerical values on both sides of the "=" sign. One real equation is, for instance, 9 = 9. A valid equation is 5 + 4 = 9.

As a result, the true equations are,

66: 10 = 6.6

660: 10° = 66

6: 100 = 0.06​

Thus, equations A, B, and E are true, i.e 66: 10 = 6.6, 660: 10° = 66, 6: 100 = 0.06​.

Learn more about the equation here,

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Step-by-step explanation:

Proportional = time/cars washed

= 1/3

no. of hours= 90hours

cars washed = 30 cars washed

Answer:

I don't know

Step-by-step explanation:

Answer:

Sometimes it's better to leave them as roots because it's easier sometimes to solve problems with them still as roots

Answer:

We choose to leave radicals as roots without calculating them because calculating the square roots of a non perfect squares result in an irrational, non terminating decimal.

Step-by-step explanation:

Why do we do Radicals in the first place?

Radicals are used to write the square root or the nth root of a number. We sometimes leave specific numbers (non-perfect squares) as a radical because the output would be infinity

Example:

[tex]\sqrt45[/tex] is not a perfect square, it lies between [tex]\sqrt36[/tex]  and [tex]\sqrt49[/tex]

This means the number lies in between 6 and 7

The true root of 45 is irrational. Recall that irrational numbers are numbers of non-perfect squares. [tex]\sqrt45[/tex] = 6.7082039.......

Simplify:

[tex]\sqrt 45 = \sqrt 9 * \sqrt 5\\[/tex]

[tex]= \sqrt3^2 * \sqrt 5\\\\ \\= 3\sqrt5[/tex]

We choose not to pursue simplifying this because  [tex]\sqrt5[/tex]  is irrational (square root of a non-perfect square)

Summary:

We choose to leave radicals as roots without calculating them because calculating the square roots of a non perfect squares result in an irrational, non terminating decimal.

-Chetan K

9514 1404 393

Answer:

  y = 2x -5

Step-by-step explanation:

The parallel line will differ only in the value of c. That can be found using the given point.

  y = mx +c

  c = y -mx . . . . . . subtract mx to solve for c

  c = 1 -2·3 = -5 . . . . . . the value of m is 2 in the given equation (x, y) = (3, 1)

The equation of the parallel line is ...

  y = 2x -5

Answer:

15227707.5

More info

Step-by-step explanation:

45x676787 the divide it by 2

make two pair of line segment of PQ andQP and construct use of a scale and the parallel line give the point name

Answer:

25 text messages

Step-by-step explanation:

First of all you need to find how much money was added to his phone bill. 31.92-27.42 would equal 4.5. Then you would divide that number by 0.18 to find out the total text messages, which is 25

Answer:

yamete kudesai

Step-by-step explanation:

Answer:

I believe it's 2/4.

Step-by-step explanation:

Let me know if it's incorrect.

Recall the half-angle identity for cosine:

cos²(x) = 1/2 (1 + cos(2x))

Then we can rewrite the integrand as

cos³(4x) = cos(4x) cos²(4x) = 1/2 cos(4x) (1 + cos(8x))

So we have

[tex]\displaystyle \int \cos^3(4x) \, dx = \frac12 \int (\cos(4x) + \cos(4x)\cos(8x)) \, dx[/tex]

Next, recall the cosine product identity,

cos(a) cos(b) = 1/2 (cos(a - b) + cos(a + b))

so that the integral is equivalent to

[tex]\displaystyle \int \cos^3(4x) \, dx = \frac12 \int \cos(4x) \, dx + \frac14 \int (\cos(4x - 8x) + \cos(4x + 8x)) \, dx[/tex]

[tex]\displaystyle \int \cos^3(4x) \, dx = \frac34 \int \cos(4x) \, dx + \frac14 \int \cos(12x) \, dx[/tex]

Computing the rest is trivial:

[tex]\displaystyle \int \cos^3(4x) \, dx = \boxed{\frac3{16} \sin(4x) + \frac1{48} \sin(4x) + C}[/tex]