4x+ 2( 3 – 3x) = 6 answer

Answer:

0.20<n<0.25

Step-by-step explanation:

0.20<n<0.25

Answer:

No

Step-by-step explanation:

It is not, because we can only add the terms that contain x of the same order.

For x to be grouped with x 2 resulting in x 3 the terms would have to be multiplying

In this case they are grouped

x * x 2 = x 3

In this case they are not grouped

x + x 2 = x + x 2

x = # of hours the bike was rented.

$40 = $12 + $7x

Subtract $12 from both sides.

$28 = $7x

Divide both sides by $7

4 = x

Sandy rented the bike for 4 hours.

Answer:

the answer is 42

Step-by-step explanation:

12-6+(14-8)^2

12-6(6)^2

12-6+36

=42

Answer:

Q1:

[tex]-5\sqrt{27c^2}[/tex]

[tex]-5\sqrt{27}\sqrt{c^2}[/tex]

[tex]-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}[/tex]

[tex]-5\times3\sqrt{3}\sqrt{c^2}[/tex]

[tex]-5\times3\sqrt{3}c[/tex]

[tex]-15\sqrt{3}c[/tex]

Q2:

[tex]5\sqrt{72}-3\sqrt{32}[/tex]

[tex]5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}[/tex]

[tex]5\times6\sqrt{2}-3\times4\sqrt{2}[/tex]

[tex]30\sqrt{2}-12\sqrt{2}[/tex]

[tex]18\sqrt{2}[/tex]

Q3:

[tex]\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}[/tex]

[tex]\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}[/tex]

[tex]6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}[/tex]

[tex]16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}[/tex]

Q4:

[tex]\sqrt{15n^2}\sqrt{10n^3}[/tex]

[tex]\sqrt{15}n\sqrt{10n^3}[/tex]

[tex]\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}[/tex]

[tex]\sqrt{15}\sqrt{10}n^2\sqrt{n}[/tex]

[tex]\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}[/tex]

[tex]5\sqrt{3}\sqrt{2}n^2\sqrt{n}[/tex]

[tex]5\sqrt{6}n^2\sqrt{n}[/tex]

Q5:

[tex]\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}[/tex]

[tex]\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}[/tex]

Cancel off [tex]\sqrt{x}[/tex]:

[tex]\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}[/tex]

Cancel off [tex]y:[/tex]

[tex]\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}[/tex]

Cancel off [tex]\sqrt{y} :[/tex]

[tex]\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}[/tex]

Multiply [tex]\sqrt{5}[/tex] on the numerator and denominator:

[tex]\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}[/tex]

[tex]\frac{\sqrt{15}\sqrt{x}}{20}[/tex]

sorry i pushed add answer

Answer:

4 gallons

Step-by-step explanation:

He needs 105 over 3 to fill all the cups. 1 gallon would be 10 and 2 third cups or 32 over 3. 2 gallons would be 21 and 1 third cups or 64 over 3. 3 gallons would be 32 or 96 over 3. 4 gallons would be 42 and 2 third cups or 128 over 3. So 4 gallons would fill up all 35 of his sisters 12 ounces cups. That would leave 7 and 2 third cups that hold the same amount. His sister gets all 35 of her 12 ounces each cups filled and he gets 7 and 2 thirds of new and unused 12 ounces cups. Basically out of the 4 gallons there would be 512 ounces and his sister with all 35 cups that hold 12 ounces each she would get 420 ounces. Which would leave him with 92 ounces of juice for himself. Hope this understandable and helpful.

Answer:

1

Step-by-step explanation:

Answer:

x>-2

Step-by-step explanation:

first you subtract 10 from both sides to find x

10-3x-10<16-10

-3x<6

now here you divide both sides by -3

-3x/-3<6/-3

BUT since you are dividing by a negative number the sign will have to flip

so the answer will be

x>-2

Answer:

1.) Reflection over y=1

2.) Translation rule: (x-5, y-3)

3.) Reflection over the y axis

4.)Translation rule: (x-4, y+1)

Step-by-step explanation:

Answer:

x< 9

Step-by-step explanation:

I'm not sure if it's right but I think it is .

Answer: 3,4,5,6,52,72,86,105

Step-by-step explanation: when solving the range you find the difference between the highest and lowest values in the set. To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

Answer:

w = -4

Step-by-step explanation:

w - 2 + 2w = 6 + 5w

Add 2 to both sides.

w + 2w = 8 + 5w

Subtract w from each side.

2w = 8 + 4w

Subtract 4w from each side.

-2w = 8

Divide.

w = -4

Answer:

x= 2.5

Step-by-step explanation:

-7.5 (x-3) = 3.75

(divide both sides of the equation by -7.5)

x-3 = -0.5

(move the constant to the righthand side and change the sign)

x = -0.5+3

(calculate the sum)

x = 2.5

Answer: 114

Step-by-step explanation:

To find the perimeter, you will find the distance around the shape by adding the numbers.

The is one missing side  and to find that side you will subtract  10 from 38.

38 - 10 = 28

Now add the them.

28 + 5 +  10 + 26 + 10 + 35 = 114

Answer:

x=[tex]-\frac{1+2i\sqrt{31} }{5}[/tex]

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

−25=  [tex]\frac{1}{2}[/tex]  (10x−2)+3x

−25=([tex]\frac{1}{2}[/tex])(10x)+( [tex]\frac{1}{2}[/tex] )(−2)+3x(Distribute)

−25=5x+−1+3x

−25=(5x+3x)+(−1)(Combine Like Terms)

−25=8x+−1

−25=8x−1

Step 2: Flip the equation.

8x−1=−25

Step 3: Add 1 to both sides.

8x−1+1=−25+1

8x=−24

Step 4: Divide both sides by 8.

8x  ÷ 8   =   −24  ÷ 8

Answer:

Around 22200 dollars

Step-by-step explanation:

Firstly, it was depreciating 20% per year for 17 years. So, if we were to go back in time, it would be appreciating by 25%. Therefore, after doing the plugging in, it is 500 * 1.25^17. The initial value is around 22200. It is around 22204, to be exact.

Answer:

[tex]C = 180 - 3a[/tex]

Step-by-step explanation:

Given

[tex]A = a[/tex]

[tex]B = 2a[/tex]

Required

[tex]Find\ C[/tex]

Since, ABC is a triangle, we have:

[tex]A + B + C = 180[/tex]

Substitute values for A and C

[tex]a + 2a + C = 180[/tex]

[tex]3a + C = 180[/tex]

Subtract 3a from both sides

[tex]C = 180 - 3a[/tex]

Answer:

180°-3α

Step-by-step explanation:

If you forgot to put the degree sign on 180, that's why you got it wrong!

Answer:

-6300

Step-by-step explanation:

I just plugged it into my calculator, Google's works just fine :)

Answer:

times -6

Explanation... 2 x 10-6 x -6=56

                      6 x 10-4=56      

Hope this helps

Answer:

C

Step-by-step explanation:

39*34= 1326 (the area of the full square

8*10=80 (the area of the small square that is cut off)

1326-80= 1246

Answer:

C = 1246 sq. cm.

Step-by-step explanation:

finding the area is simply splitting the area into two (see image)

A1 = 26 x 39 = 1014

A2 = 8 x 29 = 232

total area = 232 + 1014

total area = 1246 sq. cm.

therefore, the answer is C = 1246 sq. cm.

Answer:

entire orchestra I'm gonna say

Answer:

the answer is -1 3/4

Step-by-step explanation:

Answer:

270°

Step-by-step explanation:

[tex]m\widehat{BC} = 360\degree - (146\degree + 90\degree) \\

m\widehat{BC} = 360\degree -236\degree \\

m\widehat{BC} = 124\degree \\\\

m\widehat{ABC} =m\widehat {AB} + m\widehat {BC} \\

m\widehat{ABC} =146\degree + 124\degree \\

\huge \red {\boxed {m\widehat{ABC} =270\degree}} \\

[/tex]

Answer:

Step-by-step explanation:

Collinear points A, B, and C and point B being midpoint of AC means:

AB = BC

12x - 398  =  22

   + 398      + 398

 12x = 420

  ÷12    ÷12  

    x = 35

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π                    →    A + B = π - C

                                                    →    A + C = π - B

Use the Cofunction Identities:   sin (π - A) = sin A

                                                    sin (A - π/2) = cos A

                                                    cos (π/2 - A) = - sin A

Use the Power Reducing Identity:  sin ² A - sin² B = sin (A + B) · sin (A - B)

Use the Sum to Product Identity:

                                               sin A - sin B = 2 [cos (A + B)/2] · [sin (A - B)/2]

Proof LHS → RHS:

LHS:                                   sin² A - sin² B - sin² C

                                       = (sin² A - sin² B) - sin² C

Power Reducing:           sin (A + B) · sin (A - B) - sin² C

Given:                             sin (π - C) · sin (A - B) - sin² C

Cofunction:                    sin C · sin (A - B) - sin² C

Factor:                            sin C [sin (A - B) - sin C]

[tex]\text{Sum to Product:}\qquad \sin C\bigg[2\cos \bigg(\dfrac{(A-B)+C}{2}\bigg)\cdot \sin \bigg(\dfrac{(A-B)-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{(A+C)-B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-(B+C)}{2}\bigg)\bigg][/tex]

[tex]\text{Given:}\qquad \qquad 2\sin C\bigg[\cos \bigg(\dfrac{(\pi - B)-B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-(\pi - A)}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{\pi -2B}{2}\bigg)\cdot \sin \bigg(\dfrac{2A-\pi}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{\pi}{2} -B}\bigg)\cdot \sin \bigg(A-\dfrac{\pi}{2}\bigg)\bigg][/tex]

Cofunction:             2 sin C (-sin B) · (cos A)

                           = -2 sin C · sin B · cos A

                           = -2 cos A · sin B · sin C

LHS = RHS:   -2 cos A · sin B · sin C = -2 cos A · sin B · sin C  [tex]\checkmark[/tex]