45. Twenty-two runners compete in a cross-country race.
Three runners will each win a medal: gold, silver, or bronze.
Which of the following expressions gives the maximum
number of distinct ways the medals could be awarded?

Answer:

yea

Step-by-step explanation:

u need more details

Answer:

0.032%

Step-by-step explanation:

192192/600600600 x 100% = 0.00032 x 100%

0.032%

Answer: 5/6

Step-by-step explanation:

First, you find the common denominator of the two:

3/6 + 2/6

Now you can easily add the two:

5/6

Answer:

See below.

Step-by-step explanation:

We are asked to Add Fractions.

Fractions are parts of a single whole number.

To make adding these fractions similar, we should have a common denominator.

[tex]\frac{Numerator}{Denominator}[/tex]

When we add common denominators, they remain the same. This makes adding fractions much easier.

Let's identify the common denominator by finding the Least Common Multiple. (LCM)

The LCM is the smallest common multiple that 2 numbers have. A multiple is the product of that number.

An Example of Multiples:

[tex]4; 4 \times 1, 4 \times 2, 4 \times 3, 4 \times 4, 4 \times 5, 4 \times 6.\\4; 4, 8, 12, 16, 20, 24.[/tex]

An Example of the LCM:

[tex]4; 4, 8, 12, 16, 20, [24], 28\\6; 6, 12, 18, [24], 30, 36, 42. \\The \ LCM \ is \ 24.[/tex]

Let's use the example above as a guide, but for our values in the denominator.

[tex]2; 2, 4, [6], 8, 10, 12, 14.\\3; 3, [6], 9, 12, 15, 18, 21.\\The \ LCM \ is \ 6.[/tex]

Our Denominators will be 6.

Multiply both the Numerator and the Denominator by the number needed to make the denominator 6.

[tex]\frac{1 \times 3}{2 \times 3}=\frac{3}{6} \\\frac{1 \times 2}{3 \times 2} = \frac{2}{6}[/tex]

Add:

[tex]\frac{3}{6} + \frac{2}{6} = \frac{5}{6} \\[/tex]

Our final answer is [tex]\frac{5}{6} .[/tex]

Answer:

100 minutes

Step-by-step explanation:

we take 6/km an hour and make it 1 km per 10 minutes and then multiply it by 100

The factored form of 3x^2 + 13x - 10 is (3x - 2)(x + 5).

To factor 3x^2 + 13x – 10 by grouping, we need to find two numbers whose product is 3(-10) = -30 and whose sum is 13.

Let's list all the factor pairs of -30:

-1, 30

-2, 15

-3, 10

-5, 6

Out of these pairs, the pair that adds up to 13 is -2 and 15.

We can use these numbers to rewrite the middle term:

3x^2 - 2x + 15x - 10

Now, we can group the first two terms and the last two terms:

(3x^2 - 2x) + (15x - 10)

We can factor out the greatest common factor from each group:

x(3x - 2) + 5(3x - 2)

Now, we can see that we have a common factor of (3x - 2):

(3x - 2)(x + 5)

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The given question is incomplete, the complete question is:

What is the factored form of 3x^2 + 13x - 10?

Answer: 184 cm^2

Step-by-step explanation:

1st: separate the figure into smaller shapes

-> one large rectangle (20 cm x 7 cm) =140 cm

-> one triangle ( (15-7)= 1/2 (8 cm x 3 cm ) = (20-13-4) = 12 cm

-> one rectangle (4 cm x 8 cm ) = 32 cm

140 + 32 + 12 = 184 cm

Answer: 184 cm2

Step-by-step explanation: Break the shape into common shapes. If you continue the line of 13 cm you now have a rectangle and trapezoid.

The rectangle area is 140

20 x 7 = 140

The trapezoid area is 44

The 15 cm line is cut into 7 and 8

the height of the shape is now 8

Base A ( the top ) is 4 cm

Base B (the bottom) is 7

A = a+b over 2h = 4+7 over 2·8 = 44

now add the numbers

Answer:

X = 90 , Y = 37 and Z = 53 Degrees.

Step-by-step explanation:

Z = 53 as opposite angles of a parallelogram are equal

Therefore, Z + Y + 90 = 180 ( Angle sum Property of a triangle)

= 53 + Y + 90 = 180
Y = 180 - 143
Y = 37

Now to find x , we know Y is the Alternate Interior angle of the angle adjacent to the 90*

Keeping that angle as "o"

Angle O = Angle Y by Alternate Interior Angle Therom

Therefore , Angle X + Angle O + 53 = 180 (ASP of triangle)

Angle X + 37 + 53 = 180

Angle X = 180 - 90
Angle X = 90*


In summary , X = 90 , Y = 37 and Z = 53.

Hope it helps.

Answer:

The formula for compound interest is:

A = P(1 + r/n)^(nt)

Where:

A = the final amount

P = the principal (initial amount)

r = the annual interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the time the money is invested (in years)

In this case, P = $500, r = 0.12, n = 2 (compounded twice a year), and t = 2.

So, A = 500(1 + 0.12/2)^(2*2) = $673.01

Therefore, Sam's total investment will be worth $673.01 after 2 years.

Step-by-step explanation:

Answer:79

Step-by-step explanation:

y=12+91=79

Answer:144 ft³

Step-by-step explanation:

The width of the sandbox is half of its length, so we can start by finding the length:

Length = 12 feet

Width = 1/2 * Length = 1/2 * 12 feet = 6 feet

Height = 2 feet

The volume of sand needed to fill the sandbox is the product of its length, width, and height:

Volume = Length * Width * Height

Volume = 12 feet * 6 feet * 2 feet

Volume = 144 cubic feet

Answer:45%

Step-by-step explanation:

:))))

Answer:

45%

Step-by-step explanation:

99/180 = 55%

100% - 55% = 45% decrease

Answer: 45%

The lengths of the sides of the special 30°–60° right triangles are;

14. a = 8

b = 8·√3

c = 16

15. a = 4

b = 4·√3

c = 8

16. a = 7

b = 7·√3

c = 14

17. a = 12

b = 12·√3

c = 24

18. a = 5

b = 5·√3

c = 10

19. a = 9

b = 9·√3

c = 18

20. a = 10

b = 10·√3

c = 20

21. a = (√6)/2

b = 3·(√(2))/s

c = √6

Special right triangles are triangles that have 30°, 60°, and 45° interior angles.

The unknown lengths of the 30-60 special right triangle can be found as follows;

14. The length of the side a = 8

The length of the hypotenuse side, c can be found as follows;

sin(30°) = 1/2

sin(θ) = a/c

sin(30°) = 1/2 = 8/c

c = 2 × 8 = 16

c = 16

cos(θ) = b/c

cos(30°) = √3/2

Therefore; √3/2 = b/16

b = 16 × (√3/2) = 8·√3

b = 8·√3

15. a = 4, therefore;

c = 2 × 4 = 8

c = 8

b = (√3/2) × 8 = 4·√3

b = 4·√3

16. a = 7

b = 7·√3

c = 2 × 7 = 14

c = 14

17. a = b/√3, therefore;

a = 12·√3/√3 = 12

a = 12

b = 12·√3

c = 2 × a, therefore;

c = 2 × 12 = 24

c = 24

18. a = 5

b = a × √3, therefore;

b = 5 × √3 = 5·√3

b = 5·√3

c = 2 × a, therefore;

c = 2 × 5 = 10

c = 10

19. c = 18

a = c/2, therefore;

a = 18/2 = 9

a = 9

b = a × √3, therefore;

b = 9 × √3 = 9·√3

b = 9·√3

20. a = 10

b = a × √3, therefore;

b = 10 × √3 = 10·√3

b = 10·√3

c = 2 × a, therefore;

c = 2 × 10 = 20

c = 20

21. c = √6

a = c/2, therefore;

a = (√6 )/2

b = a × √3, therefore;

b = ((√6)/2) × √3 = (√(18))/2 = 3·√2/2

b = 3·√2/2

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A coffee pot that holds 2 quarts is equal to 8 cups. To determine the number of cups in a coffee pot that holds 2 quarts, multiply 2 quarts by 4 cups.

A quart is a unit of measurement that is equal to 4 cups of liquid. This means that a coffee pot that holds 2 quarts is equal to 8 cups. To figure out how many cups are in a quart, use the following equation: 1 quart = 4 cups. To determine the number of cups in a coffee pot that holds 2 quarts, multiply 2 quarts by 4 cups. The result is 8 cups. In other words, a coffee pot that holds 2 quarts is equal to 8 cups of liquid.

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the approximate volume of the tissue box to the nearest whole number is 300 cubic centimeters.

The volume of a rectangular prism is given by the formula V = lwh, where l, w, and h are the length, width, and height of the prism, respectively.

Substituting the given values, we get:

V = (5.2 cm)(9.6 cm)(6 cm)

Simplifying, we get:

V = 299.52 cubic centimeters

Therefore, the approximate volume of the tissue box is 299.52 cubic centimeters.

Since the dimensions of the tissue box are given to only two decimal places, we can reasonably assume that the answer accurate to two decimal places is a good approximation. If we want to express the answer to the nearest whole number, we would round it to the nearest integer.

Rounding 299.52 to the nearest integer, we get:

V ≈ 300 cubic centimeters

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As per the volume, the height of the fish tank is 0.4 inches.

First, we are given that the width of the tank is w inches, the length is w+8 inches, and the height is 18-w inches. We also know that all dimensions are greater than 6 inches. Using the formula for the volume of a rectangular prism, we can write:

V = lwh

Substituting the given values, we get:

1440 = (w+8)(w)(18-w)

Now, we can simplify this equation by expanding the product on the right-hand side:

1440 = 18w² + 8w(18-w)

Simplifying further, we get:

1440 = 18w² + 144w - 8w²

Combining like terms, we get:

10w² + 144w - 1440 = 0

Dividing both sides by 10, we get:

w² + 14.4w - 144 = 0

Now we can solve for w using the quadratic formula:

w = (-b ± √(b² - 4ac)) / 2a

where a = 1, b = 14.4, and c = -144. Plugging in these values, we get:

w = (-14.4 ± √(14.4² - 4(1)(-144))) / 2(1)

Simplifying, we get:

w = (-14.4 ± √(432.16)) / 2

w = (-14.4 ± 20.8) / 2

w = -17.6 or w = 3.6

Since we know that all dimensions are greater than 6 inches, we can eliminate the negative solution and conclude that w = 3.6 inches is not valid. Therefore, the width of the tank is w = 17.6 inches.

Now we can use this value to find the height of the tank. Substituting w = 17.6 into the expression for the height, we get:

h = 18 - w

h = 18 - 17.6

h = 0.4

Therefore, the height of the tank is h = 0.4 inches, or equivalently, 4/10 of an inch.

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After answering the presented question, we can conclude that As a equation result, approximately 44.4% of the original trees are still living after three years.

An equation is a mathematical statement that proves the equality of two expressions connected by the equal symbol '='. 2x - 5 Equals 13, for example. Expressions include 2x-5 and 13. The character '=' joins the two expressions. A mathematical formula with two algebraic expressions on either side of an equal sign (=) is known as an equation. It demonstrates the relationship of equivalence between the left and right formulas. In every formula, LHS = RHS (left side = right side).

Assuming that all of the trees on the farm are cut down each year, the percentage of trees that survive after three years is as follows:

60% of the trees die after the first year, leaving only 40% of the original trees.

Following the first year, 40% of the original trees are still standing.

Following the second year, 40% of the original trees remain + (40% of the original trees * 100% - 60% = 40% stump growth) = 64% of the original trees remain.

Following the third year, 40% of the original trees remain + (64% of the original trees * 100% - 60% = 4.4% stump growth) = 44.4% of the original trees remain.

As a result, approximately 44.4% of the original trees are still living after three years.

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The quotient of [tex]40y^(4)-5y^(3)-30y^(2)-10y[/tex] divided by [tex]8y^(3) - y^(2) - 6y - 2[/tex]

You can use the polynomial long division method to find the product of two polynomials. Following are the steps:

To divide [tex]40y^(4)-5y^(3)-30y^(2)-10y[/tex] by 5y, we utilize long division.  Divide dividend by divisor to obtain first term of the quotient:

[tex]40y^(4) / (5y) = 8y^(3)[/tex]

Multiply divisor (5y) by first term of quotient (8y^(3)) to obtain first term of partial product:

[tex](8y^(3))(5y) = 40y^(4)[/tex]

Subtract the partial product from the dividend to obtain remainder:

[tex]40y^(4) - 40y^(4) = 0[/tex]

[tex]-5y^(3) / (5y) = -y^(2)(-y^(2))(5y) = -5y^(3)-5y^(3) - (-5y^(3)) = 0[/tex]

[tex]-30y^(2) / (5y) = -6y(-6y)(5y) = -30y^(2)-30y^(2) - (-30y^(2)) = 0[/tex]

Repeat process:

[tex]-10y / (5y) = -2(-2)(5y) = -10y-10y - (-10y) = 0[/tex]

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Answer:

To find all the real zeros of a polynomial function algebraically, use the Rational Root Theorem to generate a list of possible rational zeros and use synthetic division to test each possible zero. The zeros that remain after testing all the possible zeros are the real zeros of the polynomial function.

To find all the real zeros of a polynomial function algebraically, you can use the Rational Root Theorem and synthetic division. The Rational Root Theorem states that if a polynomial function has integer coefficients, then any rational zero (i.e., a zero that can be expressed as a fraction) must have a numerator that is a factor of the constant term and a denominator that is a factor of the leading coefficient.

Here are the steps you can follow:

1. Write the polynomial function in descending order of degree, with all like terms combined.

2. Use the Rational Root Theorem to generate a list of possible rational zeros. This list will be a set of all the possible fractions that can be formed by dividing a factor of the constant term by a factor of the leading coefficient.

3. Use synthetic division to test each possible zero. Start with the smallest possible denominator and work your way up. If a possible zero is not a zero of the polynomial function, cross it off the list.

4. Repeat step 3 until all the possible zeros have been tested. The zeros that remain are the real zeros of the polynomial function.

For example, let's say we have the polynomial function f(x) = x^3 - 6x^2 + 11x - 6.

Write the polynomial function in descending order of degree: f(x) = x^3 - 6x^2 + 11x - 6.

Use the Rational Root Theorem to generate a list of possible rational zeros: ±1, ±2, ±3, ±6.

Use synthetic division to test each possible zero. We start with x = 1:

1 │ 1 -6 11 -6

│ 1 -5 6

└─────────────

1 -5 6 0

Since the remainder is zero, we have found a zero of the polynomial function at x = 1. We can write the factorization f(x) = (x - 1)(x^2 - 5x + 6).

Now we use synthetic division to test the other possible zeros:

2 │ 1 -6 11 -6

│ 2 12 46

└─────────────

1 -4 23 40

x = 2 is not a zero of the polynomial function.

3 │ 1 -6 11 -6

│ 3 15 78

└─────────────

1 -3 26 72

x = 3 is not a zero of the polynomial function.

-1 │ 1 -6 11 -6

│ -1 7 -4

└────────────

1 -7 18 -10

x = -1 is not a zero of the polynomial function.

-2 │ 1 -6 11 -6

│ -2 16 -50

└────────────

1 -8 27 -56

x = -2 is not a zero of the polynomial function.

-3 │ 1 -6 11 -6

│ -3 27 -102

└────────────

1 -9 38 -108

x = -3 is not a zero of the polynomial function.

6 │ 1 -6 11 -6

Hope this helps, I'm sorry if it doesn't! :]

If the length of Anna's square pencil case is 6 in and the width is 4 1/2 in, then the area of the pencil case is 27 square inches

The area of a rectangle can be calculated by multiplying its length by its width.

In this case, Anna's pencil case is a square, which means that its length and width are equal. The length of the pencil case is given as 6 inches, so its width is also 6 inches.

Therefore, the area of the pencil case is:

Area = length x width

Substitute the values in the equation

Area = 6 in x 4.5 in

Area = 27 square inches

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The amount of they share altogether is 90000

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other.

For example if two boys are to share 10 mangoes with ratio 1:4. The first boy will get 1/5 × 10 = 2 mangoes and the other boy will get 4/5 × 10 = 4×2 = 8 mangoes.

Three brothers are to share in ratio 3:4:5. The highest ratio is 5. And the the highest ratio gets 37500. The total ratio is 12 i.e 3+4+5 = 12

Represent the total money by x

Then, 5/12 × x = 37500

5x = 37500 × 12

5x = 450000

divide both sides by 5

x = 450000/5

x = 90000

therefore the amount they shared is 90000.

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The probability that a random sample of 106 pregnancies has a mean gestation period of 262 days or less is 0.00003.

What is probability?

Probability is a measure of the likelihood that an event will occur. It is a number between 0 and 1, where 0 represents an impossible event and 1 represents a certain event. Probabilities are usually expressed as fractions, decimals, or percentages.

(a) To find the probability that a randomly selected pregnancy lasts less than 262 days, we need to standardize the value using the formula z = (x - μ) / σ, where x is the value we're interested in, μ is the mean, and σ is the standard deviation.

z = (262 - 266) / 16 = -0.25

Using a standard normal distribution table or calculator, we find that the probability of getting a z-score of -0.25 or less is 0.4013. Therefore, the probability that a randomly selected pregnancy lasts less than 262 days is 0.4013.

(b) The sampling distribution of the sample mean length of pregnancies is approximately normal with mean μ = 266 and standard deviation σ = 16 / sqrt(51) = 2.2449. This is known as the central limit theorem.

Using a standard normal distribution table or calculator, we find that the probability of getting a z-score of -2.8304 or less is 0.0023. Therefore, the probability that a random sample of 51 pregnancies has a mean gestation period of 262 days or less is 0.0023.

(d) Using the same formula as in part (c), we have:

z = (262 - 266) / (16 / sqrt(106)) = -4.0077

Using a standard normal distribution table or calculator, we find that the probability of getting a z-score of -4.0077 or less is 0.00003.

Therefore, the probability that a random sample of 106 pregnancies has a mean gestation period of 262 days or less is 0.00003.

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The volume generated by rotating the region in the first quadrant bounded by y = ex and the x-axis from x = 0 to x = ln(3) about the y-axis is (πln(3)3)/3.

To find the volume generated by rotating the region in the first quadrant bounded by y = ex and the x-axis from x = 0 to x = ln(3) about the y-axis, we can use the disk method. The disk method involves slicing the region into thin disks and adding up their volumes.

The volume of each disk is πr2h, where r is the radius of the disk and h is the thickness of the disk. In this case, the radius of each disk is x and the thickness is dx.

So, the volume of the region is:

V = ∫0ln(3)πx2dx

We can use the power rule for integration to solve this integral:

V = π∫0ln(3)x2dx = π[(x3)/3]0ln(3) = π[(ln(3)3)/3 - (03)/3] = (πln(3)3)/3

Therefore, the volume generated by rotating the region in the first quadrant bounded by y = ex and the x-axis from x = 0 to x = ln(3) about the y-axis is (πln(3)3)/3. This is the exact form of the volume.

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Addressing issue at hand, we can state that the correct linear equation comparison symbol to the box. 10.09 10.9 f < = > is => 10.09 < 10.9

The algebraic equation y=mx+b is known as a linear equation. M serves as the y-intercept, and B serves as the slope. The previous clause has two variables, y and x, and is sometimes referred to as a "linear equation with two variables". Bivariate linear equations are those with two independent variables. The following are a few examples of linear equations: 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3. When an equation takes the form y=mx+b, with m denoting the slope and b denoting the y-intercept, it is referred to as being linear. The term "linear" refers to an equation having the form y=mx+b, where m stands for the slope and b for the y-intercept.

the correct comparison symbol to the box.

10.09 10.9

< = >

10.09 < 10.9

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The value of x which would make GHJK a rhombus would be 42 degrees.

Nora can construct a kite with diagonals that bisect each other if the kite is in the shape of a rhombus.

The way that a Rhombus is drawn is such that ∠ GKJ and ∠ HGK would add up to 180 degrees. If these angles are bisected as shown, then the corresponding angles would add up to 90 degrees as a result.

If this shape is to be a rhombus then the value of x would be :

= 90 - 48

= 42 degrees

A kite is a quadrilateral with two pairs of adjacent congruent sides. The diagonals of a kite intersect at a right angle, but they do not necessarily bisect each other.

If the diagonals of a kite bisect each other, it means that they cut each other into two equal parts. This can only happen if the kite is a rhombus, which is a special type of kite where all four sides are congruent.

Therefore, if Nora wants to construct a kite with diagonals that bisect each other, she would need to ensure that the kite is a rhombus.

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The baby will drink 45 liters of milk in 30 days when baby drink 3 liters of milk in 2 days.

To solve this problem, we can set up a proportion using the fact that the amount of milk the baby drinks is directly proportional to the number of days:

milk consumed / number of days = constant

Let's call the constant of proportionality k. Then we can write:

3 liters / 2 days = k

To find the value of k, we can solve for it:

k = 3 liters / 2 days = 1.5 liters/day

Now we can use this value of k to find how much milk the baby will drink in 30 days:

milk consumed / 30 days = 1.5 liters/day

Multiplying both sides by 30, we get:

milk consumed = 1.5 liters/day x 30 days = 45 liters

Therefore, the baby will drink 45 liters of milk in 30 days.

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The complete question is :

A baby drink 3 liters of milk in 2 days . How much milk will baby drink in 30 days.

Answer:

9 1/36

Step-by-step explanation:

set 7/9 and 1/4 to a common denominator

so lets do 36,

7 x 4 = 28

9 x 4 = 36

1 x 9 =9

4 x 9 =36

28/36 + 9/36 = 1 1/36

1+8 = 9

Madison will have $322.65 in her bank account in 10 years. Here is the calculation to find this amount:

Starting balance: $200

Year 1: $200 x 1.05 = $210

Year 2: $210 x 1.05 = $220.50

Year 3: $220.50 x 1.05 = $231.53

...

Year 10: $279.10 x 1.05 = $322.65

Therefore, after 10 years, Madison will have $322.65 in her bank account due to the annual interest earned.

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The equation of the tangent line to the given path at the specified value of t is (x - sin(3), 3cos(3)(y - cos(3)), -3sin(3)(z - 1), 9/2).

To determine the equation of the tangent line to the given path at the specified value of t, we need to find the derivative of the given path with respect to t. The derivative of the given path is (3cos(3t), -3sin(3t), 9t^8/2). Now, we can plug in the specified value of t = 1 to find the slope of the tangent line at that point. The slope of the tangent line at t = 1 is (3cos(3), -3sin(3), 9/2).

Next, we can find the point on the given path at t = 1 by plugging in the specified value of t into the original equation. The point on the given path at t = 1 is (sin(3), cos(3), 1).

Finally, we can use the point-slope form of an equation to find the equation of the tangent line. The equation of the tangent line in (x, y, z) coordinates is (x - sin(3)) = 3cos(3)(y - cos(3)) = -3sin(3)(z - 1) = 9/2.

Therefore, the equation of the tangent line to the given path at the specified value of t is (x - sin(3), 3cos(3)(y - cos(3)), -3sin(3)(z - 1), 9/2).

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