Find the area of a circle with Radius 8 yd.
Use the value 3.14 forn, and do not round your answer.
Answer:
[tex]64\pi yd^{2}[/tex] or 201.062 [tex]yd^{2}[/tex]
Step-by-step explanation:
Area of a circle: [tex]\pi r^{2}[/tex]
Given:
r=8 yd
[tex]\pi[/tex]=3.14
[tex]\pi (8^{2})=64\pi[/tex]
=201.062 [tex]yd^{2}[/tex]
I hope this is correct and helps!
my question has been up too long lol
Answer:
Question 2: y = -7
Question 3: All real numbers
Step-by-step explanation:
(2) - The equation has a horizontal asysmptote that is y = -7
(3) - they are all real numbers it does not stop at any point
I hope this helps!
4. Which of these is equal to sin(70°)?
a. cos(1109)
c. cos(20°)
b. cos(160)
d. cos(709)
Write an expression for the area and perimeter for the figure shown.
I WILL GIVE THE BRAINLIEST IF YOU CAN ANSWER THIS
Find the measure of Arc XY.
Answer:
arc XY = 46°
Step-by-step explanation:
the arc of an inscribed angle is equal to 2 x the inscribed angle
mXY
2m<XZY2(23)46°When x= 1, then y= 1
Answer:
When x = 1, then y = -2
19+23=2X-2
Someone help me pleaseeeeeeeeeeeeee
Answer:
x = 22
Step-by-step explanation:
19+23=2X-2
42 = 2x - 2
-2x = -2 - 42
-2x = -44
x = 22
hope this helps
Read John Muir's "Calypso Borealis" and answer the question. [1] After earning a few dollars working on my brother-in law's farm near Portage [Wisconsin], I set off on the first of my long lonely excursions, botanising in glorious freedom around the Great Lakes and wandering through innumerable tamarac and arbor-vitae swamps, and forests of maple, basswood, ash, elm, balsam, fir, pine, spruce, hemlock, rejoicing in their bound wealth and strength and beauty, climbing the trees, revelling in their flowers and fruit like bees in beds of goldenrods, glorying in the fresh cool beauty and charm of the bog and meadow heathworts, grasses, carices, ferns, mosses, liverworts displayed in boundless profusion. [2] The rarest and most beautiful of the flowering plants I discovered on this first grand excursion was Calypso borealis (the Hider of the North). I had been fording streams more and more difficult to cross and wading bogs and swamps that seemed more and more extensive and more difficult to force one's way through. Entering one of these great tamarac and arbor-vitae swamps one morning, holding a general though very crooked course by compass, struggling through tangled drooping branches and over and under broad heaps of fallen trees, I began to fear that I would not be able to reach dry ground before dark, and therefore would have to pass the night in the swamp and began, faint and hungry, to plan a nest of branches on one of the largest trees or windfalls like a monkey's nest, or eagle's, or Indian's in the flooded forests of the Orinoco described by Humboldt. [3] But when the sun was getting low and everything seemed most bewildering and discouraging, I found beautiful Calypso on the mossy bank of a stream, growing not in the ground but on a bed of yellow mosses in which its small white bulb had found a soft nest and from which its one leaf and one flower sprung. The flower was white and made the impression of the utmost simple purity like a snowflower. No other bloom was near it, for the bog a short distance below the surface was still frozen, and the water was ice cold. It seemed the most spiritual of all the flower people I had ever met. I sat down beside it and fairly cried for joy.
[4] It seems wonderful that so frail and lovely a plant has such power over human hearts. This Calypso meeting happened some forty-five years ago, and it was more memorable and impressive than any of my meetings with human beings excepting, perhaps, Emerson and one or two others. When I was leaving the University, Professor J.D. Butler said, "John, I would like to know what becomes of you, and I wish you would write me, say once a year, so I may keep you in sight." I wrote to the Professor, telling him about this meeting with Calypso, and he sent the letter to an Eastern newspaper [The Boston Recorder] with some comments of his own. These, as far as I know, were the first of my words that appeared in print.
[5] How long I sat beside Calypso I don't know. Hunger and weariness vanished, and only after the sun was low in the west I splashed on through the swamp, strong and exhilarated as if never more to feel any mortal care. At length I saw maple woods on a hill and found a log house. I was gladly received. "Where ha ye come fra? The swamp, that awfu' swamp. What were ye doin' there?" etc. "Mony a puir body has been lost in that muckle, cauld, dreary bog and never been found." When I told her I had entered it in search of plants and had been in it all day, she wondered how plants could draw me to these awful places, and said, "It's god's mercy ye ever got out."
[6] Oftentimes I had to sleep without blankets, and sometimes without supper, but usually I had no great difficulty in finding a loaf of bread here and there at the houses of the farmer settlers in the widely scattered clearings. With one of these large backwoods loaves I was able to wander many a long wild fertile mile in the forests and bogs, free as the winds, gathering plants, and glorying in God's abounding inexhaustible spiritual beauty bread. Storms, thunderclouds, winds in the woods—were welcomed as friends.
The words that Muir uses in his essay reveal that he relates to nature as a(n)
emotional professor
objective notetaker
passionate observer
removed reporter
Answer:
I think it's the third one
Step-by-step explanation:
Sorry if incorrect
hope this helps!
I know this one is hard but its hard for me. PLEASE HELPP
Answer:
G. <3 and <5 hope this helps
Answer:
G
Step-by-step explanation:
differentiate x+sinx/x+cosx with respect to x
Step-by-step explanation:
content://com.cryptotab.android.FileProvider/images/screenshot/1615820475640483392397139554304.jp
Find f(-) if f(n) = 5n + 6.
Answer:
f(-1) = 1
Step-by-step explanation:
Are you missing a number after the negative in f(-)?
If so, let me solve for f(-1) so substitute in the n with a -1 so f(-1) = 5(-1) + 6
so f(-1) = -5 + 6 so f(-1) = 1
David can jog 3.5 miles in 75 minutes. What is David’s jogging rate per hour?
PLEASE SHOW YOUR WORK!!!!
will give brainliest!
Brainly reward!!!!
What's the area of the gray shape?
Sarah is creating a triangular birthday card for her teacher. In order to glue lace
around the outside of the card, Sarah needs to know the length of each side. She
knows that two of the sides measure 4 inches and 9 inches. Between which two
numbers must the third side of the card fall?
Answer:
6-12.
Step-by-step explanation:
Between 6 to 12 two numbers must the third side of the card fall.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
We are given that Sarah is creating a triangular birthday card for her teacher.
Thus in order to glue lace around the outside of the card, Sarah needs to know the length of each side.
It should be known that two of the sides measure 4 inches and 9 inches.
Therefore, in between 6 to 12 the third number must be lie.
More about the Algebra link is given below.
brainly.com/question/953809
#SPJ2
I hate how i have to write things here
Answer: Question 1 is m=-7/4
Question 2 is -4 as the y axis where it intercepts and the other coordinate is (3,-2)
Step-by-step explanation:
Find the lengths of the missing sides in the triangle. Write your answers as integers or as decimals rounded to the nearest tenth.
Answer:
[tex]x = 9.9[/tex]
[tex]y= 7[/tex]
Step-by-step explanation:
Given
See attachment for triangle
Required
Find x and y
Considering [tex]\theta = 45[/tex]
From the attached triangle, length x is the hypotenuse and length y is the adjacent
Solving for x
[tex]Sin\theta = \frac{Opp}{Hyp}[/tex]
[tex]Sin\theta = \frac{7}{x}[/tex]
So, we have:
[tex]Sin45 = \frac{7}{x}[/tex]
[tex]x= \frac{7}{Sin45 }[/tex]
[tex]x = \frac{7}{0.7071}[/tex]
[tex]x = 9.9[/tex]
Solving for y
Considering [tex]\theta = 45[/tex]
[tex]Tin\theta = \frac{Opp}{Adj}[/tex]
So, we have:
[tex]Tin45= \frac{7}{y}[/tex]
[tex]y= \frac{7}{Tan45}[/tex]
[tex]y= \frac{7}{1}[/tex]
[tex]y= 7[/tex]
The value of x and y is 9.9 and 7.
Calculation of the value:Since theta is 45 degrees
So, we know that
Sin theta = opp/hyp
Sin theta = 7 /x
x = 7 / 0.7071
= 9.9
Now the value of Y should be
Tin theta = opp/hyp
y = 7 \tan 45
= 7 /1
= 7
Therefore, we can conclude that The value of x and y is 9.9 and 7.
Learn more about length here: https://brainly.com/question/19021872
1. What's the probability that a respondent was a boy AND in year 8?
Answer:
8/18?
Step-by-step explanation:
Help me pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Answer:
correspondence or alliance
Answer:
B
Step-by-step explanation:
Tucker worked 5.5 hours on Saturday. He earns $7.20 per hour.
How much did he earn on Saturday?
Answer:
$39.6
Step-by-step explanation:
5.5 times 7.20 = $39.6
What the slope? Can someone help me
Answer:The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points.The slope of a line is a measure of its steepness. Mathematically, slope is calculated as "rise over run" (change in y divided by change in x).
Step-by-step explanation:
It 16x = (141)²-(109)², then
the value of x is.
(a). 150
(b). 500
(c). 600
(d). 32
Answer:
b) 500
16x = (141)^2 - (109)^2
or, 16x = 19881 - 11881
or, x = 8000/16=500
You may borrow up to 2.5 times your annual income. Arianna is buying a home. Her weekly income is $900. What is the maximum amount that she may borrow?
Answer: $117,000
Step-by-step explanation:
The maximum that Arianna may borrow is 2.5 times her annual income.
First step therefore, would be to calculate her annual income:
= 900 * 52 weeks
= $46,800
She may borrow 2.5 times this:
= 46,800 * 2.5
= $117,000
Q. Which equation describes the line that passes
through the point at (-2, 1) and is perpendicular
to the line y = 1/3x + 5?
Answer:
Step-by-step explanation:
perp. -3
y - 1 = -3(x + 2)
y - 1 = -3x - 6
y = -3x - 5
Find the area of the square whose side is 14cm?GUYS??
Answer:
196 cm
Step-by-step explanation:
Area= L×W
Area = 14×14 = 196 cm
Answer and Step-by-step explanation:
To find the area, simply times the 2 sides together.
14 times 14 is 196.
The area of a square with sides 14cm is 196cm.
#teamtrees #PAW (Plant And Water)
Ariana compró cierto número de sacos de azúcar por S/. 675 y luego los vendió por S/. 1 080, ganando S/. 3 por cada saco. ¿Cuántos sacos de azúcar compró?
Responder:
135
Explicación paso a paso:
Número de bolsas compradas = x
Costo total de compra = 675
Costo total de ventas = 1080
Beneficio por bolsa = 3
Por eso :
Beneficio total + costo total de compra = costo total de ventas
3x + 675 = 1080
3x = 1080 - 675
3 veces = 405
x = 405/3
x = 135
Se compraron 135 bolsas
Interest earned: $84
Principal: 600
Interest rate: 7%
Time: ?
Answer:
2 years
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 7%/100 = 0.07 per year,
then, solving our equation
t = 84 / ( 600 × 0.07 ) = 2
t = 2 years
The time required to
accumulate simple interest of $ 84.00
from a principal of $ 600.00
at an interest rate of 7% per year
is 2 years.
x = -0.25 and y = -6
Solve the expression: xy
Answer:
If x = -0.25 and y = -6 then we have -6(-0.25) = 1.5
Hope this helps!
There are 320 students in a school. The ratio of the number of boys to the number of girls is 3:2. When some new boys and girls are admitted, the number of boys increases by 8 and the ratio of number of boys and girls changes to 4:3. Find how many new girls are admitted.
Which equation shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation 3х-5=2x+ 10?
Ox= 5
О-5а Х
O-15 = -5x
O-5х = 15
Can I please have help with question 2) a and b
Answer:
[tex]\frac{10\sqrt{6} }{3}[/tex] and [tex]\frac{11\sqrt{3} }{3}[/tex]
Step-by-step explanation:
(a)
A = [tex]\frac{1}{2}[/tex] × 4[tex]\sqrt{2}[/tex] × [tex]\frac{5}{\sqrt{3} }[/tex]
= 2[tex]\sqrt{2}[/tex] × [tex]\frac{5}{\sqrt{3} }[/tex]
= [tex]\frac{10\sqrt{2} }{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ← rationalise the denominator
= [tex]\frac{10\sqrt{6} }{3}[/tex] units²
(b)
Using Pythagoras' identity in the right triangle
let hypotenuse be h , then
h² = (4[tex]\sqrt{2}[/tex] )² + ([tex]\frac{5}{\sqrt{3} }[/tex] )²
= 32 + [tex]\frac{25}{3}[/tex]
= [tex]\frac{96}{3}[/tex] + [tex]\frac{25}{3}[/tex]
= [tex]\frac{121}{3}[/tex] ( take the square root of both sides )
h = [tex]\sqrt{\frac{121}{3} }[/tex] = [tex]\frac{11}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ← rationalise the denominator
h = [tex]\frac{11\sqrt{3} }{3}[/tex]