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An estimate for the mean is 47.6 kg.

In Mathematics and Geometry, the mean for this set of data can be calculated by using the following formula:

Mean = [F(x)]/n

Cumulative frequency = 10 + 7 + 2 + 8 + 3

Cumulative frequency = 30

For the total number of data based on the frequency, we have;

Total weight, F(x) = 10(40) + 7(52.5) + 2(65) + 8(77.5) + 3(90)

Total weight, F(x) = 40 + 367.5 + 130 + 620 + 270

Total weight, F(x) = 1427.5

Now, we can calculate the mean weight as follows;

Mean = 1427.5/30

Mean = 47.6 kg.

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The systematic sample would be A. The city manager takes a list of the residents and selects every 6th resident until 54 residents are selected.

The random sample would be C. The botanist assigns each plant a different number. Using a random number table, he draws 80 of those numbers at random. Then, he selects the plants assigned to the drawn numbers. Every set of 80 plants is equally likely to be drawn using the random number table.

The cluster sample is C. The host forms groups of 13 passengers based on the passengers' ages. Then, he randomly chooses 6 groups and selects all of the passengers in these groups.

A systematic sample involves selecting items from a larger population at uniform intervals. A random sample involves selecting items such that every individual item has an equal chance of being chosen.

A cluster sample involves dividing the population into distinct groups (clusters), then selecting entire clusters for inclusion in the sample.

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What is needed to be congruent to show that ABC=AXYZ is AC ≅ XZ. option D

Given that in ΔABC and ΔXYZ, ∠X ≅ ∠A and ∠Z ≅ ∠C.

We are to select the correct condition that we will need to show that the triangles ABC and XYZ are congruent to each other by ASA rule..

ASA Congruence Theorem: Two triangles are said to be congruent if two angles and the side lying between them of one triangle are congruent to the corresponding two angles and the side between them of the second triangle.

In ΔABC, side between ∠A and ∠C is AC,

in ΔXYZ, side between ∠X and ∠Z is XZ.

Therefore, for the triangles to be congruent by ASA rule, we must have AC ≅ XZ.

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The shape is represented as below

The figure is of three shapes, the firs two are whole numbers then the last is a fraction.

Adding them results to

shape 1 + shape 2 + shape 3

1 + 1 + 1/4

As one fraction

= 9/4

as a mixed number

= 2 1/4

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The step length 'a' for the line search method at point x(k) = (1, -1) with the descent direction PL = (1, 0) is 0.5.

To compute the step length 'a' using the line search method, we can follow these steps:

1: Calculate the gradient at point x(k).

  - Given x(k) = (1, -1)

  - Compute the gradient ∇f(x₁,x₂) at x(k):

    ∇f(x₁,x₂) = (∂f/∂x₁, ∂f/∂x₂)

    ∂f/∂x₁ = 3x₁ + 1

    ∂f/∂x₂ = 2x₂ - 1

    Substituting x(k) = (1, -1):

    ∂f/∂x₁ = 3(1) + 1 = 4

    ∂f/∂x₂ = 2(-1) - 1 = -3

  - Gradient at x(k): ∇f(x(k)) = (4, -3)

2: Compute the dot product between the gradient and the descent direction.

  - Given PL = (1, 0)

  - Dot product: ∇f(x(k)) ⋅ PL = (4)(1) + (-3)(0) = 4

3: Compute the norm of the descent direction.

  - Norm of PL: ||PL|| = √(1² + 0²) = √1 = 1

4: Calculate the step length 'a'.

  - Step length formula: a = -∇f(x(k)) ⋅ PL / ||PL||²

    a = -4 / (1²) = -4 / 1 = -4

5: Take the absolute value of 'a' to ensure a positive step length.

  - Absolute value: |a| = |-4| = 4

6: Finalize the step length.

  - The step length 'a' is the positive value of |-4|, which is 4.

Therefore, the step length 'a' for the line search method at point x(k) = (1, -1) with the descent direction PL = (1, 0) is 4.

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Answer: D. 145°

Step-by-step explanation:

Since it is a parallelogram given by the symbol, then angle B is equal to angle D which is 145°.

The total number of times the digit "9" would have been written to number the entire photo album is 12 + 9 = 21 times.

To determine how many times the digit "9" would have been written to number all the pages of the photo album, we need to analyze the numbering pattern.

Since the album has 108 pages, we can observe that the numbers 1 to 9 are repeated 12 times (1-9, 10-19, 20-29, ..., 90-99) to cover the first 99 pages. Each repetition consists of ten numbers, and the digit "9" appears once in each repetition.

So, the digit "9" would have been written 12 times for the numbers 9, 19, 29, ..., 89 and 99.

However, we have an additional 9 pages to consider, which are 100, 101, 102, ..., 108. Each of these pages contains a single "9" in its numbering.

Therefore, the total number of times the digit "9" would have been written to number the entire photo album is 12 + 9 = 21 times.

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Answer:

a. Y(t) = At³ + Be^t + Ct² + Dt + E

b. Y(t) = At + B + Ce^t + Dsin(t) + Ecos(t)

c. Y(t) = Aet + Bte^t + Csin(t) + Dcos(t)

d. Y(t) = At³ + Bt² + Ct + D + Ecos(2t) + Fsin(2t)

e. Y(t) = At² + Bt + C + Dsin(t) + Ecos(t) + Fsin(t) + Gcos(t)

f. Y(t) = Aet + Bte^-t + Ccos(t) + Dsin(t) + E + Ft + G

Answer: Therefore, the perimeter of the soccer field is 332 meters.

Step-by-step explanation:

To determine the perimeter of a soccer field with a length of 97 meters and a width of 69 meters, we can use the formula for the perimeter of a rectangle, which is given by:

Perimeter = 2 * (length + width)

Plugging in the values, we have:

Perimeter = 2 * (97 + 69)

Perimeter = 2 * 166

Perimeter = 332 meters

The computed mean of 52.4 and the actual mean of 52.7 suggest a close relationship in terms of central tendency.

A computed mean is a statistical measure calculated by summing up a set of values and dividing by the number of observations. In this case, the computed mean of 52.4 implies that when the values are averaged, the result is 52.4.

The actual mean of 52.7 refers to the true average of the population or data set being analyzed. Since it is higher than the computed mean, it indicates that the sample used for computation might have slightly underestimated the true population mean.

However, the difference between the computed mean and the actual mean is relatively small, with only a 0.3 unit discrepancy.

Given the proximity of these two values, it suggests that the computed mean is a reasonably accurate estimate of the actual mean.

However, it's important to note that without additional information, such as the sample size or the variability of the data, it is difficult to draw definitive conclusions about the relationship between the computed mean and the actual mean.

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To solve this problem, we can set up a system of equations based on the given information.

Let's assume the amount of money Ralph Chase will receive through the short-term note is represented by "x" and the amount through the long-term note is represented by "y".

According to the problem, the total amount Ralph plans to sell the property for is $145,000. Therefore, we have the equation:

[tex]\displaystyle x+y=145000[/tex] ...(1)

Now let's consider the interest paid annually. The interest paid on the short-term note at 10% is calculated as [tex]\displaystyle 0.10x[/tex], and the interest paid on the long-term note at 8% is [tex]\displaystyle 0.08y[/tex]. The total annual interest paid is given as $13,100. Therefore, we have the equation:

[tex]\displaystyle 0.10x+0.08y=13100[/tex] ...(2)

We now have a system of two equations (1) and (2). We can solve this system to find the values of "x" and "y".

Multiplying equation (2) by 100 to eliminate decimals, we get:

[tex]\displaystyle 10x+8y=1310000[/tex] ...(3)

Now we can solve equations (1) and (3) simultaneously using any method such as substitution or elimination.

Multiplying equation (1) by 10, we get:

[tex]\displaystyle 10x+10y=1450000[/tex] ...(4)

Subtracting equation (3) from equation (4), we can eliminate "x" and solve for "y":

[tex]\displaystyle 2y=140000[/tex]

Dividing both sides by 2, we find:

[tex]\displaystyle y=70000[/tex]

Now substituting the value of "y" back into equation (1), we can solve for "x":

[tex]\displaystyle x+70000=145000[/tex]

Subtracting 70000 from both sides, we have:

[tex]\displaystyle x=75000[/tex]

Therefore, the amount of money Ralph Chase will receive through the short-term note is 75,000 and through the long-term note is $70,000.

The solution to the system of equations using the inverse matrix method is x = -1, y = 2, z = 3.

To solve the system of equations using the inverse matrix method, we need to represent the system in matrix form.

The given system of equations can be written as:

| 5 -4 1 | | x | = | 12 |

| 1 7 -1 | [tex]\times[/tex]| y | = | -9 |

| 2 3 3 | | z | | 8 |

Let's denote the coefficient matrix on the left side as A, the variable matrix as X, and the constant matrix as B.

Then the equation can be written as AX = B.

Now, to solve for X, we need to find the inverse of matrix A.

If A is invertible, we can calculate X as [tex]X = A^{(-1)} \times B.[/tex]

To find the inverse of matrix A, we can use the formula:

[tex]A^{(-1)} = (1 / det(A)) \times adj(A)[/tex]

Where det(A) is the determinant of A and adj(A) is the adjugate of A.

Calculating the determinant of A:

[tex]det(A) = 5 \times (7 \times 3 - (-1) \times 3) - (-4) \times (1 \times 3 - (-1) \times 2) + 1 \times (1 \times (-1) - 7\times 2)[/tex]

= 15 + 10 + (-13)

= 12.

Next, we need to find the adjugate of A, which is obtained by taking the transpose of the cofactor matrix of A.

Cofactor matrix of A:

| (73-(-1)3) -(13-(-1)2) (1(-1)-72) |

| (-(53-(-1)2) (53-12) (5[tex]\times[/tex] (-1)-(-1)2) |

| ((5(-1)-72) (-(5(-1)-12) (57-(-1)[tex]\times[/tex](-1)) |

Transpose of the cofactor matrix:

| 20 -7 -19 |

| 13 13 -3 |

| -19 13 36 |

Finally, we can calculate the inverse of A:

A^(-1) = (1 / det(A)) [tex]\times[/tex] adj(A)

= (1 / 12) [tex]\times[/tex] | 20 -7 -19 |

| 13 13 -3 |

| -19 13 36 |

Multiplying[tex]A^{(-1)[/tex] with B, we can solve for X:

[tex]X = A^{(-1)}\times B[/tex]

= | 20 -7 -19 | | 12 |

| 13 13 -3 | [tex]\times[/tex] | -9 |

| -19 13 36 | | 8 |

Performing the matrix multiplication, we can find the values of x, y, and z.

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The exact circumferences of the inscribed and circumscribed circles for the given polygons are 8π cm and 15π cm, respectively.

To find the exact circumference of a circle inscribed or circumscribed by a polygon, we can use the Pythagorean theorem to determine the diameter of the circle.

In the case of an inscribed polygon, the diameter of the circle is equal to the diagonal of the polygon. Let's consider the polygon with a diagonal of 8 cm. If we draw a line connecting two non-adjacent vertices of the polygon, we get a diagonal that represents the diameter of the inscribed circle.

Using the Pythagorean theorem, we can find the length of this diagonal. Let's assume the sides of the polygon are a and b. Then the diagonal can be found using the equation: diagonal^2 = a^2 + b^2. Substituting the given values, we have 8^2 = a^2 + b^2. Solving this equation, we find that a^2 + b^2 = 64.

For the circumscribed polygon with a diagonal of 15 cm, the diameter of the circle is equal to the longest side of the polygon. Let's assume the longest side of the polygon is c. Therefore, the diameter of the circumscribed circle is 15 cm.

Once we have determined the diameter of the circle, we can calculate its circumference using the formula C = πd, where C is the circumference and d is the diameter.

For the inscribed circle, the circumference would be C = π(8) = 8π cm.

For the circumscribed circle, the circumference would be C = π(15) = 15π cm.

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Answer:

x = 2

Step-by-step explanation:

We are given the following equation:

[tex]\sqrt{x+7} -1=x[/tex], which we want to solve for x.

To do this, we should isolate the square root on one side, then square both sides. We can then solve the equation as normal, but then we have to check the domain in the end for any extraneous solutions.

Start by adding 1 to both sides.

[tex]\sqrt{x+7} -1=x[/tex]

            +1      +1

________________________

[tex]\sqrt{x+7} = x+1[/tex]

Now, square both sides.

[tex](\sqrt{x+7} )^2= (x+1)^2[/tex]

We get:

x + 7 = x² + 2x + 1

Subtract x + 7 from both sides.

x + 7 = x² + 2x + 1

-(x+7)   -(x+7)

________________________

0 = x² + x - 6

This can be factored to become:

0 = (x+3)(x-2)

Solve:

x+3 = 0

x = -3

x-2 = 0

x = 2

We get x = -3 and x = 2. However, we must check the domain.

Substitute -3 as x and 2 as x into the original equation.

We get:

[tex]\sqrt{-3+7} -1 = -3[/tex]

[tex]\sqrt{4} -1 = -3[/tex]

2 - 1 = -3

-1 = -3

This is an untrue statement, so x = -3 is an extraneous solution.

We also get:

[tex]\sqrt{2+7} -1 = 2[/tex]

[tex]\sqrt{9}-1=2[/tex]

3 - 1 = 2

2 = 2

This is a true statement, so x = 2 is a real solution.

Our only answer is x = 2.

The equation for Harry's hunger in terms of time can be written as,H(t) = 7.5.cos(π.t) + 22.5

Given:Hunger of Harry as a function of time,H(t)H(t) can be modeled by a sinusoidal expression of the form,a⋅cos(b⋅t)+da⋅cos(b⋅t)+d, where Harry wakes up at t=0t=0t=0, his hunger is at a maximum, and he desires 30 kg 30 kg30, start text, space, k, g, end text of pigs.

Within 2 22 hours, his hunger subsides to its minimum, when he only desires 15 kg 15 kg15, start text, space, k, g, end text of pigs.

Therefore, the equation of the form for H(t)H(t) will be,H(t) = A.cos(B.t) + C where, A is the amplitude B is the frequency (number of cycles per unit time)C is the vertical shift (or phase shift)

Thus, the maximum and minimum hunger of Harry can be represented as,When t=0t=0t=0, Harry's hunger is at maximum, i.e., H(0)=30kgH(0)=30kg30, start text, space, k, g, end text.

When t=2t=2t=2, Harry's hunger is at the minimum, i.e., H(2)=15kgH(2)=15kg15, start text, space, k, g, end text.

According to the given formula,

H(t) = a.cos(b.t) + d ------(1)Where a is the amplitude, b is the angular frequency, d is the vertical shift.To find the value of a, subtract the minimum value from the maximum value.a = (Hmax - Hmin)/2= (30 - 15)/2= 15/2 = 7.5To find the value of b, we will use the formula,b = 2π/period = 2π/(time for one cycle)The time for one cycle is (2 - 0) = 2 hours.

As Harry's hunger cycle is a sinusoidal wave, it is periodic over a cycle of 2 hours.

Therefore, the angular frequency,b = 2π/2= π

Therefore, the equation for Harry's hunger in terms of time can be written as,H(t) = 7.5.cos(π.t) + 22.5

Answer: H(t) = 7.5.cos(π.t) + 22.5.

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Comparing the characteristics of the two functions, we can conclude that the graph of g(x) = -2² is a reflection of the graph of f(x) = 3x² over the x-axis (option C).

The given functions are f(x) = 3x² and g(x) = -2².

To understand the difference between their graphs, let's examine the characteristics of each function individually:

Function f(x) = 3x²:

The coefficient of x² is positive (3), indicating an upward-opening parabola.

The graph of f(x) will be symmetric with respect to the y-axis, as any change in x will result in the same y-value due to the squaring of x.

The vertex of the parabola will be at the origin (0, 0) since there are no additional terms affecting the position of the graph.

Function g(x) = -2²:

The coefficient of x² is negative (-2), indicating a downward-opening parabola.

The negative sign will reflect the graph of f(x) across the x-axis, resulting in a vertical flip.

The vertex of the parabola will also be at the origin (0, 0) due to the absence of additional terms.

Comparing the characteristics of the two functions, we can conclude that the graph of g(x) = -2² is a reflection of the graph of f(x) = 3x² over the x-axis (option C). This means that g(x) is obtained by taking the graph of f(x) and flipping it vertically. The reflection occurs over the x-axis, causing the parabola to open downward instead of upward.

Therefore, the correct answer is option C: g(x) is a reflection of f(x) over the x-axis.

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Approximately 76.5% of the student body at Walton High School loves math.

To determine the percentage of the student body that loves math, we need to consider the proportions of males and females in the Walton High School student body and their respective percentages of loving math.

Given that 45% of the student body are males, we can deduce that 55% are females (since the total percentage must add up to 100%). Now let's calculate the percentage of the student body that loves math:

For the females:

55% of the student body are females.

90% of the females love math.

So, the percentage of females who love math is 55% * 90% = 49.5% of the student body.

For the males:

45% of the student body are males.

60% of the males love math.

So, the percentage of males who love math is 45% * 60% = 27% of the student body.

To find the total percentage of the student body that loves math, we add the percentages of females who love math and males who love math:

49.5% + 27% = 76.5%

As a result, 76.5% of Walton High School's student body enjoys maths.

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When 2 items are selected without replacement from a population of 6 items, there are 15 possible samples that can be formed. Option A.

To determine the number of possible samples when 2 items are selected at random without replacement from a population of 6 items, we can use the concept of combinations.

The number of combinations of selecting k items from a set of n items is given by the formula C(n, k) = n! / (k! * (n-k)!), where n! represents the factorial of n.

In this case, we have a population of 6 items and we want to select 2 items. Therefore, the number of possible samples can be calculated as:

C(6, 2) = 6! / (2! * (6-2)!) = 6! / (2! * 4!) = (6 * 5 * 4!) / (2! * 4!) = (6 * 5) / (2 * 1) = 15. Option A is correct.

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Answer:

$3606.44

Step-by-step explanation:

The question asks us to calculate the principal amount that needs to be invested in order to earn an interest of $6180 in 28 years at an annual interest rate of 6.12%.

To do this, we need to use the formula for simple interest:

[tex]\boxed{I = \frac{P \times R \times T}{100}}[/tex],

where:

I = interest earned

P = principal invested

R = annual interest rate

T = time

By substituting the known values into the formula above and then solving for P, we can calculate the amount that James needs to invest:

[tex]6180 = \frac{P \times 6.12 \times 28}{100}[/tex]

⇒ [tex]6180 \times 100 = P \times 171.36[/tex]     [Multiplying both sides by 100]

⇒ [tex]P = \frac{6180 \times 100}{171.36}[/tex]    [Dividing both sides of the equation by 171.36]

⇒ [tex]P = \bf 3606.44[/tex]

Therefore, James needs to invest $3606.44.

Answer:

x = 11.5

Step-by-step explanation:

using the sine ratio in the right triangle

sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{x}{23}[/tex] ( multiply both sides by 23 )

23 × sin30° = x , then

x = 11.5

The central angles for the categories with the numbers 40, 100, 50, and 50 are 60 degrees, 150 degrees, 75 degrees, and 75 degrees, respectively.

To calculate the central angles for each category based on the given numbers 40, 100, 50, and 50, we need to find the proportion of each value to the total sum of all the values. Let's proceed with the following steps:

Step 1: Calculate the total sum of the given numbers: 40 + 100 + 50 + 50 = 240.

Step 2: Find the proportion of each value by dividing it by the total sum and multiplying it by 360 (since a full circle has 360 degrees).

Central angle for the first category: (40/240) * 360 = 60 degrees.

Central angle for the second category: (100/240) * 360 = 150 degrees.

Central angle for the third category: (50/240) * 360 = 75 degrees.

Central angle for the fourth category: (50/240) * 360 = 75 degrees.

The central angles for each category based on the given numbers are 60 degrees, 150 degrees, 75 degrees, and 75 degrees, respectively.

These central angles represent the relative proportions of each category's spending in relation to the total spending. They can be used to create a pie chart or visualize the distribution of expenses in a circular graph.

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Note the search engine cannot find the complete question

Alonso spent all of his money, this confirms that he can buy 3 bags of avocados.

Alonso has $21.00 to spend on eggs and avocados. He buys eggs that cost $2.50, which leaves him with $18.50. Since the store only sells avocados in bags of 3, he will need to find the cost per bag in order to calculate how many bags he can buy.

First, divide the cost of 3 avocados by 3 to find the cost per avocado. $5.00 ÷ 3 = $1.67 per avocado.

Next, divide the money Alonso has left by the cost per avocado to find how many avocados he can buy.

$18.50 ÷ $1.67 per avocado = 11.08 avocados.

Since avocados only come in bags of 3, Alonso needs to round down to the nearest whole bag. He can buy 11 avocados, which is 3.67 bags.

Thus, he will buy 3 bags of avocados.Let's test our answer to make sure that Alonso has spent all his money:

$2.50 for eggs3 bags of avocados for $5.00 per bag, which is 9 bags of avocados altogether. 9 bags × $5.00 per bag = $45.00 spent on avocados.

Total spent:

$2.50 + $45.00 = $47.50

Total money had:

$21.00

Remaining money:

$0.00

Since Alonso spent all of his money, this confirms that he can buy 3 bags of avocados.

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Answer: the answer is (3,-2)

Step-by-step explanation: when you rotate a point about the origin 180 degrees clockwise, (x,y) turns into (-x,-y)

therefore

(-3,2) becomes (3,-2)

I'm pretty sure

Julio bought clothes for $5000 with a 20% down payment, which amounts to $1000. Hence, he ends up paying $4000 for the clothes.

Julio's clothing purchase involved a total cost of $5000. To secure the purchase, he made a down payment of 20% of the total cost. To calculate the down payment, we multiply the total cost by the down payment percentage:

Down payment = 20% * $5000

Down payment = 0.20 * $5000

Down payment = $1000

The down payment amount is $1000. To determine the final amount that Julio ends up paying for the clothes, we need to subtract the down payment from the total cost:

Total cost - Down payment = $5000 - $1000

Total cost - Down payment = $4000

Therefore, Julio ends up paying $4000 for the clothes.

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The question probable may be:

Julio bought clothes for a cost of $5000, for which he left a 20% down payment. How much money does he end up paying for the clothes?

The equation of the ellipse with foci (7, 17) and (7, -13), and a major axis of length 34 is[tex](x^2/289) + (y^2/225) = 1.[/tex]

To determine the equation of an ellipse given its foci and the length of its major axis, we need to use the standard form equation for an ellipse. The standard form equation for an ellipse centered at the origin is:

[tex](x^2/a^2) + (y^2/b^2) = 1[/tex]

where 'a' represents the semi-major axis and 'b' represents the semi-minor axis.

In this case, we know that the distance between the foci is equal to 2a, which means a = 34/2 = 17. The foci of the ellipse are given as (7, 17) and (7, -13). The foci lie on the major axis of the ellipse, and since their y-coordinates differ by 30 (17 - (-13) = 30), the length of the major axis is equal to 2b, which means b = 30/2 = 15.

Now we have the values of a and b, so we can substitute them into the standard form equation:

[tex](x^2/17^2) + (y^2/15^2) = 1[/tex]

Simplifying further, we have:

[tex](x^2/289) + (y^2/225) = 1[/tex]

Therefore, the equation of the ellipse with foci (7, 17) and (7, -13), and a major axis of length 34 is:

[tex](x^2/289) + (y^2/225) = 1.[/tex]

This equation represents an ellipse centered at the point (0, 0) with a semi-major axis of length 17 and a semi-minor axis of length 15.

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Answer:

The equation of the ellipse with foci (7, 17) and (7, -13), and a major axis of length 34 is

To determine the equation of an ellipse given its foci and the length of its major axis, we need to use the standard form equation for an ellipse. The standard form equation for an ellipse centered at the origin is:

where 'a' represents the semi-major axis and 'b' represents the semi-minor axis.

In this case, we know that the distance between the foci is equal to 2a, which means a = 34/2 = 17. The foci of the ellipse are given as (7, 17) and (7, -13). The foci lie on the major axis of the ellipse, and since their y-coordinates differ by 30 (17 - (-13) = 30), the length of the major axis is equal to 2b, which means b = 30/2 = 15.

Now we have the values of a and b, so we can substitute them into the standard form equation:

Simplifying further, we have:

Therefore, the equation of the ellipse with foci (7, 17) and (7, -13), and a major axis of length 34 is:

This equation represents an ellipse centered at the point (0, 0) with a semi-major axis of length 17 and a semi-minor axis of length 15.

Answer:A

Step-by-step explanation:the graph shows the values that are greater than 2

(a) 58 = 2(w + 5 + w)

(b)  I. The width of the rectangle is 12 cm.

II. The length of the rectangle is 17 cm.

III. The area of the rectangle is 204 cm².

Let's solve the problem step by step:

(a) To write an equation for the perimeter of the rectangle, we know that the perimeter is the sum of all four sides. Let's denote the width of the rectangle as "w" (in cm). Given that the length is 5 cm more than the width, the length would be "w + 5" (in cm). The formula for the perimeter is:

Perimeter = 2(length + width)

Substituting the values, we have:

58 = 2(w + 5 + w)

Simplifying the equation, we get:

58 = 2(2w + 5)

(b) Now let's solve for the width and length of the rectangle:

I. To find the width, we solve the equation:

58 = 2(2w + 5)

Dividing both sides by 2, we get:

29 = 2w + 5

Subtracting 5 from both sides, we have:

24 = 2w

Dividing both sides by 2, we find:

w = 12 cm

Therefore, the width of the rectangle is 12 cm.

II. To find the length, we substitute the value of the width into the equation:

Length = w + 5 = 12 + 5 = 17 cm

Therefore, the length of the rectangle is 17 cm.

III. The area of the rectangle can be calculated using the formula:

Area = length × width

Substituting the values, we have:

Area = 17 cm × 12 cm = 204 cm²

Therefore, the area of the rectangle is 204 cm².

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