what is the second longest wavelength for a standing wave on a wire with one fixed end and one open end that is 3.0 m long?
define nuclear energy
Answer:
Nuclear energy is the energy stored in atoms that can produce electricity.
Hope that helps. x
Which would ba another example of newtons first law?
The velocity of an ocean wave is 5m/s. The distance between crests is 3m. What is the frequency of the wave
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
1.67m
5m/s
Explanation:
Wavelength of the wave = 3m
Speed of the wave = 5m/s
The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.
To find the frequency ;
V = f∧
V is the speed of the wave
f is the frequency
∧ is the wavelength
Insert the parameters and find the frequency;
f = V/ ∧ = 5 / 3 = 1.67Hz
The rate at which the wave passed a given point is the speed of the wave and it is 5m/s
What is the boiling point of water?
Group of answer choices
373.15 degrees Fahrenheit
373.15 degrees Celsius
373.15 Kelvin
Answer:
373.15 Kelvin
Explanation:
Boiling Point of water
= 100 degree Celsius
= (100 + 273.15) Kelvin
= 373.15 Kelvin
Two hockey players are skating toward each other on a frictionless ice. One is moving at 1 m/s while the other is traveling at 2 m/s. The players collide and stick together. Find their combined speed.
Their combined speed will be 1m/s
Given the following parameters;
The velocity of the first hockey player is 1m/s.The velocity of the second hockey player is 2m/s.If the player collides and stick together, the combined speed is expressed as;
Combined speed = differences in velocityCombined speed = 2m/s - 1m/sCombined speed = 1m/s.Hence their combined speed will be 1m/s
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A 2,000 kg car, initially traveling at a speed of 15 m/s, is accelerated by a constant force of 10,000 N for 3 seconds. The new speed of the car is
Answer:
The new speed of the car is 30 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
How do you un rewrap something?
yes that.
Read the excerpt below and then answer the question that follows:
The Book of Dragons
Chapter III The Deliverers of Their Country, an excerpt
By E. Nesbit
It all began with Effie's getting something in her eye. It hurt very much indeed, and it felt something like a red-hot spark—only it seemed to have legs as well, and wings like a fly. Effie rubbed and cried—not real crying, but the kind your eye does all by itself without your being miserable inside your mind—and then she went to her father to have the thing in her eye taken out. Effie's father was a doctor, so of course he knew how to take things out of eyes.
When he had gotten the thing out, he said: "This is very curious." Effie had often got things in her eye before, and her father had always seemed to think it was natural—rather tiresome and naughty perhaps, but still natural. He had never before thought it curious.
Effie stood holding her handkerchief to her eye, and said: "I don't believe it's out." People always say this when they have had something in their eyes.
"Oh, yes—it's out," said the doctor. "Here it is, on the brush. This is very interesting."
Effie had never heard her father say that about anything that she had any share in. She said: "What?"
The doctor carried the brush very carefully across the room, and held the point of it under his microscope—then he twisted the brass screws of the microscope, and looked through the top with one eye.
"Dear me," he said. "Dear, dear me! Four well-developed limbs; a long caudal appendage; five toes, unequal in lengths, almost like one of the Lacertidae, yet there are traces of wings." The creature under his eye wriggled a little in the castor oil, and he went on: "Yes; a bat-like wing. A new specimen, undoubtedly. Effie, run round to the professor and ask him to be kind enough to step in for a few minutes."
"You might give me sixpence, Daddy," said Effie, "because I did bring you the new specimen. I took great care of it inside my eye, and my eye does hurt."
The doctor was so pleased with the new specimen that he gave Effie a shilling, and presently the professor stepped round. He stayed to lunch, and he and the doctor quarreled very happily all the afternoon about the name and the family of the thing that had come out of Effie's eye.
But at teatime another thing happened. Effie's brother Harry fished something out of his tea, which he thought at first was an earwig. He was just getting ready to drop it on the floor, and end its life in the usual way, when it shook itself in the spoon—spread two wet wings, and flopped onto the tablecloth. There it sat, stroking itself with its feet and stretching its wings, and Harry said: "Why, it's a tiny newt!"
The professor leaned forward before the doctor could say a word. "I'll give you half a crown for it, Harry, my lad," he said, speaking very fast; and then he picked it up carefully on his handkerchief.
"It is a new specimen," he said, "and finer than yours, Doctor."
It was a tiny lizard, about half an inch long—with scales and wings.
So now the doctor and the professor each had a specimen, and they were both very pleased. But before long these specimens began to seem less valuable. For the next morning, when the knife-boy was cleaning the doctor's boots, he suddenly dropped the brushes and the boot and the blacking, and screamed out that he was burnt.
And from inside the boot came crawling a lizard as big as a kitten, with large, shiny wings.
"Why," said Effie, "I know what it is. It is a dragon like the one St. George killed."
And Effie was right. That afternoon Towser was bitten in the garden by a dragon about the size of a rabbit, which he had tried to chase, and the next morning all the papers were full of the wonderful "winged lizards" that were appearing all over the country. The papers would not call them dragons, because, of course, no one believes in dragons nowadays—and at any rate the papers were not going to be so silly as to believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail and great wings like bats' wings, only the wings were a pale, half-transparent yellow, like the gear-boxes on bicycles.
Based on the rising action in the bolded paragraphs, what do we know about Daddy? (5 points)
He is calm and curious.
He is angry and upset.
He is hysterical.
He is uninterested and bored.
believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail.
Explanation:
YOUR WELCOME :)
Answer:
its "calm and curious"
Explanation:
hope tis helps!!!
a truck in a traffic circle travels in a circular path at constant speed v0 while passing through region x of the circle, as shown in figure 1 above. a diagram representing the forces exerted on the truck in region x is shown in figure 2. at a later time a car with less mass than the truck passes through region x at the same speed and the same distance from the center of the traffic circle as the truck. the coefficient of friction between the car’s tires and the ground is the same as that for the truck’s tires and the ground. which of the following diagrams could represent the forces exerted on the car in region x compared to the truck in region x ? assume that the length of each arrow is proportional to the magnitude of the force represented by the arrow.
The Diagram that represents the forces exerted on the car in region x when compared to the truck in region X is : Diagram C
Given that the mass of the car is less than the mass of the truck the force due to gravity will be greater on the truck than it could be on the car
i.e. | Fg |car < | Fg | truck
also : | Fₙ | car < | Fₙ | truck
Since the gravitational force on the car is less than the gravitational force on the truck
| Ff | car < | Ff | truck
where : Ff = frictional force
Fg = force due to gravity
Fn normal force
Therefore from the diagrams attached below the correct diagram that represents the forces exerted on the car in region x when compared to the truck in region X is : Diagram C.
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Attached below is the missing data related to your question
John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s
The horizontal component of the velocity is equal to: D. 15 m/s.
Given the following data:
Velocity = 30 m/sAngle = 60°To determine the horizontal component of the velocity:
The horizontal component of the velocity represents the influence of velocity in displacing an object or projectile in the horizontal direction.
Mathematically, the horizontal component of velocity is given by the formula:
[tex]V_x = Vcos(\theta)[/tex]
Substituting the given parameters into the formula, we have;
[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]
Horizontal component, Vx = 15 m/s
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How would you describe the motion of a transverse wave
With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s
[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]
[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]
[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]
[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]
[tex]\\ \sf\longmapsto s=55+121[/tex]
[tex]\\ \sf\longmapsto s=176m[/tex]
what planets experience an eclipse from the sun
Answer:
Earth
Explanation:
The sun and the moon come together and they seem like one bonded.
Two sections of genetic material from a fruit fly are shown in the diagram.
X
-Eye color
-Wing shape
What does the diagram reveal about the inherited traits of fruit flies?
А Inherited traits are controlled by tissues, which are found in organs.
B
Inherited traits are controlled by organs, which are found in tissues.
с
Inherited traits are controlled by genes, which are found in chromosomes.
OD
Inherited traits are controlled by chromosomes, which are found in genes.
the answer is c, inherited traits are controlled by genes, which are found in chromosomes
What is the change in velocity of a 1068 kg truck that experiences an impulse of 440 N ⋅ s? Include 2 decimal places in your answer.
Answer:
try 2.4136 as an answer/ good luck
what has to increase in order for an object to accelerate?
Answer:
Answer: B. Explanation: For an object to accelerate the force on it must be increased. According to Newton's second law of motion.
Explanation:
I do Accelerate to good luck
according to newton, doubling the distance between two interacting objects:
Answer:
So as two objects are separated from each other, the force of gravitational attraction between them also decreases. If the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power).
Explanation:
hope his helps
Tim is pushing a heavy box across the floor. He is using 300N of force and can accelerate at 2m/s/s. What is the mass of the box?
-298 kg
-600 kg
-0.006 kg
-150 kg
Using Newton's second law
[tex]\\ \sf\Rrightarrow F=ma[/tex]
[tex]\\ \sf\Rrightarrow 300=2m[/tex]
[tex]\\ \sf\Rrightarrow m=150kg[/tex]
Hey there!
The formula of “mass” in physics is:
m = F/a
Whereas “f” is ‘force’, “a” is ‘acceleration’, & “m” is your ‘mass’ of course.
mass = 300 Net force/2 acceleration
300 Net force/2 acceleration = m
mass = 150
Therefore, your answer is: 150 kg
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
What is the momentum of a 5 kg object that has a velocity of 1. 2 m/s? 3. 8 kg • m/s 4. 2 kg • m/s 6. 0 kg • m/s 6. 2 kg • m/s.
Answer:
6 kg.m/s
Explanation:
Momentum is the product of mass and velocity. So,
p = mvHere,
p denotes momentum [?]m denotes mass [5kg]v denotes velocity [1.2 m/s]→ p = 5 kg × 1.2 m/s
→ p = (5 × 1.2) kg.m/s
→ p = (5 × 12/10) kg.m/s
→ p = 12/2 kg.m/s
→ p = 6 kg.m/s
Therefore, momentum of the object is 6 kg.m/s.
The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
MOMENTUM:Momentum of a substance is the product of its mass and velocity. That is;
Momentum (p) = mass (m) × velocity (v)
According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:
Momentum = 5kg × 1.2m/s
Momentum = 6kgm/s.
Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
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The frequency of a wave is 4hz. If the wavelength is 2m how fast is the water moving?
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
This is the answer that I got
Explanation:
Hope it is right.
the maximum displacement of a particle by a wave is called
Classify the statement below as either Speed or Velocity?
A jeep was driving 40 mph
heading to the grocery store.
Answer:
Hello There!
It is Speed.
[tex]\Large\bold\red{Reason}[/tex]
Because in the question it is said that at which speed car is travelling.
Speed is a scalar quantity.
If it is velocity then first know this that it is a vector quantity.
It must include both magnitude and direction.
If it is velocity then it would be 40 mph east or west or north or south.
I hope it is helpful to you...Cheers!_____________Which design of the walls would be most desirable help avoid echoes?
A
They should use bumpy walls for all four sides.
B
They should use bumpy walls for only one side.
С
They should use smooth walls for all four sides.
D
They should use smooth walls for only one side.
Answer:
a
Explanation:
because the sound wont bounce off
1. Which of the following types of energy is
potential energy? More than one answer is
possible,
A kinetic energy
B.thermal energy
C.sound energy
D.gravitational energy
Answer:
Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.
can someone explain please?
Hi there!
We can begin by solving for the velocity in which the ball was thrown at using the following:
[tex]v_f^2 = v_i^2 + 2ad[/tex]
At the top of the trajectory, the ball's velocity is equal to 0 m/s, so:
[tex]0 = v_i^2 + 2ad\\\\vi^2 = 2ad \\\\[/tex]
'a' = acceleration due to gravity and 'd' is the max height, so:
[tex]v_i^2 = 2(10)(5)\\\\v_i^2 = 10 m/s[/tex]
Now, we can use the same equation to calculate the final speed at 4.5 m. Remember, the acceleration is NEGATIVE in this instance (taking the negative direction to be in the direction of gravity).
[tex]v_f^2 = 10^2 - 2(10)(4.5)[/tex]
[tex]v_f^2 = 10^2 - 2(10)(4.5)\\\\v_f^2 = 100 - 90 \\\\v_f^2 = 10 \\\\v_f = \boxed{3.1 m/s}[/tex]
What is the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4 m/s? (Formula: ) 3 J 6 J 12 J 24 J.
The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
HOW TO CALCULATE KINETIC ENERGY:
The kinetic energy of a moving body can be calculated by using the following formula:
K.E = ½mv²
Where;
K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:
K.E = ½ × 0.75 × 4²
K.E = 8 × 0.75
K.E = 6J
Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
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SOMEONE, PLEASE HELP ME AS FAST AS YOU CAN, I WOULD GIVE MORE POINTS BUT THIS IS THE REST OF MY POINT, PLEASE SOMEONE WHO IS SUPER KIND HELP ME.
Answer:
1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time
2. 36÷4= 9
(formula) Speed = distance ÷ time
3. Meter (M) centimeter (cm) kilometers (km)
4. Seconds , Hour, Minute
5. 65÷13=5 (object A)
125÷ 25= 5 (object B)
their both Equal of the amount of speed, so they are travelling at the same speed
Hope I helped
Plz help!
A person walks the path shown
below. The total trip consists of
four straight-line paths. At the end of the walk, what is the person's
resultant displacement measured from the starting point?
The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:
Graphic. In this case, the origin of a vector is placed at the tip of the previous one and the resulting vector goes from the origin of the first vector to the tip of the last, this method is not very precise. Analytical. In this method the vectors are decomposed into a coordinate system, the sum of the components is performed and the resulting vector is built, this method is very expensive.
Indicate in the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.
Vector A.
Aₓ = 100.0 m
Vector B.
B_y = -300.0 m
The negative sign indicates that it goes in the negative direction of the y-axis
Vector C.
We use trigonometry.
The angle measured from the positive side of the x-axis counterclockwise is
θ = 180 + 30 = 210
sin 210 = [tex]\frac{C_y}{C}[/tex]
cos 210 = [tex]\frac{C_x}{C}[/tex]
C_y = C sin 210
Cₓ = C cos 210
C_y = 150.0 sin 210 = -75.0 m
Cₓ = 150.0 cos 210 = -129.9 m
Vector D.
The angle from the positive side of the x-axis counterclockwise.
θ = 180-60 = 120º
sin 120 = [tex]\frac{D_y}{D}[/tex]
cos 120 = [tex]\frac{D_x}{D}[/tex]
D_y = D sin 120
Dₓ = D cos 120
D_y = 200.0 sin 120 = 173.2 m
Dₓ = 200.0 cos 120 = -100.0 m
we add the component with algebraic sum.
x = Aₓ + Cₓ + Dₓ
y = B_y + C_y + D_y
x = 100 - 129.9 -100 = -129.9 m
y = -300 - 75.0 + 173.2 = -201.8 m
We construct the resulting vector.
We use the Pythagorean theorem for the Modulus.
[tex]R+ \sqrt{x^2 +y^2}[/tex]
R = [tex]\sqrt{129.9^2 + 201.8^2 }[/tex]
R = 239.99 m
We use trigonometry for the angle.
tan θ = [tex]\frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{201.8}{129.9}[/tex]tan-1 (201.8 / 129.9)
θ = 57.2º
Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.
θ = 270 - θ'
θ = 270 - 57.2
θ = 212.8º
In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
Learn more about vector addition here: brainly.com/question/24855749
Mike drops a rock from the top of a suspension bridge. If the rock falls for 4.88 seconds,
how high is the bridge?
This question involves the concepts of the equations of motion in vertical direction.
The height of the bridge is "116.8 m".
We will use the second equation of motion in vertical direction to find out the height of the bridge.
[tex]h=v_it+\frac{1}{2}gt^2\\\\[/tex]
where,
h = hieght = ?
vi = initial speed = 0 m/s
t = time taken = 4.88 s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h=(0\ m/s)(4.88\ s)+\frac{1}{2}(9.81\ m/s^2)(4.88\ s)^2[/tex]
h = 116.8 m
Learn more about the equations of motion here:
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