Transverse wave is an example of mechanical wave which requires a medium Which statement BEST describes the movement of transverse waves with reference to the direction of its travel? to propagate. a. The individual particles mo ve in a circle. b. Th e individual particles move in an ellipse. c. The individual particles move parallel to the direction of ravel. d. The individual particles move perpendicular to the direction of travel.
Answer:
d) the individual particles move perpendicular to the direction of travel
Which of the following is true of a boat moving on water with
no net force acting on it?*
A. It is rising with increasing speed.
B. It is sinking with increasing speed.
C. It is traveling at a constant velocity.
D. It is accelerating forward.
[3]2] Resistors X and Y are connected in series with a 6.0 V battery of negligible intemal
resistance.
R
X has resistance R and Y has resistance > .
A voltmeter of resistance R is connected across Y.
x
6ov |
Y
h
What is the reading on the voltmeter?
[1 mark]
A00V [Le]
B15V [e]
C 3.0V [=]
D45V fe] \
Using ohm's law and the characteristics of series and parallel circuits, we find that the correct answer is B: Voltage on the voltmeter 1.5 V
given parameters
* The element X has a resistance Rₓ = R
* Element Y with resistance R_y = R / 2
* The voltmeter with internal resistance R_v = R
* Battery voltage V = 6V
* the circuit is in the diagram
To find
The Voltmeter reading.
For this exercise we use ohm's law which establishes a linear relationship between voltage and current
V = i R
Let's solve the circuit in parts:
1 part. We reduce the part in parallel, finding its equivalent resistance
R_ {eq1}
The equivalent resistance between Y element and the voltmeter that is in parallel, therefore their equivalent resistance is
[tex]\frac{1}{R_{eq1} } = \frac{1}{R_y} + \frac{1}{R_v}[/tex]
[tex]\frac{1}{R_{eq1} }= \frac{1}{\frac{R}{2} } + \frac{1}{R} = \frac{3}{R}[/tex]
[tex]R_{eq1} = \frac{R}{3}[/tex]
Now element X and this equivalent resistance are in series ( see attached), so the equivalent resistance of the entire circuit is
R_{eq} = Rₓ + R_{eq1}
we substitute
R_{eq} = [tex]R + \frac{R}{3} = \frac{4}{3} \ R[/tex]
2 part. We look for the current of the circuit, usin the ohm's Law
V = i R_{eq}
i = [tex]\frac{V}{R_{eq} }[/tex]
i = [tex]\frac{6}{\frac{4R}{3} } = \frac{18}{4R}[/tex]
i = 4.5 / R
In a series circuit the current is constant and the total voltage is the sum voltage of each element, so the voltage in the parallel R_{eq1}
V₂ = I R_{eq1}
V₂ = [tex]\frac{4.5}{R} \ \frac{R}{3}[/tex]4.5 / R R / 3
V₂ = 1.5 V
3 part. The voltmeter and the Y element are in parallel, so the voltage in the two elects is the same, consequently the voltage of the voltmeter (V_v)
V_v = V₂ = 1.5 V
Using ohm's law and the properties of series and parellel circuits we find the voltage across the voltmeter
V_v = 1.5 V
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PLEASE HELP MEE PLEASE!
Answer:
Answer C. gramsExplanation:
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The diagram shows four locations in the electric field of a positive point charge.
A positively charged particle has vectors perpendicular to the surface and pointing laterally outward. The vectors farther from the surface are shorter. There are 4 dots to the right of the positively charged particle. The closest to the particle is labeled W and the particles further away are labeled X, Y and Z.
At which point is the electric potential the greatest?
W
X
Y
Z
Answer:
W
Explanation:
The closer you get to the center of the positive point of the electrical feild the stronger the pull gets. Therfore W is the best option.
Answer:
W
Explanation:
The closer you get to the center of the positive point of the electrical feild the stronger the pull gets. Therfore W is the best option.
how does gravity affect objects of different mass close to earth, and how does that effect change as an object moves farther from earth?
Answer:
It makes it lighter when its closer and heavier when its farther way.
Explanation:
Which point has more gravitational potential energy?
How is the energy changing in the picture
A transformer is designed to provide 6 V from a 150 V supply. If the primary coil has 1000 turns, how many turns does the secondary one have?
A roller coaster does a loop de loop at 35 m/s, with a radius of 32 meters. What is the
acceleration?
Answer:
The answer to the question is:
[tex]38.28 m {s}^{ - 2} [/tex]
The acceleration of the roller coaster is 38.28 m/s.
What is centripetal acceleration?
Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
Given that: the speed of the roller coaster: v = 35 m/s.
Radius of the loop: r = 32 meter.
Centripetal acceleration of the roller coaster = speed²/radius
= (35×35)/32 m/s²
= 38.28 m/s².
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Types of telescope
for Space
observation
Answer:The three main types are reflecting telescopes, refracting telescopes, and catadioptric telescopes. Radio telescopes collect and focus radio waves from distant objects. Space telescopes orbit Earth, collecting wavelengths of light that are normally blocked by the atmosphere.
Answer:
oii me manda mensagem fofo vc tem namorada fofo
A uniform ladder of length 10.8 m is leaning against a vertical frictionless wall. The weight of the ladder is 323 N, and it makes an angle of 1.16 radians with the floor. A man weighing 734 N climbs slowly up the ladder. When he has climbed to a point that is 7.46 m from the base of the ladder (measured along the ladder), the ladder starts to slip. Find the coefficient of static friction between the floor and the ladder.
Answer:
0.3625
Explanation:
From the given information:
Consider the equilibrium conditions;
On the ladder, net torque= 0
Thus,
[tex]\tau_{net} = 0[/tex]; and
[tex]-fL \s in \theta +m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta = 0[/tex]
However, by rearrangement;
[tex]fL \s in \theta =m_L g \dfrac{L}{2} cos \theta + mg (7.46\ m) cos \theta \\ \\ \mu(m_L + m) gL \ sin \theta = (323 \ N) ( 10.8 \ meters) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0[/tex]
[tex]\mu= \dfrac{ (323 \ N) ( 10.8 \ m) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0}{\Big [(323 \ N)+(734 \ N) \Big] (10.8 \ m)}[/tex]
[tex]\mathbf{\mu= 0.3625 }[/tex]
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Part A
What is the magnitude of the momentum of a 2500 kg
k
g
car traveling at 11 m/s
m
/
s
?
Express your answer to two significant figures and include the appropriate units.
Part B
What is the magnitude of the momentum of a 200 g
g
baseball thrown at 32 m/s
m
/
s
?
Express your answer to two significant figures and include the appropriate units.
Answer:
A) 28000kgm/s
B) 6.40kgm/s
Explanation:
Momentum = mass * velocity of a body
A) Given
mass m = 2500kg
velocity v = 11m/s
Substitute
Momentum = 2500 * 11
Momentum = 27500kgm/s
Momentum = 28000kgm/s (to 2 sf)
B) Given
mass m = 200g = 0.2kg
velocity v = 32m/s
Substitute
Momentum = 0.2 * 32
Momentum = 6.4kgm/s
Momentum = 6.40kgm/s (to 2 sf)
What is the answer to this?
Answer:
B
Explanation:
Answer:
B
Explanation:
6. A barber raises his customer's chair by applying a force of 150 N to the
hydraulic piston of area 0.01 m2. If the chair is attached to a piston with an
area of 0.1 m², how much force is needed to raise the customer?
STEP 1: List the known
and unknown values F =
A=
A,
STEP 2: Write the
correct equation
STEP 3: Insert the
known values into the
equation to solve for
the unknown value
Answer:
15N
Explanation:
F¹=150N
A=0.01m2²
F2=?
A2=0.1m²
P=F/A
F1/A2=F2/A1
150/0.1=F2/0.01
A transparent oil with index of refraction 1.15 spills on the surface of water (index of refraction 1.33), producing a maximum of reflection with normally incident violet light (wavelength 400 nm in air). Assuming the maximum occurs in the first order, determine the thickness of the oil slick.
Answer:
The thickness of the oil slick. t = 173.91 nm
Explanation:
Oil film thickness t is given by the equation
[tex]t = \frac{\lambda}{2n}[/tex]
where λ = wavelength of incident light in air = 400 nm
and n = index of refraction of oil
therefore,
[tex]t =\frac{400}{2\times 1.15}\\t= 173.91 nm[/tex]
The thickness of the oil slick. t = 173.91 nm
X-rays have wavelengths between 0.1 to 10 nanometers (x10-9). What is the range of its frequency?
3x1017-3x1015 Hz
3x10, 18, -3x10, 16, Hz
3x1018-3x1017 Hz
3x1017-3x1016 Hz
The environment of Ecology is made up of how many levels?
Answer:
There are 5 general layers; organism, population, community, ecosystem, and biosphere.
Explanation:
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please help me with this! i will give brainliest if you get it right! NO LINKS OR IM REPORTING
Determine the angle between the directions of vector A with rightwards arrow on top = 3.00i + 1.00j and vector B with rightwards arrow on top = -3.00i + 3.00j.
A) 117°
B) 88.1°
C) 26.6°
D) 30.0°
E) 45.2°
Answer:
C) 26.6
Explanation:
I don't know how to calculate vector
The angle between the two vectors is 117⁰
The given parameters;
vector A = 3.00i + 1.00j
vector B = -3.00i + 3.00j
The angle between the two vectors is calculated as follows;
[tex]cos \ \theta = \frac{A\ . \ B}{|A| \ . \ |B|}[/tex]
The dot product of vector A and B is calculated as;
[tex]A \ . \ B = (3i \ + j) \ . \ (-3i \ + 3j) = (3\times -3) + (1 \times 3) = -9 + 3 =- 6[/tex]
The magnitude of vector A and B is calculated as;
[tex]|A| = \sqrt{3^2 + 1^2} = \sqrt{10} \\\\|B| = \sqrt{(-3)^2 + (3)^2} = \sqrt{18}[/tex]
The angle between the two vectors is calculated as;
[tex]cos \ \theta = \frac{-6}{\sqrt{10} \ . \sqrt{18} } \\\\cos \ \theta = \frac{-6}{\sqrt{180} } \\\\cos \ \theta = -0.4472\\\\\theta = cos \ ^{-1} (-0.4472) \\\\\theta = 116.6^0 \approx 117^0[/tex]
Thus, the angle between the two vectors is 117⁰
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A 90-gram wire that is 1.0 m long is under tension. When a transverse wave of frequency 890 Hz travels down the wire, its wavelength is 0.10 m and its amplitude is 6.5 mm. What is the tension in the wire
Answer:
The tension will be "713 N".
Explanation:
The given values are:
Frequency,
= 890 Hz
Mass,
= 90 gm
or,
= 0.09 kg
Length of wire,
= 1.0 m
Wavelength,
= 0.10 m
The velocity will be:
= [tex]Frequency\times Wavelength[/tex]
= [tex]890\times 0.10[/tex]
= [tex]89 \ m/s[/tex]
Now,
The tension will be:
⇒ [tex]T=v^2\times \frac{M}{L}[/tex]
On substituting the values, we get
⇒ [tex]=(89)^2\times \frac{0.09}{1.0}[/tex]
⇒ [tex]=7921\times \frac{0.09}{1.0}[/tex]
⇒ [tex]=7921\times 0.09[/tex]
⇒ [tex]=713 \ N[/tex]
Calculate the workdone to stretch an elastic string by 40cm if a force of 10 newton produces an extension of 4cm in it
Answer:
Workdone = 20 Joules
Explanation:
Given the following data;
Force = 10N
Extension, e = 4cm to meters = 4/100 = 0.04 meters
Workdone extension = 40cm to meters = 40/100 = 0.4 meters
To find the work done;
First of all, we would find the spring constant using the formula;
Force = spring constant * extension
10 = spring constant * 0.04
Spring constant = 10/0.04
Spring constant = 250 N/m
Next, we find the work done;
Workdone = ½ke²
Where;
k is the spring constant.
e is the extension.
Substituting into the formula, we have;
Workdone = ½ * 250 * 0.4²
Workdone = 125 * 0.16
Workdone = 20 Joules
A positively charged particle travels horizontally northward and enters a region where a field may exist. This region may contain only a magnetic field, only an electric field, or both a magnetic field and an electric field. When the particle enters the region, the particle does not speed up or slow down, but it does deflect in the downward direction. What is correct about the field or fields within the region and provides correct reasoning?
Answer:
Only magnetic field present
Explanation:
Since, the positively charged particle does not speed up or slow down, but it does deflect in the downward direction. This means only magnetic field is present.
This is because electric field changes the velocity and magnetic field changes the direction.
The magnetic force F is given by
F = qvBsinθ
Where, q = charge magnitude, v = velocity of charge, B = strength of magnetic field. and θ =the angle between the directions of v and B.
suppose a scientist was able to construct a barometer with a liquid being twice denser than mercury, then how high would the liquid raise at standard pressure?
Answer:
............... .............
Cart 1 of mass m is traveling with speed 2vo in the +x-direction when it has an elastic collision with cart 2 of
mass 2m traveling with speed vo in the same direction.
What are the velocities of the carts after the collision?
please hurry and answer
Answer:
Explanation:
Momentum conservation
[tex]m2v_0+2mv_0=mv_1+2mv_2 \quad (1/m) \quad 4v_0=v_1+2v_2\\[/tex]
Kinetic energy conservation
[tex]\displaystyle \frac{1}{2}m(2v_0)^2+\frac{1}{2}2mv_0^2=\frac{1}{2}mv_1^2+\frac{1}{2}2mv_2^2 \quad (1/m) \quad 6v_0^2=v_1^2+2v_2^2[/tex]
Solve the system
Answer:
cart 1 of mass m is traveling with 2v0 in the +x-direction when it has an elastic collision with cart 2 of mass 2m traveling with speed v0 in the same direction.
What are the velocities of the carts after the collision?
and don't delete this
1. All living things are made of what?
2. What are the different parts of the cell that have jobs called?
3. What is the gel like material that fills the cell called?
4. What is the nucleus of the cell?
5. What organelle provides energy for the cell?
6. Where can you find ribosomes in a cell?
7. What does the cell membrane do for the cell?
8. What is the difference between genotype and phenotype?
10. Refraction occurs...
A. only with light waves
B. at any, unpredictable time
C. when a wave changes speed
D. only at a wave front
E. All of the above
Anatomy and Phys PLEASE HELP
Identify at least two STDs that are caused by different microorganisms (such as bacteria, viruses, and so on). Propose at least two ethical strategies for helping to prevent these STDs OTHER THAN abstinence and male and female condoms.
least two STDs that are caused by different microorganisms (such as bacteria, viruses, and so on). Propose at least two ethical strategies for helping to prevent these STDs OTHER THAN abstinence and male and female condoms.
Answer:
Explanation:
Chlamydia is a bacterial infection that affects the reproductive system in a myriad of nasty and invasive ways, including pain during micturition, genital discharge, and spreading to the rectum and eyes. Other than safe sex practices and abstinence, ways to prevent and treat Chlamydia are antibiotics for both partners (if they're both infected) and surgical intervention in severe cases.
Trichomoniasis is a parasitic sexually transmitted disease that infects women but can affect men during intercourse, women who are infected are more likely to suffer from pain in the vaginal area during moments including micturition and intercourse as foul-smelling discharge. The more concerning aspect of this disease is how women afflicted are more likely to give premature birth and spread the infection to the baby upon birth. Much like Chlamydia, Trichomoniasis can be prevented via safe-sex practices and abstinence, but it can also be treated by antibiotics for both sexual partners to prevent spreading it between them.
A student is giving a presentation to a class describing magnetic and electric fields in a region of space. First, the student describes what happens when there is a constant magnetic field in the region of space. Then, the student describes what happens when there is a time-dependent magnetic field in the region of space. Which of the following a correct description by the student abo what occurs when the magnetic field changes from being constant to being time dependent?
a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.
b. When the magnetic field is constant, there will be both a magnetic field and an electric field in the region of space. When the magnetic field is time dependent, there is only a magnetic field in the region of space.
с. In both situations, there will be both a magnetic field and an electric field in the region of space. In both situations, there will only be a magnetic field in the region of space. If the magnetic field is not constant over the region, then there will be both a magnetic field and an electric field in the region of space
d. In both situations there will only be a magnetic field in the region of space. If the magnetic field is not constant over the region, there will still be only a magnetic field in the region of space.
Answer:
a. When the magnetic field is constant, there is only a magnetic field in the region of space. When the magnetic field is time dependent, there will be both a magnetic field and an electric field in the region of space.
Explanation:
This is true because according to Maxwell's equation, a time dependent magnetic field produces an electric field.
When the magnetic field is constant, there is no electric field in that region of space. But, when it begins to vary, an electric field is then generated by Maxwell's equation which is given by
CurlE = -dB/dt
So, there is initially no electric field when the magnetic field is constant, but it exists when the magnetic field becomes time dependent.
So when dB/dt = 0
CurlE = 0 ⇒ E = 0
So when dB/dt ≠ 0
CurlE ≠ 0 ⇒ E ≠ 0
please help with both questions I’m giving all my points :) it’s 23 and 24
helpppppppppppppppppppppppppppp............
an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.
Answer:
0.5 m/s 2 is the acceleration
Explanation:
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