Answer:
they can asked to sue
Explanation:
bud
1 kg block slides down a frictionless inclined plane that makes an angle of 300 with respect to the ground. The total length of the plane is 2 m, but midway down it collides with a second block, weighing 0.5 kg. The two blocks stick together and travel as one unit the rest of the way down the ramp. What is the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane
Answer:
the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J
Explanation:
Given that the data in the question;
angle of inclination with respect to the ground [tex]\theta[/tex] = 30°
length of plane d = 2m
m₁ = 1 kg
m₂ = 0.5 kg
now, velocity of the first block at midpoint;
[tex]\frac{1}{2}[/tex]mv² = mgsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]
[tex]\frac{1}{2}[/tex]v² = gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]
v² = gsin[tex]\theta[/tex]d
v = √( gsin[tex]\theta[/tex]d)
g is 9.8 m/s
so we substitute
v = √( 9.8 × sin30° × 2)
v = √( 19.6 )
v = 3.13 m/s
Now, velocity just after collision of the blocks will be;
(m₁ + m₂)v₂ = m₁v
v₂ = m₁v / (m₁ + m₂)
we substitute
v₂ = (1 × 3.13) / (1 + 0.5)
v₂ = 3.13 / 1.5
v₂ = 2.0866 m/s
now, final kinetic energy will be;
[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + Initial Kinetic energy
[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + [tex]\frac{1}{2}[/tex]mv₂²
we substitute
[tex]KE_f[/tex] = [(1 + 0.5)9.8 × sin30 × [tex]\frac{2}{2}[/tex]] + [[tex]\frac{1}{2}[/tex] × 1.5 × 2.0866 ]
[tex]KE_f[/tex] = 7.35 + 3.2654
[tex]KE_f[/tex] = 10.62 J
Therefore, the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J
what happens to a neutron that is not attached to a proton?
Diana has just been diagnosed with "pre-diabetes," and her doctor has instructed her to watch her intake of sugar. This is easy at home, but this weekend she will be going to a restaurant with her family. What should she do? (1 point) Order anything on the menu labeled "sugar-free" or "fat-free." Use a phone app to check the sugar content in items or ingredients on the menu. Order something off the salad options and skip the soda or dessert. Split an entrée with a friend to reduce her calorie intake at the meal.
Answer:
sugar free
Explanation:
she should most likely take anything sugar free and avoid any bread, bread can increase your blood level as well, my mother had pre diabetes and what she did was eat salads and drink vegetable smoothies until your sugar goes down. splitting an entrée won't do anything, you technically get the same amount of sugar so at the point just eat the whole meal.
Proton traveling across a capacitor A proton enters with a velocity v between the plates of a capacitor as shown in the figure. What is the direction of the magnetic field needed so that the proton continues its trajectory, undeflected? Explain each step of your reasoning.
Answer:
Please see the direction of force in the attachment
Explanation:
As the particle enters the capacitor, it experiences electric. In order to move in the same direction as the electron was moving before entering the capacitor, the force due to the electric field of capacitor must be balanced by the magnetic field.
The direction of particle is shown in the attachment.
As we know,
Force = q (v *B)
You leave a pastry in the refrigerator on a plate and ask your roommate to take it out before youget home so you can eat it at room temperature, the way you like it. Instead, your roommateplays video games for hours. When you return, you notice that the pastry is still cold, but thegame console has become hot. Annoyed, and knowing that the pastry will not be good if it ismicrowaved, you warm up the pastry by unplugging the console and putting it in a clean trashbag (which acts as a perfect calorimeter) with the pastry on the plate. After a while, you find thatthe equilibrium temperature is a nice, warmTeq.. You know that the game console has a mass ofm1. Approximate it as having a uniform initial temperature ofT1. The pastry has a mass ofm2and a specific heat ofc2, and is at a uniform initial temperature ofT2. The plate is at the sameinitial temperature and has a mass ofm3and a specific heat ofc3. What is the specific heat ofthe console
Answer:
[tex]c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }[/tex]
Explanation:
This is a calorimeter problem where the heat released by the console is equal to the heat absorbed by the cupcake and the plate.
Q_c = Q_{abs}
where the heat is given by the expression
Q = m c_e ΔT
m₁ c_{e1) (T₁-T_{eq}) = m₂ c_{e2} (T_{eq} -T₂) + m₃ c_{e3} (T_{eq}- T₁)
note that the temperature variations have been placed so that they have been positive
They ask us for the specific heat of the console
[tex]c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }[/tex]
Select the correct answer.
Which graph shows the correct relationship between kinetic energy and speed?
Answer:
D
Explanation:
Kinetic energy = 1/2mV^2
From the formula above, we can deduce that kinetic energy is proportional to the square of speed. That is,
K.E = V^2
Graphically, the relationship isn't linear but a positive exponential. Therefore, option D is the correct answer.
Answer:
Its D
Explanation:
What is the equivalent resistance of the circuit?
Answer:
(B) 80 ohms
Explanation:
Since the circuit is a series connection, simply add the two resistances together to get 80 ohms.
an object has a velocity of 0.12 rad/s. how many revolutions will the object make after traveling for 30 seconds?
Answer:
We can write S = v * t where S is the distance traveled in time t
S = .12 rad/sec * 30 sec = 3.6 rad distance traveled
Also 2 * pi * N = S since there are 2 * pi rad / revolution
So 2 * pi * N = 3.6
N = 3.6 / (2 * pi) = .573 revolutions
What is the frequency of a wave that has a speed of 500 m/s and a wavelength of 12m?
Answer:
41.7 Hz
Explanation:
Wavelength= velocity/frequency
or
frequency= velocity/Wavelength
f=500/12
f=41.6666
f=41.7 Hz
Please like and rate. Tnks
Assertion: In electrical circuits the connecting wires are usually made of thick copper wires. Reason: Thicker wires offer higher resistance and the wires are made of copper as the electrical conductivity of copper is low
a)Both A and R are true and R is the correct explanation of A.b)Both A and R are true, and R is not the correct explanation of A.c)A is true, but R is false. d)A is false, but R is true. e)Both A and R are false.
There actually three assertions here: one in A and two more in B.
All three assertions, as well as the reasoning described in this mess, are all False.
The correct choice from the list is e), but that doesn't even describe the complete Falseness of this disaster.
1.A body of mass 10kg falling freely was found to be falling at a rat of 20m/s what force will stop the body in 2second?
Answer:
50N
Explanation:
force it is falling with can be found by mass into acceleration and then devide by half to find force that could stop it in 2 sec
Will give brainliest!!
How much KClO3 is needed to make a saturated solution in 100 mL of water at 70⁰ C?
Answer:
iam not sure but I think its NaNO3
Question 9 of 10
What happens to light as it moves at an angle into a medium that has a higher index of refraction?
A. It slows down, and the angle decreases.
B. It speeds up, and the angle increases.
C. It slows down, and the angle increases.
D. It speeds up, and the angle decreases.
Answer:
v = C / n light slows entering a medium of higher index of refraction
ni sin theta i = nr sin theta r Snell's Law where i refers to incidence and r refers to refraction
sin theta r = (ni / nr) sin theta i
So if the index of refraction is greater than the angle of incidence then the light ray would be refracted towards the normal
Answer:
A. It slows down, and the angle decreases.
Explanation:
got it right, trust
PLEASE HELP ASAP!
A machine has an efficiency of 70%. What happens to the other 30% of the work?
Answer:
The other 30% is lost from friction.
Explanation:
friction 30% ---> |O| <------ 70% work
A machine has an efficiency of 70%, and the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.
What is work done by machine?In any machine, the total work input is equal to the total work output plus any work that is lost or dissipated due to various factors such as friction, heat transfer, etc., so, for example, if a machine receives 100 units of energy as input, only 70 units of energy are converted into useful output work, and the remaining 30 units of energy are lost as waste energy.
Hence, the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.
Learn more about the work by machine here.
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A woman has one damaged fallopian tube. The damage completely blocks the opening of the tube at the ovary. How will this most likely affect her fertility?
Her likelihood of conceiving will be reduced by at least 50%.
Her eggs, if fertilized, will not implant properly.
Her eggs will not mature inside the ovary.
Her chances of conceiving twins will be doubled.
Answer:Her likelihood of conceiving will be reduced by at least 50%.
Explanation:
EDGE 2020
Answer:
Her likelihood of conceiving will be reduced by at least 50%
Explanation:
took the test on edge, got it right
Why do astronomers use frequencies other than the visible ones when they are
investigating the universe?
The density of 2 kilograms of iron on Earth's surface is
A. Zero.
B. The same on the moon.
C. Less on the moon.
D. Greater on the moon.
E. None of them
Answer:
B. The same on the moon.
Explanation:
The density of an object is the ratio of the mass contained by the object to the volume occupied by that mass.
[tex]Density = \frac{Mass}{Volume}[/tex]
When the object is taken from the earth to anywhere in the universe, its mass remains constant. The dimensions of the object and hence its volume also remains constant anywhere in the universe.
Therefore, the density of the object will also remain the same as it depends upon the mass and the volume of the object.
So, the correct option is:
B. The same on the moon.
A.) A gemstone of mass 1.8 kg compresses a scale's spring by 2.6 cm.
Determine the spring constant.
B.) How much would the spring in the previous question compress if a 5.2 kg mass was placed on the scale?
Explanation:
Given that,
Mass, m = 1.8 kg
Compression, x = 2.6 cm
We know that,
Force on spring = weight
So,
[tex]mg=kx[/tex]
Where
k is spring constant
[tex]k=\dfrac{mg}{x}\\\\k=\dfrac{1.8\times 9.8}{2.6\times 10^{-2}}\\\\k=678.46\ N/m[/tex]
(2) If m = 5.2 kg
[tex]x=\dfrac{mg}{k}\\\\x=\dfrac{1.8\times 9.8}{678.46}\\\\x=2.6 \ cm[/tex]
Hence, this is the required solution.
A wave has a frequency of 30Hz and wave length of 40cm. What is the velocity of the wave?
Answer:
12m/s
Explanation:
v=fλ
30×(40÷100)=
12m/s
A block is pulled
7.00 meters along a
horizontal
surfacewith a
constant 30.0
newton force.
Calculate the
workdone on the
block.
The work done by the force for pulling a block till 7 meter along horizontal direction by using force of 30 N is, 210 joules.
What is work ?In physics, the work is defined as product of Force in the direction motion into distance travelled.
The work done on the block is given by the formula:
Work = Force x Distance x Cos(θ)
where Force is the force applied on the block, Distance is the distance the block is moved, and θ is the angle between the force and the direction of motion.
Given that,
F = 30 N
Distance = 7 m
W = ?
The force is constant and the surface is horizontal,
so the angle θ is equal to 0°, and cos(0°) is equal to 1.
Therefore, the work done on the block can be calculated as:
Work = Force x Distance x Cos(θ)
= 30.0 N x 7.00 m x 1
= 210 J
So, the work done on the block is 210 Joules.
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When a mass is suspended from a spring the latter extends over a distance of 10cm. What will be the period of oscillations of the same system if it is placed horizontal on a frictionless surface
Answer:
0.64 s
Explanation:
It's period of oscillation (T) can be determined by,
T = 2[tex]\pi[/tex][tex]\sqrt{\frac{l}{g} }[/tex]
Where l is the length (extension on the spring), and g the acceleration due to gravity.
But,
l = 10 cm = 0.1 m
g = 9.8 m/[tex]s^{2}[/tex]
Thus,
T = 2 x [tex]\frac{22}{7}[/tex] [tex]\sqrt{\frac{0.1}{9.8} }[/tex]
= 0.6350
T = 0.64 s
The period of oscillation would be 0.64 s.
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per minute. At point 2 in the pipe, the gauge pressure is 152kPa and the cross-sectional area is 8.00cm2. At point 1, 1.35m above point 2, the cross-sectional area is 2.00cm2. Part A Find the mass flow rate. M
Answer:
[tex]1.302\ \text{kg/s}[/tex]
Explanation:
[tex]\rho[/tex] = Density of water = [tex]1\ \text{kg/L}[/tex]
[tex]dV[/tex] = Change in volume = [tex]220\times 0.355\ \text{L}[/tex]
[tex]dt[/tex] = Time elapsed = 1 minute = 60 seconds
Mass flow rate is given by
[tex]\dot{m}=\rho\dfrac{dV}{dt}\\ =1\times \dfrac{220\times 0.355}{60}\\ =1.302\ \text{kg/s}[/tex]
The mass flow rate is [tex]1.302\ \text{kg/s}[/tex].
A 67.0 kg person is riding in a car moving at 19.0 m/s when the car runs into a bridge abutment. (Assume the initial velocity is in the positive direction.) (a) Calculate the average force (in N) on the person if he is stopped by a padded dashboard that compresses an average of 1.00 cm. (Indicate the direction with the sign of your answer.) N (b) Calculate the average force (in N) on the person if he is stopped by an air bag that compresses an average of 15.0 cm. (Indicate the direction with the sign of your answer.) N
Answer:
a) F = - 1.21 10⁶ N, b) F = - 8.06 10⁴ N
Explanation:
a) For this part let's use the kinematics relations
v² = v₀² - 2 a x
distance traveled to stop is x = 1.00 cm = 0.0100 cm, final speed is zero
0 = v₀² - 2 ax
a = v₀² / 2x
a = [tex]\frac{19^2 }{2 \ 0.01}[/tex]
a = 1.81 10⁴ m / s²
this acceleration is in the opposite direction to velocity
let's use Newton's second law
F = ma
F = 67.0 (-1.81 10⁴)
F = - 1.21 10⁶ N
the negative sign indicates that it is going in the opposite direction to the speed
b) in this case it is stopped by an airbag x = 15.0 cm = 0.15 m
a = v₀² / 2x
a = [tex]\frac{19^2}{2 \ 0.15}[/tex]
a = 1.203 10³ m / s²
calculate the force
F = m a
F = 67.0 (- 1.203 10³)
F = - 8.06 10⁴ N
HELP PLEASEE
when a person receives an electric shock from wires , is he most affected by a spark, corona, arc or humus solution?
Answer:
Usually an eletric shock. You can be left with numbness and MAYBE problems with your eyes.
Explanation:
An iron wire has a length of 1.50 m and a cross sectional area of 0.450 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and a potential difference of 0.800 V is maintained across its length, determine the current in the wire (in A)
Answer:
2400A
Explanation:
R=pL/A
R-Resistance
p-Resistivity=10.0 x 10^-8
L-1.5m
A-Cross sectional Area=0.00045
R=10.0 x 10^-8 x 1.5 ÷ 0.00045
and=0.000333333
I-current
V-potential difference
I=V/R
0.800÷0.000333333
Ans=2400A
A 5kg block rests on a 30° incline. The coefficient of static friction between the block and the incline is 0.20. How large a horizontal force must push on the block if the block is to be on the verge of sliding. a) up the incline, b) down the incline ?
Answer:
Hope It Help
Explanation:
That's all I know
A molecule with a charge of 9 x 10-8 C is moving with a velocity of 7 x 107 m/s perpendicular to a magnetic field with a value of 0.57 Tesla. What is the magnitude force (in N) on the molecule?
Answer:
3.591 N
Explanation:
Applying,
F = Bvq................. Equation 1
Where F = magnitude of force on the molecule, B = Magnetic field, v = Velocity of the molecule, q = charge of the molecule.
From the question,
Given: B = 0.57 Tesla, q = 9×10⁻⁸ C, v = 7×10⁷ m/s
Substitute these values into equation 1
F = 0.57×9×10⁻⁸×7×10⁷
F = 35.91×10⁻¹
F = 3.591 N
Hence the force on the molecule is 3.591 N
Before we make measurements, let's make sure we understand the circuit. 1. Select all of the following that correctly describe what a volt meter and ammeter measure. Select all that apply: A volt meter measures the potential difference (or voltage) across a circuit element. A volt meter measures the potential difference (or voltage) passing through a circuit element. A ammeter measures the electric current passing through a circuit element. A ammeter measures the electric current across a circuit element.
Answer:
the correct answers are a and c
Explanation:
In an electrical circuit there are two important quantities to measure, such as voltage and current.
Voltage is the potential difference between two points in a circuit
current is the number of electrons you pass through a given point per unit of time.
Now let's analyze each answer
a) true. The potential difference across an element
b) False. The potential difference is u field there is no physical entity that moves
c) True. The current is electrons in motion and these pass through the given element
d) False. There is a physical quantity that passes through the point
the correct answers are a and c
the melting point and boiling point of Ice are respectively
a. 273k,373k. b. 373k,273k c.0k,100k d.100k,0k
a. 273k,373k
This is the answer.
An ideal horizontal spring-mass system is set into motion. At an instant when the mass passes through its equilibrium position: The potential energy in the spring is at its _____. The kinetic energy of the mass is at its ______. The magnitude of net force acting on the mass is at its ______.
Answer:
the potential energy is zero, and the kinetic energy must be maximum
F = 0
Explanation:
In this exercise you are asked to complete the sentences of a simple harmonic movement of a mass-spring system.
In this system mechanical energy is conserved
at the most extreme point the carousel potential energy is
K_e = ½ k x²
the kinetic energy is zero for that stopped.
At the equilibrium point
the spring elongation is x = 0 so the potential energy is zero
and the kinetic energy must be maximum since total energy of the system is conserved
the spring force is
F =- k x
as in the equilibrium position x = 0 this implies that the force is also zero
F = 0
In this exercise we have to use the knowledge of force to calculate the energy of a spring, in this way we find that:
The potential energy in the spring is at its [tex]K_e = 1/2 k x^2[/tex]. The kinetic energy of the mass is at its zero . The magnitude of net force acting on the mass is at its Zero.
In this system mechanical energy is conserved, at the most extreme point the carousel potential energy is:
[tex]K_e = 1/2 k x^2[/tex]
The kinetic energy is zero for that stopped or when at the equilibrium point, so:
the spring elongation is x = 0 so the potential energy is zero the kinetic energy must be maximum since total energy of the system is conserved
the spring force is:
[tex]F =- k x\\F=0[/tex]
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