6 1/6 6 1/3 6 2/3 6 3/2

Answer:

-13

Step-by-step explanation:

Answer:

[tex]x\geq 4y\\y\leq \frac{x}{4}[/tex]

Answer:

what kanguage s this?!!

Step-by-step explanation:

Answer:

-6y

Step-by-step explanation:

6 - 12 = -6

-6 * y = -6y

Hope this helps :)

Answer:

6y-72

Step-by-step explanation:

Step-by-step explanation:

1: Solve one Equation for one of the variables

2: Substitute (plug-in) this expression into the other equation and solve

3: Resubtitue the value into the original equation to find the corresponding variable

Answer:

1. Solve one equation for one of the variables.

2. Substitute (plug-in) this expression into the other equation and solve.

3. Resubstitute the value into the original equation to find the corresponding variable.

Now at first glance, this may seem complicated, but it'll get easier along the way. <3

Done by NeighborhoodDealer

Answer:

$1881.25

Step-by-step explanation:

Final cost of the computer

[tex] = 1750 + 7.5\% \: of \: 1750 \\ \\ = 1750 + 0.075 \times 1750 \\ \\ = 1750 + 131.25 \\ \\ = \$ 1,881.25[/tex]

Answer:

it's answer is C. 12/10 = 4 / x

Step-by-step explanation:

As the triangles are similar so

4/12 = x/10

Or cross multiply then

12/10 = 4/x

Hope it will help :)

Given:

The inequality is

[tex]3(q+6)>11[/tex]

To find:

The inequality that has the same solution set as the given inequality.

Solution:

We have,

[tex]3(q+6)>11[/tex]

Using distributive property, we get

[tex]3(q)+3(6)>11[/tex]

[tex]3q+18>11[/tex]

Since the given inequality can be rewritten as [tex]3q+18>11[/tex], therefore the inequality [tex]3q+18>11[/tex] has the same solution set as [tex]3(q+6)>11[/tex].

Hence, all options are incorrect. The required inequality is [tex]3q+18>11[/tex].

Answer:

3q+18 > 11

Step-by-step explanation:

Answer:

37 Degree celcius; is the correct answer...

Answer:

5

Step-by-step explanation:

Answer:

look at the picture i sent.......

Answer:

[tex]a = 8[/tex] and [tex]b = 2[/tex]

Step-by-step explanation:

Given

[tex]\sqrt[3]{x^{10}}[/tex]

[tex]x = -2[/tex]

Required

Express as: [tex]a\sqrt[3]{b}[/tex]

Substitute -2 for x in [tex]\sqrt[3]{x^{10}}[/tex]

[tex]\sqrt[3]{x^{10}} = \sqrt[3]{(-2)^{10}}[/tex]

[tex]\sqrt[3]{x^{10}} = \sqrt[3]{1024}[/tex]

Express 1024 as 2^10

[tex]\sqrt[3]{x^{10}} = \sqrt[3]{2^{10}}[/tex]

Apply law of indices:

[tex]\sqrt[3]{x^{10}} = \sqrt[3]{2^{9+1}}[/tex]

Apply law of indices: Split

[tex]\sqrt[3]{x^{10}} = \sqrt[3]{2^{9}*2^1}}[/tex]

[tex]\sqrt[3]{x^{10}} = \sqrt[3]{2^{9}} *\sqrt[3]{2^1}}[/tex]

[tex]\sqrt[3]{x^{10}} = \sqrt[3]{2^{9}} *\sqrt[3]{2}}[/tex]

[tex]\sqrt[3]{x^{10}} = 2^{9*\frac{1}{3}}} *\sqrt[3]{2}}[/tex]

[tex]\sqrt[3]{x^{10}} = 2^3 *\sqrt[3]{2}}[/tex]

[tex]\sqrt[3]{x^{10}} = 8\sqrt[3]{2}}[/tex]

By comparison:

[tex]a = 8[/tex] and [tex]b = 2[/tex]

Answer:

a=-8 and b=-2

Step-by-step explanation:

Edge

Answer:

13.5 and 7

Step-by-step explanation:

x + y = 20.5

x - y = 6.5

Hence,

x = 20.5 - y

20.5 - 2y = 6.5

Hence,

2y = 14

y = 7

and x = 20.5 - y = 20.5 - 7 = 13.5

The two numbers are are 13.5 and 7.

a + b = 20.5 equation 1

a  - b = 6.5 equation 2

Where a and b represents the two numbers

In order to determine the value of b, subtract equation 2 from 1

2b = 14

Divide both sides by 2

b = 7

Substitute for b in equation 1

a + 7 = 20.5

a = 20.5 - 7

a = 13.5

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552

Answer:

The median is 5, mode is 5, and range is 12

Step-by-step explanation:

Answer:

MEDIAN - 5

MODE - 2 (4times)

RANGE - 13-1=12 (12 is the range)

Step-by-step explanation:

MEDIAN - Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers.

MODE - The mode is the element that occurs most in the data set. In this case, 2 occurs 4 times.

RANGE - Subtract the minimum data value from the maximum data value to find the data range. In this case, the data range is 13-1=12

Answer:

48p2+4p-4

Step-by-step explanation:

Answer:

48p² +4p -4

Step-by-step explanation:

A polynomial of two terms is called a 'binomial'.

Here, we are multiplying 2 binomials.

This is so common, there is a standard way to do it. The method is called FOIL, which means "firsts, outsides, insides, then lasts"

You do it like this:

multiply the 'first terms' of each binomial                           -->  8p*6p = 48p²

multiply the 'outside' terms, far left and far right                 -->  8p*2 = 16p

multiply the 'inside' terms, the two terms in the 'middle'    -->  -2*6p = -12p

multiply the 'last' terms of each binomial                              -->  -2 * 2 = -4

Add 'like' terms: 48p² + (16p - 12p) -4

Answer --->  48p² +4p -4

Answer:

Answer is

11

I'm just now learning

11 is the answer dear friend

Answer:

5 %

Step-by-step explanation:

Answer:

180-140=a

180-90=b

180-a-b= your ans

Answer:

The odds of rolling a 3 on a 6-sided number cube is 1 out of 6. The odds of rolling a 3 on either of two 6-sided cubes are 1/3. This is because 1/6 * 2 = 1/3. Therefore, an average of one-third of rolls will have a 3 in them. 1/3 expressed as a decimal is .3 repeating (.3333333 etc) and that rounds to 33 which is less than 34.

Step-by-step explanation:

Answer:

$0.96

Step-by-step explanation:

You will pay $0.96 for a item with original price of $2.40 when discounted 60%. In this example, if you buy an item at $2.40 with 60% discount, you will pay 2.40 - 1.44 = 0.96 dollars.

Hope this helps

Answer:

P-value = 0.0046  

Step-by-step explanation:

Given that:

Sample size n = 290

sample mean [tex]\overline{x_1}[/tex] = 4.1

standard deviation [tex]\sigma[/tex] = 0.6

population mean [tex]\mu[/tex] = 4.2

The null and the alternative hypothesis

[tex]\mathbf{H_o: \mu = 4.2} \\ \\ \mathbf{H_a: \mu \ne 4.2}[/tex]

This is a two-tailed test.

The test statistics can be computed as:

[tex]Z = \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}}[/tex]

[tex]Z = \dfrac{4.1 - 4.2 }{\dfrac{0.6}{\sqrt{290}}}[/tex]

[tex]Z = \dfrac{-0.1 }{\dfrac{0.6}{\sqrt{290}}}[/tex]

Z = -2.838

P-value = P(Z> 2.838)

P-value = P(Z< -2.838) +P(Z > 2.838)

P-value = 0.00227 + (1 - 0.9977)

P-value = 0.00457

P-value = 0.0046      (to 4 decimal places)

Answer:

the answer is 0

Step-by-step explanation:

hoped I helped:)

Answer: 2 1/2

Step-by-step explanation:

Answer:

The​ y-intercept is 663 and the slope is 13.56.Thus, the equation for the trend line is y = 13.56x + 663

Step-by-step explanation:

After one​ hour, her altitude will be

1476.60 feet above sea level.                  that was only if u get a part b

Answer:

Step-by-step explanation:

Dorința de a mă juca este mare.

de a (mă) juca - atribut verbal (care dorință?) exprimat prin verb la modul infinitiv;

Avea aerul a nu înțelege.

a nu înțelege - atribut verbal (ce fel de aer?) exprimat prin verb la modul infinitiv;

El dovedise un curaj de invidiat.

de invidiat - atribut verbal (ce fel de curaj?), exprimat prin verb la modul supin.

Casele aveau coșuri fumegânde.

fumegânde - atribut adjectival, exprimat prin verb la gerunziu acordat (cu valoare adjectivală)

Nevoia de a o lua din de a o lua dinloc din cauza frigului era mare.

de a o lua din loc - atribut verbal, exprimat prin locuțiune verbală la modul infinitiv;

A lipi bileţele pe un frigider este un mijloc de adus aminte.

de adus aminte - atribut verbal, exprimat prin locuțiune verbală la modul supin;

Fata ținând nasul pe sus a alunecat pe gheață.

ținând nasul pe sus - atribut verbal, exprimat prin locuțiune verbală la modul gerunziu (neacordat);

Blocul de acolo este înalt.

de acolo - atribut adverbial, exprimat prin adverb de loc;

Trezitul devreme nu-mi place.

devreme - atribut adverbial, exprimat prin adverb de timp;

Mersul de colo până colo l-a obosit.

de colo până colo - atribut adverbial exprimat prin locuțiune adverbială;

E o vreme brrr!

brrr - atribut interjecțional, exprimat prin interjecție.

Answer: I would believe all you have to do is round up making the number 658 lad :)

Step-by-step explanation:

Have a good day :)

Stay safe and stay awesome :D