5. In an electric bell, electromagnet attracts________
towards itself.​

Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

Answer:

the bike

Explanation:

it has less mass than the motorcycle so so it would have more acceleration

Explanation:

Hey there!

Given that 4kg ball struck by 12 N force.

So, we need acceleration.

Force = Mass × Acceleration

And, so

Acceleration = Force / Mass.

Acceleration = 12/4

Acceleration is equal to 3m/s² in SI units.

Hope it helps :)

Answer:

Newtons 3sd law

Force = mass × acceleration

3rd photo about momentum

Answer:

(10 L)(100° C) + (90 L)(10°) = (100 L)T

1,000 + 900 = 100T

1,900 = 100T

100T = 1,900

T = 1,900/100

Explanation:

Answer:

Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface

Answer:

a) ρ = 2.33 10⁵ C / m³, b) INSULATING

Explanation:

a) For this exercise we use the important concept of density

            ρ = Q / V

The volume of a sphere is

           V = 4/3 πr3

            V = 4/3 π (1.27 10⁻²)³

            V = 8.58 10⁻⁶ m³

let's calculate

           ρ = 2 / 8.58 10⁻⁶

           ρ = 2.33 10⁵ C / m³

b) in a conductor the charges are mobile, therefore due to electoral repulsion all the charges must concentrate on the surface.

In an insulator the charges are fixed, therefore they are distributed throughout the volume

Consequently the sphere must be INSULATING

b...radio waves answer

Answer:

work done=fdcosø

f=mg=450N

d=+3m

ø=180

450×3×cos(180°) power=work done/

time taken

1350×-1 p=135watts

Answer:

177 coulomb

Explanation:

Given data

I=2.95A

T=60

The relationship between current I and quantity of charge Q.

Q=IT

Substitute

Q=2.95*60

Q=177 coulomb

Answer:

Speed = 106.67mph

Explanation:

Let the first motion be A.

Given the following data;

Speed A = 40mph

Time A = 4 hours

To find the distance covered in A;

Distance = speed * time

Distance = 40 * 4

Distance = 160 miles.

To find the speed required to cover the above distance in 1.5 hours;

Speed = distance/time

Speed = 160/1.5

Speed = 106.67mph

Answer:

the mass of object is 2000

Explanation:

don't know don't know don't know

Answer:

0.57 kg

Explanation:

We are given that

Force, F=20 N

Acceleration ,a =[tex]35m/s^2[/tex]

We have to find the mass of Aero-plane.

To find the value of mass we will divide the force by acceleration.

We know that

Force, F=ma

Using the formula

[tex]20=m\times 35[/tex]

[tex]\frac{20}{35}=m[/tex]

[tex]m=0.57 kg[/tex]

Hence, the mass of the aero-plane=0.57 kg

The velocity at the bottom : v = 8.85 m/s

Given

height of the hill = 4 m

Required

The velocity at the bottom

Solution

The law of conservation energy :

ME₁=ME₂

(PE+KE)₁ = (PE+KE)₂

initially at rest⇒vo=0⇒KE₁=0

At the bottom⇒h=0⇒PE₂=0

So the equation becomes :

PE₁=KE₂

mgh=1/2.mv²

gh = 1/2v²

[tex]\tt v=\sqrt{2gh}[/tex]

v = √2x9.8x4

v = 8.85 m/s

Answer:

The net charge on each sphere is -1.5 q

Explanation:

Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again

The given parameters of the conducting spheres meant to touch are;

The net charge on the first sphere, Q₁ = +5.0 q

The net charge on the second sphere, Q₂ = -8.0 q

The net charge on each sphere after touching and then separated, 'Q', is given as follows;

[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]

Therefore, by substituting the known values of the variables, we have;

[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]

The net charge on each sphere, Q = -1.5 q.

The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q

Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again

The given parameters of the conducting spheres meant to touch are;

The net charge on the first sphere, Q₁ = +5.0 q

The net charge on the second sphere, Q₂ = -8.0 q

The net charge on each sphere after touching and then separated, 'Q', is given as follows;

[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]

Therefore, by substituting the known values of the variables, we have;

[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]

Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q

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Answer:

IVE BEEN TRYNA FIND THE ANSWER FOR THE PAST HOUR T-T

Explanation:

Answer:

3.2 x10^11 bits of storage

Explanation:

Answer:

the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².

Explanation:

Given;

applied force, F = 5000 N

cross sectional area of the steel wire, A = 0.2 m²

The tensile stress of the steel wire, is calculated as;

[tex]\sigma = \frac{F}{A} \\\\\sigma = \frac{500}{0.2} \\\\\sigma = 2500 \ N/m^2\\\\\sigma = 2.5 \ \times \ 10^3 \ Nm^{-2}[/tex]

Therefore, the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².

Answer:

b. d. f.

Explanation:

Got it right on Edge

Answer:

2. Gina gathers information about a court case.

4. Hana interviews and advises a person who has been accused of a crime.

6. Dewayne creates the paperwork for a business contract.

Answer: C

Explanation:

The model which represents best of transverse wave with very high crests and low troughs is the third graph. Hence, option C is correct.

Sound is a physical perturbation from an equilibrium position that travels through an elastic medium of material. It is also possible to define sound solely subjectively, as that which is regarded by the ear, but this definition lacks clarity and is overly constrictive because it is useful to discuss sounds that are produced by devices other than the human ear, such as dog whistles and sonar hardware, which cannot be done here by the auditory system.

The characteristics of sound waves should be examined first in any study of sound. Transverse and longitudinal waves are the two fundamental forms of waves, and they differ by the direction wherein they move.

The first graph is uniform trough and crest, but the third one has higher crest but lower trough.

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Answer:

the value of the charge is   q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position  x= l/3

Explanation:

The forces in this system are given by Coulomb's law

           F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]

As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .

Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge

Let's find the location of charge 3 so that it is in balance

               ∑ F = F₁₃ - F₂₃ = 0

               F₁₃ = F₂₃

we seek every force

              F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]

              F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]

the distances are

              x₁₃ = x-0 = x

              x₂₃ = l -x

we substitute

              k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}

we solve

             (l-x)² = [tex]\frac{q_2}{q_1}[/tex]   x²

              l² - 2lx + x² = \frac{4q}{q} x²

              3x² + 2l x - l² = 0

we solve the quadratic equation

              x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)

              x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6

              x₁ = -l

              x₂ = l / 3

as charge 3 must be between the two charges the correct answer is

              x = l / 3

with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.

now let's analyze the force on the other charges

charge 1 so that it is in balance

           ∑F = F₁₃ - F₁₂ = 0

           F₁₃ = F₁₂

          [tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]

           l² q₃ = q₂ (l/3)²

           q₃ = q₂ / 9

            q₃ = 4q / 9

            q₃ = [tex]\frac{4}{9} q[/tex]

in summary the value of the charge is   q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q

in the position  x= l/3

Answer:

it is somewhat frozen

Explanation:

The centripetal force : F = 293.3125 N

Given

mass = 65 kg

v = 9.5 m/s

r = 20 m

Required

the centripetal force

Solution

Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle  

[tex]\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}[/tex]

F = centripetal force, N  

m = mass, Kg  

v = linear velocity, m / s  

r = radius, m  

Input the value :

F = 65 x 9.5² / 20

F = 293.3125 N

Answer:

woh its really exist?

Explanation:

cakra

F₂ = 1.723 x 10⁸ N

Given

Area of small piston : 0.004 m²

Area of large piston : 3.5 m²

Force 225 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

225/0.004 m² = F₂/3.5² m²

F₂ = 1.723 x 10⁸ N

Answer:

amplitude

Explanation:

wave is a called the crest, and the low point is called the trough. For longitudinal waves, the compressions and rarefactions are analogous to the crests and troughs of transverse waves. The distance between successive crests or troughs is called the wavelength. The height of a wave is the amplitude.…

Answer:

i. 15.6 m/s

ii. I = 1.44 KNs

Explanation:

The impulse, I, on a body is the product of force applied on it and the time it acts.

i.e I = F x t

Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.

i. mass, m, of the player = 92 kg

initial velocity of the player, u = 9.4 m/s

final velocity of the player, v = 6.2 m/s

Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.

So that,

change in velocity of the player = final velocity - initial velocity

                                          = 6.2 - (-9.4)

                                         = 6.2 + 9.4

                                         = 15.6 m/s

change in velocity of the player is 15.6 m/s

ii. Impulse, I = m(v - u)

                    = 92 x 15.6

                    = 1435.2

Impulse on the player is 1.44 KNs.