Answer:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. The total momentum of the trolleys after separation is zero
c. The momentum of the 2 kg trolley after separation is 12 kg·m/s
d. The momentum of the 3 kg trolley is -12 kg·m/s
e. The velocity of the 3 kg trolley = -4 m/s
Explanation:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0
c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s
d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s
e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley
∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s
The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s
a-The total momentum of the trolleys before separation=0
b.The total momentum of the trolleys after separation=0
c. The momentum of 2kg trolley after separation=12kg-m/sec
d. The momentum of 3kg trolley after separation=-12kg-m/sec
e. The velocity of the 3kg trolley=4kg-m/sec
Given-
Trolley A with mass= 2kg
Trolly B with mass= 3kg
Velocity of trolly A =6m/sec
A- Total momentum of the trolleys before separation-
Here, in this problem both the trolleys are in the rest position hence the momentum of both trolleys = 0
B- Total momentum of the trolleys after separation-
We know that motion never changes in an isolated collection of objects,
hence the momentum of the trolleys before and after the separation=0
C- Momentum of the Trolley A (2kg)-
It is known that momentum= Mass x Velocity
[tex]P=m\times v[/tex]
[tex]P=2\times 6[/tex]
[tex]P=12[/tex]
Hence, the momentum of the 2kg trolley is 12 kg-m/sec
D- Momentum of the Trolley B (3kg)-
As we know that motion never changes in an isolated collection of an object hence the total moment of after saparation = 0
hance the momentum of the trolley B will be equal and opposite to the momentum of trolley A=
[tex]P= -12[/tex]
Momentum of trolley B (3kg) is -12kg-m/sec
E- The velocity of the 3kg trolley-
The momentum of trolley A= Momentum of trolley B
[tex]m_{b} v_{a} =m_{b} v_{a}[/tex]
[tex]-2\times 6=3\times v_{a}[/tex]
[tex]v_{a}=-4[/tex]
The value of the velocity of the 3kg trolley is -4m/sec
For more about the momentum, follow the link below-
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Explanation:
What is the pigment in the leaves called?
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2.Green
3.Stroma
4.Chlorophyll
Answer: D: Chloroplasts
Explanation:
Answer: d
Explanation:
Two identical spheres (of equal mass) a distance of 10 meters apart exert a force of gravity of 0.00050 N on each other. What are their masses?
Answer:
The gravitational force between two objects is written as:
F = G*m1*m2/r^2
Where:
G = 6.67*10^(-11) m^3/kg*s
m1 and m2 are the masses of the objects.
r is the distance between the objects.
In this case, we know that:
F = 0.0005 N
r = 10m
and because the two spheres are identical, we have that:
m1 = m2 = M
then we have the equation:
0.0005 N = (6.67*10^(-11) m^3/kg*s)*(M^2/(10m)^2)
0.0005 N*(10m)^2/(6.67*10^(-11) m^3/kg*s) = M^2
√( 0.0005 N*(10m)^2/(6.67*10^(-11) m^3/kg*s) ) = M = 27,379.3 kg
The mass of each sphere is 27,379.3 kg