[tex]\text{Solve:}\\\\4(x-2+y)\\\\\text{Use the distributive property:}\\\\4x-8+4y\\\\\text{Since you can't simplify it any further, that'll be your answer}\\\\\boxed{4x-8+4y}[/tex]
Answer:
4x-8+4y
Explanation:
///
In a grinding operation, there is an upper specification of 3.150 in. on a dimension of a certain part after grinding. Suppose that the standard deviation of this normally distributed dimension for parts of this type ground to any particular mean dimension LaTeX: \mu\:is\:\sigma=.002 μ i s σ = .002 in. Suppose further that you desire to have no more than 3% of the parts fail to meet specifications. What is the maximum (minimum machining cost) LaTeX: \mu μ that can be used if this 3% requirement is to be met?
Answer:
Step-by-step explanation:
Let X denote the dimension of the part after grinding
X has normal distribution with standard deviation [tex]\sigma=0.002 in[/tex]
Let the mean of X be denoted by [tex]\mu[/tex]
there is an upper specification of 3.150 in. on a dimension of a certain part after grinding.
We desire to have no more than 3% of the parts fail to meet specifications.
We have to find the maximum [tex]\mu[/tex] such that can be used if this 3% requirement is to be meet
[tex]\Rightarrow P(\frac{X- \mu}{\sigma} <\frac{3.15- \mu}{\sigma} )\leq 0.03\\\\ \Rightarrow P(Z <\frac{3.15- \mu}{\sigma} )\leq 0.03\\\\ \Rightarrow P(Z <\frac{3.15- \mu}{0.002} )\leq 0.03[/tex]
We know from the Standard normal tables that
[tex]P(Z\leq -1.87)=0.0307\\\\P(Z\leq -1.88)=0.0300\\\\P(Z\leq -1.89)=0.0293[/tex]
So, the value of Z consistent with the required condition is approximately -1.88
Thus we have
[tex]\frac{3.15- \mu}{0.002} =-1.88\\\\\Rrightarrow \mu =1.88\times0.002+3.15\\\\=3.15[/tex]
A board of directors consists of 10 people, in how many ways can a chief executive officer, director, a treasurer, and a secretary be selected?
Answer:
The correct answer to the following question will be "5040".
Step-by-step explanation:
Given:
The number of directors,
n = 10
and they select on 4 peoples, then
Number of ways will be:
⇒ [tex]10_{P}_{4}[/tex]
⇒ [tex]\frac{10!}{10-4!}[/tex]
⇒ [tex]\frac{10!}{6!}[/tex]
⇒ [tex]\frac{10\times 9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1!}{6\times 5\times 4\times 3\times 2\times 1!}[/tex]
⇒ [tex]5040[/tex]
What is the solution to the equation a+5-2/3=9
Answer:
a= [tex]\frac{14}{3}[/tex]
a≈4.6
Step-by-step explanation:
a+5- [tex]\frac{2}{3}[/tex] =9
a+ [tex]\frac{15}{3} -\frac{2}{3}[/tex] =9
a+ [tex]\frac{13}{3}[/tex] =9
Subtract [tex]\frac{13}{3}[/tex] from both sides
a=[tex]\frac{14}{3}[/tex]
a≈4.6
Answer:
a
Step-by-step explanation:
Find the slope of a line perpendicular to the graph of the equation. y = –8
Answer:
undefined
Step-by-step explanation:
y = -8 is a horizontal line with a slope of zero
A line that is perpendicular is a vertical line, which has a slope of undefined
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications, which if a multiplication takes sec would take these times:
n 10 15 20 25
Time 0.004 sec 22 min 77 years 0.5.109years
Answer:
number of multiplies is n!n=10, 3.6 msn=15, 21.8 minn=20, 77.09 yrn=25, 4.9×10^8 yrStep-by-step explanation:
Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...
mpy[n] = n·mp[n-1]
mpy[2] = 2
So, ...
mpy[n] = n! . . . n ≥ 2
__
If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...
10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10
Then the larger matrices take ...
n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min
n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years
n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years
_____
For the shorter time periods (less than 100 years), we use 365.25 days per year.
For the longer time periods (more than 400 years), we use 365.2425 days per year.
A trip took you 5 hours and you traveled 283.5 miles. If you averaged 49 mph
for the first part of the trip and 60 mph for the 2nd part, how long did you drive
at each rate?
Answer:
1.5 hr and 3.5 hr
Step-by-step explanation:
Time in the first part= x
Time in the second part= 5 - x
49x+60(5-x)=283.549x+300-60x=283.511x=300-283.511x= 16.5x= 16.5/11x= 1.5 hrand5-x= 5-1.5= 3.5 hrJustin and Hayley conducted a mission to a new planet, Planet X, to study arm length. They took a random sample of 100 Planet X residents. Then they calculated a 95% confidence interval for the mean arm length.
Answer:
The correct answer is I am 95% sure that this interval includes the population mean arm length.
Note: Kindly find an attached image or copy of the complete question to this solution below:
Sources: The complete question was researched from Quizlet and Course hero sites.
Step-by-step explanation:
Solution
From the given question, i will say that I am 95 % confident interval that this interval include the population mean arm length is correct because using sample mean and confidence level we can obtain an interval which gives us the certain level of confidence that population mean is within this interval and here we are 95% confident that population mean is within this interval.
I NEED HELP WITH THIS PLEASE HELP ME
Answer:
156 minutes
Step-by-step explanation:
So we need to create an equation to represent how Frank's phone company bills him
I will denote "y" as the total for his billI will denote "x" as the number of minutes Frank usesSo the phone company charges an $8 monthly fee, so this value remains constant and will be our "y-intercept"
They then charge $0.06 for every minute he talks, this will be our "slope"
Combining everything into an equation, we have: y = 0.06x + 8
Now since we were given Franks phone bill total and want to figure out how many minutes he used, we just need to solve the equation for x and plug in our known y value
y = 0.06x + 8 → y - 8 = 0.06x → [tex]x=\frac{y-8}{0.06}[/tex] Then plugging in our y value we get [tex]x=\frac{17.36-8}{0.06}=\frac{9.36}{0.06}= 156[/tex]Frank used up a total of 156 minutes
Isaac is organizing a 5-kilometer road race. The safety committee
recommends having a volunteer every 1 of a kilometer and at
the finish.
| Are 10 volunteers enough?
Answer:
10 volunteers are more than recommendedStep-by-step explanation:
The recommended number of volunteers is five (5)
Since the the distance of the race is 5km,
and the safety committees recommends 1 volunteer per kilometre.
Hence ten (10) volunteers is more than enough
Simplify this equation x2-5x-36
Answer:
[tex]=\left(x+4\right)\left(x-9\right)[/tex]
Step-by-step explanation:
[tex]x^2-5x-36\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(x^2+4x\right)+\left(-9x-36\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2+4x\mathrm{:\quad }x\left(x+4\right)\\\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9x-36\mathrm{:\quad }-9\left(x+4\right)\\=x\left(x+4\right)-9\left(x+4\right)\\\mathrm{Factor\:out\:common\:term\:}x+4\\=\left(x+4\right)\left(x-9\right)[/tex]
Enter the y-coordinate of the solution. Round to the nearest tenth. 5x+2y=7 -2x+6y=9
Answer:
59/34
Step-by-step explanation:
5x+2y=7
-2x+6y=9
Multiply the top equation by 3:
15x+6y=21
Subtract the second equation from the first:
17x=12
x=12/17
Plug this back into one of the other equations to find y:
5(12/17)+2y=7
60/17+2y=7
2y=59/17
y=59/34
Hope this helps!
Dan buys a car for £2100.
It depreciates at a rate of 2.2% per year.
How much will it be worth in 6 years?
Give your answer to the nearest penny where appropriate.
Answer:
£472.92
Step-by-step explanation:
£2100(0.78)^6
PLEASE HELP!!! Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10. Enter your answers below. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12). Solution Step 1: Find the slope of the line 4x−5y=−10. Use a forward slash (i.e. "/") for all fractions (e.g. 1/2 for 12). m= _____ What would the perpendicular slope be? m= _____ Step 2: Use the slope to find the y-intercept of the perpendicular line. b= ____ Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10 y= ____ x+ Answer
Linear equations are typically organized in slope-intercept form:
[tex]y=mx+b[/tex]
m = slopeb = y-interceptPerpendicular lines have slopes that are negative reciprocals.
Example: 2 and -1/2Example: 3/4 and -4/3SolutionWe're given:
Perpendicular to [tex]4x-5y=-10[/tex]Passes through (6,3)1) Determine the slope
Let's first rearrange this equation into slope-intercept form:
[tex]4x-5y=-10\\-5y=-4x-10\\\\y=\dfrac{4}{5}x+2[/tex]
Notice how [tex]\dfrac{4}{5}[/tex] is in the place of m in y = mx + b. This is the slope of the give line.
Since perpendicular lines are negative reciprocals, we know the slope of the other line is [tex]-\dfrac{5}{4}[/tex]. Plug this into y = mx + b:
[tex]y=-\dfrac{5}{4}x+b[/tex]
2) Determine the y-intercept
We're also given that the line passes through (6,3). Plug this point into our equation and solve for b:
[tex]y=-\dfrac{5}{4}x+b\\\\3=-\dfrac{5}{4}(6)+b\\\\b=3+\dfrac{5}{4}(6)\\\\b=\dfrac{21}{2}[/tex]
Plug this back into our original equation:
[tex]y=-\dfrac{5}{4}x+\dfrac{21}{2}[/tex]
Answer[tex]y=-\dfrac{5}{4}x+\dfrac{21}{2}[/tex]
8 cm
10 cm
The surface area of the above figure is
A. 816.8 cm2
B. 879.6 cm2
C. 565.5 cm2
D. 1131.0 cm
Hi there u have not given us the figure please correct the answer and I will send my answer.Is it a cylinder cuboid cube or?
(Please hurry)
Explain how to find the value of x
Answer:
96
Step-by-step explanation:
Exterior angles add up to 360
360 - 134-130 = 96
x = 96
Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade of B equals .30. The probability that a randomly selected student from this class will receive either an A or a B equals.
a. .09
b. .6
c. .9
d. .3
Answer:
Answer D is correct
How do I set up this problem. I'm lost
Answer:
the answer is 64 .
Step-by-step explanation:
basically i just divided 48 by 2.4 and got 20 .. so that means that 20 has to be the multiplied factor so i just multiplied 3.2 by 20 and got 64.
If a triangle has sides that are 21 and 6 what is the range for third side x?
Enter your answer without spaces in range format.
Example: 1<x<3
Answer:
15<x<27
Step-by-step explanation:
Rule for the sides of a triangle:
The sum of the two smallest sides of a triangle must be greater than the biggest side.
In this question:
Sides of 6, 21 and x. We have to find the range for x.
If 21 is the largest side:
Two smallest are 6 and x.
x + 6 > 21
x > 21 - 6
x > 15
If x is the largest side:
Two smallest and 6 and 21. So
21 + 6 > x
27 > x
x < 27
Then
x has to be greater than 15 and smaller than 27. So the answer is:
15<x<27
Given that the area of a rectangle is 36 square cm and its length is 12 cm. Find the
width of the rectangle.
Answer:
is 3
Step-by-step explanation:
because to find the area for a ractangle you have to multiply LxW and 12x3=36
Each limit represents the derivative of some function f at some number a. State such an f and a in each case.
lim √9 + h - 3 / h
h-->0
Answer:
a = 0f(h) = [tex]\frac{\sqrt{9+h} - 3}{h}[/tex]limit of the function is 1/6Step-by-step explanation:
The general form representing limit of a function is expressed as shown below;
[tex]\lim_{h \to a} f(h)[/tex] where a is the value that h will take and use in the function f(h). It can be expressed in words as limit of function f as h tends to a. Comparing the genaral form of the limit to the limit given in question [tex]\lim_{h \to 0} \frac{\sqrt{9+h} - 3}{h}[/tex], it can be seen that a = 0 and f(h) = [tex]\frac{\sqrt{9+h} - 3}{h}[/tex]
Taking the limit of the function
[tex]\lim_{h \to 0} \frac{\sqrt{9+h} -3}{h}\\= \frac{\sqrt{9+0}-3 }{0}\\= \frac{0}{0}(indeterminate)[/tex]
Applying l'hopital rule
[tex]\lim_{h \to 0} \frac{\frac{d}{dh} (\sqrt{9+h} - 3)} {\frac{d}{dh} (h)}\\= \lim_{h \to 0} \frac{1}{2} (9+h)^{-1/2} /1\\=\frac{1}{2} (9+0)^{-1/2}\\= \frac{1}{2} * \frac{1}{\sqrt{9} } \\= 1/2 * 1/3\\= 1/6[/tex]
find the next two terms in this sequence. 5,-5,10,-10,15,?,?
Answer:
I think the answer is -15
What’s the correct answer for this question?
Answer: choice D 1/2
Step-by-step explanation:
Events A and B are independent if the equation P(A∩B) = P(A) · P(B) holds true.
so
1/6=1/3*p(A)
p(A)=1/2
The mean family income for a random sample of 600 suburban households in Loganville shows that a 95 percent confidence interval is ($43,100, $59,710). Alma is conducting a test of the null hypothesis H0: µ = 42,000 against the alternative hypothesis Ha: µ ≠ 42,000 at the α = 0.05 level of significance. Does Alma have enough information to conduct a test of the null hypothesis against the alternative?
Answer:
[tex] 43100 \leq \mu \leq 59710[/tex]
And for this case we want to test the following hypothesis:
Null hypothesis: [tex] \mu =42000[/tex]
Alternative hypothesis: [tex] \mu \neq 42000[/tex]
For this case since the lower value of the confidence interval is higher than 42000 we have enough evidence to reject the null hypothesis at the 55 of significance and we can conclude that the true mean is significantly different from 42000
Step-by-step explanation:
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
And for this case the 95% confidence interval is already calculated as:
[tex] 43100 \leq \mu \leq 59710[/tex]
And for this case we want to test the following hypothesis:
Null hypothesis: [tex] \mu =42000[/tex]
Alternative hypothesis: [tex] \mu \neq 42000[/tex]
For this case since the lower value of the confidence interval is higher than 42000 we have enough evidence to reject the null hypothesis at the 55 of significance and we can conclude that the true mean is significantly different from 42000
Answer: Yes, because $42,000 is not contained in the 95% confidence interval, the null hypothesis would be rejected in favor of the alternative, and it could be concluded that the mean family income is significantly different from $42,000 at the α = 0.05 level
Step-by-step explanation:
took the test
In a village
The number of houses and the number of flats are in the ratio 9:5
The number of flats and the number of bungalows are in the ratio 10:3
There are 30 bungalows in the village.
How many houses are there in the village?
Note: please make sure your final answer clear by writing ... houses
The number of houses are 180, and the number of flats are 100.
It is given that the number of houses and the number of flats ratio is 9:5 the number of flats and the number of bungalows ratio is 10:3.
It is required to find the number of houses in the village if the number of bungalows is 30.
What is a fraction?Fraction number consists of two parts one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
The ratio of the number of houses and the number of flats:
= 9:5 and
The ratio of the number of flats and the number of bungalows :
=10:3
It means we can write the ratio of the number of houses and the number of flats = 18:10
And the ratio of the number of:
Houses : Flats : Bungalows = 18:10:3
But the number of bungalows are 30.
Then the ratios are:
180:100:30
Thus, the number of houses are 180, and the number of flats are 100.
Learn more about the fraction here:
brainly.com/question/1301963
Which triangle’s area would be calculated using the trigonometric area formula?
Triangle E F D is shown. The length of E F is 10, the length of D F is 7, and the length of D E is 12.
Triangle Q R P is shown. The length of Q R is 5 and the length of R P is 6. Angle Q R P is 40 degrees.
Triangle A B C is shown. The length of A B is 4 and the length of B C is 5. Angle B C A is 25 degrees.
Triangle X Y Z is shown. The length of Y Z is 4. Angle Z X Y is 29 degrees and angle X Y Z is 110 degrees.
Answer:
Triangle Q R P is shown. The length of Q R is 5 and the length of R P is 6. Angle Q R P is 40 degrees.
Step-by-step explanation:
The trigonometric formula refers the two sides length of the triangle and it also consists of included angle to find out the area
A = [tex]\frac{1}{2}[/tex] ab sin C
QPR contains two sides and the included angle
XYZ has one side and the two angles
DEF has only three sides
And, the ABC contains two sides but does not have the included angle
Based on the explanation above, the correct option is B
Answer: the second option aka B
Step-by-step explanation: The other person explained it and I'm just here to tell you they gave the correct and answer for edge 2020.
(Bonus) A rectangular box has its edges changing length as time passes. At a par-ticular instant, the sides have lengthsa= 150 feet,b= 80 feet, andc= 50 feet.At that instant,ais increasing at 100 feet/sec,bis decreasing 20 feet/sec, andcisincreasing at 5 feet/sec. Determine if the volume of the box is increasing, decreasing,or not changing at all, at that instant.
Answer:
the volume of the box is increasing
dV = +310,000 ft^3/s
Step-by-step explanation:
Volume of a rectangular box with side a,b and c can be expressed as;
V = abc
The change in volume dV can be expressed as;
dV = d(abc)/da + d(abc)/db + d(abc)/dc
dV = bc.da + ac.db + ab.dc ......1
Given:
a= 150 feet,
b= 80 feet, and
c= 50 feet
ais increasing at 100 feet/sec,bis decreasing 20 feet/sec, andcisincreasing at 5 feet/sec
da = +100 feet/s
db = -20 feet/s
dc = +5 feet/s
Substituting the values into the equation 1;
dV = (80×50×+100) + (150×50×-20) + (150×80×+5)
dV = +400000 - 150000 + 60000 ft^3/s
dV = +310,000 ft^3/s
Since dV is positive, the volume of the box is increasing at that instant.
Please answer this question for me thank you !! 20 Points !! Will give brainliest !!
Answer:
b
Step-by-step explanation:
In a parralel graph, the slopes would always be the same. The intercept in the answer is 2, showing that the coordinate points are (0,2)
Hope this helps!:)
Answer:
B) y = 2x + 2
Step-by-step explanation:
Firstly, you have to know that parallel lines have congruent slopes. That means that the slope of this line will be 2.
Next, make a point slope form of the equation:
y - y1 = m(x - x1)
y - 2 = 2(x - 0)
y - 2 = 2x - 0
Now, we can make it into slope intercept form.
y - 2 = 2x
y = 2x + 2
Hope this helps :)
Zed went to the store and bought a bag of chips. He estimated there would 1 point
be 350 chips in the package, but realized there were only 210 chips in that
package. What was his percent error?'
Answer:
66.67%
Step-by-step explanation:
They do not say that I estimate a value of 350 chips but in reality there were 210 chips in total, we have that the error formula is:
Percentage error (%) = (estimated value - actual value) / actual value × 100 (in absolute value)
replacing:
Percentage error (%) = | 350 - 210 | / 210 × 100
Percentage error (%) = 140/210 * 100
Percentage error (%) = 66.67
Which means that the percentage error is 66.67%
You have $150 to spend at a store. If you shoes cost $30 and belts cost $25, write an equation that represents the different ways that you could spend a total of $150
Answer:
you could buy a pair of shoes and a belt still have 95 dollars to spend
if you’re good with set theory and word problems in math 30 please help with questions 42 and 43 !! real answers only !!
Answer: 42) 2, 3 43) 144
Step-by-step explanation:
42)
1. n(P) = 8 + 5 = 13 (not 8) This statement is False.
2. n(Q but not P) = 9 This statement is True!
3. n(neither P nor Q) = 2 This statement is True!
4. n(Q') --> (n (not Q) = 8 + 2 = 10 (not 8) This statement is False.
5. P ∪ Q = 8 + 9 - 5 = 12 (not 5) This statement is False.
43)
Fill in the Venn Diagram as follows (from left to right):
M only = 55 --> 89 - (17 + 4 + 13) = 55
M ∩ E = 17 --> 30 - 13 = 17
E only = 5 --> 46 - (17 + 13 + 11) = 5
B ∩ M = 4 --> 17 - 13 = 4
M ∩ E ∩ B = 13 --> given
B ∩ E = 11 --> 24 - 13 = 11
E only = 35 --> 63 - (13 + 4 + 11) = 35
(M ∪ E ∪ B)' = 4 --> given
Total = 144