4. Taylor Swift pushes Kanye West,
headfirst fearless, off a high dive with and
initial speed of 6m/s. If the platform is 20m
high, what is Kanye's impact velocity with
the water? (velocity and angle)

Answer:

Conductivity, [tex]\sigma=500\ (\Omega-m)^{-1}[/tex]

Explanation:

Given that,

The resistivity of a material, [tex]\rho=2\times 10^{-3}\ \Omega-m[/tex]

We need to find the conductivity of the material.

We know that the reciprocal of resistivity is called conductivity.

[tex]\sigma=\dfrac{1}{\rho}\\\\\sigma=\dfrac{1}{2\times 10^{-3}}\\\\\sigma=500\ (\Omega-m)^{-1}[/tex]

So, the conductivity of the material is [tex]500\ (\Omega-m)^{-1}[/tex].

Answer:

When we have a plane interface, the angle of incidence of the ray is the same as the angle of reflection.

In this case, we have a mirror (we assume that it is plane) and we know that we need to have an angle of reflection equal to 38° in order to reach Sam.

Then the angle of incidence of the ray must also be exactly 38°.

Then Billy needs to shine his laser at an angle of 38° at the mirror.

(where the angle is measured between the normal line to the surface of the mirror and the incident ray)

Billy needs to shine the laser at an incident angle of 38 degrees.

LASER is an acronym that stands for “light amplification by the stimulated emission of radiation.” We know that according to the laws of reflection, the angle of incidence is equal to the angle of reflection.

As such, knowing that Sam is at a 38 degree reflection angle from the mirror, Billy needs to shine the laser at an incident angle of 38 degrees.

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Answer:

[tex]F_N>F_N'[/tex]

Explanation:

From the question we are told that

Radius of curvature[tex]r=100m[/tex]

Mass [tex]M=300kg[/tex]

initial Speed of Motorcycle  [tex]V_1=30m/s[/tex]

Final  Speed of Motorcycle  [tex]V_2=33m/s[/tex]

Generally the equation Force at initial speed is  mathematically given as

[tex]F_N=mg-\frac{mv^2}{R}[/tex]

[tex]F_N=300*9.8-\frac{(300*30)^2}{100}[/tex]

[tex]F_N=240N[/tex]

Generally the equation Force at Final speed is  mathematically given as

[tex]F_N'=mg-\frac{mv'^2}{R}[/tex]

[tex]F_N'=300*9.8-\frac{(300*33)^2}{100}[/tex]

[tex]F_N'=-327N[/tex]

Therefore

[tex]F_N>F_N'[/tex]

Following are the calculation to the given question:

Solution:

Using formula:

[tex]\to mg - F^{'}_N=\frac{mv^{2}}{R} \\[/tex]

Calculating the Initial value:    

[tex]\to F_N = mg - \frac{mv^2}{R}\\\\[/tex]

          [tex]= 300 \times (9.8 - \frac{(30)^2}{100}) \\\\= 300 \times (9.8 - \frac{900}{100}) \\\\= 300 \times (9.8 - 9) \\\\= 300 \times (0.8) \\\\ = 240\ N \\\\[/tex]

Calculating the Final value:

[tex]\to F^{'}_{N}= 300 (9.8 -\frac{33^2}{100})\\\\[/tex]

          [tex]= 300 (9.8 -\frac{1089}{100})\\\\= 300 (9.8 - 10.89)\\\\= 300 (- 1.09)\\\\=-327[/tex]

Therefore, the answer is "the new normal force is less than [tex]F_{N}[/tex]" or [tex]\bold{F^{'}_{N}< F_{N}}[/tex].

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Answer: 0.24 m/s

Explanation:

Answer:

The calculation that you then need to do is 25000 x 0.0136 = 340. You must not forget the units of speed, which here are metres per second, or m/s. Your final answer is 340 m/s.

Answer:

3 bending

Explanation:

Answer:

The starting velocity.

Explanation:

We must understand that this equation comes from the following equation of kinematics.

[tex]v_{f}=v_{o}+a*t[/tex]

where:

Vf = final velocity = 33 [m/s]

Vo = starting velocity [m/s]

a = acceleration = 3 [m/s²]

t = time = 30 [s]

So, these values can be assembly in the following way:

[tex]v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}[/tex]

Answer:

grams

Explanation:

Answer:

1.825 miles

Explanation:

Given that :

Distance driven = hypotenus = 1.5 miles

Elevation at distance of 1.5 miles = 510 feets

Converting miles to feets for the hypotenus :

1 mile = 5280 feets

1.5 miles = (5280 * 1.5) = 7920 feets

To obtain the angle of inclination :

Using Pythagoras rule :

Sinθ = opposite / hypotenus

θ = Sin^-1(510 / 7920)

θ = 3.692°

For an additional elevation of 110 ft ; new height = 110 + 510 = 620 feets

Distance driven, d =?

Sin 3.69 = (620 / d)

0.0643581 * d = 620

d = 620 / 0.0643581

d = 9633.5970 feets

Converting to feets :

9633.5970 / 5280 = 1.8245448

= 1.825 miles

Answer:

1.56×10¯¹⁰ V.

Explanation:

From the question given above, the following data were obtained:

Capicitance (C) = 0.9 MF

Quantity of electricity (Q) = 1.4x10¯⁴ C

Potential difference (V) =?

Next, we shall convert 0.9 MF to farad (F). This can be obtained as follow:

1 MF = 10⁶ F

Therefore,

0.9 MF = 0.9 MF × 10⁶ F / 1 MF

0.9 MF = 9×10⁵ F

Finally, we shall determine the potential difference. This can be obtained as follow:

Capicitance (C) = 9×10⁵ F

Quantity of electricity (Q) = 1.4x10¯⁴ C

Potential difference (V) =?

Q = CV

1.4x10¯⁴ = 9×10⁵ × V

Divide both side by 9×10⁵

V = 1.4x10¯⁴ / 9×10⁵

V = 1.56×10¯¹⁰ V

Therefore, the potential difference is 1.56×10¯¹⁰ V.

Answer: The Boat will rise

Explanation: Because high amplitude means high in heights.

Answer:

Explanation:

Cheetahs can go from 0 to 60 miles per hour in just 3.4 seconds and reach a top speed of 70 miles per hour. While they are the fastest land animal in the world, they can only maintain their speed for only 20 to 30 seconds.

Answer:

x = 41.2 m

Explanation:

The electric force is a vector magnitude, so it must be added as vectors, remember that the force for charges of the same sign is repulsive and for charges of different sign it is negative.

In this case the fixed charges (q₁ and q₂) are positive and separated by a distance (d = 100m), the charge (q₃ = -1.0 10⁻³ C)) is negative so the forces are attractive, such as loads q₃ must be placed between the other two forces subtract

             F = F₁₃ - F₂₃

let's write the expression for each force, let's set a reference frame on the charge q1

           F₁₃ = [tex]k \frac{q_1 q_3}{x^2}[/tex]

           F₂₃ = [tex]k \frac{q_2 q_3}{(d-x)^2}[/tex]

they ask us that the net force be zero

           F = 0

           0 = F₁₃ - F₂₃

           F₁₃ = F₂₃

          k \frac{q_1 q_3}{x^2} =k \frac{q_2 q_3}{(d-x)^2}

          [tex]\frac{q_1}{x^2} = \frac{q_2}{(d-x)^2 }[/tex]q1 / x2 = q2 / (d-x) 2

           (d-x)² = [tex]\frac{q_2}{q_1}[/tex] x²

we substitute

           (100 - x)² = 2/1  x²

           100- x = √2  x

           100 = 2.41 x

           x = 41.2 m

Answer:

It should be Mass, Gravity and Height

Explanation:

No

because that is a light

The light travel faster in fresh water as compare to sea water.

Hence, the light travel faster in fresh water as compare to sea water.

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Answer:

Explanation:

The net force is in the same direction of the acceleration. Acceleration changes the speed of an object.

Answer:

Both charges must have the same charge, Qt/2.

Explanation:

Let the two charges have charge Q1 and Q2, respectively.

Use Coulombs's Law to find an expression for the force between the two charges.

[tex]F = k_e\frac{Q_1Q_2}{r^2}[/tex], where

Ke is Coulomb's contant and

r is the distance between the charges.

We know from the question that

Q1 + Q2 = Qt

So,

Q2 = Qt - Q1

[tex]F = k_e\frac{Q_1(Q_t - Q_1)}{r^2}[/tex]

Simplify to obtain,

[tex]F = \frac{k_e}{r^2} (Q_tQ_1 - Q_1^2)[/tex]

In order to find the value of Q1 for which F is the maximum, we will use the optimization technique of calculus.

Differentiate F with respect to Q1,

[tex]\frac{dF}{dQ_1} = \frac{k_e}{r^2} (Q_t - 2Q_1)[/tex]

Equate the differential to 0, to obtain the value of Q1 for which F is the maximum.

[tex]\frac{k_e}{r^2} (Q_t - 2Q_1) = 0\\Q_t - 2Q_1 = 0\\2Q_1 = Q_t\\Q1 = \frac{Q_t}{2}[/tex]

It follows that

[tex]Q_2 = \frac{Q_t}{2}[/tex].

Answer:

The two main types of bonds formed between atoms are ionic bonds and covalent bonds.

Explanation:

Hope this helped <3

Answer:

  F = 69.3 N

Explanation:

For this exercise we use Newton's second law, remembering that the static friction force increases up to a maximum value given by

               fr = μ N

We define a reference system parallel to the floor

block B  ( lower)

Y axis  

            N - W₁-W₂ = 0

            N = W₂ + W₂

            N = (M + m) g

X axis

              F -fr = M a

for block A (upper)

X axis

              fr = m a                 (2)

so that the blocks do not slide, the acceleration in both must be the same.

Let's solve the system by adding the two equations

             F = (M + m) a          (3)

             a =[tex]\frac{F}{ M+m}[/tex]

the friction force has the formula

            fr = μ N

             fr = μ (M + m) g

let's calculate

            fr = 0.34 (2.0 + 0.250) 9.8

            fr = 7.7 N

we substitute in equation 2

             fr = m a

             a = fr / m

             a = 7.7 / 0.250

             a = 30.8 m / s²

we substitute in equation 3

             F = (2.0 + 0.250) 30.8

             F = 69.3 N

Answer: 1. The law of consevation of energy sates that energy can neither be created nor destroyed. It can only be transformed or transfered from one form to another. The law of conservation of energy is found everywhere for example, Water falls from the sky, converting potential energy to kinetic energy.

2. Different forms of energy are related because energy cannot be created or destroyed. they can all be transformed into from one form to another.

Explanation:

Answer:

105 kg.m/s

Explanation:

Formula for change in momentum is given as;

ΔP = m(v - u)

We are given;

Mass; m = 35 kg

Initial velocity; u = 3 m/s

Final velocity; v = 6 m/s

Thus;

ΔP = 35(6 - 3)

ΔP = 35 × 3

ΔP = 105 kg.m/s

Answer:

weight

Explanation:

weight is the pull of gravity so its a force !!

Answer:

the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

Explanation:

We can analyze this exercise from several points of view, if we use Newton's second law

Bowling ball

           F = M a₁

pingpongg ball

           F = m a₂

as the forces the same

          M a₁ = m a₂

          a₂ = [tex]\frac{M}{m}[/tex] a₁

Since the mass of the bowling ball is much greater than the ping pong ball,

          a₂ »a₁

so the acceleration of the ping pong ball is much greater than the acceleration of the bowling ball.

If we use the relationship of momentum and momentum, assuming that the time for the two cases is the same and that both start from rest

Bowling ball

           I = F t = Δp

           I = M (v₁ - v₀)

Ping pong ball

           I = F t = Δp

           I = m (v₂ -v₀)

the impulse itself

          M v₁ = m v₂

          v₂ = [tex]\frac{M }{ m}[/tex] v₁

so we conclude that the speed of the ping pong ball is much greater than the speed of the bowling ball.

In conclusion the speed and aceleration of the ping pong ball is greater than that of the bowling ball.

Answer:

a)  v = 4.37 10⁶ m / s,  speed is much less than c

b)     v = 2.01 10⁸  m / s,  this value is 67% of the speed of light, , for which relativistic corrections should be used

Explanation:

The bohr model for the hydrogen atom and dendroids is a classical model with a quantization of the angular momentum

let's start by using Newton's second law with the electric force

         F = m a

Coulomb's law electric force

         F = [tex]k \frac{q_1q_2}{r^2}[/tex]

in this case in an atom the number of protons is equal to the atomic number and there is only one electron

        q₁ = Ze

        q₂ = e

acceleration is centripetal

         a = v² / r

we substitute

        [tex]k \frac{Z e^2}{r^2} = m \frac{v^2}{r}[/tex]

        v² =  [tex]k \frac{Ze^2}{m r}[/tex]

quantization is imposed without justification in this model,

       L = p x r = n [tex]\hbar[/tex]

       \hbar= h /2π

if we consider circular orbits, the speed and position are perpendicular

       m v r = n \hbar

       r = [tex]\frac{n \hbar}{m v}[/tex]

we substitute

     v² = [tex]k \frac{Z e^2}{m} \frac{m v}{n \hbar}[/tex]

     v = [tex]k \frac{Z e^2 }{ n \hbar}[/tex]

let's apply this equation

     \hbar= h / 2π

     \hbar= 6.626 10-34 / 2π

     \hbar= 1.05456 10⁻³⁴ J s

a) He1 ion,  the atomic number of helium is 2

      v =  [tex]\frac{9 \ 10^9 \ 2 ( 1.6 \ 10^{-19})^2 }{n \ 1.0546 \ 10^{-34}}[/tex]

       v =4.3695 10⁶ / n m / s

the ground state occurs for N = 1

        v = 4.37 10⁶ m / s

the relationship of this value to the speed of light is

        v / c = 4.37 10⁶/3 10⁸

        v / c = 1.46 10⁻²

speed is much less than c

b) the uranium ion with atomic number Z = 92

       v = [tex]\frac{9 \ 10^9 \ 92 ( 1.6 \ 10^{-19})^2 }{n \ 1.054 \ 10^{-34} }[/tex]

       v = 2.01 10⁸  m / s

       v/c = [tex]\frac{2.01 \ 10^8 }{3 \ 10^8}[/tex]

       v/c =  0.67

this value is 67% of the speed of light, for atoms with a higher atomic number the effects are increasingly important, for which relativistic corrections should be used

Answer:

1.Lactose

I Hope its help for you

Have a good day